Restlet - JUnit - testing MULTIPART_FORM_DATA form Post - junit

Question

I was wondering what the best way to use JUnit to test a Resource for a Form post?
On a #Get I get service values via a Resource with the following:
#Test
public void testGetCollections() throws Exception {
String url ="http://localhost:14502/api/v1/collections";
Client client = new Client(Protocol.HTTP);
ChallengeResponse challengeResponse = new ChallengeResponse(ChallengeScheme.HTTP_BASIC,"user", "f399b0a660f684b2c5a6b4c054f22d89");
Request request = new Request(Method.GET, url);
request.setChallengeResponse(challengeResponse);
Response response = client.handle(request);
System.out.println("request"+response.getStatus().getCode());
System.out.println("request test::"+response.getEntityAsText());
assertEquals(200, response.getStatus().getCode());
ObjectMapper mapper = new ObjectMapper();
List<Collection> collectionList = mapper.readValue(response.getEntityAsText(), new TypeReference<List<Collection>>(){});
for(Collection collection : collectionList){
System.out.println("TITLE: "+collection.getTitle());
}
assertTrue(collectionList.size()>0);
}
On the #Post I'm trying to do the following:
#Test
public void testPostCollections() throws Exception {
String url ="http://localhost:14502/api/v1/collections";
Client client = new Client(Protocol.HTTP);
ChallengeResponse challengeResponse = new ChallengeResponse(ChallengeScheme.HTTP_BASIC,"user", "f399b0a660f684b2c5a6b4c054f22d89");
Request request = new Request(Method.POST, url);
ClientInfo info = new ClientInfo(MediaType.APPLICATION_JSON);
info.getAcceptedMediaTypes().add(
new Preference<MediaType>(MediaType.APPLICATION_JSON));
request.setClientInfo(info);
request.setEntity(
"collectionName=testCollection123&collectionDescription=testCollectionDescription123",
MediaType.MULTIPART_FORM_DATA);
request.setChallengeResponse(challengeResponse);
Response response = client.handle(request);
//boolean valid = false;
System.out.println("request"+response.getStatus().getCode());
System.out.println("request test::"+response.getEntityAsText());
assertEquals(200, response.getStatus().getCode());
}
I'm getting the following 500 error:
The server encountered an unexpected condition which prevented it from fulfilling the request.
BASED ON THE BELOW POSTED ANSWER I MADE THE FOLLOWING WORKING METHOD:
#Test
public void testAssetsPost() throws Exception {
ClientResource cr = new ClientResource("http://localhost:14502/api/v1/ass");
FormDataSet fds = new FormDataSet();
fds.getEntries().add(new FormData("metaData", "metaDataTest123"));
fds.setMultipart(true);
FormData fileRep = new FormData("file",
new FileRepresentation(new File("/Users/og/Documents/gump.jpg"),
MediaType.IMAGE_JPEG));
fds.getEntries().add(fileRep);
FormData fileRep2 = new FormData("associatedDoc",
new FileRepresentation(new File("/Users/og/Documents/gump.jpg"),
MediaType.IMAGE_JPEG));
fds.getEntries().add(fileRep2);
Representation r = null;
try{
r = cr.post(fds);
} catch (ResourceException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println( "Got Context: " + cr.getContext() );
System.out.println( "Got Response: " + cr.getResponse());
System.out.println( "Got Resonse Attribute : " + cr.getResponseAttributes() );
System.out.println( "Got Resonse Entity: " + cr.getResponseEntity() );
System.out.println("Got response !! , response : " + r.getText());
System.out.println(r.getText());
}

Answer 1

I don't know what is exactly the error you encountered within your server application. I would be interesting if we could have a stacktrace.
That said, you can build programmatically HTML forms using the org.restlet.ext.html extension. For more details, you could read this blog post: http://restlet.com/blog/2015/10/27/implementing-file-upload-with-restlet-framework/.
At a first sight, the media type isn't correct since you don't send a multipart form but a simple form. So you should use MediaType.APPLICATION_WWW_FORM instead of MediaType.MULTIPART_FORM_DATA.
A sample for a form containing a file:
Form fileForm = new Form();
fileForm.add(Disposition.NAME_FILENAME, "myimage.png");
Disposition disposition = new Disposition(Disposition.TYPE_INLINE, fileForm);
FileRepresentation entity = new FileRepresentation(f, MediaType.IMAGE_PNG);
entity.setDisposition(disposition);
And for a simple form:
FormDataSet fds = new FormDataSet();
fds.setMultipart(true);
FormData fdFile = new FormData("fileToUpload", entity);
fds.getEntries().add(fdFile);
FormData fdValue = new FormData("field", "value");
fds.getEntries().add(fdValue);
Hope it helps you,
Thierry