I have a problem with background:
I have 3 child elements.
Each of them got background-image by #nth_image ID.
Also they got background gradient by .background-gradient class.
All png images got alpha channel
The problem is that background-image overwrite background gradient.
As result I want png image on front and gradient on background
.background_gradient {
background: -webkit-radial-gradient(top, ellipse cover, #f9f9f9 0%,#eaeaea 100%);
}
#first_image {
background: url(images/img01.png);
}
#second_image {
background: url(images/img02.png);
}
#third_image {
background: url(images/img03.png);
}
<div class="parent">
<div id="first_iamge" class="background_gradient"></div>
<div id="second_image" class="background_gradient"></div>
<div id="third_image" class="background_gradient"></div>
</div>
Both the gradient and image background utilize the same image property of the background. Its as if you are writing it like this:
.class {
background-image: url('/path/to/image.png');
background-image: -webkit-radial-gradient(top, ellipse cover, #f9f9f9 0%,#eaeaea 100%);
}
so basically you are overwriting the image part of the background with the gradient or vice versa depending on which rule takes precedence over the other.
My suggestion would be to style your markup differently. Have a div inside of the div with the background you want.
<div class="background-gradient">
<div id="first-background"></div>
</div>
If you want to mix 2 types of background on a single element, my suggestion is to use css pseudo element.
You could use the before pseudo element having the same size as your element for your gradient part.
You could have something like this:
.background_gradient {
position: relative;
}
.background_gradient:before {
content: "";
position: absolute;
top: 0;
left: 0;
width: 100%;
height: 100%;
z-index:-1;
background: -webkit-radial-gradient(top, ellipse cover, #f9f9f9 0%,#eaeaea 100%);
}
#first_image {
background: url(images/img01.png);
}
#second_image {
background: url(images/img02.png);
}
#third_image {
position: relative;
background: url(images/img03.png);
}
Related
I am trying to put gradient on an image that is not loaded from the background. in all the examples I've seen, they load the image from the background and do the gradient, but in my case I don't want to have the background image, and when I add the gradient it doesn't do anything. I show you the HTML code:
<section class="fourth_section">
<h1>Nuevos destinos que descubrir</h1>
<ul class="flex_list">
<li class="picture_list_first">
<figure>
<img src="/img/oporto.jpg" alt="imagen1">
</figure>
<div>
<h3>Oporto</h3>
</div>
</li>
and this is what i tried but it doesn't work:
.picture_list_first img {
width: 330px;
height: 332px;
border-radius: 5px;
margin: 0px -20px 0px -30px;
background: rgb(0,0,0);
background: linear-gradient(0deg, rgba(0,0,0,1) 0%, rgba(255,255,255,1) 100%);
}
Thank you all.
the issue with your code is you are adding a background gradient then covering it up with an image so you cant see the gradient any more.
Im not entirely sure what your aim is however if you want to add a semi transparent gradient to your image, you can do that by adding another element on top of your image and style that with the background property.
it seems this question was already answered here:
How to add a gradient/filter in the image in CSS
You can simply add the background to the parent element (div/anchor/whatever) and then make the image semi transparent. See the snippet below -- hover to see the difference
.gradient-img {
background: rgb(131,58,180);
background: linear-gradient(90deg, rgba(131,58,180,1) 0%, rgba(253,29,29,1) 50%, rgba(252,176,69,1) 100%);
display: flex;
}
.gradient-img img {
opacity: 0.5;
width: 100%;
transition: opacity 500ms 0ms ease-in-out;
}
.gradient-img img:hover { opacity: 1 }
<div class="gradient-img"><img src="https://picsum.photos/200"></div>
I have panel which I colored blue if this panel is being selected (clicked on it). Additionally, I add a small sign (.png image) to that panel, which indicates that the selected panel has been already selected before.
So if the user sees for example 10 panels and 4 of them have this small sign, he knows that he has already clicked on those panels before. This work fine so far. The problem is now that I can't display the small sign and make the panel blue at the same time.
I set the panel to blue with the css background: #6DB3F2; and the background image with background-image: url('images/checked.png'). But it seems that the background color is above the image so you cannot see the sign.
Is it therefore possible to set z-indexes for the background color and the background image?
You need to use the full property name for each:
background-color: #6DB3F2;
background-image: url('images/checked.png');
Or, you can use the background shorthand and specify it all in one line:
background: url('images/checked.png'), #6DB3F2;
For me this solution didn't work out:
background-color: #6DB3F2;
background-image: url('images/checked.png');
But instead it worked the other way:
<div class="block">
<span>
...
</span>
</div>
the css:
.block{
background-image: url('img.jpg') no-repeat;
position: relative;
}
.block::before{
background-color: rgba(0, 0, 0, 0.37);
content: '';
display: block;
height: 100%;
position: absolute;
width: 100%;
}
Based on MDN Web Docs you can set multiple background using shorthand background property or individual properties except for background-color. In your case, you can do a trick using linear-gradient like this:
background-image: url('images/checked.png'), linear-gradient(to right, #6DB3F2, #6DB3F2);
The first item (image) in the parameter will be put on top. The second item (color background) will be put underneath the first. You can also set other properties individually. For example, to set the image size and position.
background-size: 30px 30px;
background-position: bottom right;
background-repeat: no-repeat;
Benefit of this method is you can implement it for other cases easily, for example, you want to make the blue color overlaying the image with certain opacity.
background-image: linear-gradient(to right, rgba(109, 179, 242, .6), rgba(109, 179, 242, .6)), url('images/checked.png');
background-size: cover, contain;
background-position: center, right bottom;
background-repeat: no-repeat, no-repeat;
Individual property parameters are set respectively. Because the image is put underneath the color overlay, its property parameters are also placed after color overlay parameters.
And if you want Generate a Black Shadow in the background, you can use
the following:
background:linear-gradient( rgba(0, 0, 0, 0.5) 100%, rgba(0, 0, 0, 0.5)100%),url("logo/header-background.png");
You can also use short trick to use image and color both like this :-
body {
background:#000 url('images/checked.png');
}
really interesting problem, haven't seen it yet. this code works fine for me. tested it in chrome and IE9
<html>
<head>
<style>
body{
background-image: url('img.jpg');
background-color: #6DB3F2;
}
</style>
</head>
<body>
</body>
</html>
The next syntax can be used as well.
background: <background-color>
url('../assets/icons/my-icon.svg')
<background-position-x background-position-y>
<background-repeat>;
It allows you combining background-color, background-image, background-position and background-repeat properties.
Example
background: #696969 url('../assets/icons/my-icon.svg') center center no-repeat;
This actually works for me:
background-color: #6DB3F2;
background-image: url('images/checked.png');
You can also drop a solid shadow and set the background image:
background-image: url('images/checked.png');
box-shadow: inset 0 0 100% #6DB3F2;
If the first option is not working for some reason and you don't want to use the box shadow you can always use a pseudo element for the image without any extra HTML:
.btn{
position: relative;
background-color: #6DB3F2;
}
.btn:before{
content: "";
display: block;
width: 100%;
height: 100%;
position:absolute;
top:0;
left:0;
background-image: url('images/checked.png');
}
Here is how I styled my colored buttons with an icon in the background
I used "background-color" property for the color and "background" property for the image.
<style>
.btn {
display: inline-block;
line-height: 1em;
padding: .1em .3em .15em 2em
border-radius: .2em;
border: 1px solid #d8d8d8;
background-color: #cccccc;
}
.thumb-up {
background: url('/icons/thumb-up.png') no-repeat 3px center;
}
.thumb-down {
background: url('/icons/thumb-down.png') no-repeat 3px center;
}
</style>
<span class="btn thumb-up">Thumb up</span>
<span class="btn thumb-down">Thumb down</span>
Assuming you want an icon on the right (or left) then this should work best:
.show-hide-button::after {
content:"";
background-repeat: no-repeat;
background-size: contain;
display: inline-block;
background-size: 1em;
width: 1em;
height: 1em;
background-position: 0 2px;
margin-left: .5em;
}
.show-hide-button.shown::after {
background-image: url(img/eye.svg);
}
You could also do background-size: contain;, but that should be mostly the same. the background-position will depened on your image.
Then you can easily do an alternative state on hover:
.show-hide-button.shown:hover::after {
background-image: url(img/eye-no.svg);
}
You can try with box shadow: inset
.second_info_block {
background: url('imageURL');
box-shadow: inset 0 0 0 1000px rgba(0,0,0,.4);
}
<li style="background-color: #ffffff;"><img border="0" style="border-radius:5px;background: url(images/picture.jpg') 50% 50% no-repeat;width:150px;height:80px;" src="images/clearpixel.gif"/></li>
Other Sample Box Center Image and Background Color
1.First clearpixel fix image area
2.style center image area box
3.li background or div color style
body
{
background-image:url('image/img2.jpg');
margin: 0px;
padding: 0px;
}
Hi I am trying to create a highlight on a CSS shape as shown below.
There will also be content inside of the hexagon including image and text,
The highlight I am referring to is the part in the top left.
the code I currently have for creating the hexagon is:
HTML
<div class="hexagon-big"></div>
CSS
.hexagon-big {
position: relative;
width: 200px;
height: 115.47px;
background-color: #343434;
}
.hexagon-big:before,
.hexagon-big:after {
content: "";
position: absolute;
width: 0;
border-left: 100px solid transparent;
border-right: 100px solid transparent;
}
.hexagon-big:before {
bottom: 100%;
border-bottom: 57.74px solid #343434;
}
.hexagon-big:after {
top: 100%;
width: 0;
border-top: 57.74px solid #343434;
}
There is other code for the content but i left it out because I don't think it is necessary
Do the hexagon shape differently and you can rely on gradient to create that highlight effect:
.hex {
width: 200px;
display: inline-flex;
margin:0 5px;
background:
conic-gradient(at top,#000 230deg, #0000 0),
linear-gradient(to bottom left,#fff , #000 60%);
clip-path: polygon(0% 25%,0% 75%,50% 100%,100% 75%,100% 25%,50% 0%);
}
.hex::before {
content: "";
padding-top: 115%; /* 100%/cos(30) */
}
<div class="hex"></div>
The solution in this answer is heavily based on the previous answer. To use clip-path and stacked gradients is by far the smartest thing to do here, but I still wanted to post this in order to show, how this solution could be improved and adjusted for your use case (text box, coloring, variables for maintenance, etc.).
.hexagon-big {
/* define box and text space */
width: 200px;
height: 230px;
padding: 10.8% 5px; /* adjust text box padding here; mind that top/bottom tip are part of the box */
box-sizing: border-box; /* width/height should include padding */
/* text formatting (optional) */
color: white;
text-align: center;
/* hex shape */
--hex-col: hsl(0deg 0% 20%); /* just your #343434 as a HSL color */
--hex-shadow: hsl(0deg 0% 50%); /* increased lightness by 15% to define highlight root color; 100% would be fully white */
background:
conic-gradient(at top, var(--hex-col) 232deg, transparent 0), /* change the angle of the shadow at "232deg": increase → narrower, decrease → wider */
linear-gradient(to bottom left, var(--hex-shadow), var(--hex-col) 55%);
clip-path: polygon(0% 25%,0% 75%,50% 100%,100% 75%,100% 25%,50% 0%);
}
<div class="hexagon-big">
Lorem ipsum dolor sit amet...
</div>
It should also be mentioned that your current way of using border is well better supported by older browsers than clip-path and conic-gradient (same with var()).
If this should be a problem, you might have to add another HTML tag and work out a way with transform: matrix(...) and box-shadow: inset ... (for example).
I have following CSS class :
.acceptRejectAll a, .acceptRejectAll a:visited{
background-image: url("../images/view-patient.png");
background-position: left top;
background-repeat: no-repeat;
color: #4B555C;
float: left;
height: 35px;
padding-top: 12px;
text-align: center;
text-decoration: none;
width: 100px;
}
and following HTML :
<div style="float: none; display: inline-table" class="acceptRejectAll">
<a style="display:inline-block;height:25px;" href="#" class="fontBlack" id="ctl00_ContentPlaceHolder1_btnAcceptAll">Accept All</a>
</div>
this is display as follows :
when i decrease the size of in css class like : width : 85px
it displays as follows :
it cuts image from right side:
i tried to set background-Position in css class : but either left side or right side, image is not display correctly
wht is solution ?
Thanks
You will need to use background-size for this. Example:
background-size: 100% 100%;
Please note that this setting can scale your image to fill parent.
As the image is 100px (at least the visible part is about 92px so I guess the size is 100px) if you change the size of the button you need to scale the background image rather than change the position.
background-size:85px 35px;
Gradient and Border radius
Another way to approach this — considering the kind of button style you are using — is to go the gradient and border radius route. Whilst the code to use a css gradient looks rather messy, it is dynamically generated so you wont end up with stretched curved corners like you will using background-size.
Everything used below is pretty well supported now by most browsers. For anything that doesn't support the gradient you will get a solid blue background with curved corners instead, and it almost isn't worth worrying about non-support for border radius any more.
markup:
<div class="acceptRejectAll">
Accept All
</div>
css:
.acceptRejectAll {
display: inline-table;
border-radius: 20px;
text-align: center;
padding: 10px;
width: 100px; /* You can change the width as you like */
background: #c3e5fe; /* Old browsers */
background: -moz-linear-gradient(top, #c3e5fe 0%, #98d1fd 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,#c3e5fe), color-stop(100%,#98d1fd)); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, #c3e5fe 0%,#98d1fd 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, #c3e5fe 0%,#98d1fd 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, #c3e5fe 0%,#98d1fd 100%); /* IE10+ */
background: linear-gradient(to bottom, #c3e5fe 0%,#98d1fd 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#c3e5fe', endColorstr='#98d1fd',GradientType=0 );
}
.fontBlack {
font-family: sans-serif;
font-size: 10pt;
color: black;
text-decoration: none;
}
The gradient was generated using:
http://www.colorzilla.com/gradient-editor/#c3e5fe+0,98d1fd+100;Custom
You end up with:
http://jsfiddle.net/NDHtn/
Or as a preview:
When you must use an image
If there is no other choice but to use an image as a background for a button — say, the graphics are too complicated to replicate using css effects — rather than use one image stretched and distorted to fit, you can use something like the following. There are many ways to essentially achieve the same result, I prefer to keep my mark-up simple and my css more complicated (rather than the other way around). However, to make things more supportive of the wider browser community you can break your mark-up into three parts, rather than make use of ::before and ::after:
markup:
<a class="button" href="#">
<span>Round Button with lots of text and then some</span>
</a>
css:
.button:before {
position: absolute;
content: '';
background: url('image.png') left top;
top: 0;
left: -50px;
width: 50px;
height: 99px;
}
.button:after {
position: absolute;
content: '';
background: url('image.png') right top;
top: 0;
right: -50px;
width: 50px;
height: 99px;
}
.button {
background: url('image.png') center -99px;
height: 99px;
margin: 0 50px;
position: relative;
display: inline-block;
color: white;
text-decoration: none;
}
.button span { display: block; padding: 35px 0px; }
image.png, hacked together using this original image and pixlr.com:
Which will give:
http://jsfiddle.net/2K5Kg/1/
Example mark-up without use of psuedo elements:
<a class="button" href="#">
<span class="before"></span>
<span class="after"></span>
<span>Round Button with lots of text and then some</span>
</a>
Then in the css just replace the .button:before with .button .before and the same for :after.
I'm interested in technique, that allows to make such gradients OVER another div (white fading horizontal line). This is what I want it look like:
And this is what I have at the moment (yeah, I know):
Horizontal line is a simple with color css property,
Gradient is:
pointer-events: none;
height: 457px;
position: absolute;
right: 0;
top: -80px;
width: 100%;
background: radial-gradient(circle at center, rgba(255,255,255,0.15) 0%,rgba(255,255,255,0) 20%);
Image is a simple (rails image_tag) with absolute positioning.
Here is a hint. You can create multiple shapes of triangle with CSS and you have to just position and rotate the shapes to match your logo.
For instance, below is an example of one shape. You can take references of it and replicate it and make it the way you want. Here you go.
The HTML:
<div class="shape"></div>
The CSS:
.shape{
height: 100px;
width: 100px;
position:relative;
background: rgb(xxx,xxx,xxx);
background: -moz-linear-gradient(top, rgba(xxx,xxx,xxx,xxx) xxx%, rgba(xxx,xxx,xxx,xxx) xxx%);
background: -webkit-gradient(linear, left top, left bottom, color-stop(xxx%,rgba(xxx,xxx,xxx,x)), color-stop(xxx%,rgba(xxx,xxx,xxx,x)));
-webkit-linear-gradient(top, rgba(xxx,xxx,xxx,x) xxx%,rgba(xxx,xxx,xxx,x) xxx%);
-o-linear-gradient(top, rgba(xxx,xxx,xxx,x) xx%,rgba(xxx,xxx,xxx,x) xxx%);
-ms-linear-gradient(top, rgba(xxx,xxx,xxx,x) 0%,rgba(xxx,xxx,xxx,x) xxx%);
linear-gradient(top, rgba(xxx,xxx,xxx,x) 0%,rgba(xxx,xxx,xxx,x) xxx%);
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#xxx', endColorstr='#xxx',GradientType=0 );
}
.shape:after {
-moz-transform: rotate(xxdeg);
-ms-transform:rotate(xxdeg);
-webkit-transform:rotate(xxdeg);
-o-transform:rotate(xxdeg);
background: none repeat 0 0 xxx;
content: "";
height: xxx;
left: xxx;
position: absolute;
top: xxx;
width: xxx;
}
The "xx" or "x" or "xxx" are dummy values which you can replace it with yours.
Hope this helps.