01) I have a MySQL table named issue. It is storing book details as book_no, book_name, is_date etc.. issued for various members.
02) I need to select list of books that should return on current date. The return date is calculated by adding 3 days to the is_date. I used following script. But I returned an empty result.
Variables used to Store return dates
$rdate=mysql_fetch_array(mysql_query("SELECT * FROM issue"));
$is_date=$rdate['is_date'];
$rt_date=mysql_fetch_array(mysql_query("SELECT
DATE_ADD('$is_date', INTERVAL 3 DAY) FROM dual"));
SELECT statement
SELECT issue.b_no, issue.b_name, issue.is_date
FROM issue WHERE '$rt_date' = CURDATE()
03) I can not understand what I am doing wrong.
Related
I am using the Graph Reports for the select below. The MySQL database only has the active records in the database, so if no records are in the database from X hours till Y hours that select does not return anything. So in my case, I need that select return Paypal zero values as well even the no activity was in the database. And I do not understand how to use the UNION function or re-create select in order to get the zero values if nothing was recorded in the database in time interval. Could you please help?
select STR_TO_DATE ( DATE_FORMAT(`acctstarttime`,'%y-%m-%d %H'),'%y-%m-%d %H')
as '#date', count(*) as `Active Paid Accounts`
from radacct_history where `paymentmethod` = 'PayPal'
group by DATE_FORMAT(`#date`,'%y-%m-%d %H')
When I run the select the output is:
Current Output
But I need if there are no values between 2016-07-27 07:00:00 and 2016-07-28 11:00:00, then in every hour it should show zero active accounts Like that:
Needed output with no values every hour
I have created such select below , but it not put to every hour the zero value like i need. showing the big gap between the 12 Sep and 13 Sep anyway, but there should be the zero values every hour
(select STR_TO_DATE ( DATE_FORMAT(acctstarttime,'%y-%m-%d %H'),'%y-%m-%d %H')
as '#date', count(paymentmethod) as Active Paid Accounts
from radacct_history where paymentmethod <> 'PayPal'
group by DATE_FORMAT(#date,'%y-%m-%d %H'))
union ALL
(select STR_TO_DATE ( DATE_FORMAT(acctstarttime,'%y-%m-%d %H'),'%y-%m-%d %H')
as '#date', 0 as Active Paid Accounts
from radacct_history where paymentmethod <> 'PayPal'
group by DATE_FORMAT(#date,'%y-%m-%d %H')) ;
I guess, you want to return 0 if there is no matching rows in MySQL. Here is an example:
(SELECT Col1,Col2,Col3 FROM ExampleTable WHERE ID='1234')
UNION (SELECT 'Def Val' AS Col1,'none' AS Col2,'' AS Col3) LIMIT 1;
Updated the post: You are trying to retrieve data that aren't present in the table, I guess in reference to the output provided. So in this case, you have to maintain a date table to show the date that aren't in the table. Please refer to this and it's little bit tricky - SQL query that returns all dates not used in a table
You need an artificial table with all necessary time intervals. E.g. if you need daily data create a table and add all day dates e.g. start from 1970 till 2100.
Then you can use the table and LEFT JOIN your radacct_history. So for each desired interval you will have group item (group by should be based on the intervals table.
I have attendance data for employees stored in the table attendance with the following column names:
emp_id (employee ID)
date
type (leave, absent, etc.)
(there are others but I'm omitting them for the sake of simplicity)
My objective is to retrieve all dates of the given month on which the employee was on leave (type = 'Leave') and the last leave taken in the last month, if any.
It's easy to do it using two queries (I'm using PHP to get process the data), but is there any way this can be done in a single query?
I'm answering my own question so as to close it. As #bpgergo pointed out in the comments, UNION will do the trick here.
SELECT * FROM table_name
WHERE type="Leave" AND
date <= (CURRENT_DATE() - 30)
Select the fields, etc you want then se a combined where clause using mysql's CURRENT_DATE() function. I subtracted 30 for 30 days in a month.
If date is a date column, this will return everyone who left 1 month or longer ago.
Edit:
If you want a specific date, change the 2nd month like this:
date <= (date_number - 30)
I'm using PHP/MySQL booking system and i'm using a Google Line Chart to try and display the gross sales from the current month, and also the previous 3 months.
Each booking has a date in the standard phpmyadmin "date" format, so yyyy:mm:dd.
So, im looking to get 4 results from 4 queries, each query filtering out a certain month and grabbing the sum of each booking from that month.
My question is, how can i distinguish between the months in the query? How would i structure the query?
Based on the title:
select * from bookings where MONTH(CURDATE())=MONTH(booking_date);
select * from bookings where MONTH(booking_date) > MONTH(CURDATE()-INTERVAL 3 MONTH) and < MONTH(CURDATE() + INTERVAL 1 MONTH);
For simple per-month searches you can use the following:
Select * from bookings where MONTHNAME(booking_date)='July' and YEAR(booking_date)=2013;
Or:
Select * from bookings where MONTH(booking_date)=7 and YEAR(booking_date)=2013;
Also since you've already got the months, you could do this (this method requires that you maintain a table of ending dates for each month an compensate for leap year though):
select * from bookings where booking_date>'2013-06-30' AND booking_date<'2013-08-01';
In first place, excuse my english....
I know this is old thread and cant comment but, #AbsoluteƵERØ, that answer apply to the current month, in example, if i got records of July in 2013-2014-2015, the query will return the records on the month for those years.... To avoid that and using your posted code:
SELECT * FROM bookings WHERE MONTH(CURDATE()) = MONTH(booking_date) AND YEAR(CURDATE()) = YEAR(booking_date);
Note: if use the "name form" and specify the year there's no problem, like this:
SELECT * FROM bookings WHERE MONTH(CURDATE()) = MONTH(booking_date) AND YEAR(booking_date) = 2013;
I have a MySQL db that stores orders, and has a date field that gets populated when the order reaches a certain point.
I want to create a cron job that checks for all orders where this date is in multiples of 'weeks' ago. For example:
Date stored: 12/1/2012
this row would be returned if the cron job triggered on the following days:
12/8/2012
12/15/2012
12/22/2012
12/29/2012
etc...
How do i structure the MySQL query to fetch data in this way?
You can use modular arithmetic:
SELECT * FROM my_table WHERE DATEDIFF(CURDATE(), my_date) % 7 = 0
My web application has a report that shows the number of logins by a particular user each week. However, I'm struggling to get the query just right. The problem I'm running into is that I can't seem to get the weeks during which the user did not login at all.
Currently my query looks like this:
SELECT
DATE_ADD(logDate, INTERVAL(1-DAYOFWEEK(logDate)) DAY) weekStart,
DATE_ADD(logDate, INTERVAL(7-DAYOFWEEK(logDate)) DAY) weekEnd,
COUNT(*) loginCount
FROM log
WHERE
logDate > $startDate AND
logDate < $endDate
I would create a table for week numbers:
CREATE TEMPORARY TABLE weeks (weeknum INT PRIMARY KEY);
Then populate that table with integer values 0..53.
Then join it to your log table using the WEEK() function:
SELECT weeks.weeknum, COUNT(*) loginCount
FROM weeks LEFT OUTER JOIN log ON weeks.weeknum = WEEK(log.logDate)
WHERE log.logDate BETWEEN ? AND ?
GROUP BY weeks.weeknum;
If you need this query to support a date range that spans multiple years, use YEARWEEK() instead, and populate your temp table with more rows in the YYYYWW format like values returned by YEARWEEK().