I have attendance data for employees stored in the table attendance with the following column names:
emp_id (employee ID)
date
type (leave, absent, etc.)
(there are others but I'm omitting them for the sake of simplicity)
My objective is to retrieve all dates of the given month on which the employee was on leave (type = 'Leave') and the last leave taken in the last month, if any.
It's easy to do it using two queries (I'm using PHP to get process the data), but is there any way this can be done in a single query?
I'm answering my own question so as to close it. As #bpgergo pointed out in the comments, UNION will do the trick here.
SELECT * FROM table_name
WHERE type="Leave" AND
date <= (CURRENT_DATE() - 30)
Select the fields, etc you want then se a combined where clause using mysql's CURRENT_DATE() function. I subtracted 30 for 30 days in a month.
If date is a date column, this will return everyone who left 1 month or longer ago.
Edit:
If you want a specific date, change the 2nd month like this:
date <= (date_number - 30)
Related
01) I have a MySQL table named issue. It is storing book details as book_no, book_name, is_date etc.. issued for various members.
02) I need to select list of books that should return on current date. The return date is calculated by adding 3 days to the is_date. I used following script. But I returned an empty result.
Variables used to Store return dates
$rdate=mysql_fetch_array(mysql_query("SELECT * FROM issue"));
$is_date=$rdate['is_date'];
$rt_date=mysql_fetch_array(mysql_query("SELECT
DATE_ADD('$is_date', INTERVAL 3 DAY) FROM dual"));
SELECT statement
SELECT issue.b_no, issue.b_name, issue.is_date
FROM issue WHERE '$rt_date' = CURDATE()
03) I can not understand what I am doing wrong.
I have to perform a query on a MySQL database.
I have a table with records, have a column called "date" (the date type), and a column called "time" (type. Integer is stored by multiplying the time of day by 60. eg 8 am is stored as 480).
Unfortunately, the format of this table can not be modified.
My table stores attentions of doctors on call. The doctors on duty working in two shifts: from 8-20, and 20-8.
I need to know the amount of attention for every doctor.
My query must be filtered by date range and shift.
The problem is that, in the case of doctors working at the turn of 20-8, I have to consider a change of day. (sorry for my bad English).
What I have done is this, this would be an example to date of yesterday, and doctors shift 20-8.
SELECT * FROM attentions WHERE (date >= '2015-07-23' and time >=1200) and (date <= '2015-07-24' and time <480)
the query does not work at all.
Supposing the date field is called: 'a_date' with format 'yyyy-mm-ss' and the time field is a number, the query should be:
SELECT * FROM attentions WHERE (date(a_date) >= '2015-07-23' and time >=1200) and (date(a_date) <= '2015-07-24' and time <480)
Can you check using between?
SELECT * FROM attentions WHERE date between '2015-07-23' and '2015-07-24' and time between 1200 and 480
I think you can also use this -
SELECT * FROM ***** where CREATED_DATETIME between '2015-03-12 00:00:00' and '2015-05-11 00:00:00';
In my database, there is a field called birthday(date) and I want to retrieve records that their birth month and birth day is equal to the current month and the day. Is there a way to write a query for this? Or I just have to do it by retrieving all of the records and find the matching records after by using another program? Thanks!
This might also work: (NOTE that I am not sure if you mean day within a Month or day within a week)?
SELECT * FROM TABLE
WHERE MONTH(birthday) = MONTH(CURRENT_DATE)
AND DAY(birthday) = DAY(CURRENT_DATE) --assuming day within a month
select * from table
where date_format(birthday, '%m%d')=date_format(current_date, '%m%d');
The above query would not make use of mysql index
I have several rows in a table, each containing a start date and an end date. The user has a checkbox for each month of the year. I need to determine which rows contain a date range that includes any of the user's chosen months.
It's easy to check the start & end months by, for example, MONTH(start_date) IN ($month_list), but this approach won't match any months between the two dates.
So I suppose what I'm asking is: is there a way of obtaining the inclusive months from a date range purely in SQL?
I assume you would want to include data rows where the date range spans or intersects with the selected periods - in which case, I'd shove the user selected periods into a table and do a fuzzy join, something like.....
SELECT DISTINCT at.*
FROM a_table at, user_periods up
WHERE at.start_date<=up.end_date
AND at.end_date>=up.start_date
AND up.trans_id=$SOME_VAR
(the trans_id just allows the table to be used for multiple operations)
To minimise the effort here, the user_periods table should have an index on start_date and end_date, and similar for a_table.
Can something like this help?
WHERE
MONTH(start_date) < MONTH_YOU_ARE_CHECKING and
MONTH() > MONTH_YOU_ARE_CHECKING
If you need to check all at once you can do a list of all the months and after delete from the list the month that the user choose, and after compare against the list. It will be better with a pseudocode example :)
MONTHS = 1,2,3,4,5,6,7,8,9,10,11,12
USER_SELECTED_MONTHS= 1,6,8,9,12
LIST_TO CHECK = 2,3,4,5,7,10,11
so, now you can do:
MONTH(start_date) NOT IN (2,3,4,5,7,10,11)
What do you think, could it help you?
regards
I'm not sure if this is even within the scope of MySQL to be honest or if some php is necessary here to parse the data. But if it is... some kind of stored procedure is likely necessary.
I have a table that stores rows with a timestamp and an amount.
My query is dynamic and will be searching based on a user-provided date range. I would like to retrieve the SUM() of the amounts for each day in a table that are between the date range. including a 0 if there are no entries for a given day
Something to the effect of...
SELECT
CASE
WHEN //there are entries present at a given date
THEN SUM(amount)
ELSE 0
END AS amountTotal,
//somehow select the day
FROM thisTableName T
WHERE T.timeStamp BETWEEN '$start' AND '$end'
GROUP BY //however I select the day
This is a two parter...
is there a way to select a section of a returned column? Like some kind of regex within mysql?
Is there a way to return the 0's for dates with no rows?
select * from thisTableName group by date(created_at);
In your case, it would be more like
SELECT id, count(id) as amountTotal
FROM thisTableName
WHERE timeStamp BETWEEN '$start' AND '$end'
GROUP BY DATE(timeStamp);
Your question is a duplicate so far: link.