I've inherited a database that includes a lookup table to find other patents that are related to a given patent.
So it looks like
╔════╦═══════════╦════════════╗
║ id ║ patent_id ║ related_id ║
╠════╬═══════════╬════════════╣
║ 1 ║ 1 ║ 2 ║
║ 2 ║ 1 ║ 3 ║
║ 3 ║ 2 ║ 1 ║
║ 4 ║ 2 ║ 3 ║
║ 5 ║ 3 ║ 2 ║
╚════╩═══════════╩════════════╝
And I want to filter out the reciprocal relationships. 1->2 and 2->1 are the same for my purposes so I only want 1->2.
I don't need to make the edit in the table, I just need a query the returns a list of the unique relationships, and while I'm sure it's simple I've been banging my head against the keyboard for far too long.
Here is a clever query which you can try using. The general strategy is to identify the unwanted duplicate records and then subtract them away from the entire set.
SELECT t.id, t.patent_id, t.related_id
FROM t LEFT JOIN
(
SELECT t1.patent_id AS t1_patent_id, t1.related_id AS t1_related_id
FROM t t1 LEFT JOIN t t2
ON t1.related_id = t2.patent_id
WHERE t1.patent_id = t2.related_id AND t1.patent_id > t1.related_id
) t3
ON t.patent_id = t3.t1_patent_id AND t.related_id = t3.t1_related_id
WHERE t3.t1_patent_id IS NULL
Here is the inner temporary table generated by this query. You can convince yourself that by applying the logic in the WHERE clause you will select the correct records. Non-duplicate records are characterized by t1.patent_id != t2.related_id, and all these records are retained. In the case of duplicates (t1.patent_id = t2.related_id), the record chosen from each pair of duplicates is the one where patent_id < related_id, as you requested in your question.
╔════╦══════════════╦═══════════════╦══════════════╦═══════════════╗
║ id ║ t1.patent_id ║ t1.related_id ║ t2.patent_id ║ t2.related_id ║
╠════╬══════════════╬═══════════════╬══════════════╬═══════════════╣
║ 1 ║ 1 ║ 2 ║ 2 ║ 1 ║ * duplicate
║ 1 ║ 1 ║ 2 ║ 2 ║ 3 ║
║ 2 ║ 1 ║ 3 ║ 3 ║ 2 ║
║ 3 ║ 2 ║ 1 ║ 1 ║ 2 ║ * duplicate
║ 3 ║ 2 ║ 1 ║ 1 ║ 3 ║
║ 4 ║ 2 ║ 3 ║ 3 ║ 2 ║ * duplicate
║ 5 ║ 3 ║ 2 ║ 2 ║ 1 ║
║ 5 ║ 3 ║ 2 ║ 2 ║ 3 ║ * duplicate
╚════╩══════════════╩═══════════════╩══════════════╩═══════════════╝
Click the link below for a running example of this query.
SQLFiddle
Try something like
select distinct * from
(select patient_id, related_id from TABLENAME
union
select related_id, patient_id from TABLENAME
);
Okay you're right the above won't work. Try
select patient_id, related_id from TABLENAME p1
where p1.patiend_id not in
(select patient_id from TABLENAME p2
where p2.related_id = p1.related_id)
Related
I have three mysql tables.
Table-01: table_item
In this table, all items with their corresponding ids are stored. Items are categorized in two categories. One is writing category (catid-1) and another is clothing category (catid-2).
---------------------------------------------
| id | catname | catid | itemid | itemname |
---------------------------------------------
║ 1 ║ writing ║ 1 ║ 1 ║ Pen ║
║ 2 ║ writing ║ 1 ║ 2 ║ Pencil ║
║ 3 ║ writing ║ 1 ║ 3 ║ Sharpner ║
║ 4 ║clothing ║ 2 ║ 4 ║ Pant ║
║ 5 ║clothing ║ 2 ║ 5 ║ shirt ║
║ 6 ║clothing ║ 2 ║ 6 ║ coat ║
║ 7 ║clothing ║ 2 ║ 7 ║ Tie ║
---------------------------------------------
Table-02: bid_item
Each year bid/tender is called for purchasing selective items from the above item table (table_item). So in this table, selected items, those are selected for bid/tender, are stored per year basis.
----------------------
║ id ║ itemid ║ year ║
----------------------
║ 1 ║ 1 ║ 2015 ║
║ 2 ║ 2 ║ 2015 ║
║ 3 ║ 3 ║ 2015 ║
║ 4 ║ 4 ║ 2015 ║
║ 5 ║ 5 ║ 2015 ║
║ 6 ║ 6 ║ 2015 ║
║ 7 ║ 1 ║ 2016 ║
║ 8 ║ 2 ║ 2016 ║
║ 9 ║ 3 ║ 2016 ║
║ 10 ║ 4 ║ 2016 ║
║ 11 ║ 7 ║ 2016 ║
----------------------
Table-03: bid_2015
After calling bid/Tender, rate of the corresponding companies for selected items are stored in this table. Each company will not give bid price for each items selected for a particular year. Tables are created according to the year alias. Here bid rate for year 2015 are stored as below:
--------------------------------
║ id ║ itemid ║ company ║ rate ║
--------------------------------
║ 1 ║ 1 ║ X ║ 2.0 ║
║ 2 ║ 2 ║ X ║ 2.2 ║
║ 3 ║ 3 ║ X ║ 1.0 ║
║ 4 ║ 4 ║ X ║ 10.0 ║
║ 5 ║ 5 ║ X ║ 15.0 ║
║ 6 ║ 1 ║ Y ║ 1.5 ║
║ 8 ║ 2 ║ Y ║ 2.0 ║
║ 9 ║ 3 ║ Y ║ 1.5 ║
║ 10 ║ 4 ║ Y ║ 12.0 ║
║ 11 ║ 6 ║ Y ║ 20.0 ║
--------------------------------
I need a html table (with input field) for data entry/edit for a particular year (Here, for 2015). Table will contain following:
1) Table will show each items for clothing catagory (catid-2)those are declared for the bid/tender for 2015.
2) If a company bids price, price will be in rate column, otherwise rate column will be blank. Administrator can either change the price (if entered wrong bid price) or add rate for other items which was not entered at first for a particular table.
So the look of the html table form will be as below:
HTML Form-Table (For Data Entry/Edit) : For Company-Y and clothing catagory for the year-2015
Company: (drop-down menu- Company-Y)
------------------------------------------------------
Item Name | Rate |
----------------------
Pant | 12.0 |
-----------------------
Shirt |
-----------------------
Coat | 20.0 |
-----------------------
============
Submit
============
As you can see Rate of Shirt is blank for Company-Y as this company did not give bid price for Shirt. If this company give the price of Shirt at later, rate can be entered and can update the table.
So what would be mysql query to get a html form table like above?
If I execute this query:
SELECT i.itemname,d.rate FROM table_item as i INNER JOIN bid_item as b ON i.itemid=b.itemid LEFT JOIN bid_2015 as d ON b.itemid=d.itemid WHERE i.catid=2 AND d.company='Y' AND b.year=2015
But the expected html table is not coming. As INNER and LEFT Join are used, Item Names are shown more than once in the form table.
What will be the effective mysql query to output a html form table like above?
this works for all data of company Y in 2015
select itemname,
rate
from table_item join bid_item on(table_item.itemid=bid_item.itemid and year=2015 and catid=2)
left join bid_2015 on( bid_2015.itemid=bid_item.itemid and
bid_item.itemid=table_item.itemid and company='Y' and year=2015 and catid=2)
This query will work fine.
SELECT i.itemname,
d.rate
FROM table_item as i
INNER JOIN bid_item as b ON i.itemid=b.itemid AND b.year=2015
LEFT JOIN bid_2015 as d ON b.itemid=d.itemid AND d.company='Y'
WHERE i.catid=2
Note:
When ever you are making LEFT/RIGHT joins on a table (say b as in
your example below). Never put conditions of table 'b' in WHERE
clause. It will act as INNER JOIN .
So the this code
SELECT i.itemname,
d.rate
FROM table_item as i
INNER JOIN bid_item as b ON i.itemid=b.itemid
LEFT JOIN bid_2015 as d ON b.itemid=d.itemid
WHERE i.catid=2 AND d.company='Y' AND b.year=2015
Act as INNER JOIN as given below.
SELECT i.itemname,
d.rate
FROM table_item as i
INNER JOIN bid_item as b ON i.itemid=b.itemid
INNER JOIN bid_2015 as d ON b.itemid=d.itemid
WHERE i.catid=2 AND d.company='Y' AND b.year=2015
Hope this helps.
I'd like to merge rows based on multiple criteria, essentially removing duplicates where I get to define what "duplicate" means. Here is an example table:
╔═════╦═══════╦═════╦═══════╗
║ id* ║ name ║ age ║ grade ║
╠═════╬═══════╬═════╬═══════╣
║ 1 ║ John ║ 11 ║ 5 ║
║ 2 ║ John ║ 11 ║ 5 ║
║ 3 ║ John ║ 11 ║ 6 ║
║ 4 ║ Sam ║ 14 ║ 7 ║
║ 5 ║ Sam ║ 14 ║ 7 ║
╚═════╩═══════╩═════╩═══════╝
In my example, let's say I want to merge on name and age but ignore grade. The result should be:
╔═════╦═══════╦═════╦═══════╗
║ id* ║ name ║ age ║ grade ║
╠═════╬═══════╬═════╬═══════╣
║ 1 ║ John ║ 11 ║ 5 ║
║ 3 ║ John ║ 11 ║ 6 ║
║ 4 ║ Sam ║ 14 ║ 7 ║
╚═════╩═══════╩═════╩═══════╝
I don't particularly care if the id column is updated to be incremental, but I suppose that would be nice.
Can I do this in MySQL?
My suggestion, based on my above comment.
SELECT distinct name, age, grade
into tempTable
from theTable
This will ignore the IDs and give you only a distinct dump, and into a new table.
Then you can either drop the old and, and rename the new one. Or truncate the old one, and dump this back in.
You could just delete the duplicates in place like this:
delete test
from test
inner join (
select name, age, grade, min(id) as minid, count(*)
from test
group by name, age, grade
having count(*) > 1
) main on test.id = main.minid;
Example: http://sqlfiddle.com/#!9/f1a38/1
My head is turning to mush when trying to get this nesting around my head.
So basically I got 2 tables:
Brokers, which is my "user" table:
╔══════════╦════════════╦
║ ID ║ EMAIL ║
╠══════════╬════════════╬
║ 1 ║ 1#email.co ║
║ 2 ║ 2#email.co ║
║ 3 ║ 3#email.co ║
╚══════════╩════════════╝
Houses, which is houses that the users have added. Currently user and house is connected by the email column (I know, makes more sense to do with a ID):
╔══════════╦════════════╦════════════╦
║ ID ║ TYPE ║ EMAIL ║
╠══════════╬════════════╬════════════╬
║ 1 ║ 1 ║ 1#email.co ║
║ 2 ║ 3 ║ 1#email.co ║
║ 3 ║ 2 ║ 1#email.co ║
║ 4 ║ 3 ║ 1#email.co ║
║ 5 ║ 3 ║ 1#email.co ║
║ 6 ║ 2 ║ 1#email.co ║
║ 7 ║ 3 ║ 1#email.co ║
║ 8 ║ 1 ║ 2#email.co ║
║ 9 ║ 1 ║ 2#email.co ║
║ 10 ║ 2 ║ 2#email.co ║
║ 11 ║ 2 ║ 2#email.co ║
║ 12 ║ 3 ║ 2#email.co ║
║ 13 ║ 3 ║ 3#email.co ║
║ 14 ║ 2 ║ 3#email.co ║
║ 15 ║ 3 ║ 3#email.co ║
║ 16 ║ 1 ║ 3#email.co ║
║ 17 ║ 3 ║ 3#email.co ║
║ 18 ║ 2 ║ 3#email.co ║
║ 19 ║ 2 ║ 3#email.co ║
║ 20 ║ 3 ║ 3#email.co ║
╚══════════╩════════════╩════════════╝
Now what I want to do, is that I want to select all brokers that have type 3 as the highest, most popular kind of house added. So for example if house type 3 represents "Apartments", I want to find the brokers that sell apartments as their number one most popular type.
My current query is:
SELECT b.id, b.email, h.email, h.type, h.total
FROM brokers b
INNER JOIN (
SELECT COUNT( * ) AS total, email, type
FROM house
GROUP BY email, type
ORDER BY total DESC
)h ON b.email = h.email
AND h.type = "3"
ORDER BY b.id DESC
Now this only selects the total amount of houses that that broker has for type 3. It does not only select the brokers where type 3 is their most popular type.
Now to do that, I need to use what is called "Groupwise Max". But I can not use max() on a count(*) like:
MAX(COUNT(*)) as max_value
So I guess that what I need to do is to nest my query further with additional subqueries to first count, and then select the max value.
I've been trying to get it right for a while now and I just can't get my head around it. Anyone can help?
EDIT:
Expected Output:
Based on the table above, Broker 1#email.co got:
1 House with Type 1.
2 Houses with Type 2.
4 Houses with Type 3.
Broker 2#email.co got:
2 houses with Type 1
2 houses with Type 2
1 house with Type 3.
Broker 3#email.co got:
1 house with Type 1.
3 houses with Type 2.
4 houses with Type 3.
Since both 1#email.co and 3#email.co is selling House Type 3 most commonly, they should be included in the output. 2#email.co do not sell type 3 as his most popular type, so he should not be included in the result.
So output:
╔══════════╦════════════╦════════════╦
║ ID ║ EMAIL ║ Total ║
╠══════════╬════════════╬════════════╬
║ 1 ║ 1#email.co ║ 4 ║
║ 3 ║ 3#email.co ║ 4 ║
╚══════════╩════════════╝════════════╝
Posting answer without executing, hope this works!
Select a.ID,a.Email,b.Cnt from Brokers as a
inner join (
Select Email,count(ID) as Cnt from Houses where Type =
(Select max(Type) from Houses)
group by Email
) as b on a.Email = b.Email
I can't understand why you need Count()? I think, according to you question ("select all brokers that have type 3") , it doesn't make sense, or do I misunderstand something?
EDIT:
I have done it in SQL SERVER by temporary table and variable
If you can convert it to mysql syntax, your problem will we solved:
SELECT COUNT(*) as total, Email, [Type]
into #tbl3
from house
group by Email, Type
declare #a int
set #a = (select MAX(total) from #tbl3)
SELECT b.id, b.email, h.email, h.type, h.total
FROM brokers b
inner join
(
select * from #tbl3
where total=#a
) h
on h.Email=b.Email and h.Type=3
EDIT: This is MySql syntax which will do your job.
CREATE TEMPORARY TABLE IF NOT EXISTS table2 AS (
SELECT COUNT(*) as total, Email, Type
from house
group by Email, Type
);
set #a = (select MAX(total) from table2);
SELECT b.id, b.email, h.email, h.type, h.total
FROM brokers b
inner join
(
select * from table2
where total=#a
) h
on h.Email=b.Email and h.Type=3
I have two tables:
╔════════════════╗ ╔════════════════╗
║ ITEM ║ ║ ITEM_TRACK ║
╠════════════════╣ ╠════════════════╣
║ ID ║ ║ ID ║
║ GUID ║ ║ ITEM_GUID ║
║ COUNT1 ║ ║ CONTEXT ║
║ ENDDATE ║ ║ ║
╚════════════════╝ ╚════════════════╝
╔═════╦══════╦════════╗ ╔═════╦═══════════╦══════════╗
║ ID ║ GUID ║ COUNT1 ║ ║ ID ║ ITEM_GUID ║ CONTEXT ║
╠═════╬══════╬════════╣ ╠═════╬═══════════╬══════════╣
║ 1 ║ aaa ║ ║ ║ 1 ║ abc ║ ITEM ║
║ 2 ║ bbb ║ ║ ║ 2 ║ aaa ║ PAGE ║
║ 3 ║ ccc ║ ║ ║ 3 ║ bbb ║ ITEM ║
║ 4 ║ abc ║ ║ ║ 4 ║ ccc ║ ITEM ║
╚═════╩══════╩════════╝ ║ 5 ║ abc ║ ITEM ║
║ 6 ║ aaa ║ ITEM ║
║ 7 ║ abc ║ ITEM ║
║ 8 ║ ccc ║ PAGE ║
╚═════╩═══════════╩══════════╝
What I'm trying to do is fill in the COUNT1 column in ITEM with the count of the number of times ITEM_GUID appears in ITEM_TRACK for all ITEM.GUIDs where ENDDATE is still in the future. I need to do this once an hour for all GUIDS in ITEM.
I can get the counts I need easily
SELECT ITEM_GUID, COUNT(*) from ITEM_TRACK GROUP BY ITEM_GUID;
What I don't know how to do is, how do I merge this with an INSERT INTO statement to automatically update all the items in the items table with the count based on their ENDDATE?
UPDATE:
I have a working solution based on Aquillo's answer:
UPDATE ITEM a
SET COUNT1 = (SELECT COUNT(*) AS total FROM ITEM_TRACK b WHERE b.item_guid=a.guid);
Is there any other way to do this without a subquery?
You can insert from a select like this:
INSERT INTO myTable (foreignKey, countColumn) VALUES
SELECT ITEM_GUID, COUNT(*) from ITEM_TRACK GROUP BY ITEM_GUID;
In case you want to update, try something like this:
UPDATE from SELECT using SQL Server
If you use INSERT INTO you'll put additional rows in your ITEM table, not update the existing ones. If this is what you meant then that's great, but if you want to update the existing ones, you'll need to use update. You do this by joining the table you want to update with the table you want to update from. However, in your case you want to update from an aggregation and so you need to create a table with the aggregated values. Try this:
UPDATE ITEM SET Count1 = temp.total
FROM Item
INNER JOIN (
SELECT ITEM_GUID, COUNT(*) AS total
FROM ITEM_TRACK
GROUP BY ID) AS temp
ON Item.GUID = temp.ITEM_GUID
WHERE ENDDATE > NOW()
I've tried this on SQL Server (using GETDATE() instead of NOW()) to double check and it worked, I think it should work on MYSQL.
╔════════╦═══════════╦═══════╗
║ MSG_ID ║ RANDOM_ID ║ MSG ║
╠════════╬═══════════╬═══════╣
║ 1 ║ 22 ║ apple ║
║ 2 ║ 22 ║ bag ║
║ 3 ║ 0 ║ cat ║
║ 4 ║ 0 ║ dog ║
║ 5 ║ 0 ║ egg ║
║ 6 ║ 21 ║ fish ║
║ 7 ║ 21 ║ hen ║
║ 8 ║ 20 ║ glass ║
╚════════╩═══════════╩═══════╝
Want to fetch 3 records in a lot such a way that all the data of a particular random_id is picked up .
Result Required:
║ MSG_ID ║ RANDOM_ID ║ MSG ║
╠════════╬═══════════╬═══════╣
║ 1 ║ 22 ║ apple ║
║ 2 ║ 22 ║ bag ║
║ 3 ║ 0 ║ cat ║
Current Result:
║ MSG_ID ║ RANDOM_ID ║ MSG ║
╠════════╬═══════════╬═══════╣
║ 1 ║ 22 ║ apple ║
║ 3 ║ 0 ║ cat ║
║ 4 ║ 0 ║ dog ║
______________________________
Query Used:
SELECT ID,Random_ID, GROUP_CONCAT(message SEPARATOR ' ' ),FLAG,mobile,sender_number,SMStype
FROM messagemaster
WHERE Random_ID > 0
GROUP BY Random_ID
UNION
SELECT ID,Random_ID, message,FLAG,mobile,sender_number,SMStype
FROM messagemaster
WHERE Random_ID = 0
order by random_id LIMIT 100;
I don't want to pick up records using group by.I want to fetch all the records w rt random_ids .Like , if there is a random_id for which there are 3 records and if the query has limit =3 , then i want all the data w r t those random_id to be picked up.
The situation is if I fetch rows with limit 100 , i dont want that some of the data with the random id present in the result set is not picked.
For example if i am picking records limit by 3 then for random id=22 , all records with random id =22 should be picked .
Consider the following...
SELECT b.*
FROM
( SELECT x.*, SUM(y.cnt)
FROM
( SELECT random_id,COUNT(*) cnt FROM messagemaster GROUP BY random_id) x
JOIN
( SELECT random_id,COUNT(*) cnt FROM messagemaster GROUP BY random_id) y
ON y.random_id >= x.random_id
GROUP
BY x.random_id
HAVING SUM(y.cnt) < 4
) a
JOIN messagemaster b
ON b.random_id = a.random_id;