Groupwise-max on count() with nested subqueries - mysql

Question

My head is turning to mush when trying to get this nesting around my head.
So basically I got 2 tables:
Brokers, which is my "user" table:
╔══════════╦════════════╦
║ ID ║ EMAIL ║
╠══════════╬════════════╬
║ 1 ║ 1#email.co ║
║ 2 ║ 2#email.co ║
║ 3 ║ 3#email.co ║
╚══════════╩════════════╝
Houses, which is houses that the users have added. Currently user and house is connected by the email column (I know, makes more sense to do with a ID):
╔══════════╦════════════╦════════════╦
║ ID ║ TYPE ║ EMAIL ║
╠══════════╬════════════╬════════════╬
║ 1 ║ 1 ║ 1#email.co ║
║ 2 ║ 3 ║ 1#email.co ║
║ 3 ║ 2 ║ 1#email.co ║
║ 4 ║ 3 ║ 1#email.co ║
║ 5 ║ 3 ║ 1#email.co ║
║ 6 ║ 2 ║ 1#email.co ║
║ 7 ║ 3 ║ 1#email.co ║
║ 8 ║ 1 ║ 2#email.co ║
║ 9 ║ 1 ║ 2#email.co ║
║ 10 ║ 2 ║ 2#email.co ║
║ 11 ║ 2 ║ 2#email.co ║
║ 12 ║ 3 ║ 2#email.co ║
║ 13 ║ 3 ║ 3#email.co ║
║ 14 ║ 2 ║ 3#email.co ║
║ 15 ║ 3 ║ 3#email.co ║
║ 16 ║ 1 ║ 3#email.co ║
║ 17 ║ 3 ║ 3#email.co ║
║ 18 ║ 2 ║ 3#email.co ║
║ 19 ║ 2 ║ 3#email.co ║
║ 20 ║ 3 ║ 3#email.co ║
╚══════════╩════════════╩════════════╝
Now what I want to do, is that I want to select all brokers that have type 3 as the highest, most popular kind of house added. So for example if house type 3 represents "Apartments", I want to find the brokers that sell apartments as their number one most popular type.
My current query is:
SELECT b.id, b.email, h.email, h.type, h.total
FROM brokers b
INNER JOIN (
SELECT COUNT( * ) AS total, email, type
FROM house
GROUP BY email, type
ORDER BY total DESC
)h ON b.email = h.email
AND h.type = "3"
ORDER BY b.id DESC
Now this only selects the total amount of houses that that broker has for type 3. It does not only select the brokers where type 3 is their most popular type.
Now to do that, I need to use what is called "Groupwise Max". But I can not use max() on a count(*) like:
MAX(COUNT(*)) as max_value
So I guess that what I need to do is to nest my query further with additional subqueries to first count, and then select the max value.
I've been trying to get it right for a while now and I just can't get my head around it. Anyone can help?
EDIT:
Expected Output:
Based on the table above, Broker 1#email.co got:
1 House with Type 1.
2 Houses with Type 2.
4 Houses with Type 3.
Broker 2#email.co got:
2 houses with Type 1
2 houses with Type 2
1 house with Type 3.
Broker 3#email.co got:
1 house with Type 1.
3 houses with Type 2.
4 houses with Type 3.
Since both 1#email.co and 3#email.co is selling House Type 3 most commonly, they should be included in the output. 2#email.co do not sell type 3 as his most popular type, so he should not be included in the result.
So output:
╔══════════╦════════════╦════════════╦
║ ID ║ EMAIL ║ Total ║
╠══════════╬════════════╬════════════╬
║ 1 ║ 1#email.co ║ 4 ║
║ 3 ║ 3#email.co ║ 4 ║
╚══════════╩════════════╝════════════╝

Answer 1

Posting answer without executing, hope this works!
Select a.ID,a.Email,b.Cnt from Brokers as a
inner join (
Select Email,count(ID) as Cnt from Houses where Type =
(Select max(Type) from Houses)
group by Email
) as b on a.Email = b.Email

Answer 2

I can't understand why you need Count()? I think, according to you question ("select all brokers that have type 3") , it doesn't make sense, or do I misunderstand something?
EDIT:
I have done it in SQL SERVER by temporary table and variable
If you can convert it to mysql syntax, your problem will we solved:
SELECT COUNT(*) as total, Email, [Type]
into #tbl3
from house
group by Email, Type
declare #a int
set #a = (select MAX(total) from #tbl3)
SELECT b.id, b.email, h.email, h.type, h.total
FROM brokers b
inner join
(
select * from #tbl3
where total=#a
) h
on h.Email=b.Email and h.Type=3
EDIT: This is MySql syntax which will do your job.
CREATE TEMPORARY TABLE IF NOT EXISTS table2 AS (
SELECT COUNT(*) as total, Email, Type
from house
group by Email, Type
);
set #a = (select MAX(total) from table2);
SELECT b.id, b.email, h.email, h.type, h.total
FROM brokers b
inner join
(
select * from table2
where total=#a
) h
on h.Email=b.Email and h.Type=3