ID lost after left join on table - mysql

Question

Hey I tried this thread but it doesn't work and i can't figure out why...
here's my SQL:
SELECT * FROM gone_items
LEFT JOIN items
ON gone_items.item_ID=items.ID
WHERE
gone_items.aus_ID='$ID'
ORDER BY items.name ASC
Now, I fetch that via PHP and have a $row and try another mysql to get the individual ID's of the gone_items table. But if i use $row['ID'] I get the ID of the items.ID not the one from gone_items.ID.
I tried setting the variable manually in the first query but it doesn't work.
I also tried this: MYSQL Left join A.table and b.table while retaining a.table id
Also didn't help me...
All I want is to retain the ID (Primary key) from the gone_items table..
Can anyone please tell me what I'm doing wrong ?
Love
Gram
EDIT
//Query for Joined infos
$sqlx="SELECT foto_res_ausgeliehene_geg.ID, foto_res_ausgeliehene_geg.aus_ID, foto_res_ausgeliehene_geg.geg_ID, foto_res_ausgeliehene_geg.zusaetzliches, foto_res_gegenstaende.ID, foto_res_gegenstaende.bezeichnung, foto_res_gegenstaende.seriennummer, foto_res_gegenstaende.interne_seriennummer, foto_res_gegenstaende.zusaetzliches FROM foto_res_ausgeliehene_geg
LEFT JOIN foto_res_gegenstaende
ON foto_res_ausgeliehene_geg.geg_ID=foto_res_gegenstaende.ID
WHERE
foto_res_ausgeliehene_geg.aus_ID='$ID'
ORDER BY foto_res_gegenstaende.bezeichnung ASC
";
$ergebnisx = mysqli_query($db,$sqlx);
while ($zeilex = mysqli_fetch_assoc($ergebnisx))
{
//Query for individual infos
$sqly="SELECT * FROM foto_res_ausgeliehene_geg
WHERE `geg_ID`='".$zeilex['ID']."'
AND `aus_ID`='$ID'
GROUP BY `geg_ID`
";
$ergebnisy = mysqli_query($db,$sqly);
while ($zeiley = mysqli_fetch_assoc($ergebnisy))
{};
Now I did select all items individually. The foto_res_ausgeliehene_geg.ID still merges with the foto_res_gegenstanede.ID due to the LEFT JOIN.
So if i access $zeilex['ID'] im getting the ID of foto_res_gegenstaende.ID.
Would it help if I rename the ID field in one of the tables into lets say item_ID ?
Thanks alot.
Love
Gram.

Answer 1

Instead of using select *, you should explicitly state what items you want to select. Else you can get conflicts with multiple id fields. In your case something like:
select gone_items.id, gone_items.column1, gone_items.column2, items.column1, items.column2
It is also considered good practice, to limit the amount of data there is being selected. But is meanwhile also a highly debateable what is the right way. Performance issue in using SELECT *?

Answer 2

WORKS!
I simply renamed one of the Primary ID keys to something else, in this case, one of them got ID -> item_ID. The other one still is ID that way the left join won't merge them.
yolo
EDIT
WORKING CODE
$sqlx="SELECT foto_res_ausgeliehene_geg.item_ID, foto_res_ausgeliehene_geg.aus_ID, foto_res_ausgeliehene_geg.geg_ID, foto_res_ausgeliehene_geg.zusaetzliches, foto_res_gegenstaende.ID, foto_res_gegenstaende.bezeichnung, foto_res_gegenstaende.seriennummer, foto_res_gegenstaende.interne_seriennummer, foto_res_gegenstaende.zusaetzliches FROM foto_res_ausgeliehene_geg
LEFT JOIN foto_res_gegenstaende
ON foto_res_ausgeliehene_geg.geg_ID=foto_res_gegenstaende.ID
WHERE
foto_res_ausgeliehene_geg.aus_ID='$ID'
ORDER BY foto_res_gegenstaende.bezeichnung ASC
";
$ergebnisx = mysqli_query($db,$sqlx);
while ($zeilex = mysqli_fetch_assoc($ergebnisx))
{
//Query for individual infos
$sqly="SELECT * FROM foto_res_ausgeliehene_geg
WHERE `item_ID`='".$zeilex['item_ID']."'
";
$ergebnisy = mysqli_query($db,$sqly);
while ($zeiley = mysqli_fetch_assoc($ergebnisy))
{