Basically I need to merge these into one single query:
SELECT COUNT( DISTINCT id ) AS totalRows1
FROM other_events WHERE status = "approved"
AND Location = 1
SELECT COUNT( DISTINCT Id ) AS totalRows2
FROM core_events WHERE Status = "Active"
AND Location_id = 1
When I do it like below, if there is no event with Location_id = 1 query returns 0. In that condition I need it to return the count of the first table only.
SELECT COUNT( DISTINCT t1.id ) + COUNT( DISTINCT t2.Id ) AS total
FROM other_events AS t1, core_events AS t2
WHERE t1.status = "approved"
AND t1.Location = 1
AND t2.Location_id = 1
AND t2.Status = 'Active'
ps. column names are exactly like above
Use a UNION statement to merge the result like this:
SELECT SUM(total) FROM (
SELECT COUNT(DISTINCT id) AS total
FROM other_events
WHERE (status = "approved" AND Location = 1)
UNION ALL
SELECT COUNT(DISTINCT Id) AS total
FROM core_events
WHERE (Location_id = 1 AND Status = 'Active')
) union_result
Related
I have one table which has the following data, I want to skip row 3, just want to fetch OPEN status only once, I am using below query but it skipping wor 5 as well.
SELECT t.*
FROM emailEvent t
JOIN
( SELECT MIN(id) AS minid
FROM emailEvent WHERE email_id = 3
GROUP BY status
) AS grp
ON grp.minid = t.id
WHERE (t.email_id = 3)
I came up with this as a solution but not sure if there are any other best solution for this
SELECT t.*
FROM emailEvent t
WHERE t.status != "Open" and t.email_id = 3
UNION
(
SELECT et.*
FROM emailEvent et
WHERE et.status = "Open" and et.email_id = 3
ORDER BY et.createdAt DESC LIMIT 1
)
I want the result to be look like something like this
SELECT *
FROM
(
SELECT t.*,
min(id) over (partition by status) as min_id
FROM emailEvent t
WHERE (t.email_id = 3) -- only email 3
) AS dt
WHERE id = min_id -- only for 'Open' status
OR status <> 'Open'
For older releases not supporting Windowed Aggregates:
select *
from emailEvent
where email_id = 3
and
(
e.status <> 'Open'
or id in (select min(id) -- only for 'Open' status
from emailEvent
where status = 'Open'
and email_id = 3)
)
With NOT EXISTS:
select e.* from emailEvent e
where e.status <> 'Open'
or not exists (select 1 from emailEvent where status = e.status and id < e.id)
I have this working query. It has count with subquery.
SELECT
COUNT(*) AS total
FROM
(SELECT
COUNT(aset)
FROM
`public_1`
WHERE `public_1`.`aset` NOT IN
(SELECT
asset_code
FROM
application_detail
WHERE application_id = 6)
AND org_id = 7
AND status_id = 8
GROUP BY aset) t
now I need to union with different table and get the total from both table. This code could get count record but the value is incorrect.
SELECT
COUNT(*) AS total
FROM
(SELECT
COUNT(aset)
FROM
`public_1`
WHERE `public_1`.`aset` NOT IN
(SELECT
asset_code
FROM
application_detail
WHERE application_id = 6)
AND org_id = 7
AND status_id = 8
UNION
SELECT
COUNT(aset)
FROM
`public_2`
WHERE `public_2`.`aset` NOT IN
(SELECT
asset_code
FROM
application_detail
WHERE application_id = 6)
AND org_id = 7
AND status_id = 8
GROUP BY aset) z
Please assist me in getting the query correct. Thanks in advance
Use SELECT COUNT(DISTINCT aset) to get your counts, and then add them together.
SELECT t1.total + t2.total AS total
FROM (
SELECT COUNT(DISTINCT aset) AS total
FROM `public_1`
WHERE `public_1`.`aset` NOT IN
(SELECT
asset_code
FROM
application_detail
WHERE application_id = 6)
AND org_id = 7
AND status_id = 8) AS t1
CROSS JOIN (
SELECT COUNT(DISTINCT aset) AS total
FROM `public_2`
WHERE `public_2`.`aset` NOT IN
(SELECT
asset_code
FROM
application_detail
WHERE application_id = 6)
AND org_id = 7
AND status_id = 8) AS t2
I have this two MySQL statements from same table :
SELECT
`table1`.`product_id` As product_id,
COUNT(DISTINCT(table1.user_id)) AS NonebuyersNumber
FROM table1
WHERE status = 1 AND `ispaid` != 2
GROUP BY `table1`.`product_id`
The second statement is :
SELECT l
`table1`.`product_id` As product_id,
COUNT(DISTINCT(table1.user_id)) AS BuyersNumber
FROM table1
WHERE `ispaid` = 1
GROUP BY `table1`.`product_id`
The result that I want is a table like this one :
I tried to use Union but doesn't work because I have two different columns
Any idea how I can get this 3rd table?
Use conditional aggregation:
SELECT
product_id,
COUNT(DISTINCT CASE WHEN status = 1 AND ispaid != 2
THEN user_id ELSE NULL END) AS NonebuyersNumber
COUNT(DISTINCT CASE WHEN ispaid = 1 THEN user_id ELSE NULL END) AS BuyersNumber
FROM table1
WHERE
(status = 1 AND ispaid != 2) OR
ispaid = 1
GROUP BY
product_id;
This should work because both of your queries aggregate over the product_id and the only differences are the WHERE clauses. We can combine the records from both queries and then use CASE expressions to target records intended for each original query.
SELECT t1.product_id AS product_id
SELECT CASE WHEN t1.NonebuyersNumber IS NULL
THEN 0
ELSE t1.NonebuyersNumber
END
AS NonebuyersNumber,
SELECT CASE WHEN t2.BuyersNumber IS NULL
THEN 0
ELSE t2.BuyersNumber
END
AS BuyersNumber
FROM
(SELECT
`table1`.`product_id` As product_id ,
COUNT(DISTINCT(table1.user_id)) AS NonebuyersNumber
FROM table1 WHERE status =1
AND `ispaid` != 2
GROUP BY `table1`.`product_id`)
AS t1
INNER JOIN
(SELECT
`table1`.`product_id` As product_id ,
COUNT(DISTINCT(table1.user_id)) AS BuyersNumber
FROM table1 WHERE `ispaid` = 1
GROUP BY `table1`.`product_id`)
AS t2
ON t1.product_id = t2.product_id
Basically, you need following
Join both the views on product_id
Use CASE statements in select in case one of the buyers numbers is NULL
I have below table and SQL query written, this query should not return any result but its returning ID = 1 , what is wrong with the SQL query? Can anyone please help?
** Note balance data type is decimal rest are varchar
ID code balance level
1 C 150.00
1 P 40027.42 F
1 P 40027.42 F
select distinct ID from table
(
(code = 'P' and balance = 40027.42 and level = 'F') or
(code = 'C' and balance = 151.00 )
)
group by ID
having count(ID) >=2
If you do not want to count the same code twice, you can use count(distinct code):
select ID
from t
where (code = 'P' and balance = 40027.42 and level = 'F')
or (code = 'C' and balance = 151.00 )
group by ID
having count(distinct code) >=2
If you want to only count a distinct set of values once, you can use a derived table/subquery to select distinct rows:
select ID
from (
select distinct id, code, balance, level
from t
) as s
where (code = 'P' and balance = 40027.42 and level = 'F')
or (code = 'C' and balance = 151.00 )
group by ID
having count(ID) >=2
rextester demo for both: http://rextester.com/LBKO57534
I have some thing to do here with subquery but I am not able to do.
I want the result from a table with a extra field to show to no of results from other table with a column value from table 1.
table1:
CountryId Country ISO2 ISO3
table2:
id noof_country state
I have to retrive noof_country count in table 1 as count field
EDIT
my actual tables are
table 1:
ad_id job_country status delete days_left
table 2:
CountryId Country ISO2 status
I have done query in two phase:
$sql_map = "select distinct c.ISO2, c.Country, a.job_country
from rec_countries c, rec_advert a
where c.status = 1
and DATE(a.modified_date) >= CURDATE() - INTERVAL 30 DAY
and c.ISO2 <> '--'
and c.ISO2 <> ''
and c.CountryId = a.job_country
and a.status = 1
and a.`delete` = 0
and a.days_left >0
";
$res = mysql_query($sql_map);
while($row = mysql_fetch_array($res)){
$jobs_no = count($row['job_country']);
$sql_job = "SELECT COUNT( job_country ) AS jobs_no
FROM rec_advert
WHERE job_country = ".$row['job_country']."
and status = 1
and `delete` = 0
and days_left >0";
$resjob=mysql_query($sql_job);
$rowjob = mysql_fetch_array($resjob);
//here jobs_no is the count of total rows
}
Here I want to do with subquery.
If I read the question right, this should work:
SELECT
CountryId,
Country,
ISO2,
ISO3,
(
SELECT COUNT(DISTINCT noof_country)
FROM table2
WHERE table2.id = table1.CountryId
) AS noof_country_count
FROM table1
It's not immediately clear in your question which column in table1 is a foreign key to which column in table2... or if they are even related that way. If this query doesn't work for you, please clarify your schema.
Based on your updated information, try this:
select distinct c.ISO2, c.Country, a.job_country,
(
select COUNT(a2.job_country)
from rec_advert a2
where a2.job_country = a.job_country
and a2.status = 1
and a2.`delete` = 0
and a2.days_left >0
) as jobs_no
from rec_countries c, rec_advert a
where c.status = 1
and DATE(a.modified_date) >= CURDATE() - INTERVAL 30 DAY
and c.ISO2 <> '--'
and c.ISO2 <> ''
and c.CountryId = a.job_country
and a.status = 1
and a.`delete` = 0
and a.days_left >0