I have this two MySQL statements from same table :
SELECT
`table1`.`product_id` As product_id,
COUNT(DISTINCT(table1.user_id)) AS NonebuyersNumber
FROM table1
WHERE status = 1 AND `ispaid` != 2
GROUP BY `table1`.`product_id`
The second statement is :
SELECT l
`table1`.`product_id` As product_id,
COUNT(DISTINCT(table1.user_id)) AS BuyersNumber
FROM table1
WHERE `ispaid` = 1
GROUP BY `table1`.`product_id`
The result that I want is a table like this one :
I tried to use Union but doesn't work because I have two different columns
Any idea how I can get this 3rd table?
Use conditional aggregation:
SELECT
product_id,
COUNT(DISTINCT CASE WHEN status = 1 AND ispaid != 2
THEN user_id ELSE NULL END) AS NonebuyersNumber
COUNT(DISTINCT CASE WHEN ispaid = 1 THEN user_id ELSE NULL END) AS BuyersNumber
FROM table1
WHERE
(status = 1 AND ispaid != 2) OR
ispaid = 1
GROUP BY
product_id;
This should work because both of your queries aggregate over the product_id and the only differences are the WHERE clauses. We can combine the records from both queries and then use CASE expressions to target records intended for each original query.
SELECT t1.product_id AS product_id
SELECT CASE WHEN t1.NonebuyersNumber IS NULL
THEN 0
ELSE t1.NonebuyersNumber
END
AS NonebuyersNumber,
SELECT CASE WHEN t2.BuyersNumber IS NULL
THEN 0
ELSE t2.BuyersNumber
END
AS BuyersNumber
FROM
(SELECT
`table1`.`product_id` As product_id ,
COUNT(DISTINCT(table1.user_id)) AS NonebuyersNumber
FROM table1 WHERE status =1
AND `ispaid` != 2
GROUP BY `table1`.`product_id`)
AS t1
INNER JOIN
(SELECT
`table1`.`product_id` As product_id ,
COUNT(DISTINCT(table1.user_id)) AS BuyersNumber
FROM table1 WHERE `ispaid` = 1
GROUP BY `table1`.`product_id`)
AS t2
ON t1.product_id = t2.product_id
Basically, you need following
Join both the views on product_id
Use CASE statements in select in case one of the buyers numbers is NULL
Related
I have a table called votes with 4 columns: id, name, choice, date.
****id****name****vote******date***
****1*****sam*******A******01-01-17
****2*****sam*******B******01-05-30
****3*****jon*******A******01-01-19
My ultimate goal is to count up all the votes, but I only want to count 1 vote per person, and specifically each person's most recent vote.
In the example above, the result should be 1 vote for A, and 1 vote for B.
Here is what I currently have:
select name,
sum(case when uniques.choice = A then 1 else 0 end) votesA,
sum(case when uniques.choice = B then 1 else 0 end) votesB
FROM (
SELECT id, name, choice, max(date)
FROM votes
GROUP BY name
) uniques;
However, this doesn't work because the subquery is indeed selecting the max date, but it's not including the correct choice that is associated with that max date.
Don't think "group by" to get the most recent vote. Think of join or some other option. Here is one way:
SELECT v.name,
SUM(v.choice = 'A') as votesA,
SUM(v.choice = 'B') as votesB
FROM votes v
WHERE v.date = (SELECT MAX(v2.date) FROM votes v2 WHERE v2.name = v.name)
GROUP BY v.name;
Here is a SQL Fiddle.
Your answer are close but need to JOIN self
Subquery get Max date by name then JOIN self.
select
sum(case when T.vote = 'A' then 1 else 0 end) votesA,
sum(case when T.vote = 'B' then 1 else 0 end) votesB
FROM (
SELECT name,Max(date) as date
FROM T
GROUP BY name
) AS T1 INNER JOIN T ON T1.date = T.date
SQLFiddle
Try this
SELECT
choice,
COUNT(1)
FROM
votes v
INNER JOIN
(
SELECT
id,
max(date)
FROM
votes
GROUP BY
name
) tmp ON
v.id = tmp.id
GROUP BY
choice;
Something like this (if you really need count only last vote of person)
SELECT
sum(case when vote='A' then cnt else 0 end) voteA,
sum(case when vote='B' then cnt else 0 end) voteB
FROM
(SELECT vote,count(distinct name) cnt
FROM (
SELECT name,vote,date,max(date) over (partition by name) maxd
FROM votes
)
WHERE date=maxd
GROUP BY vote
)
PS. MySQL v 8
select
name,
sum( case when choice = 'A' then 1 else 0 end) voteA,
sum( case when choice = 'B' then 1 else 0 end) voteB
from
(
select id, name, choice
from votes
where date = (select max(date) from votes t2
where t2.name = votes.name )
) t
group by name
Or output just one row for the total counts of VoteA and VoteB:
select
sum( case when choice = 'A' then 1 else 0 end) voteA,
sum( case when choice = 'B' then 1 else 0 end) voteB
from
(
select id, name, choice
from votes
where date = (select max(date) from votes t2
where t2.name = votes.name )
) t
Based on #d-shish solution, and since introduction (in MySQL 5.7) of ONLY_FULL_GROUP_BY, the GROUP BY statement must be placed in subquery like this :
SELECT v.`name`,
SUM(v.`choice` = 'A') as `votesA`,
SUM(v.`choice` = 'B') as `votesB`
FROM `votes` v
WHERE (
SELECT MAX(v2.`date`)
FROM `votes` v2
WHERE v2.`name` = v.`name`
GROUP BY v.`name` # << after
) = v.`date`
# GROUP BY v.`name` << before
Otherwise, it won't work anymore !
I have this kind of table (simplified):
orders sample data below
---------------------------------------------
id INT: 1 2 3 4 5
userid INT 10 10 10 20 20
status CHAR(1) A A B A C
and want to select all orders where for each userid status is IN ('A','B') but have no orders at all IN ('C','D').
So output for above data would give orders with ID=1, 2 and 3. User ID=10 have orders A and B, but no C or D.
In other words: Select orders for customers who have orders with status A or B, but none of statuses C or D.
I started with this:
SELECT
xcart_orders.orderid,
xcart_orders.*
FROM xcart_orders
JOIN (
select count(*) as bad_statuses, userid from xcart_orders
where status in ('C','D')
group by userid
) bo
ON bo.userid=xcart_orders.userid
JOIN (
select count(*) as good_statuses, userid from xcart_orders
where status in ('A','B')
group by userid
) bo2
ON bo2.userid=xcart_orders.userid
WHERE bo2.good_statuses>0 and bo.bad_statuses=0
but think count(*) won't return zero for 'bad' statuses, so I get no results.
You have an aggregation without GROUP BY and for check the result you need us HAVING instead of WHERE
SELECT
xcart_orders.orderid,
xcart_orders.*,
SUM(CASE WHEN xcart_orders.status in ('C','D') THEN 1 ELSE 0 END) AS bad_statuses,
SUM(CASE WHEN xcart_orders.status in ('A','B') THEN 1 ELSE 0 END) AS good_statuses
FROM xcart_orders
GROUP BY orderid
HAVING bad_statuses = 0
AND good_statuses > 0
Please be aware the fields you get from xcart_orders.* will be random (or non deterministc) if you need a particular one you need to order it first.
First you GROUP BY user_id to check if have any status different to 'A', 'B'
Then you select orders from those user_id:
SQL DEMO
SELECT `user_id`
FROM orders1
GROUP BY `user_id`
HAVING COUNT(*) = COUNT(CASE WHEN `status` IN ('A', 'B') THEN 1 END);
SELECT *
FROM orders1
WHERE `user_id` IN (SELECT `user_id`
FROM orders1
GROUP BY `user_id`
HAVING COUNT(*) = COUNT(CASE WHEN `status` IN ('A', 'B') THEN 1 END)
);
OUTPUT
Basically I need to merge these into one single query:
SELECT COUNT( DISTINCT id ) AS totalRows1
FROM other_events WHERE status = "approved"
AND Location = 1
SELECT COUNT( DISTINCT Id ) AS totalRows2
FROM core_events WHERE Status = "Active"
AND Location_id = 1
When I do it like below, if there is no event with Location_id = 1 query returns 0. In that condition I need it to return the count of the first table only.
SELECT COUNT( DISTINCT t1.id ) + COUNT( DISTINCT t2.Id ) AS total
FROM other_events AS t1, core_events AS t2
WHERE t1.status = "approved"
AND t1.Location = 1
AND t2.Location_id = 1
AND t2.Status = 'Active'
ps. column names are exactly like above
Use a UNION statement to merge the result like this:
SELECT SUM(total) FROM (
SELECT COUNT(DISTINCT id) AS total
FROM other_events
WHERE (status = "approved" AND Location = 1)
UNION ALL
SELECT COUNT(DISTINCT Id) AS total
FROM core_events
WHERE (Location_id = 1 AND Status = 'Active')
) union_result
This is my table structure:
CUST_ID ORDER_MONTH
---------------------
1 1
1 5
2 3
2 4
My objective is to tag these customers as either New or Returning customers.
When I filter the query lets say for month 1 then customer 1 should have the tag 'New' but when I filter it for month 5 then customer 1 should show up as 'Return' as he already made a purchase in month 1.
Same way customer ID 2 should show up as New for month 3 and return for month 4.
I want to do this using a CASE statement and not inner join.
Thanks
If you insist on using a case statement, the logic would be something like "If this is the first month for that user, write new, otherwise write returning." The query would be as follows:
SELECT CASE
WHEN m.month = (SELECT MIN(month) FROM myTable WHERE customer = m.customer) THEN 'New'
ELSE 'Returning' END AS customerType
FROM myTable m;
However, I think this would be nicer and more readable in a JOIN. You can write an aggregation query to get the earliest month for each user, and then use COALESCE() to replace null values with 'Returning'. The aggregation:
SELECT customer, MIN(month) AS minMonth, 'New' AS customerType
FROM myTable
GROUP BY customer ;
To get the rest:
SELECT m.customer, m.month, COALESCE(t.customerType, 'Returning') AS customerType
FROM myTable m
LEFT JOIN(
SELECT customer, MIN(month) AS minMonth, 'New' AS customerType
FROM myTable
GROUP BY customer) t ON t.customer = m.customer AND t.minMonth = m.month;
Here is an SQL Fiddle example that shows both examples.
You don't need a JOIN and a case statement would probably be overkill...
SELECT CUST_ID, IF(COUNT(1)>1, 'Returning', 'New') AS blah
FROM the_table
WHERE ORDER_MONTH <= the_month
GROUP BY CUST_ID
;
Of course, using just month is going to cause problems after a year (or really, after passing December.)
This would be better
SELECT CUST_ID, IF(COUNT(1)>1, 'Returning', 'New') AS blah
FROM the_table
WHERE order_date <= some_date
GROUP BY CUST_ID
;
Well I do not reccomend this way but this is what you want.
select *
,case when order_month = (select MIN(order_month) from #temp t2 where t1.cust_ID =t2.cust_id) THEN 'NEW' ELSE 'Return' end 'Type'
from #temp t1
I think I get what you're trying to do. Your case statement basically just needs to check if the customer's month equals the month you're filtering by. Something like this:
SELECT
<your other fields>,
CASE WHEN Order_Month = <your filter> THEN 'New'
ELSE 'Return'
END AS 'SomeName'
FROM <your table>
Try this query
select a.CUST_ID, a.ORDER_MONTH ,case when b is not null then 'Return' else 'New' end as type
from tablename a
join tablename b on a.CUST_ID=b.CUST_ID and a.ORDER_MONTH>b.ORDER_MONTH
SELECT *,
CASE
WHEN EXISTS (SELECT *
FROM [YourTable] t2
WHERE t1.cust_id = t2.cust_id
AND t2.order_month < t1.order_month) THEN 'Return'
ELSE 'New'
END
FROM [YourTable] t1
This query uses CASE on an EXISTS clause.
The EXISTS is on a subquery which queries the same table for any rows in previous months.
If there are rows for previous months then the EXISTS is true and the CASE returns 'Return'. If there are no rows for previous months then the EXISTS is false and the CASE returns 'New'.
I'm trying to make a statistics page in my php script. in order to select the count from each table I need more than 30 Queries like this
SELECT COUNT(order_id) as `uncompleted_orders` FROM `orders` WHERE `order_status` != 0
and then I need to run another query like this:
SELECT COUNT(order_id) as `completed_orders` FROM `orders` WHERE `order_status` = 1
I've tried this approach, but it didn't work:
SELECT COUNT(order_id) as `uncompleted_orders` FROM `sd_orders` WHERE `order_status` != 4;
SELECT COUNT(order_id) as `completed_orders` FROM `sd_orders` WHERE `order_status` = 4;
Is there any way to creat a new temp table in MySQL contains the count for other tables?
You could try something like this:
SELECT
(
SELECT COUNT(order_id) FROM `sd_orders` WHERE `order_status` != 4
) as `uncompleted_orders`,
(
SELECT COUNT(order_id) FROM `sd_orders` WHERE `order_status` = 4
) as `completed_orders`
You will have a result set with one row and a field for each count.
Without more information it's impossible to generalise, but there are many constructs that can help you here.
First, your example is actually from one table, and not two. This means that you can do the following...
SELECT
COUNT(CASE WHEN order_status = 4 THEN order_id END) AS complete_orders,
COUNT(CASE WHEN order_status <> 4 THEN order_id END) AS incomplete_orders
FROM
sd_orders
This works because COUNT(<something>) doesn't include an NULLs in the results. And by not including an ELSE clause, anything that doesn't match returns NULL. Another way people accomplish the same result is SUM(CASE WHEN ? THEN 1 ELSE 0 END).
Second, where you do actually have multiple tables, you can combine the results in several different ways...
-- Where you want one value from each table...
--------------------------------------------------------------------------------
SELECT
(SELECT COUNT(*) FROM table1 WHERE fieldx = ?) AS value1,
(SELECT COUNT(*) FROM table2 WHERE fieldy = ?) AS value2
-- Where you want one row of values from each table...
--------------------------------------------------------------------------------
SELECT
table1_summary.value1 AS table1_value1,
table1_summary.value2 AS table1_value2,
table2_summary.value1 AS table2_value1,
table2_summary.value2 AS table2_value2
FROM
(
SELECT
COUNT(CASE WHEN fieldx = ? THEN id END) AS value1,
COUNT(CASE WHEN fieldx <> ? THEN id END) AS value2
FROM
table1
)
AS table1_summary
CROSS JOIN
(
SELECT
COUNT(CASE WHEN fieldy = ? THEN id END) AS value1,
COUNT(CASE WHEN fieldy <> ? THEN id END) AS value2
FROM
table2
)
AS table2_summary
-- Where you want many rows, but of the same fields, from each table...
--------------------------------------------------------------------------------
SELECT
*
FROM
(
SELECT
'Table1' AS source_table,
fielda AS some_grouping,
COUNT(CASE WHEN fieldx = ? THEN id END) AS value1,
COUNT(CASE WHEN fieldx <> ? THEN id END) AS value2
FROM
table1
GROUP BY
fielda
UNION ALL
SELECT
'Table2' AS source_table,
fieldb AS some_grouping,
COUNT(CASE WHEN fieldy = ? THEN id END) AS value1,
COUNT(CASE WHEN fieldy <> ? THEN id END) AS value2
FROM
table2
GROUP BY
fieldb
)
AS summary
ORDER BY
source_table,
some_grouping,
value1,
value2
As you can see, there are a lot of ways to do this. How you approach it totally depends on your data and your needs.