I have a query as the following
SELECT
sum(price),
count(id),
sum case(when spec='bath' then price else 0 END) as bath_money
FROM
table1
LEFT JOIN table2 ON table1.id = table2.fkt1
LEFT JOIN table3 ON table2.id = table3.fkt2
WHERE 1
group by sale;
Now my problem is that table 3 has 2 rows for each row in Table 2. Table 2 is the one I actually use to add up sales and to sum price but since I need to left join for Table 3 everything is added twice.
Would there be a way of adding up prices of table 2 ignoring all double lines generated by joining Table 3? Otherwise I'd just write another query, but I'd like to know whether I can do a sum ignoring a specific join??
Does this work :
SELECT
sum(price),
count(id),
sum(case when spec='bath' then price else 0 END) as bath_money
FROM table1 t1
LEFT JOIN table2 ON table1.id = table2.fkt1
LEFT JOIN (select * from table3 GROUP BY fkt2) table3a ON table2.id = table3a.fkt2
group by sale;
You can try something like
SELECT
sum(t1.price),
count(t1.id),
sum (case when t2.spec='bath' then t2.price else 0 END) as bath_money
FROM
table1 t1
LEFT JOIN table2 t2 ON t1.id = t2.fkt1
LEFT JOIN table3 t3 ON t2.id = t3.fkt2
group by t1.sale
Related
Thanks for assisting with the previous query (SQL Query that selects a column in table 1 and uses that to select sum in table 2) of SUM from 2 tables, I now have a additional Condition for 1 of the tables. I would like to add WHERE Group1 = 1 AND IN/OUT = 'OUT'
I have 3 tables,
Names ,Groups
Names ,Payments
Names ,Payments and IN/OUT
I want to only SUM the OUT Payments in Table 3, I am getting total payments only So FAR is have:
SELECT t1.name1, SUM(t2.sale2),SUM(t3.sale3)
FROM table1 t1 JOIN table2 t2 ON t1.name1 = t2.name2
JOIN table3 t3 ON t1.name1 = t3.name3
WHERE group1 = 1
GROUP BY t1.name1
i would also like to add a zero if there is no data to sum instead of removing the whole record, Currently if a name has no payments in Table 3 but has payments in table 2 it deletes the record.
Please check the query below =>
To Get OutPayment group by Name
SELECT t1.Names,SUM(t3.Payments) As OutPayment
FROM TABLE3 as t3
INNER JOIN TABLE1 as t1 ON t1.Names = t3.Names
INNER JOIN TABLE2 as t2 ON t1.Names = t2.Names
WHERE t1.GroupID = 1 AND t3.INOROUT=2 --INOROUT =2 is OUT and 1 is IN
GROUP BY t1.Names;
To Get TotalOutPayment
SELECT SUM(t3.Payments) As TotalOutPayment
FROM TABLE3 as t3
INNER JOIN TABLE1 as t1 ON t1.Names = t3.Names
INNER JOIN TABLE2 as t2 ON t1.Names = t2.Names
WHERE t1.GroupID = 1 AND t3.INOROUT=2; --INOROUT =2 is OUT and 1 is IN
Note: Code is in DBFiddle too Check the Demo Query Link
In MySQL, how would you re-write a SELECT query which JOIN SELECT subqueries that are doing almost the same thing.
In my case, I am getting performance issues because in the subqueries, I need to join on the same tables for each subqueries which is an heavy operation.
Consider the below (ugly) example:
set #businessdate = '2020-01-24';
Select Daily.*, Monthly.Price, Yearly.Price FROM
# DAILY
(Select #businessdate as BusinessDate, t1.Owner , SUM(t.Price) AS DailyPrice
FROM Table t
INNER JOIN Table2 t2 on ...
INNER JOIN Table1 t1 on ...
where t2.date = #businessdate
GROUP BY t1.Owner) Daily
INNER JOIN
# MONTHLY
(Select SUM(t.Price) AS Price, t1.Owner
FROM Table t
INNER JOIN Table2 t2 on ...
INNER JOIN Table1 t1 on ...
where MONTH(t2.date) = MONTH(#businessdate) and YEAR(t2.date) = YEAR(#businessdate)
GROUP BY t1.Owner) Monthly
INNER JOIN
#YEARLY
(Select SUM(t.Price) AS Price, t1.Owner
FROM Table t
INNER JOIN Table2 t2 on ...
INNER JOIN Table1 t1 on ...
where YEAR(t2.date) = YEAR(#businessdate)
GROUP BY t1.Owner) Yearly
The reason is I need the date in my where clause (coming from t2), and one field in my group by coming from t1. I also need to display some fields from t1.
I only need the SUM(Price) (the Price from Monthly and Yearly...) so to me it sounds like the joins in subqueries is overkill even if it is working fine (very slow...)
You could use conditional aggregation with a single query:
Select
#businessdate as BusinessDate, ... ,
SUM(CASE WHEN t2.date = #businessdate THEN t.Price ELSE 0 END) AS DailyPrice,
SUM(CASE WHEN MONTH(t2.date) = MONTH(#businessdate) AND
YEAR(t2.date) = YEAR(#businessdate)
THEN t.Price ELSE 0 END) AS MonthlyPrice,
SUM(CASE WHEN YEAR(t2.date) = YEAR(#businessdate)
THEN t.Price ELSE 0 END) AS AnnualPrice
FROM Table t
INNER JOIN Table2 t2 on ...
INNER JOIN Table1 t1 on ...
GROUP BY t1.Owner
This at least would allow you to avoid unneeded passes over the joined tables. Note that your GROUP BY clause is invalid as written; the business date is the only valid single column which can be selected, other than the conditional sums.
I have 2 tables
table 1
id product
1 P1
2 P2
table 2
id amount product_t1
1 100 P1
2 200 P1
3 300 P2
4 400 P1
5 500 P2
I want my output to be:
product totalAmount(sum of amount)
P1 700
P2 800
EDIT: Here is my query so far
SELECT T1.product, SUM(T2.amount)
FROM table1 T1
INNER JOIN table2 T2
ON T1.product = T2.product_t1
Thanks!
you should use group by
SELECT T1.product, SUM(T2.amount)
FROM table1 T1
INNER JOIN table2 T2
ON T1.product = T2.product_t1
GROUP BY product
Since you're not using foreign keys you don't even need the table 1 for the desired result.
SELECT
product_t1 AS product,
SUM(amount) AS totalAmount
FROM table2
GROUP BY product_t1
What you're missing is the GROUP BY statement in order to get a separate row for each individual product
SELECT T1.product, SUM(T2.amount)
FROM table1 T1
INNER JOIN table2 T2
ON T1.product = T2.product_t1
GROUP BY product T1.product
Use the GROUP BY tag . Group by helps to group your result via value of product
Try to play with GROUP BY and AS
SELECT product_t1 as product, SUM(amount) AS totalAmount FROM table2
GROUP BY product
https://dev.mysql.com/doc/refman/5.7/en/group-by-modifiers.html
OR add to your code group by
SELECT T1.product, SUM(T2.amount)
FROM table1 T1
INNER JOIN table2 T2 ONT1.product = T2.product_t1
Gruop by T1.product
I have 2 columns in 1 table that I need to combine the COUNT() of each together. However, if both columns have a value, then that row needs to only be counted once.
Here's what I've tried but doesn't work:
SELECT SUM( IF (table1.col1 IS NOT NULL OR table1.col2 IS NOT NULL, 1, 0) )
FROM table1 INNER JOIN table2 ON table2.col1 = table1.id
INNER JOIN table3 ON table3.id = table2.personid
WHERE table3.otherid = 1
AND table1.col1 > '2000-01-01';*
Sample Data:
Table 1
Col1......Col2
04/17/2013........04/17/2013
null..........04/17/2013
03/26/2013.......02/17/2013
03/25/2013.........null
null.........null
02/22/2013...........02/21/2013
Result should be = 5. Because 5 records with at least 1 date in either column, but the records with dates in both columns are only counted once
Figured it out.
SELECT COUNT(*)
FROM table1 INNER JOIN table2 ON table2.col1 = table1.id
INNER JOIN table2 ON table3.id = table2.personid
WHERE table3.otherid = 1
AND (table1.col1 > '2000-01-01' OR table1.col2 > '2000-01-01');
SELECT
count(t1.id) AS c1
FROM
table2
LEFT JOIN table1 AS t1 ON (t1.uid = table2.uid)
WHERE
table2.mode = 'ls'
GROUP BY
t1.id
c1 = 6 -> CORRECT!
SELECT
count(t2.id) AS c2
FROM
table2
LEFT JOIN table1 AS t2 ON (t2.pid = table2.id)
WHERE
table2.mode = 'ls'
GROUP BY
t1.id
c2 = 1 -> CORRECT!
SELECT
count(t1.id) AS c1,
count(t2.id) AS c2
FROM
table2
LEFT JOIN table1 AS t1 ON (t1.uid = table2.uid)
LEFT JOIN table1 AS t2 ON (t2.pid = table2.id)
WHERE
table2.mode = 'ls'
GROUP BY
t1.id
c1 = 6 -> CORRECT!
c2 = 6 -> WRONG!
How do I request both counts in one query, without getting wrong results?
I need to count two different requests at the same table (table1).
so, I'm using an alias for both request. (t1). Each alias-request is working fine alone. If I use both in the same query, i got wrong results.
count() will get you the number of records that are returned by your query. Since if you removed the counts and replaced it with * you would have 6 rows both of those counts are giving you 6.
Is there any reason why you cant use two sub selects and return the result of each of those?
So:
SELECT subQ1.c1, subQ2.c2 FROM
(SELECT count(t1.id) AS c1 FROM table2
LEFT JOIN table1 AS t1 ON (t1.uid = table2.uid)
WHERE table2.mode = 'ls') as subQ1,
(SELECT count(t2.id) AS c2 FROM table2
LEFT JOIN table1 AS t2 ON (t2.pid = table2.id)
WHERE table2.mode = 'ls') as SubQ2;
I believe your problem on the full query is your group by function. You are grouping by t.id, thus a1.id will have a different count based on how many rows you have.
What I mean by this is if there are 6 rows in table t, then count is going to return 6 for table t; but also since there looks to be a 1 to 1 relation on table a, there are 6 matching rows in table a to the 6 matching rows in table t. such that
t.id = a.id
1 = 1
2= 2 ...etc.
Thus your count is returning rows versus the count you believe you should have? I believe sum function is what you want to use here.
You could try this...but I'm not really sure what you're trying to do.
SELECT (...)
count(CASE WHEN t1.uid = t3.uid THEN t1.id ELSE NULL END) AS CBanz,
count(CASE WHEN ta1.pid = t3.id THEN a1.id ELSE NULL END) AS CBanz1
FROM
t0
LEFT JOIN (...)
LEFT JOIN t1 ON (t1.uid = t3.uid)
LEFT JOIN t1 AS a1 ON (a1.pid = t3.id)
WHERE (...)