I have 2 columns in 1 table that I need to combine the COUNT() of each together. However, if both columns have a value, then that row needs to only be counted once.
Here's what I've tried but doesn't work:
SELECT SUM( IF (table1.col1 IS NOT NULL OR table1.col2 IS NOT NULL, 1, 0) )
FROM table1 INNER JOIN table2 ON table2.col1 = table1.id
INNER JOIN table3 ON table3.id = table2.personid
WHERE table3.otherid = 1
AND table1.col1 > '2000-01-01';*
Sample Data:
Table 1
Col1......Col2
04/17/2013........04/17/2013
null..........04/17/2013
03/26/2013.......02/17/2013
03/25/2013.........null
null.........null
02/22/2013...........02/21/2013
Result should be = 5. Because 5 records with at least 1 date in either column, but the records with dates in both columns are only counted once
Figured it out.
SELECT COUNT(*)
FROM table1 INNER JOIN table2 ON table2.col1 = table1.id
INNER JOIN table2 ON table3.id = table2.personid
WHERE table3.otherid = 1
AND (table1.col1 > '2000-01-01' OR table1.col2 > '2000-01-01');
Related
Thanks for assisting with the previous query (SQL Query that selects a column in table 1 and uses that to select sum in table 2) of SUM from 2 tables, I now have a additional Condition for 1 of the tables. I would like to add WHERE Group1 = 1 AND IN/OUT = 'OUT'
I have 3 tables,
Names ,Groups
Names ,Payments
Names ,Payments and IN/OUT
I want to only SUM the OUT Payments in Table 3, I am getting total payments only So FAR is have:
SELECT t1.name1, SUM(t2.sale2),SUM(t3.sale3)
FROM table1 t1 JOIN table2 t2 ON t1.name1 = t2.name2
JOIN table3 t3 ON t1.name1 = t3.name3
WHERE group1 = 1
GROUP BY t1.name1
i would also like to add a zero if there is no data to sum instead of removing the whole record, Currently if a name has no payments in Table 3 but has payments in table 2 it deletes the record.
Please check the query below =>
To Get OutPayment group by Name
SELECT t1.Names,SUM(t3.Payments) As OutPayment
FROM TABLE3 as t3
INNER JOIN TABLE1 as t1 ON t1.Names = t3.Names
INNER JOIN TABLE2 as t2 ON t1.Names = t2.Names
WHERE t1.GroupID = 1 AND t3.INOROUT=2 --INOROUT =2 is OUT and 1 is IN
GROUP BY t1.Names;
To Get TotalOutPayment
SELECT SUM(t3.Payments) As TotalOutPayment
FROM TABLE3 as t3
INNER JOIN TABLE1 as t1 ON t1.Names = t3.Names
INNER JOIN TABLE2 as t2 ON t1.Names = t2.Names
WHERE t1.GroupID = 1 AND t3.INOROUT=2; --INOROUT =2 is OUT and 1 is IN
Note: Code is in DBFiddle too Check the Demo Query Link
I have a query as the following
SELECT
sum(price),
count(id),
sum case(when spec='bath' then price else 0 END) as bath_money
FROM
table1
LEFT JOIN table2 ON table1.id = table2.fkt1
LEFT JOIN table3 ON table2.id = table3.fkt2
WHERE 1
group by sale;
Now my problem is that table 3 has 2 rows for each row in Table 2. Table 2 is the one I actually use to add up sales and to sum price but since I need to left join for Table 3 everything is added twice.
Would there be a way of adding up prices of table 2 ignoring all double lines generated by joining Table 3? Otherwise I'd just write another query, but I'd like to know whether I can do a sum ignoring a specific join??
Does this work :
SELECT
sum(price),
count(id),
sum(case when spec='bath' then price else 0 END) as bath_money
FROM table1 t1
LEFT JOIN table2 ON table1.id = table2.fkt1
LEFT JOIN (select * from table3 GROUP BY fkt2) table3a ON table2.id = table3a.fkt2
group by sale;
You can try something like
SELECT
sum(t1.price),
count(t1.id),
sum (case when t2.spec='bath' then t2.price else 0 END) as bath_money
FROM
table1 t1
LEFT JOIN table2 t2 ON t1.id = t2.fkt1
LEFT JOIN table3 t3 ON t2.id = t3.fkt2
group by t1.sale
Please consider this query:
SELECT table1.* ,
(SELECT quantity FROM table2 WHERE id = table1.id AND table2.location = 10) quantity,
(SELECT reorder_level FROM table2 WHERE id = table1.id AND table2.location = 10) reorder_level,
(SELECT stock_date FROM table2 WHERE id = table1.id AND table2.location = 10) stock_date
FROM table1
WHERE category_id = 5 ORDER BY table1.id;
The aliases quantity, location and stock_date are obviously referencing a a row in table2 that fulfill the condition: id=table1.id and location=10.
This query works, but is probably suboptimal as a result of the clumsy subqueries.
How can I best join table1 to table2 USING(id) but only on rows where location is also 10.
TIP: One row from table1 has many rows in table2.
Unfortunately, the actual table definitions are much more complex, and I reckoned it might be counter-productive to dump the entire thing on this thread.
You can use additional condition in ON() part so it will join only rows which fulfills the provided criteria
SELECT t1.* ,
t2.quantity ,
t2.reorder_level,
t2.stock_date
FROM table1 t1
LEFT JOIN table2 t2 ON t1.id = t2.id AND t2.location = 10
WHERE t1.category_id = 5
ORDER BY t1.id;
Another way would be use a subselect for your table2 and select only rows where location is equal to 10
SELECT t1.* ,
t2.quantity ,
t2.reorder_level,
t2.stock_date
FROM table1 t1
LEFT JOIN
(SELECT * FROM table2 WHERE t2.location = 10) t2
ON t1.id = t2.id
WHERE t1.category_id = 5
ORDER BY t1.id;
I have 3 tables: table1, table2 & table3
I make a select query from table1 which LEFT JOINS the other two tables. In the select I have a group_concat which takes a value from table3. Everything works well until a row with a specific row doesn't exist. The group_concat list becomes empty. Instead, I would like it to set values in the group_concat to NULL for the ones where the rows doesn't exist.
Like I said if the value in table3 exist for all the rows in table2 then it works. If not, the whole group_concat is empty.
Some "simplified" code of what I got so far:
SELECT
table1.table2Id,
table1.dateAdded,
IF(COUNT(table2.table3Id) = COUNT(*), GROUP_CONCAT(table2.table3Id), NULL) as group1,
IF(COUNT(table3.ext) = COUNT(*), GROUP_CONCAT(table3.ext), NULL) as group2
FROM table1
LEFT JOIN table2 ON
table2.id = table1.table2Id
LEFT JOIN table3 ON
table3.id = table2.table3Id
Fixed it by changing
IF(COUNT(table3.ext) = COUNT(*), GROUP_CONCAT(table3.ext), NULL) as group2
to
GROUP_CONCAT(IFNULL(table3.ext, NULL)) as group2
In your situation when you are using joins use derieved sub query in join and use IFNULL and set its default value to 0 then in the outer table this value (0) will be used if there comes null.
EDITS :
as there is no data to test you can do it like this. Use INNER JOIN instead of left join.
SELECT
table1.table2Id,
table1.dateAdded,
IF(COUNT(table2.table3Id) = COUNT(*), GROUP_CONCAT(table2.table3Id), NULL) as group1,
IF(COUNT(table3.ext) = COUNT(*), GROUP_CONCAT(table3.ext), NULL) as group2
FROM table1
INNER JOIN table2 ON
table2.id = table1.table2Id
INNER JOIN table3 ON
table3.id = table2.table3Id
Also try using derieved sub query
SELECT
table1.table2Id,
table1.dateAdded,
IF(COUNT(t2.table3Id) = COUNT(*), GROUP_CONCAT(t2.table3Id), NULL) as group1,
IF(COUNT(table3.ext) = COUNT(*), GROUP_CONCAT(table3.ext), NULL) as group2
FROM table1
LEFT JOIN (
SELECT
id,
IFNULL(table3Id,0) as table3Id,
table3Id
FROM table2
GROUP BY id table3Id
)as t2 ON t2.id = table1.table2Id
INNER JOIN table3 ON table3.id = t2.table3Id
SELECT
count(t1.id) AS c1
FROM
table2
LEFT JOIN table1 AS t1 ON (t1.uid = table2.uid)
WHERE
table2.mode = 'ls'
GROUP BY
t1.id
c1 = 6 -> CORRECT!
SELECT
count(t2.id) AS c2
FROM
table2
LEFT JOIN table1 AS t2 ON (t2.pid = table2.id)
WHERE
table2.mode = 'ls'
GROUP BY
t1.id
c2 = 1 -> CORRECT!
SELECT
count(t1.id) AS c1,
count(t2.id) AS c2
FROM
table2
LEFT JOIN table1 AS t1 ON (t1.uid = table2.uid)
LEFT JOIN table1 AS t2 ON (t2.pid = table2.id)
WHERE
table2.mode = 'ls'
GROUP BY
t1.id
c1 = 6 -> CORRECT!
c2 = 6 -> WRONG!
How do I request both counts in one query, without getting wrong results?
I need to count two different requests at the same table (table1).
so, I'm using an alias for both request. (t1). Each alias-request is working fine alone. If I use both in the same query, i got wrong results.
count() will get you the number of records that are returned by your query. Since if you removed the counts and replaced it with * you would have 6 rows both of those counts are giving you 6.
Is there any reason why you cant use two sub selects and return the result of each of those?
So:
SELECT subQ1.c1, subQ2.c2 FROM
(SELECT count(t1.id) AS c1 FROM table2
LEFT JOIN table1 AS t1 ON (t1.uid = table2.uid)
WHERE table2.mode = 'ls') as subQ1,
(SELECT count(t2.id) AS c2 FROM table2
LEFT JOIN table1 AS t2 ON (t2.pid = table2.id)
WHERE table2.mode = 'ls') as SubQ2;
I believe your problem on the full query is your group by function. You are grouping by t.id, thus a1.id will have a different count based on how many rows you have.
What I mean by this is if there are 6 rows in table t, then count is going to return 6 for table t; but also since there looks to be a 1 to 1 relation on table a, there are 6 matching rows in table a to the 6 matching rows in table t. such that
t.id = a.id
1 = 1
2= 2 ...etc.
Thus your count is returning rows versus the count you believe you should have? I believe sum function is what you want to use here.
You could try this...but I'm not really sure what you're trying to do.
SELECT (...)
count(CASE WHEN t1.uid = t3.uid THEN t1.id ELSE NULL END) AS CBanz,
count(CASE WHEN ta1.pid = t3.id THEN a1.id ELSE NULL END) AS CBanz1
FROM
t0
LEFT JOIN (...)
LEFT JOIN t1 ON (t1.uid = t3.uid)
LEFT JOIN t1 AS a1 ON (a1.pid = t3.id)
WHERE (...)