I have a subscription table that tracks membership renewals by date. Renewals are for calendar year but members are allowed to renew as early as Oct 1, in which case they would be current until Dec. 31 of the following year . Therefore it is possible to renew in January and then renew again in October of the same year. I'm reporting total memberships by month and I want to avoid counting that as 2 memberships.
Each record has a unique prodID but can have more than 1 record of a memberID due to the renewal option above. payDate is the transaction date
My statement is:
$sql = "SELECT
EXTRACT(MONTH FROM payDate) as month,
EXTRACT(YEAR FROM payDate) as year,
count(*)
FROM
memberDues
WHERE payDate >= $lastYear-10-01
GROUP BY
month,
year
ORDER BY
year ASC,
month ASC";
I get an output like this (not formatted):
Member dues paid by month
October 46
November 30
December 99
January 42
February 8
March 9
April 4
May 1
June 3
Member Total: 242
How do I modify the select statement to avoid duplicate renewals in a report period?
you need to group by memberID to get one member renewal not being repeated.
SELECT year, month, count(memberID) FROM (
SELECT memberID,
EXTRACT(MONTH FROM payDate) as month,
EXTRACT(YEAR FROM payDate) as year,
count(*)
FROM
memberDues
WHERE payDate >= $lastYear-10-01
GROUP BY
memberID,
month,
year
ORDER BY
year ASC,
month ASC";
)TMP GROUP BY year, month
Counting the distinct memberID's for each month should do the job:
SELECT
EXTRACT(MONTH FROM payDate) as month,
EXTRACT(YEAR FROM payDate) as year,
count(DISTINCT memberID)
FROM
memberDues
WHERE payDate >= $lastYear-10-01
GROUP BY
month,
year
ORDER BY
year ASC,
month ASC
Related
How can we get record of first or second month of current year in MySQL query?
Like I want this data for January and then for February:
select Sum(amount) as Amount from tbl_incomes where created_at = 'here the month January OR February of current year should be claused'
You can use the following, using YEAR and MONTH:
SELECT SUM(amount) AS Amount
FROM tbl_incomes
WHERE YEAR(created_at) = YEAR(NOW()) AND MONTH(created_at) IN (1, 2)
In case you want the SUM for January and February in separate rows you can use this:
SELECT SUM(amount) AS Amount
FROM tbl_incomes
WHERE YEAR(created_at) = YEAR(NOW()) AND MONTH(created_at) IN (1, 2)
GROUP BY YEAR(created_at), MONTH(created_at)
You should use a range expression.
SELECT sum(amount) amount
FROM tbl_incomes
WHERE created_at >= concat(year(now), '-01-01')
AND created_at < concat(year(now), '-03-01');
That way an index on created_at can support the query.
I have a table with columns day, month, year, total_payments. And I have to calculate total_payments according to days, months, years.
How can I calculate values?
I am thinking code like :
select
month, year, sum(total_payments)
from
webassignment.subscription_stats
group by
day;
select
month, year, sum(total_payments)
from
webassignment.subscription_stats
group by
month;
select
month, year, sum(total_payments)
from
webassignment.subscription_stats
group by
year;
but it will not return the correct answers. And I want to calculate total_payments daywise, monthwise, yearwise. Please help me to find values.
Sample input :
Day Month Year Total_payments
10 01 2008 10
10 01 2008 20
11 02 2008 10
10 03 2010 10
Output:
Daywise :
day month year total_payments
-----------------------------
10 01 2008 30
11 02 2008 10
10 03 2010 10
Same for month and yearwise
You can get a summary with Totals by Year, Month and Day using GROUP BY WITH ROLLUP:
SELECT
`Year`,
`Month`,
`Day`,
SUM(`Total_payments`) as `Totals`
FROM `webassignment`.`subscription_stats`
GROUP BY `Year`,`Month`,`Day` WITH ROLLUP;
If you want individual queries for Year, Month and Day:
By Year:
SELECT
`Year`,
SUM(`Total_payments`) as `Totals`
FROM `webassignment`.`subscription_stats`
GROUP BY `Year`
ORDER BY `Year;
By Month:
SELECT
`Year`,
`Month`,
SUM(`Total_payments`) as `Totals`
FROM `webassignment`.`subscription_stats`
WHERE `Year` = 2017
GROUP BY `Year`,`Month`
ORDER BY `Year`,`Month`;
By Day:
SELECT
`Year`,
`Month`,
`Day`,
SUM(`Total_payments`) as `Totals`
FROM `webassignment`.`subscription_stats`
GROUP BY `Year`,`Month`,`Day`
ORDER BY `Year`,`Month`,`Day`;
A way could be the use on an union for show the different result based on different group by level
select day, month,year,sum(total_payments)
from webassignment.subscription_stats group by day, month,year
union
select null, month,year,sum(total_payments)
from webassignment.subscription_stats group by month,year
union
select null, null ,year,sum(total_payments)
from webassignment.subscription_stats group by year
order by year, month, day
for the sample you provided should be enough
select day, month,year,sum(total_payments)
from webassignment.subscription_stats group by day, month,year
order by day, month,year
SR_ AREA INS_PRODUCT DATEADD TOTAL
Clinical Question PS 2016-01-06 280
I'm trying to show the month by name say January and I want all the totals for the month of January not just for one day in the month.
I got it to show just Month and total how do I get it to show all the months this is the code I have so far.
SELECT DATENAME(MM,GETDATE()) AS MONTH, COUNT(*) AS TOTAL
FROM S_SRV_REQ WITH (NOLOCK)
WHERE (dbo.fn_dstoffset(CREATED) >= '11-15-2015')
AND (dbo.fn_dstoffset(CREATED) <= DATEADD(D, 1, '3-31-2016'))
AND (INS_PRODUCT IN ('PS'))
AND [SR_AREA] IS NOT NULL
AND (SR_AREA IN ('Clinical Question'))
select date_format(dateadd, '%M'), sum(total)
from your_table
group by date_format(dateadd, '%M')
You can use MONTH
select month(dateadd), sum(total)
from your_table
group by month(dateadd)
I have a table event, where i have records with a field end_date, so my problem is i want to fetch number of records, grouping month wise, where end_date should with in that month only, so for example:
If a record have end_date as 2013-01-01 00:00:00 then it should be counted in January 2013, and i am not able to do that. I am unable to put that where condition, how to do tell database that end_date should be between the month for which it is currently grouping.
SELECT COUNT(*) AS 'count', MONTH(created) AS 'month', YEAR(created) AS 'year' FROM event WHERE is_approved =1 GROUP BY YEAR(created), MONTH(created)
Please help me out.
EDIT :
Data say i have is like:
Record name end_date
record_1 2013-11-01 00:00:00
record_2 2013-11-30 00:00:00
record_3 2013-12-01 00:00:00
record_4 2013-12-04 00:00:00
record_5 2013-12-06 00:00:00
record_6 2013-12-10 00:00:00
...many more
Result Expected is:
Count month year
2 11 2013
4 12 2013
....so on
Try this:
SELECT COUNT(1) AS 'count', MONTH(end_date) AS 'month', YEAR(end_date) AS 'year'
FROM event
WHERE is_approved = 1
GROUP BY EXTRACT(YEAR_MONTH FROM end_date);
OR
SELECT COUNT(1) AS 'count', MONTH(end_date) AS 'month', YEAR(end_date) AS 'year'
FROM event
WHERE is_approved = 1
GROUP BY YEAR(end_date), MONTH(end_date);
::EDIT::
1. end date is greater than that particular month - Simply add where condition in your query and pass particular month in format of YYYYMM instead of 201411
2. event is started - Add one more where condition to check whether the created date is less then current date
SELECT COUNT(1) AS 'count', MONTH(end_date) AS 'month', YEAR(end_date) AS 'year'
FROM event
WHERE is_approved = 1 AND
EXTRACT(YEAR_MONTH FROM end_date) > 201411 AND
DATE(created) <= CURRENT_DATE()
GROUP BY EXTRACT(YEAR_MONTH FROM end_date);
OR
SELECT COUNT(1) AS 'count', MONTH(end_date) AS 'month', YEAR(end_date) AS 'year'
FROM event
WHERE is_approved = 1 AND
EXTRACT(YEAR_MONTH FROM end_date) > 201411 AND
DATE(created) <= CURRENT_DATE()
GROUP BY YEAR(end_date), MONTH(end_date);
The count is aggregated based on the month and year so if you are spanning years, you wont have Jan 2013 mixed with Jan 2014, hence pulling those values too and that is the same basis of the group by.
As for your criteria, that all goes in the WHERE clause. In this case, I did anything starting with Jan 1, 2013 and ending Dec 31, 2014 via 'yyyy-mm-dd' standard date recognized format. That said, and the structure of the table you provided, I am using the "end_date" column.
SELECT
YEAR(end_date) AS EventYear,
MONTH(end_Date) AS EventMonth,
COUNT(*) AS EventCount
FROM
event
WHERE is_approved = 1
and end_date between '2013-01-01' and '2014-12-31'
GROUP BY
YEAR(end_date),
MONTH(end_Date)
Now, if you want them to have the most recent events on the top, I would put the year and month descending so 2014 is listed first, then 2013, etc and months within them as December (month 12), before the others.
GROUP BY
YEAR(end_date) DESC,
MONTH(end_Date) DESC
Your criteria could be almost anything from as simple as just a date change, approved status, or even get counts per account status is so needed, such as (and these are just EXAMPLES if you had such code status values)
SUM( is_approved = 0 ) as PendingEvent,
SUM( is_approved = 1 ) as ApprovedEvent,
SUM( is_approved = 2 ) as CancelledEvent
Per comment feedback.
For different date ranges, ignore the between clause and change the WHERE to something like
WHERE end_date > '2014-08-01' or all after a date...
where end_date < '2014-01-01' or all before a date...
They will still group by month / year. If you wanted based on a start date of the event, just change that column in instead, or do IN ADDITION to the others.
MySQL has a bunch of date and time functions that can help you with that. For example:
MONTH() Return the month from the date passed
or
YEAR() Return the year
So you can just get the month and year of your dates. And group your results by them.
SELECT
COUNT(*) cnt
,MONTH(end_date) month
,YEAR(end_date) year
FROM events
GROUP BY month, year
Result :
cnt month year
2 11 2013
4 12 2013
Update:
For filtering only the records that have an end_date greater than a particular month AND have already started, you just need to add a WHERE clause. For example, if the particular month were February 2015:
SELECT
COUNT(*) cnt
,MONTH(end_date) month
,YEAR(end_date) year
FROM events
WHERE end_date >= '2015-03-01'
AND created < NOW()
GROUP BY month, year
Alternatively, the first part of the WHERE clause can be rewritten in the following way, which is probably more comfortable to use if you have to pass the year and month as distinct parameters.
...
WHERE (YEAR(end_date) > 2015
OR (YEAR(end_date) = 2015 AND MONTH(end_date) > 02))
AND created...
SELECT COUNT(*) AS 'count', MONTH(created) AS 'month', YEAR(created) AS 'year' FROM event WHERE is_approved =1 and month(created) = "the month u want" and year(created) = "the year you want" group by GROUP BY YEAR(created), MONTH(created)
you will need to pull the month and year... i could help with that but not sure how you are getting it but months would be 01/02/03 ect and year is 2013/2014/2015 ect
Currently, my codes here produces such results:
SELECT YEAR(date_added) AS YEAR, MONTHNAME(date_added) AS MONTH, COUNT(*) AS TOTAL
FROM news
GROUP BY MONTH
UNION ALL
SELECT YEAR(date_added) AS YEAR, MONTHNAME(date_added) AS MONTH , COUNT(*) AS TOTAL
FROM equipment
GROUP BY MONTH
RESULTS:
YEAR MONTH TOTAL
2013 FEB 1 (news table)
2013 JAN 12 (news table)
2013 FEB 1 (equipment table)
2013 JAN 11 (equipment table)
How do I edit the SQL query such that I will be able to only show:
RESULTS:
YEAR MONTH TOTAL
2013 FEB 2 (both news and equipment table)
2013 JAN 23 (both news and equipment table)
Thanks in advance for any help!
Try :
SELECT YEAR, MONTH, SUM(TOTAL) AS TOTAL
FROM (SELECT YEAR(date_added) AS YEAR, MONTHNAME(date_added) AS MONTH, COUNT(*) AS TOTAL
FROM news
GROUP BY MONTH
UNION ALL
SELECT YEAR(date_added) AS YEAR, MONTHNAME(date_added) AS MONTH , COUNT(*) AS TOTAL
FROM equipment
GROUP BY MONTH) x
GROUP BY YEAR, MONTH
try
Select year, month, sum(total) from
(
SELECT YEAR(date_added) AS YEAR, MONTHNAME(date_added) AS MONTH, COUNT(*) AS TOTAL
FROM news
GROUP BY MONTH
UNION ALL
SELECT YEAR(date_added) AS YEAR, MONTHNAME(date_added) AS MONTH , COUNT(*) AS TOTAL
FROM equipment
GROUP BY MONTH
)
group by year, month
select x.year, x.month, sum(x.total) from x(
SELECT YEAR(date_added) AS YEAR, MONTHNAME(date_added) AS MONTH, COUNT(*) AS TOTAL
FROM news
GROUP BY MONTH
UNION ALL
SELECT YEAR(date_added) AS YEAR, MONTHNAME(date_added) AS MONTH , COUNT(*) AS TOTAL
FROM equipment
GROUP BY MONTH ) x
group by x.month, x.year
Try this:
SELECT YEAR, MONTH, SUM(total) total
FROM (SELECT YEAR(date_added) AS YEAR, MONTHNAME(date_added) AS MONTH, COUNT(*) AS TOTAL
FROM news
GROUP BY MONTH
UNION ALL
SELECT YEAR(date_added) AS YEAR, MONTHNAME(date_added) AS MONTH , COUNT(*) AS TOTAL
FROM equipment
GROUP BY MONTH
) AS A
GROUP BY YEAR, MONTH