How Do I Count Number of Males and Females - mysql

Question

I have the query as follows:
select d.question, b.response, count(b.response)
from sl_flow a
INNER JOIN ul_attempt_responses b on a.question_id = b.question_id and b.type = 1
INNER JOIN us_attempts c on c.id = b.attempt_id
INNER JOIN ss_questions d on d.id = a.question_id
where a.status = 1
and a.ckm_question = 0
and b.response
group by a.question_id, b.response
order by a.question_order asc
The above gives me the questions that I have in the DB which are active and their responses and counts.
However I need a query that will give me number of males and females that answered each of the question. Therefore, I have another query that gives me the number of males and females which is:
SELECT
concat(a.response, 's') as gender,
count(a.response) as count
FROM
ul_attempt_responses a
INNER JOIN us_attempts b ON a.attempt_id = b.id
WHERE
a.question_id = 6 and a.type = 0 AND trim(a.response) != ''
GROUP by a.response;
I am not sure, how to do so. For the gender, the question_id is 6 and type on the a table has to be 0 (the a table is ul_attempt_responses).
This is what I got so far. However, it appears that the results I am getting may not be consistent:
SELECT
gender.question
,coalesce(sum(case final.Response when 'male' then gender.total end),0) as 'Males'
,coalesce(sum(case final.Response when 'female' then gender.total end),0) as 'Females'
FROM
(SELECT
stats . *,
(CASE concat(stats.userid, stats.QuestionID, stats.type)
WHEN #curType THEN #curRow:=coalesce(#curRow, 0) + 1
ELSE #curROw:=1
AND #curType:=concat(stats.userid, stats.QuestionID, stats.type)
END) + 1 AS rank
FROM
(SELECT
d.question as Question,
a.user_id AS UserID,
c.question_id AS QuestionID,
c.type as Type,
c.response AS Response,
a.campaign_id as campaign_id
FROM
us_attempts a
INNER JOIN ul_attempt_responses c ON a.id = c.attempt_id
RIGHT OUTER JOIN ss_profile_questions d ON c.question_id = d.id AND c.type = 0
LEFT OUTER JOIN sl_profile_flow f ON c.question_id = f.profile_question_id
RIGHT OUTER JOIN us_users g ON g.id = a.user_id
WHERE
f.status = 1
ORDER BY a.user_id , c.question_id , c.type , a.id desc) stats) final
INNER JOIN
(select b.user_id, c.question as question, count(1) as total
from ul_attempt_responses a
INNER JOIN us_attempts b on a.attempt_id = b.id
INNER JOIN ss_questions c on a.question_id = c.id and a.type = 1
group by b.user_id, c.id) gender on final.UserID = gender.user_id
where
final.rank = 2 and final.QuestionID = 6 and final.campaign_id = 3
group by gender.question;
Is there a way I can reduce the above query, or is there a better optimized way?

Answer 1

You could use a combination of sum and case/if to get the counts. Given your full table structures are not clear, I am assuming you have a table (or an SQL that can produce a set of rows) with the following fields:
response_id
question_id
response
Then an SQL such as
select question_id
, response
, sum(if(gender='M',1,0)) as males
, sum(if(gender='F',1,0)) as females
from (select q.question_id
, q.response
, g.response as gender from answers as q
left join answers as g on q.response_id=g.response_id and g.question_id=6
where q.question_id!=6) as t
group by question_id, response
would give you a result of the form
question_id,response,males,females
1,A,1,2
1,B,1,0
2,A,0,1
2,B,1,1
2,C,1,0
To explain the code, the sub query produces a set of rows for each response with the question mapped with the gender question's response. In the main select statement the if statement produces a 1 for the specific gender in the proper column and summing them up gives you how many of that specific gender responded to that question.
EDIT
As suggested by #Strawberry, the shorter version would be
select q.question_id
, q.response_id
, sum(g.response='M') as males
, sum(g.response='F') as females
from answers as q
left
join test as g
on q.response_id = g.response_id
and g.question_id = 6
where q.question_id != 6
group
by q.question_id
, q.response