count a specific row on a nested query - mysql

I'm trying to count the number of records on a particular field with the query below.
SELECT COUNT(DISTINCT CASE WHEN seen='n' and reciever_id=1 THEN 'varb' ELSE 'novarb' END) AS count ,c.id, c.vmsg, c.sender_id, p.fname, p.lname, p.profile_pix, p.profile_id
FROM chats c LEFT JOIN profile p ON c.sender_id = p.profile_id
WHERE c.reciever_id = 1 AND c.id in (SELECT MAX(c.id) as id FROM chats c
GROUP BY c.sender_id )
But the answer i get only returns it just one record whiles there other hundreds to be displayed

If you use varb and novarb the dictinct count is max 2 if you have 1 mean that you have one condition only
could be you need that count the number of varb entries
SELECT COUNT(
CASE WHEN seen ='n' and reciever_id=1
THEN 'varb'
ELSE NULL
END) AS count ,c.id, c.vmsg, c.sender_id, p.fname, p.lname, p.profile_pix, p.profile_id
FROM chats c
LEFT JOIN profile p ON c.sender_id = p.profile_id
WHERE c.reciever_id = 1 AND c.id in (
SELECT MAX(c.id) as id FROM chats c
GROUP BY c.sender_id )

I usually use SUM() for this purpose. If I understand correctly, you want the number of rows that meet the condition and don't meet the condition:
SELECT SUM( seen = 'n' and reciever_id = 1 ) as varb,
SUM( not (seen = 'n' and reciever_id = 1) ) as novarb,
c.id, c.vmsg, c.sender_id, p.fname, p.lname, p.profile_pix, p.profile_id
FROM chats c JOIN -- I doubt a left join is necessary
profile p
ON c.sender_id = p.profile_id
WHERE c.reciever_id = 1 AND
c.id in (SELECT MAX(c2.id) FROM chats c2 GROUP BY c2.sender_id)

Related

MYSQL Count where active across tables

I have three tables:
person
-----------
person_id, active
person_team
-----------
person_id, team_id, active
team
-----------
team_id, active
I'd like to get the count on teams from each person where active is true in each table.
So far I have:
SELECT t.id, t.title, t.created_timestamp, COUNT(p_t.tag_id) AS count
FROM team t
LEFT JOIN
person_team p_t ON p_t.team_id = t.id AND p_t.active = 1
WHERE
t.active = 1
GROUP BY t.id
ORDER BY t.title
This gets the count where team and person - team are active, but doesn't take into account whether person is active. Should I use a sub query or another type of join?
You need to add the person table in a join, and count a column from that table:
SELECT t.id, t.title, t.created_timestamp, COUNT(p.id) AS count
FROM team t
LEFT JOIN
person_team p_t ON p_t.team_id = t.id AND p_t.active = 1
LEFT JOIN
person p ON p_t.person_id = p.id AND p.active = 1
WHERE
t.active = 1
GROUP BY t.id
ORDER BY t.title
You should use a inner join on sub select for get the columns not in group by
select k.id, t.title, t.created_timestamp, k.count from
( SELECT t.id COUNT(p_t.tag_id) AS count
FROM team t
LEFT JOIN
person_team p_t ON p_t.team_id = t.id AND p_t.active = 1
WHERE
t.active = 1
GROUP BY t.id ) k
inner join team t on t.id = k.id

mysql subquery select with field from query

i have a little problem with a subquery in sql.
her the query
SELECT st.title, count(q.id) as question_count, max(a.id) as maxid,
sum(case when a.answer is not null then 1 else 0 end) as answer_count, g.user_id as game_user_id,
a.game_id as a_game_id, a.modified as finished, (select modified as finished from answers a where a.id = g.maxid limit 1) as subquery
FROM games g
left join answers a on(a.game_id = g.id)
left join questions q on(a.question_id = q.id)
left join sessions s on(s.id = q.session_id)
left join sessiontypes st on(st.id = s.sessiontype_id)
WHERE g.user_id = 21
group by g.id
having(question_count = answer_count)
order by finished DESC;
i want that the subquery returns the modified value from answers where the id is the highest grouped by game.
so i tried to select max(id) as maxid... and the use max id in the subquery. where a.id = maxid. nice try, but dont work.
mysql error is this one: Reference 'maxid' not supported (reference to group function)
can anybody give a hint how to solve that?
Join on a subquery which returns the MAX(answers.id) grouped by the answers.game_id.
Then use that maxid to join on the answers table to get the row of the corresponding answers.id.
Not sure, how your result is supposed to look, in your select I removed a.modified AS finished, and replaced it with the modified column of the row with maxid.
SELECT
st.title,
count(q.id) AS question_count,
sum(
CASE
WHEN a.answer IS NOT NULL THEN
1
ELSE
0
END
) AS answer_count,
g.user_id AS game_user_id,
a.maxid,
a.game_id AS a_game_id,
modifiedAnswer.modified AS finished,
FROM
games g
LEFT JOIN (SELECT MAX(answers.id) AS maxid, game_id FROM answers GROUP BY answers.game_id) AS a ON (a.game_id = g.id)
LEFT JOIN answers AS modifiedAnswer ON modifiedAnswer.id = a.maxid
LEFT JOIN questions q ON (a.question_id = q.id)
LEFT JOIN sessions s ON (s.id = q.session_id)
LEFT JOIN sessiontypes st ON (st.id = s.sessiontype_id)
WHERE
g.user_id = 21
GROUP BY
g.id
HAVING
(
question_count = answer_count
)
ORDER BY
finished DESC;

How Do I Count Number of Males and Females

I have the query as follows:
select d.question, b.response, count(b.response)
from sl_flow a
INNER JOIN ul_attempt_responses b on a.question_id = b.question_id and b.type = 1
INNER JOIN us_attempts c on c.id = b.attempt_id
INNER JOIN ss_questions d on d.id = a.question_id
where a.status = 1
and a.ckm_question = 0
and b.response
group by a.question_id, b.response
order by a.question_order asc
The above gives me the questions that I have in the DB which are active and their responses and counts.
However I need a query that will give me number of males and females that answered each of the question. Therefore, I have another query that gives me the number of males and females which is:
SELECT
concat(a.response, 's') as gender,
count(a.response) as count
FROM
ul_attempt_responses a
INNER JOIN us_attempts b ON a.attempt_id = b.id
WHERE
a.question_id = 6 and a.type = 0 AND trim(a.response) != ''
GROUP by a.response;
I am not sure, how to do so. For the gender, the question_id is 6 and type on the a table has to be 0 (the a table is ul_attempt_responses).
This is what I got so far. However, it appears that the results I am getting may not be consistent:
SELECT
gender.question
,coalesce(sum(case final.Response when 'male' then gender.total end),0) as 'Males'
,coalesce(sum(case final.Response when 'female' then gender.total end),0) as 'Females'
FROM
(SELECT
stats . *,
(CASE concat(stats.userid, stats.QuestionID, stats.type)
WHEN #curType THEN #curRow:=coalesce(#curRow, 0) + 1
ELSE #curROw:=1
AND #curType:=concat(stats.userid, stats.QuestionID, stats.type)
END) + 1 AS rank
FROM
(SELECT
d.question as Question,
a.user_id AS UserID,
c.question_id AS QuestionID,
c.type as Type,
c.response AS Response,
a.campaign_id as campaign_id
FROM
us_attempts a
INNER JOIN ul_attempt_responses c ON a.id = c.attempt_id
RIGHT OUTER JOIN ss_profile_questions d ON c.question_id = d.id AND c.type = 0
LEFT OUTER JOIN sl_profile_flow f ON c.question_id = f.profile_question_id
RIGHT OUTER JOIN us_users g ON g.id = a.user_id
WHERE
f.status = 1
ORDER BY a.user_id , c.question_id , c.type , a.id desc) stats) final
INNER JOIN
(select b.user_id, c.question as question, count(1) as total
from ul_attempt_responses a
INNER JOIN us_attempts b on a.attempt_id = b.id
INNER JOIN ss_questions c on a.question_id = c.id and a.type = 1
group by b.user_id, c.id) gender on final.UserID = gender.user_id
where
final.rank = 2 and final.QuestionID = 6 and final.campaign_id = 3
group by gender.question;
Is there a way I can reduce the above query, or is there a better optimized way?
You could use a combination of sum and case/if to get the counts. Given your full table structures are not clear, I am assuming you have a table (or an SQL that can produce a set of rows) with the following fields:
response_id
question_id
response
Then an SQL such as
select question_id
, response
, sum(if(gender='M',1,0)) as males
, sum(if(gender='F',1,0)) as females
from (select q.question_id
, q.response
, g.response as gender from answers as q
left join answers as g on q.response_id=g.response_id and g.question_id=6
where q.question_id!=6) as t
group by question_id, response
would give you a result of the form
question_id,response,males,females
1,A,1,2
1,B,1,0
2,A,0,1
2,B,1,1
2,C,1,0
To explain the code, the sub query produces a set of rows for each response with the question mapped with the gender question's response. In the main select statement the if statement produces a 1 for the specific gender in the proper column and summing them up gives you how many of that specific gender responded to that question.
EDIT
As suggested by #Strawberry, the shorter version would be
select q.question_id
, q.response_id
, sum(g.response='M') as males
, sum(g.response='F') as females
from answers as q
left
join test as g
on q.response_id = g.response_id
and g.question_id = 6
where q.question_id != 6
group
by q.question_id
, q.response

sql select distinc where max date

I have 3 tables "maintenances", "cars", "users" . I want to select all data from table maintenance with a distinct car_id and the last record for each distinct (based on max maintenance_date)
SELECT
m. * , u.username, c.Model, c.Make, c.License, c.Milage, COUNT( m.process_id ) AS count_nr
FROM
maintenances AS m
LEFT JOIN users AS u ON u.id = m.user_id
LEFT JOIN cars AS c ON c.id = m.car_id
WHERE
maintenance_date = (SELECT MAX(maintenance_date) FROM maintenances WHERE car_id = m.car_id)
The problem is that this query returns only one record which has the max date from all records. I want all records (distinct car_id and from records with the same car_id to display only values for max(maintenance_date))
This is your query:
SELECT m. * , u.username, c.Model, c.Make, c.License, c.Milage, COUNT( m.process_id ) AS count_nr
----------------------------------------------------------------^
FROM maintenances AS m LEFT JOIN
users AS u
ON u.id = m.user_id LEFT JOIN
cars AS c
ON c.id = m.car_id
WHERE maintenance_date = (SELECT MAX(maintenance_date) FROM maintenances WHERE car_id = m.car_id);
It is an aggregation query. Without a group by, only one row is returned (all the rows are in one group). So, add the group by:
SELECT m. * , u.username, c.Model, c.Make, c.License, c.Milage, COUNT( m.process_id ) AS count_nr
FROM maintenances AS m LEFT JOIN
users AS u
ON u.id = m.user_id LEFT JOIN
cars AS c
ON c.id = m.car_id
WHERE maintenance_date = (SELECT MAX(m2.maintenance_date) FROM maintenances m2 WHERE m2.car_id = m.car_id);
GROUP BY c.id
I also fixed the correlation statement, to be clear that it is correlated to the outer query.
add GROUP BY u.username .
WHERE
maintenance_date = (SELECT MAX(maintenance_date) FROM maintenances WHERE car_id = m.car_id)
GROUP BY u.username

MySQL how do I not include duplicate rows when I use SUM and COUNT with multiple INNER JOINS?

SELECT SUM(case when p.status = 2 then p.value end) as 'val_accepted'
FROM
props AS p
INNER JOIN (p_contents AS pc
INNER JOIN contents AS c ON c.id = pc.library_id)
ON p.id = pc.prop_id
WHERE p.account_id = 3
GROUP BY (pc.library_id)
so, what's happening:
there are two p_contents that are associated with a prop. those two p_contents have the same library_id which points to a corresponding content.
So, the SUM of p.value is double what it should be because there are two p_contents that point to the same content
How do I not double SUM the p.value?
EDIT:
I figured out how to use DISTINCT, but I still need access to the inner columns...
SELECT c.name as 'library_name',
SUM(case when p.status = 2 then p.value end) as 'val_accepted',
FROM
props AS p
INNER JOIN
(
SELECT DISTINCT(pc.library_id), prop_id
FROM prop_contents AS pc
INNER JOIN
(
SELECT name, visibility, id, updated_at
FROM contents AS c
) as c
ON c.id = pc.library_id
)as pc
ON p.id = pc.prop_id
WHERE p.account_id = 3
GROUP BY (pc.library_id)
and now I get the error:
Unknown column 'c.name' in 'field list')
Here's one solution. First reduce the set to distinct rows in an derived table, then apply the GROUP BY to that result:
SELECT SUM(case when d.status = 2 then d.value end) as 'val_accepted'
FROM (
SELECT DISTINCT p.id, p.status, p.value, pc.library_id
FROM props p
INNER JOIN p_contents AS pc ON p.id = pc.prop_id
INNER JOIN contents AS c ON c.id = pc.library_id
WHERE p.account_id = 3) AS d
GROUP BY d.library_id
You use DISTINCT(pc.library_id) in your example, as if DISTINCT applies only to the column inside the parentheses. This is a common misconception. DISTINCT applies to all columns of the select-list. DISTINCT is not a function; it's a query modifier.