I have:
$buyingNet = DB::table('parts_enquiries_buying AS PEB')
->select(DB::raw('SUM((PEB.quantity*PEB.net)/IF(ISNULL(currencyRate), rate, currencyRate)) AS total'))
->join('currencies_rates AS CR', function ($q) {
$q->on('CR.id', '=', 'PEB.currencyId')
//->where(DB::raw('YEAR(CR.date)'), '=', date('Y'))
->where(DB::raw('MONTH(CR.date)'), '=', date('m'));
})
->leftJoin('jobs', 'jobs.enquiryId', '=', 'PEB.enquiryId')
->leftJoin('invoices_out AS IO', 'IO.jobId', '=', 'jobs.id')
->where('PEB.enquiryId', $enquiryId)
->first()->total;
If I uncomment the where that matches the year I get null returned, but all the rows that should be there are there.
Is my syntax correct? It should translate as:
... YEAR(CR.date) = ? AND MONTH(CR.date) =? ...
I believe the issue here is that Query builder doesn't understand your DB::raw statement within the ->where clause.
You should do as folllows:
->whereRaw("YEAR(CR.date) = '". date('Y')."'")
->whereRaw("MONTH(CR.date) = '". date('n')."'")
for the month clause you need to use n instead of m since MySQL MONTH returns a single digit for months below 10.
Related
I want to get count from 'user' table with 'plan_validity' is null or more than today's date. both condition need to check for same column with user_id and status = 1.
$currentUser = User::where('user_id', $card_details->user_id)
->where('status', 1)
->where(function (Builder $query) {
return $query
->whereDate('plan_validity', '>=', Carbon::now())
->orWhere('plan_validity', null);
})->count();
giving error
[2021-11-23 10:40:31] production.ERROR: Argument 1 passed to App\Http\Controllers\ProfileController::App\Http\Controllers\{closure}() must be an instance of App\Http\Controllers\Builder, instance of Illuminate\Database\Eloquent\Builder given, called in /home/hellovcard/public_html/vendor/laravel/framework/src/Illuminate/Database/Eloquent/Builder.php on line 237 {"userId":17,"exception":"[object] (TypeError(code: 0): Argument 1 passed to App\\Http\\Controllers\\ProfileController::App\\Http\\Controllers\\{closure}() must be an instance of App\\Http\\Controllers\\Builder, instance of Illuminate\\Database\\Eloquent\\Builder given, called in /home/hellovcard/public_html/vendor/laravel/framework/src/Illuminate/Database/Eloquent/Builder.php on line 237 at /home/hellovcard/public_html/app/Http/Controllers/ProfileController.php:34)
how to modify above mentioned query?
this is output I need to get
enter image description here
You are not combining your "where" clauses properly. With the "orWhere" at the end, it essentially ignores all the conditions (ie. which user it relates to) of the preceding where clauses, so adds to the results any row where plan_validity is null. So after you query by user ID and status, you then need to combine the remainder of the query into a logical group like so :
$user = Users::where('user_id', $card_details->user_id)
->where('status', 1)
->where(function (Builder $query) {
return $query
->whereDate('plan_validity', '>=', Carbon::now())
->orWhere('plan_validity', null);
})
->get();
I want to transform my MySql query into a Query in Laravel but I really don't know how to do this. I don't know how to rename in FROM like in SQL
My query is the following one :
SELECT f2.* FROM formation f2 WHERE f2.theme_id IN
(SELECT f.theme_id FROM user_formation uf JOIN formation f ON uf.formation_id = f.id WHERE uf.user_id = 2)
AND f2.id NOT IN
(SELECT formation_id FROM user_formation WHERE user_id = 2);
I tried something like this but ...
$q = Formation::query()
->from('formation AS f2')
->whereIn('f2.theme_id', function($r)
{
$r->select('f.theme_id')->from('user_formation AS uf')
->join('formation', function($join)
{
$join->on('uf.formation_id', '=', 'f.id')
->where ('uf.user_id', '=', $id)
});
});
->whereNotIn('f2.id', function($s){
$s->select('formation.id')
->from('user_formation')
->where('user_id', '=', $id)
})->get();
thanks for help.
If you want to run this raw query you can run:
$res = DB::select('
SELECT f2.*
FROM formation f2
WHERE f2.theme_id IN
(SELECT f.theme_id FROM user_formation uf JOIN formation f ON uf.formation_id = f.id WHERE uf.user_id = 2)
AND f2.id NOT IN
(SELECT formation_id FROM user_formation WHERE user_id = 2)');
Or you can rewrite this query in laravel query builder Eloquent ORM:
Formations::query()
->whereIn('formations.theme_id', function($q){
$user_formations_table = (new UserFormation)->getTable();
$formation_table = (new Formation)->getTable();
$q->select('paper_type_id')
->from($user_formations_table)
->join($formation_table, "$user_formations_table.formation_id", '=', "$formation_table.id")
->where("$user_formations_table.user_id", 2);
})->whereNotIn('formations.id', function($q){
$user_formations_table = (new UserFormation)->getTable();
$q->select('formation_id')
->where("$user_formations_table.user_id", 2);
})
->get();
Note that I have used models Formations, UserFormation, Formation Because you have used 3 different tables, you should add this models and specify tables to run ORM query
I advice to run first RAW query if there is no another need to run it with Eloquent
Hope this helps you
First of all, you need to fix your code indentations so you don't confuse yourself. Second, you placed semicolon in the wrong places. Third, you need to pass $id inside function because of the variable scope.
$q = Formation::query()
->whereIn('f2.theme_id', function($r) use ($id) {
$r->select('f.theme_id')->from('user_formation AS uf')
->join('formation', function($join) use ($id) {
$join->on('uf.formation_id', '=', 'f.id')
->where('uf.user_id', '=', $id);
}
);
})
->whereNotIn('f2.id', function($s) use ($id) {
$s->select('formation.id')
->from('user_formation')
->where('user_id', '=', $id);
})->get();
Note : If you are using VSCode, I suggest to use PHP Intelephense as it will help with autocomplete, syntax check, etc.
I have the following raw SQL query:
select a.id user_id, a.email_address, a.name_first, a.name_last, count(b.id) number_of_videos, sum(b.vimeo_duration) total_duration, sum(b.count_watched) total_playbacks
from users a,
videos b
where a.id = b.tutor_id
and a.email_address in ('candace_rennie#yahoo.com', 'tjm#hiltoncollege.com', 'matthewjameshenshall#gmail.com', 'nkululeko#syafunda.co.za', 'khulile#syafunda.co.za', 'nzakheni#syafunda.co.za')
group by a.id;
This correctly gets 6 rows from the database. I'm trying to convert this to a Laravel database query like so:
$totals = DB::table('users')
->select(DB::Raw('users.id as user_id'), 'users.email_address', 'users.name_first', 'users.name_last', DB::Raw('count(videos.id) as number_of_videos'), DB::Raw('sum(videos.vimeo_duration) as total_duration'), DB::Raw('sum(videos.count_watched) as total_playbacks'))
->join('videos', 'users.id', '=', 'videos.tutor_id')
->where('users.id', 'videos.tutor_id')
->whereIn('users.email_address', array('candace_rennie#yahoo.com', 'tjm#hiltoncollege.com', 'matthewjameshenshall#gmail.com', 'nkululeko#syafunda.co.za', 'khulile#syafunda.co.za', 'nzakheni#syafunda.co.za'))
->groupBy('users.id')
->get();
This however return 0 rows. Is there anything I'm missing?
It should be smth like below even tho groupBy user id does not help much as id is unique.
$aggregates = [
DB::raw('count(b.id) as number_of_videos'),
DB::raw('sum(b.vimeo_duration) as total_duration'),
DB::raw('sum(b.count_watched) as total_playbacks'),
];
$simpleSelects = ['users.email_address', users.id, 'users.name_first', 'users.name_last'];
$emails = ['candace_rennie#yahoo.com', 'tjm#hiltoncollege.com'....]
$users = Users::select(array_merge($simpleSelects, $aggregates))
->leftJoin('videos as b', function ($join) use ($emails) {
$join->on('b.tutor_id', 'a.id')
->whereIn('users.email_address', $emails);
})
->groupBy('users.id')
->get();
Try to remove this line:
->where('users.id', 'videos.tutor_id')
List item
after sql code convert into laravel
DB::select('posts.id','posts.title','posts.body')
->from('posts')
->where('posts.author_id', '=', 1)
->orderBy('posts.published_at', 'DESC')
->limit(10)
->get();
Good day all, I am trying to count all records in a table but only if the table does not contain data in a specific column (deleted_at). It is a join table the table names are companies and employees. I am currently counting the records with a DB::raw but it should only count it if the deleted_at column is null. Please understand that i am a beginner.
public function index()
{
$user = Auth::user()->id;
$companies = DB::table('companies AS c')
->select([
'c.id',
'c.logo',
'c.company_name',
'c.created_at',
'c.sector',
'c.deleted_at',
DB::raw('COUNT(e.id) AS employee_count')
])
->leftJoin('employees AS e', 'e.company_id', '=', 'c.id' )
->leftJoin('company_user AS cu', 'cu.company_id', '=', 'c.id')
->where('cu.user_id', '=', $user)
->where('c.deleted_at', '=', null)
->groupBy('c.id')
->get();
return view('account.companies.index')
->with('companies', $companies);
}
If you are using Mysql then you could use conditional aggregation
$companies = DB::table('companies AS c')
->select([
'c.id',
'c.logo',
'c.company_name',
'c.created_at',
'c.sector',
'c.deleted_at',
DB::raw('SUM(c.deleted_at IS NULL) AS employee_count')
])
->leftJoin('employees AS e', 'e.company_id', '=', 'c.id' )
->leftJoin('company_user AS cu', 'cu.company_id', '=', 'c.id')
->where('cu.user_id', '=', $user)
->groupBy('c.id')
->get();
In mysql when an expression is used inside sum(a= b) it will result as a boolean 0/1 so you can get your conditional count using above
Or you could use whereNull() method in your query
->whereNull('c.deleted_at')
Use this code:
$employeeCount = DB::table('employees')
->select('companies.name', DB::raw('count(employees.id) as employee_count'))
->join('companies', 'employees.company','=','companies.id')
->groupBy('companies.id')
->get();
What i'm trying to achieve is the following:
I want to check if there is a record with the same client_code but with a lower/different campaign id. I'm using a sub-query for now and i tried to do it with a join as well but I couldn't get the logic working
This is what i got now:
$oDB = DB::table('campaigns AS c')
->select(
'c.id AS campaign_id',
'cc.id AS campaign_customer_id'
)
->join('campaign_customers AS cc', 'cc.campaign_id', '=', 'c.id')
->where('c.status', '=', ModelCampaign::STATUS_PLANNED)
->where('c.scheduled', '=', 1)
->whereRaw('c.scheduled_at <= NOW()')
->where('cc.status', '=', ModelCampaignCustomer::STATUS_INVITE_EMAIL_SCHEDULED)
->whereNotIn('cc.client_code', '=', function ($query){
$query ->select(DB::raw(1))
->from('campaign_customers')
->whereRaw('campaign_id', '!=', 'c.id');
})
->where('cc.active', '=', 1)
;
any tips on how to work the logic would be great
You can use the ->toSql(); method to see the SQL so you can refactorize your query.
The whereNotIn probably shouldn't have an = in it
->whereNotIn('cc.client_code', function ($query){
....
edit
Try:
->whereNotIn('cc.client_code', function ($query){
$query->select(DB::raw('client_code'))
->from('campaign_customers')
->whereRaw('campaign_id != c.id');
})
I think the whereRaw should be a single text string or maybe you can use where here (looking at this for reference https://laravel.com/docs/5.2/queries#advanced-where-clauses). Also DB::raw(1) is going to return a 1 for each subquery result but you want an id for the whereNotIn.