I have a table in sqlite that contains roughly about 3 billion values (a lot of them will be repeats). It's basically a giant vector of values. I'm trying to calculate the frequency in which values appear in the table by performing this:-
SELECT abs(diffs), count(*) as total FROM mzdiff GROUP by abs(diffs);
abs(diffs) is the name of my column and mzdiff is my table name, but when I try performing the code above it comes up with an error message saying that the column diffs doesn't exist. I know that the naming of my column isn't really ideal for sql, but is there any way I can get around this?
Thanks
The answer to this is not an alias since the column name must be identified before it can be aliased so use the backtick to quote the name and make it a habit to always quote identifiers.
SELECT `abs(diffs)`, count(*) as total FROM `mzdiff` GROUP by `abs(diffs)`;
Related
I have a small problem, I have a table like this:
id|name|group|date_created
1|Volvo|1,3|06-04-2020 10:00:00
2|Audi|3|06-04-2020 10:00:00
etc....
Now I wish I could get all the records that have the value 1 inside the group column.
I tried LIKE "%1%", but I don't think it's a good query. Can you address me?
SELECT id FROM cars WHERE group LIKE '%1%'
The problem with your query is that it would wrongly match '1' against a list like '45,12,5' for example.
One method is to add commas on both ends before searching:
where concat(',', `group`, ',') like '%,1,%';
But in MySQL, it is much more convenient to use string function find_in_set(), whose purpose is just what you are looking for, ie search for a value in a comma-separated list:
select id from cars where find_in_set('1', `group`) > 0
Notes:
you should fix your data model, and have a separated table to store relationship between ids and groups, with each tuple on a separate row. Related reading: Is storing a delimited list in a database column really that bad?
group is a reserved word in MySQL, so not a good choice for a column name (you would need to surround it with backticks everytime you use it, which is error-prone)
I have a MySQL column which contains a string of scores separated by a semi-colon eg: "5;21;24;25;26;28;117".
This column was created not by design, but by collecting the values from multiple rows in a table using GROUP_CONCAT and GROUP BY. The original data arrived as a spreadsheet with multiple rows with the ID value.
I can use a select clause with REPLACE function to replace the ; with a +.
SELECT values, REPLACE(values,";","+") AS score FROM [table_name] WHERE 1
values score
5;21;24;25;26;28;117 5+21+24+25+26+28+117
However what I need is the sum of: 5+21+24+25+26+28+117 to get a total of 246.
Is there any way to do this in MySQL without using some other scripting language?
The SELECT clause shows me a string of numbers joined with the + symbol.
Am looking for a way to evaluate that string to give me the result: 246
UPDATE:
As I was framing my question, I did more research and came up with this link which solves my problem:
(https://dba.stackexchange.com/questions/120747/evaluate-a-string-value-as-a-computed-expression-in-an-sql-statement-sthg-like).
Am keeping this question and the link to the answer here in case it could help other people searching for the same.
in the below image I'm using
SELECT DISTINCT(name),date,reporting,leaving from attendance where date='2016-09-01
and I'm still getting repeating names. Why?
When using DISCTINCT, MySQL uses all columns as grouping factor. If you want group by only one column and get all corresponding column values, use GROUP BY instead
SELECT name, date, reporting, leaving FROM attendance GROUP BY name WHERE ...
Actually your all rows have distinct data apart from Name column if you want only distinct names then you can get it with help of Aggregate functions, you can use MIN or MAX as per your business requirement
SELECT Name,MAX(date),MAX(reporting),MAX(leaving)
FROM attendance
WHERE date='2016-09-01'
GROUP BY Name
How do I just simply sum a column in my MySQL database? I thought:
SELECT sum(Disbursement Amount) FROM payments
but this doesn't work. Says I have a syntax error near 'Amount)
I just need to know how to SUM ONE column of data and I can take it from there
I've searched for a couple days and have found nothing of use to me. I'm also brand spanking new to MySQL so I'm sure that's why ;)
If you have a space in your column name (Disbursement Amount), then you need to use backticks to enclose the column name:
SELECT sum(`Disbursement Amount`) as Total
FROM payments;
My suggestion would be to not use spaces in your tables and column names. If you want to have a separator between the two words, you can use an underscore:
SELECT sum(Disbursement_Amount) as Total
FROM payments;
I want to be able to query for multiple statements when I have a table that connects the id's from two other tables.
My three tables
destination:
id_destination, name_destination
keyword:
id_keyword, name_keyword
destination_keyword:
id_keyword, id_destination
Where the last one connects ids from the destination- and the keyword table, in order to associate destination with keywords.
A query to get the destination based on keyword would then look like
SELECT destination.name_destination FROM destination
NATURAL JOIN destination_keyword
NATURAL JOIN keyword
WHERE keyword.name_keyword like _keyword_
Is it possible to query for multiple keywords, let's say I wanted to get the destinations that matches all or some of the keywords in the list sunny, ocean, fishing and order by number of matches. How would I move forward? Should I restructure my tables? I am sort of new to SQL and would very much like some input.
Order your table joins starting with keyword and use a count on the number of time the destination is joined:
select
d.id_destination,
d.name_destination,
count(d.id_destination) as matches
from keyword k
join destination_keyword dk on dk.keyword = k.keyword
join destination d on d.id_destination = dk.id_destination
where name_keyword in ('sunny', 'ocean', 'fishing')
group by 1, 2
order by 3 desc
This query assumes that name_keyword values are single words like "sunny".
Using natural joins is not a good idea, because if the table structures change such that two naturally joined tables get altered to have columns the same name added, suddenly your query will stop working. Also by explicitly declaring the join condition, readers of your code will immediately understand how the tables are jones, and can modify it to add non-key conditions as required.
Requiring that only key columns share the same name is also restrictive, because it requires unnatural column names like "name_keyword" instead of simply "name" - the suffix "_keyword" is redundant and adds no value and exists only because your have to have it because you are using natural joins.
Natural joins save hardly any typing (and often cause more typing over all) and impose limitations on join types and names and are brittle.
They are to be avoided.
You can try something like the following:
SELECT dest.name_destination, count(*) FROM destination dest, destination_keyword dest_key, keyword key
WHERE key.id_keyword = dest_key.id_keyword
AND dest_key.id_destination = dest.id_destination
AND key.name_keyword IN ('sunny', 'ocean', 'fishing')
GROUP BY dest.name_destination
ORDER BY count(*), dest.name_destination
Haven't tested it, but if it is not correct it should show you the way to accomplish it.
You can do multiple LIKE statements:
Column LIKE 'value1' OR Column LIKE 'value2' OR ...
Or you could do a regular expression match:
Column LIKE 'something|somtthing|whatever'
The trick to ordering by number of matches has to do with understanding the GROUP BY clause and the ORDER BY clause. You either want one count for everything, or you want one count per something. So for the first case you just use the COUNT function by itself. In the second case you use the GROUP BY clause to "group" somethings/categories that you want counted. ORDER BY should be pretty straight forward.
I think based on the information you have provided your table structure is fine.
Hope this helps.
DISCLAIMER: My syntax isn't accurate.