Submitting a form using a custom button using HTML Web Components - html

I have defined a custom DOM element, but when placed inside a form, it does not submit it. How can I get the form to submit when I click the button?
<form action="/foo" method="GET">
<my-button type="submit">click me</my-button>
</form>
This is the prototype configuration for the custom element:
myButton = Object.create(HTMLButtonElement.prototype);
The template for the button looks like this:
<template>
<button type="submit" id="button"><content></content></button>
</template>

Came across this question today, but found a more modern alternative subsequently: web components can now be native form elements. There's a great read on the topic here.
The long and the short of it is you can now associate custom components with a form, meaning they're included in the form's elements property - a HTMLFormControlsCollection of all the elements controlled by the form.
To do this, you need to add the following to your component:
class MyComponent extends HTMLElement {
static get formAssociated() { return true; }
constructor() {
super();
this.internals = this.attachInternals();
}
}
this.internals will then contain everything you need to interact with the form in question, e.g. this.internals.form, this.internals.setFormValue(), this.internals.checkValidity().
For the submit button, you could, for example, use:
connectedCallback() {
const { internals: { form } } = this;
this.buttonEl.addEventListener('click', () => form.submit());
}

You are doing it wrong. Though event bubbling from shadow DOM to owner document is somehow possible, it’s tricky and in general is a wrong approach. Instead of hiding button into shadow, one should use is= attribute of button:
<form action="/foo" method="GET">
<!--my-button type="submit">click me</my-button-->
<!-- ⇓⇓⇓⇓⇓⇓⇓⇓⇓⇓⇓⇓⇓⇓ -->
<button type="submit" is="my-button">click me</button>
</form>
More info.

When your custom element extends a native element like HTMLButtonElement, you can no longer use a custom tag name like <my-button> (unfortunately). You have to use the native tag with the is= attribute:
<button type="submit" is="my-button">
If you do not extend a native element (called "type extension" in the spec), then you can use your custom tag name. Type extension example in the spec

Related

How to use submit button present outside the component and also needs validation

I have one form template driven i am handling it using id like #firstname and then using ngModel.so basically i want once the code gets validated it should let the button know to get enabled or diabled which is present outside the component.
Note: i am not using form tag here
Using form
If your component has a template variable
<form #form="ngForm">
...
</form>`
You can get it (and expose as public property of your component)
using ViewChild
#ViewChild('form') form:NgForm
Now in your parent, can access to the form if you access to the
child
<app-child #child ></app-child>
<button (click)="submit(child.form.form)">submit</button>
submit(form:FormGroup)
{
if (form.valid)
this.result=form.value;
else
this.result="Invalid form"
}
Using simple control
<input name="name" [(ngModel)]="name" #nameID="ngModel" required>
The ViewChild
#ViewChild('nameID') control:FormControl
Your parent like
<child-control #childControl></child-control>
<button (click)="submitControl(childControl.control)">submit</button>
submitControl(control:FormControl)
{
if (control.valid)
this.result=control.value;
else
this.result="Invalid control"
}
A stackblitz

What is the HTML <dialog> tag used for and when to use it?

The way I've understood it, the tag is used to open and close content like a popup alert. What I fail to understand is what advantages the tag has compared to just using a "div" and styling it with css and adding functionality to it with js. It also seems counter intuitive to manipulate the "open" property in order to show/hide the content instead of using display:none/block; with css.
I also don't understand exactly which scenarios would be considered a dialog box. Is a form login box a dialogbox? What about a popup telling you to disable adblock? Are all popups that can be hidden considered dialog boxes?
The traditional, hacky way to create a dialog, via designing a div via CSS only seems to be intuitive for you because you are used to it. However, you need to implement every functionality related to it, such as:
opening it
closing it
Also, in the future, this will be enhanced by standard functionalities, so, while it's not urgent for already existent code, but when you write code, especially when you start a project, it makes sense to start using it. Let's see an example from [Mozilla's page][1]:
var updateButton = document.getElementById('updateDetails');
var favDialog = document.getElementById('favDialog');
var outputBox = document.querySelector('output');
var selectEl = document.querySelector('select');
var confirmBtn = document.getElementById('confirmBtn');
// "Update details" button opens the <dialog> modally
updateButton.addEventListener('click', function onOpen() {
if (typeof favDialog.showModal === "function") {
favDialog.showModal();
} else {
alert("The <dialog> API is not supported by this browser");
}
});
// "Favorite animal" input sets the value of the submit button
selectEl.addEventListener('change', function onSelect(e) {
confirmBtn.value = selectEl.value;
});
// "Confirm" button of form triggers "close" on dialog because of [method="dialog"]
favDialog.addEventListener('close', function onClose() {
outputBox.value = favDialog.returnValue + " button clicked - " + (new Date()).toString();
});
<!-- Simple pop-up dialog box containing a form -->
<dialog id="favDialog">
<form method="dialog">
<p><label>Favorite animal:
<select>
<option></option>
<option>Brine shrimp</option>
<option>Red panda</option>
<option>Spider monkey</option>
</select>
</label></p>
<menu>
<button value="cancel">Cancel</button>
<button id="confirmBtn" value="default">Confirm</button>
</menu>
</form>
</dialog>
<menu>
<button id="updateDetails">Update details</button>
</menu>
<output aria-live="polite"></output>
However, at the time of this writing (February the 3rd, 2022), this is not supported in all browsers, so it is perfectly feasible to avoid using it for now, until it will become supported everywhere.
[1]: https://developer.mozilla.org/en-US/docs/Web/HTML/Element/dialog

.val() returns empry strings when i try to fetch value of input in modal [duplicate]

I have a form in Angular that has two buttons tags in it. One button submits the form on ng-click. The other button is purely for navigation using ng-click. However, when this second button is clicked, AngularJS is causing a page refresh which triggers a 404. I’ve dropped a breakpoint in the function and it is triggering my function. If I do any of the following, it stops:
If I remove the ng-click, the button doesn’t cause a page refresh.
If I comment out the code in the function, it doesn’t cause a page refresh.
If I change the button tag to an anchor tag (<a>) with href="", then it doesn’t cause a refresh.
The latter seems like the simplest workaround, but why is AngularJS even running any code after my function that causes the page to reload? Seems like a bug.
Here is the form:
<form class="form-horizontal" name="myProfile" ng-switch-when="profile">
<fieldset>
<div class="control-group">
<label class="control-label" for="passwordButton">Password</label>
<div class="controls">
<button id="passwordButton" class="secondaryButton" ng-click="showChangePassword()">Change</button>
</div>
</div>
<div class="buttonBar">
<button id="saveProfileButton" class="primaryButton" ng-click="saveUser()">Save</button>
</div>
</fieldset>
</form>
Here is the controller method:
$scope.showChangePassword = function() {
$scope.selectedLink = "changePassword";
};
If you have a look at the W3C specification, it would seem like the obvious thing to try is to mark your button elements with type='button' when you don't want them to submit.
The thing to note in particular is where it says
A button element with no type attribute specified represents the same thing as a button element with its type attribute set to "submit"
You can try to prevent default handler:
html:
<button ng-click="saveUser($event)">
js:
$scope.saveUser = function (event) {
event.preventDefault();
// your code
}
You should declare the attribute ng-submit={expression} in your <form> tag.
From the ngSubmit docs
http://docs.angularjs.org/api/ng.directive:ngSubmit
Enables binding angular expressions to onsubmit events.
Additionally it prevents the default action (which for form means sending the request to the server and reloading the current page).
I use directive to prevent default behaviour:
module.directive('preventDefault', function() {
return function(scope, element, attrs) {
angular.element(element).bind('click', function(event) {
event.preventDefault();
event.stopPropagation();
});
}
});
And then, in html:
<button class="secondaryButton" prevent-default>Secondary action</button>
This directive can also be used with <a> and all other tags
You can keep <button type="submit">, but must remove the attribute action="" of <form>.
I wonder why nobody proposed the possibly simplest solution:
don't use a <form>
A <whatever ng-form> does IMHO a better job and without an HTML form, there's nothing to be submitted by the browser itself. Which is exactly the right behavior when using angular.
Add action to your form.
<form action="#">
This answer may not be directly related to the question. It's just for the case when you submit the form using scripts.
According to ng-submit code
var handleFormSubmission = function(event) {
scope.$apply(function() {
controller.$commitViewValue();
controller.$setSubmitted();
});
event.preventDefault();
};
formElement[0].addEventListener('submit', handleFormSubmission);
It adds submit event listener on the form.
But submit event handler wouldn't be called when submit is initiated by calling form.submit(). In this case, ng-submit will not prevent the default action, you have to call preventDefault yourself in ng-submit handler;
To provide a reasonably definitive answer, the HTML Form Submission Algorithm item 5 states that a form only dispatches a submit event if it was not submitted by calling the submit method (which means it only dispatches a submit event if submitted by a button or other implicit method, e.g. pressing enter while focus is on an input type text element).
See Form submitted using submit() from a link cannot be caught by onsubmit handler
I also had the same problem, but gladelly I fixed this by changing the type like from type="submit" to type="button" and it worked.
First Button submits the form and second does not
<body>
<form ng-app="myApp" ng-controller="myCtrl" ng-submit="Sub()">
<div>
S:<input type="text" ng-model="v"><br>
<br>
<button>Submit</button>
//Dont Submit
<button type='button' ng-click="Dont()">Dont Submit</button>
</div>
</form>
<script>
var app = angular.module('myApp', []);
app.controller('myCtrl', function($scope) {
$scope.Sub=function()
{
alert('Inside Submit');
}
$scope.Dont=function()
{
$scope.v=0;
}
});
</script>
</body>
Just add the FormsModule in the imports array of app.module.ts file,
and add import { FormsModule } from '#angular/forms'; at the top of this file...this will work.

appear an html element by clicking on a button with angularjs

I have an html form ( ) , I want that it is displayed when I click on a button.
the declaration of the form is the following :
<div id = "formulaire" class="gl" >
and the button is :
Edit
I use angularjs in my code . Please help me.
It better to use a simple variable than a function in this case. I would also recommend using controller scope when setting variables instead of the application scope so you don't run into issues with the variables when your application becomes large.
I also picked data-ng-click over ng-click because it will allow the html to validate correctly (which can be checked using the W3's validator).
Try this...
"use strict";
angular.module('myApp', [])
.controller("myController", function() {
this.edit = false;
});
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.4.5/angular.min.js"></script>
<div data-ng-app="myApp" data-ng-controller="myController as ctrl">
Edit
<div id="formulaire" class="gl" data-ng-show="ctrl.edit">
<form>
<fieldset>
<label>Field:</label>
<input type="text" />
</fieldset>
</form>
</div>
</div>
Have you looked into the ngShow directive? It ables you to show or hide a DOM element depending on whether the attribute expression resolves to a truthey or falsey value.
Add model change on click
Edit
And then display the form if model is true
<div id = "formulaire" class="gl" ng-if="show">

Using 2 buttons in same ASP.NET MVC Form

In general, is it possible to have two different buttons within the same form that post to different controller actions in ASP.NET MVC?
I am essentially trying to have two input (type="button") tags in the same form, but I want them to perform different controller actions. I would like to do this in a few cases because I think it provides a good aesthetic to be able to click buttons as opposed to hyperlinks. Is there a way to do this or should I design it differently?
Not really possible without using Javascript. With Javascript you'd just have to define different click handlers that invoked the proper action.
$(function() {
$('#button1').click( function() {
$(form).attr( 'action', '<% Url.Action( "action1" ) %>' )
.submit();
return false; // prevent default submission
});
$('#button2').click( function() {
$(form).attr( 'action', '<% Url.Action( "action2" ) %>' )
.submit();
return false; // prevent default submission
});
});
Some thoughts about handling this in the browser:
You can use links which are styled to look like buttons. This is easy to do, either with images or by putting the link in a block element with borders.
You can use two buttons which don't directly submit; they instead call a javascript function that sets the form action before submitting.
If all you want is something like OK & Cancel buttons, then have a look at this post by David Findley.
I'm using this method on my Edit view, where I have an Edit button and a Delete button. The delete button only requires the Id of the item. In the code below you can see that I've named my attribute "AcceptFormValueAttribute". This is method good for me, because my Delete [Get] action just shows a message asking for confirmation, so needs the redirect.
[ActionName("Edit")]
[AcceptFormValue(Name = "Action", Value = "Delete")]
[AcceptVerbs(HttpVerbs.Post)]
[ValidateAntiForgeryToken]
public ActionResult EditDelete(int? id)
{
return RedirectToAction("Delete", new { id = id });
}
This has nothing to do with ASP.NET MVC but with html. The only way I see how you could do this is by modifying the action attribute of the form tag using javascript on submission of the form by checking which button was pressed.
Well there are a few ways you could handle this. Assuming you aren't sending data with the button click I'd go with option 3. If data must be included then consider option 1 with some sort of temporary data store (like TempData).
One form posts to one controller
action on submit and the controller
action checks which button was
clicked and then dispatches a
RedirectToAction(). (Not great)
Multiple forms on one page post to multiple controller actions (Better)
Inside or outside a form create an input type="button" and give it an onclick handler
that redirects the user to a controller action (Best)
Haven't tried this, but given the ID of the clicked button does get sent VIA http POST, you could probably do something like:
<input type="submit" name="GO" ID="GO" value="GO BUTTON" />
<input type="submit" name="STOP" ID="STOP" value="STOP BUTTON" />
Then on the mvc end, just have two methods, one with a go parameter, one with a stop parameter.
Method #1
How about using two different forms wrapping the buttons, then using CSS to position one of them so that it appears (visually) to be inside the "main" form?
A really quick example:
<fieldset id="CombinedForm">
<form ... action="Method1">
...form stuff here...
<input id="Button1" type="submit" value="Do something">
</form>
<form ... action="Method2">
...form stuff here...
<input id="Button2" type="submit" value="Do something else">
</form>
</fieldset>
...Then using CSS as follows:
#CombinedForm {
position: relative;
padding-bottom: 2em; /* leave space for buttons */
}
#Button1, #Button2 {
position: absolute;
bottom: 0;
}
#Button1 {
left: 0;
}
#Button2 {
right: 0;
}
The result should be that you have a fieldset or div which looks like a form, having two actual HTML forms inside it, and two buttons which are positioned within the parent box, yet submitting to different locations.
Method #2
Another method occurs: have both buttons in the same form, pointing to one controller action, that then decides (based on the value of the button clicked) which action to redirect to.
Its not Javascript required...
how about this
public ActionResult DoSomething()
{
// Some business logic
TempData["PostedFormValues"] = Request.Form;
if (Request.Form("ButtonA") != null)
{
return RedirectToAction("ActionA", RouteData.Values);
}
return RedirectToAction("ActionB", RouteData.Values);
}
I think that I can suggest more simple one.
For example you have two buttons : ButtonA,ButtonB and want to perform different
action on each one.
Simplest solution is : just use BeginForm statement:
#using ( Html.BeginForm("ButtonA" , "Home") )
{
<input type="submit" value="ButtonA"/>
}
#using ( Html.BeginForm("ButtonB" , "Home") )
{
<input type="submit" value="ButtonB" />
}
You must also declare ButtonA,ButtonB actions in your Home controller :
[HttpPost]
public ActionResult ButtonA()
{ . . . }
[HttpPost]
public ActionResult ButtonB()
{ . . . }