there's select which i'm trying to make work
SELECT DISTINCT a.client_key, client_name
FROM Bloggers AS a
LEFT JOIN BloggersPosts AS b
ON a.client_key = b.client_key
WHERE a.status = 1 AND
0 NOT IN (SELECT MIN(STATUS) FROM BloggersPosts AS c WHERE c.client_key=a.client_key)
For some reason 0 NOT IN (SELECT MIN(STATUS) FROM BloggersPosts AS c WHERE c.client_key=a.client_key) is not working, any ideas how to make it work?
EDIT: by not working i mean that if i delete the susbelect - my query gives result rows. But as soon as I add it - there is empty result. At the same time when i execute the subselect alone SELECT MIN(STATUS) FROM BloggersPosts - it returns 1, which means that putting it as subselect - should return results too, but it doesn't.
Thank you
I hope this will do your job. Trying different solution for your problem.
SELECT DISTINCT a.client_key, client_name
FROM Bloggers AS a
JOIN (SELECT client_key, MIN(STATUS) minstatus FROM BloggersPosts GROUP BY client_key) b
ON a.client_key = b.client_key AND minstatus <> 0
WHERE a.status = 1
Use JOIN instead, something like similar:
SELECT DISTINCT a.client_key, client_name, MIN(c.STATUS) blog_status
FROM Bloggers AS a
LEFT JOIN BloggersPosts AS b ON a.client_key = b.client_key
LEFT JOIN BloggersPosts AS c ON c.client_key = a.client_key
WHERE a.status = 1
HAVING blog_status <> 0
Related
I am not sure if my method is possible, but i'm trying to do a group_concat on a select statement that concats 2 fields. I get the error: Subquery returns more than 1 row each time. Can anyone help me as to a solution, or better way around this.
select t.recnum, (select group_concat((select concat(b.origtests,'^', d.name) as testing
from order_origtests b
join profile c on c.code = b.origtests
join department d on d.recnum = c.dept
)))
FROM order_ t
You don't put SELECT inside GROUP_CONCAT. It should be
select t.recnum, (
select group_concat(concat(b.origtests,'^', d.name))
from order_origtests b
join profile c on c.code = b.origtests
join department d on d.recnum = c.dept
) AS testing
FROM order_ t
Note that your subquery isn't correlated to anything in t, so you'll get the same testing column for every recnum.
This is my Query I want to get latest record in each group.I have two table t_service_request and t_request_chkpoint
t_service_request
------------
LTS,JFT,CUS_NO,REQUETST_ID...
t_request_chkpoint
------------
LTS ,REQUETST_ID...
Both table match by REQUETST_ID.
I want to group by cus_no in table t_service_request
SELECT S.*, A.ID as CID, A.ENTRY_ID, A.LTS
FROM maintenance.t_service_request S
WHERE JFT IN (
SELECT MAX(JFT)
FROM maintenance.t_service_request
GROUP BY CUS_NO
) LEFT OUTER JOIN maintenance.t_request_chkpoint A
ON S.REQUEST_ID = A.REQUEST_ID where S.COMPANY_ID = '0002' AND S.STATE >= 3 AND A.STATE >= 3
but didn't work any suggestions ?
t_service_request
------------
LTS|JFT|CUS_NO|REQUETST_ID|
t_request_chkpoint
------------
|LTS|REQUETST_ID|
Join above two table(Request_id) and select latest JFT in each CUS_NO
Try this, maybe works;)
SELECT DISTINCT
S.*,
A.ID AS CID,
A.ENTRY_ID,
A.LTS
FROM maintenance.t_service_request S
LEFT JOIN maintenance.t_request_chkpoint A ON A.REQUETST_ID = S.REQUETST_ID AND A.STATE >= 3
WHERE S.JFT = (SELECT MAX(B.JFT)
FROM maintenance.t_service_request B
WHERE B.CUS_NO = S.CUS_NO
GROUP BY B.CUS_NO)
AND S.COMPANY_ID = '0002' AND S.STATE >= 3
I think your sql may have some syntax errors and I am not sure I've misunderstood your requirement or not.
I must admit, I still don't understand what you are asking. Your query, however, is incomplete, and maybe fixing it solves your problem already.
You say you want "to get latest record in each group" and in your query you are looking for the maximum JFT per CUS_NO. Then, however you are only comparing the JFT and not the CUS_NO.
Moreover, your query is syntactically incorrect, as it has two WHERE clauses. Last but not least, (outer) join criteria (state >= 3 here) belongs in the ON clause, not in the WHERE clause.
Here is the corrected query:
select
sr.*,
rc.id as cid,
rc.entry_id,
rc.lts
from maintenance.t_service_request sr
left outer join maintenance.t_request_chkpoint rc on rc.request_id = sr.request_id
and rc.state >= 3
where sr.company_id = '0002' and sr.state >= 3
and (sr.cus_no, sr.jft) in
(
select cus_no, max(jft)
from maintenance.t_service_request
group by cus_no
);
I'm trying to compare 2 tables, but can't seem to get it to work. It's probably something very basic. Here's my code:
Select bin, partno, count(*) from
(SELECT parts.partno, location.bin
FROM inventory
INNER JOIN location
ON inventory.locid = location.locid
INNER JOIN parts
ON inventory.partid = parts.partid
WHERE loc = 'PnP'
UNION
select partno, bin from dlyfeedercontents) t
Group By t.bin, t.partno
HAVING COUNT(*) = 1
ORDER BY bin
Here are the results:
08-01 3052-93-7100-0C6 1
08-01 3052-93-7100-0C6 1
08-01 Test2 1
08-02 3052-90-7100-063 1
08-02 3052-90-7100-063 1
I can't seem to get the Group or Count to acknowledge that there are duplicates (for example, the first 2 lines). The results of the UNION are what I expected.
I'm not quite sure what you are trying to do, but I strongly suspect the problem is using union rather than union all. union removes duplicates. Does this version do what you want?
select bin, partno, count(*)
from ((SELECT parts.partno, location.bin
FROM inventory INNER JOIN
location
ON inventory.locid = location.locid INNER JOIN
parts
ON inventory.partid = parts.partid
WHERE loc = 'PnP'
) union all
(select partno, bin
from dlyfeedercontents
)
) t
Group By t.bin, t.partno
HAVING COUNT(*) = 1
ORDER BY bin;
The issue was a nonprinting character in some of the data (/r)! Thanks for all who helped!
I've created sqlfiddle to try and get my head around this http://sqlfiddle.com/#!2/21e72/1
In the query, I have put a max() on the compiled_date column but the recommendation column is still coming through incorrect - I'm assuming that a select statement will need to be inserted on line 3 somehow?
I've tried the examples provided by the commenters below but I think I just need to understand this from a basic query to begin with.
As others have pointed out, the issue is that some of the select columns are neither aggregated nor used in the group by clause. Most DBMSs won't allow this at all, but MySQL is a little relaxed on some of the standards...
So, you need to first find the max(compiled_date) for each case, then find the recommendation that goes with it.
select r.case_number, r.compiled_date, r.recommendation
from reporting r
join (
SELECT case_number, max(compiled_date) as lastDate
from reporting
group by case_number
) s on r.case_number=s.case_number
and r.compiled_date=s.lastDate
Thank you for providing sqlFiddle. But only reporting data is given. we highly appreciate if you give us sample data of whole tables.
Anyway, Could you try this?
SELECT
`case`.number,
staff.staff_name AS ``case` owner`,
client.client_name,
`case`.address,
x.mx_date,
report.recommendation
FROM
`case` INNER JOIN (
SELECT case_number, MAX(compiled_date) as mx_date
FROM report
GROUP BY case_number
) x ON x.case_number = `case`.number
INNER JOIN report ON x.case_number = report.case_number AND report.compiled_date = x.mx_date
INNER JOIN client ON `case`.client_number = client.client_number
INNER JOIN staff ON `case`.staff_number = staff.staff_number
WHERE
`case`.active = 1
AND staff.staff_name = 'bob'
ORDER BY
`case`.number ASC;
Check below query:
SELECT c.number, s.staff_name AS `case owner`, cl.client_name,
c.address, MAX(r.compiled_date), r.recommendation
FROM case c
INNER JOIN (SELECT r.case_number, r.compiled_date, r.recommendation
FROM report r ORDER BY r.case_number, r.compiled_date DESC
) r ON r.case_number = c.number
INNER JOIN client cl ON c.client_number = cl.client_number
INNER JOIN staff s ON c.staff_number = s.staff_number
WHERE c.active = 1 AND s.staff_name = 'bob'
GROUP BY c.number
ORDER BY c.number ASC
SELECT
case.number,
staff.staff_name AS `case owner`,
client.client_name,
case.address,
(select MAX(compiled_date)from report where case_number=case.number),
report.recommendation
FROM
case
INNER JOIN report ON report.case_number = case.number
INNER JOIN client ON case.client_number = client.client_number
INNER JOIN staff ON case.staff_number = staff.staff_number
WHERE
case.active = 1 AND
staff.staff_name = 'bob'
GROUP BY
case.number
ORDER BY
case.number ASC
try this
I have this query on Access 2010 (accdb) which is working perfectly fine:
SELECT b.category_name, a.item_name,
(SELECT COUNT(*) FROM tbl_stock_receiving AS x WHERE x.safe_stock_id = a.ID) AS received,
(SELECT COUNT(*) FROM tbl_stock_issuance AS y WHERE y.stock_receiving_id = a.ID) AS issued,
(received-issued) AS on_hand, a.safe_stock
FROM tbl_safe_stock AS a INNER JOIN tbl_category AS b
ON a.category_id = b.id
ORDER BY a.item_name;
Now, I need to modify it to include a simple WHERE statement
...
ON a.category_id = b.id
WHERE a.safe_stock > on_hand
ORDER BY a.item_name;
...
When I run the query, Access keeps popping up for a parameter value for
on_hand
on_hand is an Alias as you can see on
(received-issued) AS on_hand
What could be wrong in my query?
You've defined on_hand as the name of an output column, but the SQL parser isn't clever enough to go back through your query and "reverse engineer" where on_hand came from. Therefore, you'd need to use something like WHERE a.safe_stock > (received - issued), but they are aliases for output columns, too.
So try wrapping the whole thing up as a subquery and then applying the WHERE and ORDER BY clauses afterward:
SELECT * FROM
(
SELECT b.category_name, a.item_name,
(SELECT COUNT(*) FROM tbl_stock_receiving AS x WHERE x.safe_stock_id = a.ID) AS received,
(SELECT COUNT(*) FROM tbl_stock_issuance AS y WHERE y.stock_receiving_id = a.ID) AS issued,
(received-issued) AS on_hand, a.safe_stock
FROM tbl_safe_stock AS a INNER JOIN tbl_category AS b
ON a.category_id = b.id
)
WHERE safe_stock > on_hand
ORDER BY item_name
Edit
The suggestion above resulted in a "Query is too complex" error, so my next suggestion was to save the original query as [StockCheckBaseQuery] and then do
SELECT * FROM StockCheckBaseQuery WHERE safe_stock > on_hand ORDER BY item_name
That appears to have been successful.