I want to develop code that will allow a subset within a query. I have three fields "batchid", "month" and "year". Each batch may have several months and more than one year. The final order I need is the highest month year combination.
The following table I hope illustrates this.
Batch Month Year
5 12 2013
1 2014
6 11 2013
3 2014
4 1 2014
2 2014
The required order is
Batch Month Year
5 12 2013
1 2014
4 1 2014
2 2014
6 11 2013
3 2014
You can see each batch is sorted to the latest date in the batch and each batch is ordered to the latest date in the batch.
I have got it as far as the year is concerned but cannot figure out the month.
The first statement determines the lowest and highest dates.
I am new to this forum and for that matter not experienced using VBA and have not beanpole to get the SQL statement into this post so I apologize na hope this may make sense.
SELECT t1.batch, t1.month, t1.year
FROM tmp t1
JOIN
(SELECT batch, max(year*12+month) mord FROM tmp GROUP BY batch ORDER BY mord) t2
ON t2.batch = t1.batch
ORDER BY t2.mord, t1.year, t1.month
yields
+-------+-------+------+
| batch | month | year |
+-------+-------+------+
| 5 | 12 | 2013 |
| 5 | 1 | 2014 |
| 4 | 1 | 2014 |
| 4 | 2 | 2014 |
| 6 | 11 | 2013 |
| 6 | 3 | 2014 |
+-------+-------+------+
Related
I have a table like this
userID time NoOfVisits
1 2014 50
2 2015 60
3 2016 70
4 2017 80
5 2018 90
6 2019 100
I need to write a sql query which will print time and average of past 3 years NoOfVisits for a particular site.
output should be as
userID time NoOfVisits
1 2014 50.0000
2 2015 55.0000
3 2016 60.0000
4 2017 70.0000
5 2018 80.0000
6 2019 90.0000
Explanation :
For user Id 6 (80+90+100)/3=90.0000
Please help me to solve this problem.
You can use a cumulative average, available in MySQL 8+:
select t.*,
avg(visits) over (order by time rows between 2 preceding and current row) as avg_visits_3
from t;
Assuming there are no gaps between the years (like your sample data), you can self join the table and group by userid, time to get the average:
select
t.userid, t.time, avg(tt.noofvisits) NoOfVisits
from tablename t inner join tablename tt
on tt.time between t.time - 2 and t.time
group by t.userid, t.time
See the demo.
Results:
| userid | time | NoOfVisits |
| ------ | ---- | ---------- |
| 1 | 2014 | 50 |
| 2 | 2015 | 55 |
| 3 | 2016 | 60 |
| 4 | 2017 | 70 |
| 5 | 2018 | 80 |
| 6 | 2019 | 90 |
I am saving the reporting date as date format (ex 2017-04-05) now I want the records only between two years based on reporting date, I am giving the from year and two year as 2016 and 2017
See My table structure
report_id | report_date | user_id | amount
1 | 2015-11-12 | 12 | 5000
2 | 2016-12-01 | 17 | 5000
3 | 2017-01-12 | 21 | 5000
4 | 2017-02-12 | 07 | 5000
The above table is my table structure
Now I want to get the records where report_date between year 2016 and 2017, I will not give complete date only I will give the year.
You can use YEAR() to get just the year of a date, then you can search between years like so:
SELECT *
FROM reports
WHERE YEAR(report_date) BETWEEN 2015 AND 2016;
I have a database with a table containing information on some images, each row containing a createdAt date and a viewCount. The data ranges from September 2014 until today (July 2016). I want to get a monthly sum of the amount of views across all images for the month
When I run the query
SELECT YEAR(createdAt), MONTH(createdAt), SUM(viewCount)
FROM Images
GROUP BY MONTH(createdAt);
I'm only returned 12 rows with results between September 2014 and August 2015
Year | Month | Views
-------------------
2014 | 9 | 1452
2014 | 10 | 279
2014 | 11 | 34428
2014 | 12 | 4763
2015 | 1 | 2826
2015 | 2 | 777
2015 | 3 | 568
2015 | 4 | 1309
2015 | 5 | 46744
2015 | 6 | 1541
2015 | 7 | 8160
2015 | 8 | 91
If I add a date restraint it will give me the latest data, but again only 12 rows
SELECT YEAR(createdAt), MONTH(createdAt), SUM(viewCount)
FROM Images WHERE createdAt > DATE('2015-08-01 00:00:00')
GROUP BY MONTH(createdAt);
Year | Month | Views
--------------------
2015 | 8 | 981
2015 | 9 | 1031
2015 | 10 | 2566
2015 | 11 | 3325
2015 | 12 | 411
2016 | 1 | 2140
2016 | 2 | 710
2016 | 3 | 714
2016 | 4 | 1985
2016 | 5 | 426
2016 | 6 | 119
2016 | 7 | 81
I do realise that since it's July the second query stops there as that's where the data ends, but why does the first query not return all the results?
Group by year/month:
SELECT YEAR(createdAt), MONTH(createdAt), SUM(viewCount)
FROM Images
--WHERE createdAt > DATE('2015-08-01 00:00:00')
GROUP BY YEAR(createdAt), MONTH(createdAt);
Related Group by clause in mySQL and postgreSQL, why the error in postgreSQL?
Keep in mind that from MySQL 5.7.6+ your initial query may not even work because of only_full_group_by which is set by default.
You can simply add Year to you group by
SELECT YEAR(createdAt), MONTH(createdAt), SUM(viewCount)
FROM Images
GROUP BY YEAR(createdAt), MONTH(createdAt)
ORDER BY YEAR(createdAt), MONTH(createdAt)
I have a table XX. i need to get the records which are 20 days consecutive gap .below is my table look
ID ISmen Date
1 0 2013-05-2
2 0 2013-05-2
3 0 2014-04-2
4 1 2014-05-2
5 1 2014-05-2
6 0 2014-05-2
7 0 2014-05-2
8 0 2014-05-2
9 1 2014-05-25
10 1 2014-05-25
11 0 2014-05-26
12 1 2014-05-27
13 0 2014-05-28
From the above table i need to get the records which are ismen is 1 and the next record ismen is also 1 (i.e 4,5 and 9,10 but not 12).and one more thing 4,5 and 9,10 should have 20 days gap
i am getting the records which are 4,5 and 9,10 ..but i can't able to check date difference between the records .i know we can achieve in the loop but i am trying to get in MySQL is it possible or not.I try below query.thanks in advance for help
SELECT *
FROM XX t1,
XX t2
WHERE (t1.ID=t2.ID+1
OR t1.ID=t2.ID-1)
AND t1.Ismen=1
AND t2.Ismen=1
There is a 23 day gap between |4|5| to |9|10| but ignoring the sample data precision, this result:
| ISMEN | T1ID | T2ID | T1DATE | T2DATE |
|-------|------|------|----------------------------|----------------------------|
| 1 | 4 | 9 | May, 02 2014 00:00:00+0000 | May, 25 2014 00:00:00+0000 |
| 1 | 5 | 9 | May, 02 2014 00:00:00+0000 | May, 25 2014 00:00:00+0000 |
| 1 | 4 | 10 | May, 02 2014 00:00:00+0000 | May, 25 2014 00:00:00+0000 |
| 1 | 5 | 10 | May, 02 2014 00:00:00+0000 | May, 25 2014 00:00:00+0000 |
was produced by this query:
select
t1.ismen
, t1.id as t1id
, t2.id as t2id
, t1.`date` as t1date
, t2.`date` as t2date
from table1 as t1
inner join table1 as t2 on t1.ismen = t2.ismen
and t1.`date` + INTERVAL 23 DAY = t2.`date`
The wanted gap between records can be defined in the join conditions (change to 20 or whatever). But do note there is nothing to stop 4 relating to 9 and 10 or 5 to 9 & 10 so you get 4 records in total.
see: http://sqlfiddle.com/#!9/8d941/1
You could reduce that result by some means (e.g. using row_number() but I don't know if that is required.
Assuming I have a table like the following:
id | assignment | duedate
1 | Math | 2012-01-01
2 | History | 2012-02-02
3 | Science | 2012-01-01
4 | Government | 2012-02-01
5 | Government | 2013-01-13
6 | History | 2013-03-13
Is it possible to make some sql query such that I get a grouping of all the dates by month and year? Is there some possibility that I could get a sorted result of:
duedatemonth | count
January 2012 | 2
Feburary 2012 | 2
January 2013 | 1
March 2013 | 1
I know you can GROUP BY duedate, but that only groups those with the same month, day, and year instead of just month and year.
Would it be then possible to even further group it such that it factors in "assignment" to obtain a resulting table of
id | duedatemonth | count
1 | January 2012 | 2
3 | January 2012 | 2
2 | Feburary 2012 | 2
4 | Feburary 2012 | 2
5 | January 2013 | 1
6 | March 2013 | 1
try this
SELECT DATE_FORMAT(duedate,'%M %Y') duedatemonth, COUNT(*) count
FROM Table1
GROUP BY year(duedate), MONTH(duedate)
DEMO HERE
will output this:
DUEDATEMONTH COUNT
January 2012 2
February 2012 2
January 2013 1
March 2013 1
Use the string functions YEAR and MONTH.
SELECT YEAR(duedate), MONTH(duedate), COUNT(*)
FROM sparkles
GROUP BY YEAR(duedate), MONTH(duedate)
Use MONTHNAME or DATE_FORMAT to get the name of the month.
You can use this query.
SELECT DATE_FORMAT(duedate, '%M %Y') duedatemonth, COUNT(1) `count`
FROM Tbl
GROUP BY DATE_FORMAT(duedate, '%M %Y')