I have a database named prestashop, a table ps_product and a field mq which is tinyInt.
If I do this query on console, it runs correctly, editing the value of a field in a record:
USE prestashop UPDATE ps_product SET mq = 0 WHERE id_product = 1
If I do this query programmatically (php):
mysql_query("USE prestashop
UPDATE ps_product
SET mq = 0
WHERE id_product = 1;")
or die("Query non valida: " . mysql_error());
and this is the error:
Query non valida: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'UPDATE ps_product SET mq = 0 WHERE id_product = 1' at line 2
why?
In the console all proceeds correctly, and it really edit the value on the table
For update product detail in prestashop you should write query like that:
$sql = 'UPDATE '._DB_PREFIX_.'product SET mq=0 WHERE id_product=1';
if (!Db::getInstance()->execute($sql))
die('error!');
I hope it would help you.
Related
I need some help with the query below - I am trying to pull information regarding price and multiply with the quantity & insert the sum into the table. So far I have,
update passenger_baggage
SET passenger_baggage.total_baggage_cost=passenger_baggage.passenger_baggage_quantity*baggage_type.baggage_type_cost
FROM passenger_baggage INNER JOIN baggage_type
ON passenger_baggage.passenger_baggage_id = baggage_type.baggage_type_id
WHERE passenger_id = "3";
and getting this error
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use
near 'FROM passenger_baggage INNER JOIN baggage_type ON
passenger_baggage.passenge...' at line 3
Expecting the query to multiply the two values & insert the total.
There is no FROM clause in an UPDATE query.
Try with this modified query:
update passenger_baggage
INNER JOIN baggage_type
ON passenger_baggage.passenger_baggage_id = baggage_type.baggage_type_id
SET passenger_baggage.total_baggage_cost = passenger_baggage.passenger_baggage_quantity * baggage_type.baggage_type_cost
WHERE passenger_id = "3";
Try this:
UPDATE passenger_baggage, baggage_type
SET passenger_baggage.total_baggage_cost = passenger_baggage.passenger_baggage_quantity * baggage_type.baggage_type_cost
WHERE passenger_baggage.passenger_baggage_id = baggage_type.baggage_type_id AND passenger_id = "3";
Saw an example from the MySQL doc (https://dev.mysql.com/doc/refman/8.0/en/update.html)
I am trying to do an LEFT Join in Yii v.1 Mysql .
There are alreday 4 tables joined and I want to join this table also.
$cmd = Yii::app()->db->createCommand();
$selectString .= "table2.dir_pic, table2.pic1, table2.pic2 , table2.pic3 ";
$cmd->select($selectString);
$cmd->from('table1');
$cmd->leftjoin('table2', 'table1.id=table2.user_entry_id');
$entries = $cmd->queryAll();
$this->render('index', compact('entries', 'model'));
It is giving an CDbException
CDbCommand failed to execute the SQL statement: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '.`dir_pic`, `table2`.`pic1`, `table2`.`pic2`, ' at line 1.
I tried this query in mysql(phpmyadmin)
SELECT table1.id,table2.dir_pic,table2.pic1,table2.pic2, table2.pic3 FROM
table1 LEFT JOIN table2 ON table1.id = table2.user_entry_id
and It shows proper output.BUt not when I try in Yii .
I found the solution. Actually I missed an comma (,) after the end of previous $selectString query.
I keep getting this syntax error in my MySQL code within a PHP file. I'm simply trying to increment/add to the value already in the table with this time variable. If anyone could help me out I'd greatly appreciate it.
PHP:
$sql = "UPDATE Aircraft
SET MaintenanceFlightTime = (MaintenanceFlightTime + $MaintenanceDuration),
WHERE AircraftID = $AircraftID";
Error:
UPDATE Aircraft SET MaintenanceFlightTime = (MaintenanceFlightTime + 00:10:00), WHERE AircraftID = 8
You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near ':10:00), WHERE AircraftID = 8' at line 2
You cannot just add a string like '01:01:01' to a time column but you can use ADDTIME()
$MaintenanceDuration = '00:10:00';
$sql = "UPDATE Aircraft
SET MaintenanceFlightTime = ADDTIME(MaintenanceFlightTime, '$MaintenanceDuration')
WHERE AircraftID = $AircraftID";
String sql = ("insert into registration(pic) values(?) where email='"+Email+"' ");
i get error :error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'where email='yyy#ymail.com'' at line 1
You have to use UPDATE query to pass it like
String sql = "UPDATE registration SET pic = ? WHERE email = '" + Email + "'";
Syntax for UPDATE query is
UPDATE table_name SET column_name = value;
Insert query format should be,
"insert into tablename (columnname) values(coulmnvalue)"
OR
"update registration set pic='' where email='"+Email+"'";
Yes. that is impossible.
Either you want:
insert into registration(pic) values(?)
Which will give you a new row;
Or you want an UPDATE:
UPDATE registration SET pic = ?
WHERE email = <EMAILYouWant>
Which will update an existing row where email = the record with the email you want to update the pic column.
$produpd = "UPDATE tblnavpc SET tblnavpc.ChildName = tblnav.NavName " .
"FROM tblnav WHERE tblnavpc.CID = tblnav.NavID";
This is the error I get"
You have an error in your SQL syntax;
check the manual that corresponds to
your MySQL server version for the
right syntax to use near 'FROM tblnav
WHERE tblnavpc.CID = tblnav.NavID' at
line 1
I know keys aren't named greatly but I just trying to fix this one problem, I didn't name the tables.
You don't have a FROM clause in an update:
UPDATE tblnavpc
INNER JOIN tblnav ON tblnavpc.CID = tblnav.NavID
SET tblnavpc.ChildName = tblnav.NavName
"From" cannot be used with update statements.
Should be
$produpd = "UPDATE tblnavpc SET tblnavpc.ChildName = tblnav.NavName " .
"WHERE tblnavpc.CID = tblnav.NavID";