Can the MYSQL function STR-TO-DATE convert a string in this format 99-MMM-9999 (ex., '21-Sep-2014' to a date format? And what if that field is defined as 12 chars instead of the specific 11?
I tried this and it got NULLS.
You can, just setting proper format mask:
SELECT STR_TO_DATE('21-Sep-2014','%d-%M-%Y');
If you have 12 chars, set proper mask, sample:
SELECT STR_TO_DATE(' 21-Sep-2014',' %d-%M-%Y');
SELECT STR_TO_DATE(yourdatefield, '%m/%d/%Y')
FROM yourtable
You can also handle these date strings in WHERE clauses. For example
SELECT whatever
FROM yourtable
WHERE STR_TO_DATE(yourdatefield, '%m/%d/%Y') > CURDATE() - INTERVAL 7 DAYS
You can handle all kinds of date / time layouts this way. Please refer to the format specifiers for the DATE_FORMAT() function to see what you can put into the second parameter to STR_TO_DATE()
reference :- how to convert a string to date in mysql?
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_date-format
Related
I have a string column which acts as a date and I want to select it as a DATE.
Is it possible?
My sample data format would be:
month/day/year -> 12/31/2011
As was told at MySQL Using a string column with date text as a date field, you can do
SELECT STR_TO_DATE(yourdatefield, '%m/%d/%Y')
FROM yourtable
You can also handle these date strings in WHERE clauses. For example
SELECT whatever
FROM yourtable
WHERE STR_TO_DATE(yourdatefield, '%m/%d/%Y') > CURDATE() - INTERVAL 7 DAY
You can handle all kinds of date/time layouts this way. Please refer to the format specifiers for the DATE_FORMAT() function to see what you can put into the second parameter of STR_TO_DATE().
STR_TO_DATE('12/31/2011', '%m/%d/%Y')
Here's another two examples.
To output the day, month, and year, you can use:
select STR_TO_DATE('14/02/2015', '%d/%m/%Y');
Which produces:
2015-02-14
To also output the time, you can use:
select STR_TO_DATE('14/02/2017 23:38:12', '%d/%m/%Y %T');
Which produces:
2017-02-14 23:38:12
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html
use the above page to refer more Functions in MySQL
SELECT STR_TO_DATE(StringColumn, '%d-%b-%y')
FROM table
say for example use the below query to get output
SELECT STR_TO_DATE('23-feb-14', '%d-%b-%y') FROM table
For String format use the below link
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_date-format
The following illustrates the syntax of the STR_TO_DATE() function:
STR_TO_DATE(str,fmt);
The STR_TO_DATE() converts the str string into a date value based on the fmt format string. The STR_TO_DATE() function may return a DATE , TIME, or DATETIME value based on the input and format strings. If the input string is illegal, the STR_TO_DATE() function returns NULL.
The following statement converts a string into a DATE value.
SELECT STR_TO_DATE('21,5,2013','%d,%m,%Y');
Based on the format string ‘%d, %m, %Y’, the STR_TO_DATE() function scans the ‘21,5,2013’ input string.
First, it attempts to find a match for the %d format specifier, which
is a day of the month (01…31), in the input string. Because the
number 21 matches with the %d specifier, the function takes 21 as the
day value.
Second, because the comma (,) literal character in the format string
matches with the comma in the input string, the function continues to
check the second format specifier %m , which is a month (01…12), and
finds that the number 5 matches with the %m format specifier. It
takes the number 5 as the month value.
Third, after matching the second comma (,), the STR_TO_DATE()
function keeps finding a match for the third format specifier %Y ,
which is four-digit year e.g., 2012,2013, etc., and it takes the
number 2013 as the year value.
The STR_TO_DATE() function ignores extra characters at the end of the input string when it parses the input string based on the format string. See the following example:
SELECT STR_TO_DATE('21,5,2013 extra characters','%d,%m,%Y');
More Details : Reference
So I'm trying to insert dates into a table and the date is in this format:
8/3/2021
However I want to add a leading 0 before the month and day so the date shows 08/03/2021. Also I want to add it as a string concatenated with another string so test123-08/03/2021
If you really store date in that format then you may try this:
SELECT
DATE_FORMAT(STR_TO_DATE(date_col_string,'%d/%m/%Y'),'%d/%m/%Y') as 'zero-padded',
CONCAT(string_val,'-',DATE_FORMAT(STR_TO_DATE(date_col_string,'%d/%m/%Y'),'%d/%m/%Y')) as 'concatenated'
FROM mytable;
Use STR_TO_DATE() function to change the date value to standard MySQL date format of YYYY-MM-DD then use DATE_FORMAT() function to display the date value as per your desired output. The second operation is adding CONCAT() function on the converted date with your selected string. I'm assuming that your date value is d/m/y, because as #Stu mentioned in the comment, since you're not storing as MySQL standard date format, that means 8/3/2021 can be either d/m/y or m/d/y. With a standard date format value, the query would be shorter:
SELECT
DATE_FORMAT(date_col,'%d/%m/%Y') as 'zero-padded',
CONCAT(string_val,'-',DATE_FORMAT(date_col,'%d/%m/%Y')) as 'concatenated'
FROM mytable;
Demo fiddle
You should be inserting your source dates into a proper date or datetime column. Then, to view your dates in the format you want, use the DATE_FORMAT() function with the appropriate format mask:
SELECT DATE_FORMAT(date_col, '%d/%m/%Y') AS date_out
FROM yourTable;
I have a string column which acts as a date and I want to select it as a DATE.
Is it possible?
My sample data format would be:
month/day/year -> 12/31/2011
As was told at MySQL Using a string column with date text as a date field, you can do
SELECT STR_TO_DATE(yourdatefield, '%m/%d/%Y')
FROM yourtable
You can also handle these date strings in WHERE clauses. For example
SELECT whatever
FROM yourtable
WHERE STR_TO_DATE(yourdatefield, '%m/%d/%Y') > CURDATE() - INTERVAL 7 DAY
You can handle all kinds of date/time layouts this way. Please refer to the format specifiers for the DATE_FORMAT() function to see what you can put into the second parameter of STR_TO_DATE().
STR_TO_DATE('12/31/2011', '%m/%d/%Y')
Here's another two examples.
To output the day, month, and year, you can use:
select STR_TO_DATE('14/02/2015', '%d/%m/%Y');
Which produces:
2015-02-14
To also output the time, you can use:
select STR_TO_DATE('14/02/2017 23:38:12', '%d/%m/%Y %T');
Which produces:
2017-02-14 23:38:12
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html
use the above page to refer more Functions in MySQL
SELECT STR_TO_DATE(StringColumn, '%d-%b-%y')
FROM table
say for example use the below query to get output
SELECT STR_TO_DATE('23-feb-14', '%d-%b-%y') FROM table
For String format use the below link
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_date-format
The following illustrates the syntax of the STR_TO_DATE() function:
STR_TO_DATE(str,fmt);
The STR_TO_DATE() converts the str string into a date value based on the fmt format string. The STR_TO_DATE() function may return a DATE , TIME, or DATETIME value based on the input and format strings. If the input string is illegal, the STR_TO_DATE() function returns NULL.
The following statement converts a string into a DATE value.
SELECT STR_TO_DATE('21,5,2013','%d,%m,%Y');
Based on the format string ‘%d, %m, %Y’, the STR_TO_DATE() function scans the ‘21,5,2013’ input string.
First, it attempts to find a match for the %d format specifier, which
is a day of the month (01…31), in the input string. Because the
number 21 matches with the %d specifier, the function takes 21 as the
day value.
Second, because the comma (,) literal character in the format string
matches with the comma in the input string, the function continues to
check the second format specifier %m , which is a month (01…12), and
finds that the number 5 matches with the %m format specifier. It
takes the number 5 as the month value.
Third, after matching the second comma (,), the STR_TO_DATE()
function keeps finding a match for the third format specifier %Y ,
which is four-digit year e.g., 2012,2013, etc., and it takes the
number 2013 as the year value.
The STR_TO_DATE() function ignores extra characters at the end of the input string when it parses the input string based on the format string. See the following example:
SELECT STR_TO_DATE('21,5,2013 extra characters','%d,%m,%Y');
More Details : Reference
I have a column where a date store in ddmmyy format (e.g. 151216). How can I convert it to yyyy-mm-dd format (e.g 2016-12-15) for calculating a date difference from the current date? I try using DATE_FORMAT function but its not appropriate for this.
If you want to get the date difference, you can use to_days() after converting the string to a date using str_to_date():
select to_days(curdate()) - to_days(str_to_date(col, '%d%m%y'))
or datediff():
select datediff(curdate(), str_to_date(col, '%d%m%y'))
or timestampdiff():
select timestampdiff(day, str_to_date(col, '%d%m%y'), curdate())
You can use the function, STR_TO_DATE() for this.
STR_TO_DATE('151216', '%d%m%y')
A query would look something like:
select
foo.bar
from
foo
where
STR_TO_DATE(foo.baz, '%d%m%y') < CURDATE()
Note: Since both STR_TO_DATE() and CURDATE() return date objects, there's no reason to change the actual display format of the date. For this function, we just need to format it. If you wanted to display it in your query, you could use something like
DATE_FORMAT(STR_TO_DATE(foo.baz, '%d%m%y'), '%Y-%m-%d')
To get the difference, we can simply subtract time
select
to_days(CURDATE() - STR_TO_DATE(foo.baz, '%d%m%y')) as diff
from
foo
If you wanted to only select rows that have a difference of a specified amount, you can put the whole to_days(...) bit in your where clause.
SELECT STR_TO_DATE('151216', '%d%m%y') FROM `table`
use this '%d%m%y'
I have a string column which acts as a date and I want to select it as a DATE.
Is it possible?
My sample data format would be:
month/day/year -> 12/31/2011
As was told at MySQL Using a string column with date text as a date field, you can do
SELECT STR_TO_DATE(yourdatefield, '%m/%d/%Y')
FROM yourtable
You can also handle these date strings in WHERE clauses. For example
SELECT whatever
FROM yourtable
WHERE STR_TO_DATE(yourdatefield, '%m/%d/%Y') > CURDATE() - INTERVAL 7 DAY
You can handle all kinds of date/time layouts this way. Please refer to the format specifiers for the DATE_FORMAT() function to see what you can put into the second parameter of STR_TO_DATE().
STR_TO_DATE('12/31/2011', '%m/%d/%Y')
Here's another two examples.
To output the day, month, and year, you can use:
select STR_TO_DATE('14/02/2015', '%d/%m/%Y');
Which produces:
2015-02-14
To also output the time, you can use:
select STR_TO_DATE('14/02/2017 23:38:12', '%d/%m/%Y %T');
Which produces:
2017-02-14 23:38:12
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html
use the above page to refer more Functions in MySQL
SELECT STR_TO_DATE(StringColumn, '%d-%b-%y')
FROM table
say for example use the below query to get output
SELECT STR_TO_DATE('23-feb-14', '%d-%b-%y') FROM table
For String format use the below link
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_date-format
The following illustrates the syntax of the STR_TO_DATE() function:
STR_TO_DATE(str,fmt);
The STR_TO_DATE() converts the str string into a date value based on the fmt format string. The STR_TO_DATE() function may return a DATE , TIME, or DATETIME value based on the input and format strings. If the input string is illegal, the STR_TO_DATE() function returns NULL.
The following statement converts a string into a DATE value.
SELECT STR_TO_DATE('21,5,2013','%d,%m,%Y');
Based on the format string ‘%d, %m, %Y’, the STR_TO_DATE() function scans the ‘21,5,2013’ input string.
First, it attempts to find a match for the %d format specifier, which
is a day of the month (01…31), in the input string. Because the
number 21 matches with the %d specifier, the function takes 21 as the
day value.
Second, because the comma (,) literal character in the format string
matches with the comma in the input string, the function continues to
check the second format specifier %m , which is a month (01…12), and
finds that the number 5 matches with the %m format specifier. It
takes the number 5 as the month value.
Third, after matching the second comma (,), the STR_TO_DATE()
function keeps finding a match for the third format specifier %Y ,
which is four-digit year e.g., 2012,2013, etc., and it takes the
number 2013 as the year value.
The STR_TO_DATE() function ignores extra characters at the end of the input string when it parses the input string based on the format string. See the following example:
SELECT STR_TO_DATE('21,5,2013 extra characters','%d,%m,%Y');
More Details : Reference