I would like to replace any 'dot' character in my query string, on SELECTing fields from database.
I'll need to modify lots of queries, I'm willing there's a function that will work to all columns on SELECT. I mean something like this SELECT DOT_TO_COMMA(*) FROM...
Right now what I have:
SELECT price, lastprice FROM products
OUTPUT: 22.10, 5.24
EXPECTATION: 22,10, 5,25
SELECT REPLACE(price, '.', ',') AS price
FROM products;
read more about it here
You have to wrap each column you need to replace with the function. Using replace(*) is not possible.
please try this...
this is working
SELECT REPLACE(price,'.',',') AS price, REPLACE(lastprice,'.',',') AS lastprice FROM products
In my case replace doesn't work well with negative numbers.
I use SELECT FORMAT (price,0).
Second parameter is de decimal numbers
checkout http://www.mysqltutorial.org/mysql-format-function/
Related
All I want to do is retrieve the names of the people who start with "ma".
Eg Matt, Mathers, Mac.
First, two letters have to be 'ma'.
Have a look at string comparisons functions.
SELECT *
FROM YOUR_TABLE
WHERE NAME LIKE 'MA%';
SELECT *
FROM YOUR_TABLE
WHERE NAME LIKE 'MA%'
There can be spaces at the beginning of the name just like ' Matthew'. This would fix it:
SELECT *
FROM YOUR_TABLE
WHERE ltrim(NAME) LIKE 'MA%'
just as the question can we do something to get the length and first 3 characters of the employee name of one column
Please do not mark as answered or duplicate
i have the test tomorrow Advance SQL so I am trying to solve some imp question..
Please answer the problem
thanks again
Hi Shanu, You can use LEN() or LENGTH()(in case of oracle sql) function to get the length of a column.
SELECT LEN(column_name) FROM table_name;
And you can use SUBSTRING or SUBSTR() function go get first three characters of a column.
SUBSTRING( string, start_position, length );
SELECT SUBSTRING( column_name, 1, 3 ) FROM table_name;
To get both together use concatenation operator,
SELECT LEN(column_name)||SUBSTRING( column_name, 1, 3 ) FROM table_name;
Hope you got what you need. Any issues, feel free to ask
We can use SUBSTRING or SUBSTR() function, go get first three characters of a column.
And then try this particular query:
SELECT SUBSTRING(ename,1,3)
FROM emp;
Select len(ename) as Column_Length, left(ename,3) first_three_char from employee; ---------need to code your query. Should not use test format, will be confusing
You can also use substring function instead of left. Query will look like
Select len(ename) as Column_Length,substring(ename,1,3) first_three_char from employee;
SELECT LEN(EMPLOYEE_NAME),LEFT(EMPLOYEE_NAME,3) FROM EMPLOYEE_TABLE;
i have in my table places named field. there are space separated values(there are problem to store csv value in one field). now i want to fire query like below. how i can do ??
select * from tablename where variablename in places
i did try this way but it shows syntax error.
select * from tablename where variablename in replace(places,' ',',')
### places ###
bank finance point_of_interest establishment
Use FIND_IN_SET
For comma separated
SELECT *
FROM tablename
WHERE ( FIND_IN_SET( 'bank', variablename ) )
Refer : SQL Fiddle
For space separated
SELECT *
FROM tablename
WHERE ( FIND_IN_SET( 'bank', replace(variablename,' ',',') ) )
Refer : SQL Fiddle
The best solution would be to normalise your data structure and do not have a single field storing multiple values.
You can make a query work without normalisation, but any solutions would be lot less optimal from a performance point of view.
Use patter matching with like operator:
... where fieldname like '% searched_value %'
Use the replace() function and combine it with find_in_set():
... where find_in_set('searched_value',replace(fieldname,' ',','))>0
Hi I think your problem comes from the usage of IN
IN for MySql is used like this
SELECT *
FROM table_name
WHERE column_name IN (bank,finance,point_of_interest, establishment);
In case of you want to select places you need to specify each place into value like
I have values stored like this in a field 1,255,230,265.
Is there a function in MySQL that will give me the second value in that string? In this case it'll be 255.
I tried using locate, but that does not seem to be meant for this.
Try this
select SUBSTRING_INDEX(SUBSTRING_INDEX(field_name,',',2),",",-1) from table_name
You might want to use SUBSTRING_INDEX() function.
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(field,',',2),',',-1)
FROM yourTable.
This grabs everything infront of the second comma, then grabs everything after the last comma (-1)
Try This
select * from Table1 where ',' + Nos+ ',' like '%,255,%'
Refer:
MySQL query finding values in a comma separated string
mysql check if numbers are in a comma separated list
Use FIND_IN_SET() function:
SELECT *
FROM tableA
WHERE FIND_IN_SET(255, columnName)
OR
Use LIKE operator
SELECT *
FROM tableA
WHERE CONCAT(',', columnName, ',') LIKE '%,255,%'
I need to order by a field that contains a set of numbers. Lets say a table named TEST contains ID, NAME, QUADS with QUADS as follows.
95,273,212,405
717,450,771,504
391,176,646,272
This are the results I am getting with a query such as
SELECT * FROM TEST ORDER BY QUADS
391,176,646,272
717,450,771,504
95,273,212,405
These are the results I am looking to get
95,273,212,405
391,176,646,272
717,450,771,504
I am only interested in the first number in the set for "order". Figure it might be possible with a substring to the comma but not sure how to do that in MySQL.
Try this:
select * from test
order by cast(substring_index(quads,',',1) as unsigned)
What you want is the substring_index function.
... order by substring_index(x_field,',',1)
This extracts the text in x_field up to the first occurrence of the comma delimiter
Try with this:
select QUADS, 0+QUADS as S from TEST order by S
0+QUADS will convert your string to int and will use for it just the first digits sequence before "," which is actually what you want.