EAV table to flat table - mysql

Say I have a table eav like this (SQL Fiddle):
| Person_ID | PAttribute_ID | Value |
| 1 | 1 | Flat Street 1 |
| 1 | 2 | 634-5789 |
And want to create a query that returns all attributes as a flat table (e.g. to export to a spreadsheet)
Is there a better way than just manually left joining for all the attributes? Like this:
SELECT id , address.Value AS adressV, telephone.Value as telephoneV
FROM person
LEFT JOIN eav AS address ON address.Person_ID = person.id AND address.PAttribute_ID = 1
LEFT JOIN eav AS telephone ON telephone.Person_ID = person.id AND telephone.PAttribute_ID = 2;
With 2 attributes that's feasible, with 50 attributes you get an un-understandable query.

Related

Having extra columns in join between 3 tables MySQL

I have 3 tables : Car, Client and Car_client the latter is a junction table between car and client, since as I said Car_Client is a junction table this means the relationship between car and client is many to many. Tables have this structure:
_____________________ ___________________ ______________________
| Car | | Client | | Car_Client |
|___________________| |_________________| |____________________|
| license_plate (PK)| | Name | | license_plate(fk) |
| Model | | Surname | | Id_Code(fk) |
|___________________| | Id_Code (PK) | |____________________|
| Phone |
|_________________|
Now, what I am trying to achieve is to allow the user to research the client by name. When the name is searched I want to show all the info about the car he owns and his personal info. So basically like a select * from Car, Client but just for a specific name.To achieve this I tried different methods, the one that works best, although not perfectly is this one :
SELECT * FROM
Car_Client car_cli
INNER JOIN Car ON ( car_cli.license_plate = car.license_plate)
INNER JOIN Client ON ( car_cli.Id_Code = Client.Id_Code)
WHERE
Car_Client.Id_Code in (SELECT Id_Code FROM Client WHERE Name = 'emanuele');
The problem with this solution is that I have two extra columns of license_plate and Id_Code
SELECT Client.*, Car.* FROM
Car_Client car_cli
INNER JOIN Car ON ( car_cli.license_plate = car.license_plate)
INNER JOIN Client ON ( car_cli.Id_Code = Client.Id_Code)
WHERE
Car_Client.Id_Code in (SELECT Id_Code FROM Client WHERE Name = 'emanuele');

In mysql how can I get only rows from one table which do not link to any rows in another table with a specific ID

I have two tables with the following structures (unnecessary columns trimmed out)
----------------- ---------------------
| mod_personnel | | mod_skills |
| | | |
| - prs_id | | - prs_id |
| - name | | - skl_id |
----------------- | |
---------------------
There may be 0 to many rows in the skills table for each prs_id
What I want is all the personnel records which do NOT have an associated skill record with skill_id 1.
In plain English "I want all the people who do not have the skill x".
Currently, I have only been able to do it with the following nested select. But I am hoping to find a faster way.
SELECT * FROM `mod_personnel` WHERE `prs_id` NOT IN (
SELECT `prs_id` FROM `mod_skills` WHERE `skl_id` = 1 )
This may be faster:
SELECT `mod_personnel`.*
FROM `mod_personnel`
left outer join `mod_skills`
on `mod_skills`.`prs_id` = `mod_personnel`.`prs_id`
and `mod_skills`.`skl_id` = 1
WHERE `mod_skills`.`prs_id` is null;
Using a NOT EXISTS might be faster.
SELECT *
FROM `mod_personnel` p
WHERE NOT EXISTS (SELECT *
FROM `mod_skills` s
WHERE s.`prs_id` = p.`prs_id`
AND s.`skl_id` = 1 );

join two tables in mysql and get records

I have two tables "contacts" and "users". Users table storing data with "," separated. Need to distinct data in "Contacts" column from "Contacts" table. And need to join with "Users" table, and get the records.
Contacts Table
--------------------------
id | user_Id | contats
--------------------------
1 | 2147483647 | 90123456789,90123456789,90123456789,90123456789
2 | 2147483647 | 90123456789,90123456789,90123456789,90123456789
3 | 919444894154 | 90123456789,90123456789,90123456789,90123456789
Users Table
-----------------------------
id | username | email | phone
-----------------------------
1 | bhavan | bhavanram93#gmail.com | 90123456789
2 | bhavan | bhavanram93#gmail.com | 90123456789
3 | prince | prince#gmail.com | 1234567980
4 | bhavan | bhavanram93#gmail.com | 90123456789
5 | hello | hello#gmail.com | 1234567890
6 | bhavan | bhavanram93#gmail.com | 90123456789
Your table Contacts shouldn't be constructed this way.
Since you want 1 Users table containing all the data about a user, and 1 Contacts table containing links between different users, you'd rather do this kind of table structure :
Contacts table
id | user_id | contact_id
-------------------------
1 | 1 | 2
2 | 1 | 3
3 | 2 | 3
That'll allow you to do something like :
SELECT *
FROM Users
JOIN Contacts ON (Users.id = Contacts.contact_id)
WHERE Contacts.user_id = 1
Which will return all the data of the contacts of the user 1.
Your current structure is a huge ongoing mess, it's the opposite of being flexible.
You should restructure your db to a normalized format as Steve suggest.
But if you cant:
SELECT *
FROM Users
JOIN Contacts
ON CONCAT(',', Contacts.contacts, ',') like
CONCAT('%,', Users.phone, ',%')
WHERE Contacts.user_id = 1
the idea is you convert your contacts to
, <numbers> ,
,90123456789,90123456789,90123456789,90123456789,
and try to match with
%,90123456789,%
Note this approach cant use any index so will have bad performance with many
rows. if you are in the order of 1k-10k rows may be ok. More than that you need consider restructure your db.

Mysql: how to return value or empty string from column ids in table (multi table)

I'M trying to extract all information into my table, but I need to change id, when available, to the name into another table.
I have 1 table like that:
|------------------------------|
|-id-|-systems-|-remote-|-deco-|
| 1 | NULL | 3 | |
| 2 | 21 | NULL | 2 |
|-------------------------------
each column like "systems" / "remote" / "deco" refer to an id into another table
I know how to use INNER JOIN. But if I use that, I got an empty result because the value need to be appears into the others tables.
ex.:
SELECT qd.id,s.name as systems,r.name as remote, d.name as deco
FROM `quote_data` qd
INNER JOIN systems s ON qd.systems=s.id
INNER JOIN remote r ON qd.remote=r.id
INNER JOIN deco d ON qd.deco=d.id
I got empty result.
In the best words, I need to do something like:
|------------------------------|
|-id-|-systems-|-remote-|-deco-|
| 1 | | R42 | |
| 2 | GTV | | B21 |
|-------------------------------
Also, I use innoDB table
Any Idea how to fix that?

MySQL Intermediate-Level Table Relationship

Each row in Table_1 needs to have a relationship with one or more rows that might come from any number of other tables in the database (Table_X). So I set up an intermediate table (Table_2) where each row contains an id from Table_1, and the id from Table_X. It also has its own auto increment id since none of the relationships will be exclusive and therefore both the other ids will not be unique in the table.
My problem now is that when I retrieve the row from Table_1 and would like to see the information from each related row from Table_X, I don't know how to get it. At first I thought I could create a column for the exact name of Table_X for each row in Table_2 and have a second SELECT statement using that information, but I've been seeing inklings about things such as foreign keys and join statements that I think I need to get into. I'm just having trouble sorting it all out. Do I even need Table_2?
This probably isn't overly complicated, but I'm just getting into MySQL and this is the first real challenge I've encountered.
Edit to include requested information: If I understand correctly, I think I'm dealing with a many to many relationship. Table_3 has games; Table_1 has articles. An article can be about multiple games, and a game can also have multiple articles written about it. The only other possibly pertinent information I can see is that when a new article is made, every game that will be related to it is decided all at once. But the list of articles related to a given game can grow over time as more articles are written. That's probably not especially important, however.
If I understood correctly You are talking about one to many relationship in database (for example: one person can have multiple phone numbers), You can store data in two separate tables persons and phones.
Persons:
|person_id|person_name |person_age |
| 1 | Bodan Kustan| 28 |
Phones:
|phone_id |person_id |phone_number|
| 1 | 1 | 31337 |
| 2 | 1 | 370 |
Then you can execute query with Join:
SELLECT * FROM `persons`
LEFT JOIN `phones` ON `persons`.`person_id` = `phones`.`person_id`
WHERE `persons`.`person_id` = 1;
And it will return to You list of persons with phone numbers:
|person_id|person_name |person_age |phone_id |person_id |phone_number|
| 1 | Bodan Kustan| 28 | 1 | 1 | 31337 |
| 1 | Bodan Kustan| 28 | 2 | 1 | 370 |
Another possibility is Many to Many relationship (for example: Any person can love pizza, and pizza is not unique for that person), then You need third table to join tables together person_food
Persons:
|person_id|person_name |person_age |
| 1 | Bodan Kustan| 28 |
Food:
|food_id |food_name |
| 1 | meat |
| 2 | pizza |
Person_Food
|person_id |food_id |
| 1 | 2 |
Then you can execute query with Join:
SELLECT * FROM `persons`
LEFT JOIN `person_food` ON `person`.`person_id` = `person_food`.`person_id`
LEFT JOIN `food` ON `food`.`food_id` = `person_food`.`food_id`
WHERE `persons`.`person_id` = 1;
And it will return data from all tables:
|person_id|person_name |person_age |person_id |food_id |food_name |
| 1 | Bodan Kustan| 28 | 1 | 2 | pizza |
However sometimes you need to join n amount of tables to join, then You could use separate table to hold information about relation. My approach (I don't think it's the best) would be to store table name next to relation (for example split mobile phones and home phones into two separate tables):
Persons:
|person_id|person_name |person_age |
| 1 | Bodan Kustan| 28 |
Mobile_Phone:
|mobile_phone_id |mobile_phone_number |
| 1 | 31337 |
Home_Phone:
|home_phone_id |home_phone_number |
| 1 | 370 |
Person_Phone:
|person_id |related_id |related_column |related_table |
| 1 | 1 | mobile_phone_id | mobile_phone |
| 1 | 1 | home_phone_id | home_phone |
Then query middle table to get all relations:
SELECT * FROM person_phone WHERE person_id = 1
Then build dynamic query (pseudo code, not tested -- might not work):
foreach (results as result)
append_to_final_sql = "LEFT JOIN {related_table}
ON {related_table}.{related_column} = `person_phone`.`related_id`
AND `person_phone`.`related_table` = {related_table}"
final_sql = "SELECT * FROM `persons` "
+ append_to_final_sql +
" WHERE `persons`.`person_id` = 1"
So Your final SQL would be:
SELECT * FROM `persons`
LEFT JOIN `person_phone` ON `person_phone`.`person_id` = `person`.`person_id`
LEFT JOIN `mobile_phone` ON `mobile_phone`.`mobile_phone_id` = `person_phone`.`related_id` AND `person_phone`.`related_table` = 'mobile_phone'
LEFT JOIN `home_phone` ON `home_phone`.`home_phone_id` = `person_phone`.`related_id` AND `person_phone`.`related_table` = 'home_phone'
You only need Table2 if entries in Table_x can be related to multiple rows in Table1 - otherwise a simple key for Table1 will suffice.
Look into joins - very powerful, flexible and fast.
select * from Table1 left join Table2 on Table1_id = Table2_table_1_id
left join Table_X on Tablex_id = Table2_table_x_id
Look at the output and you'll see that it returns all table_x rows with copies of the Table1 and Table2 fields.