MYSQL - calculate values based on other ID [closed] - mysql

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ItemID Quantity CustID
1 1 1000
6 1 1000
7 2 1000
2 12 1001
3 24 1001
4 16 1001
2 1 1002
how should I calculate the quantity based on each custID purchased?
i.e.
CustID Quantity
1000 4

For a particular customer ID you can use
select custid, sum(quantity)
from table_name
where custid=1000
Or for all customer id's you can use
select custid, sum(quantity)
from table_name
group by custid
Fiddle

Seems like a simple SUM:
SELECT CustID,SUM(Quantity) as Quantity
FROM TableName
GROUP BY CustID
You need to learn more about aggregate functions. Read more here.

Related

How to sum all visits from mySQL and show it for each id like a group? [closed]

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My mySQL look like this
id visits
3 0
3 0
3 1
4 1
4 1
4 0
2 1
How can I have something more like group for all my entries id :
id visits
3 1
4 2
2 1
Use this query:
SELECT ID, SUM(visits) as visit FROM YOURTABLE GROUP BY ID;
SQLFIDDEL is here.
Use Group By Clause
SELECT ID, SUM(Visits) FROM YOURTABLE GROUP BY ID;

MySql query to count song votes in music chart [closed]

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This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 9 years ago.
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I have 4 tables for a music voting site.
Songs -id.
Charts - id.
Chart_song - id, song_id, chart_id. (join table)
votes - id, song_id_fk, chart_id_fk.
I want to count how many votes each song has for a particular chart (id = 4)
Here is how the vote table looks when people vote for a song (id = 1) to chart id (4)
id | song_id_fk | chart_id_fk |
1 | 1 | 4 |
2 | 1 | 4 |
Hopefully u understand. Please help. If I pass 'WHERE chart_id_fk = 4', I want to get a count of 2 for song_id_fk = 1.
I guess you are looking for something like
select count(*) as vote_count, song_id_fk, chart_id_fk from votes group by song_id_fk, chart_id_fk

How to select different columns as a list? [closed]

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I have a database like this:
column1 column2 column3
15 21 19
17 12 13
15 24 14
Now I want to get a list of every single number like this:
x value
1 15
2 21
3 19
4 17
5 12
...
Thank you!
Try this:
SELECT (#auto:=#auto+1) AS num, val
FROM (SELECT column1 AS val
FROM tableA
UNION
SELECT column2 AS val
FROM tableA
UNION
SELECT column3 AS val
FROM tableA
) AS A, (SELECT #auto:=0) AS B

A Tricky SQL query [closed]

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Closed 9 years ago.
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I have this table with 2 columns of interest: ID, Memo_No plus some other columns.
ID is primary key of int type and auto-increment. Memo_No. is also int.
I need query, such that if memo no. is occuring only once in the table, the ID associated with it have to be selected.Plus, if same Memo has two different ID's, ID which is greater has to be selected.
For example i have table like this:
ID || Memo_No
1 2
2 3
3 4
4 5
5 4
6 6
7 2
From above table, I want to select rows whose ID's are 2,4,5,6,7 .
Thanks.
This is quite easy as an aggregation:
select max(id), memo_no
from t
group by memo_no;

How to get counts of occurrences from two tables [closed]

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I have two tables: Items and Things. Items has_many things
Items
id name
---- -----
1 Item1
2 Item2
Things
id name item_id
---- ----- -----------
1 thing1 1
2 thing2 1
3 thing3 1
4 thing6 2
5 thing7 6
6 thing6 2
I would like a result back mathing all rows from items with things and getting count based on item_id
id name count
--- ---- ------
1 item1 3
2 item2 2
Try this:
SELECT i.id,i.name,count(*)
FROM items i
INNER JOIN things t ON t.item_id = i.id
GROUP BY i.id, i.name
ORDER BY i.id