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I have 4 tables for a music voting site.
Songs -id.
Charts - id.
Chart_song - id, song_id, chart_id. (join table)
votes - id, song_id_fk, chart_id_fk.
I want to count how many votes each song has for a particular chart (id = 4)
Here is how the vote table looks when people vote for a song (id = 1) to chart id (4)
id | song_id_fk | chart_id_fk |
1 | 1 | 4 |
2 | 1 | 4 |
Hopefully u understand. Please help. If I pass 'WHERE chart_id_fk = 4', I want to get a count of 2 for song_id_fk = 1.
I guess you are looking for something like
select count(*) as vote_count, song_id_fk, chart_id_fk from votes group by song_id_fk, chart_id_fk
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I have a table as follows:
name week effort
quentin 1 1
quentin 1 2
quentin 2 1
tracy 1 1
joe 2 2
There will only be a handful of unique names so it doesn't need to be dynamic
And I would like to query it to return something like
week QuentinEffortSum TracyEffortSum JoeEffortSum
1 3 1 0
2 1 0 2
I have tried something along the lines of
SELECT SUM(Effort) AS JoeEffort, Min (Week) AS week FROM [Group$]
WHERE name = "Joe"
GROUP BY week
ORDER By week
which returned:
week JoeEffort
1 3
2 1
and now I need the other columns and imagine in involves joins but am not sure how to complete the task
Please help
Thanks
I think a PIVOT table would work, like so:
SELECT *
FROM (
SELECT
week,name,effort
FROM [Group$]
) as s
PIVOT
(
SUM(effort)
FOR [name] IN ('quentin','joe','tracy')
)AS pvt
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My mySQL look like this
id visits
3 0
3 0
3 1
4 1
4 1
4 0
2 1
How can I have something more like group for all my entries id :
id visits
3 1
4 2
2 1
Use this query:
SELECT ID, SUM(visits) as visit FROM YOURTABLE GROUP BY ID;
SQLFIDDEL is here.
Use Group By Clause
SELECT ID, SUM(Visits) FROM YOURTABLE GROUP BY ID;
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ItemID Quantity CustID
1 1 1000
6 1 1000
7 2 1000
2 12 1001
3 24 1001
4 16 1001
2 1 1002
how should I calculate the quantity based on each custID purchased?
i.e.
CustID Quantity
1000 4
For a particular customer ID you can use
select custid, sum(quantity)
from table_name
where custid=1000
Or for all customer id's you can use
select custid, sum(quantity)
from table_name
group by custid
Fiddle
Seems like a simple SUM:
SELECT CustID,SUM(Quantity) as Quantity
FROM TableName
GROUP BY CustID
You need to learn more about aggregate functions. Read more here.
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I have this table with 2 columns of interest: ID, Memo_No plus some other columns.
ID is primary key of int type and auto-increment. Memo_No. is also int.
I need query, such that if memo no. is occuring only once in the table, the ID associated with it have to be selected.Plus, if same Memo has two different ID's, ID which is greater has to be selected.
For example i have table like this:
ID || Memo_No
1 2
2 3
3 4
4 5
5 4
6 6
7 2
From above table, I want to select rows whose ID's are 2,4,5,6,7 .
Thanks.
This is quite easy as an aggregation:
select max(id), memo_no
from t
group by memo_no;
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I have two tables: Items and Things. Items has_many things
Items
id name
---- -----
1 Item1
2 Item2
Things
id name item_id
---- ----- -----------
1 thing1 1
2 thing2 1
3 thing3 1
4 thing6 2
5 thing7 6
6 thing6 2
I would like a result back mathing all rows from items with things and getting count based on item_id
id name count
--- ---- ------
1 item1 3
2 item2 2
Try this:
SELECT i.id,i.name,count(*)
FROM items i
INNER JOIN things t ON t.item_id = i.id
GROUP BY i.id, i.name
ORDER BY i.id