Missing records from one table in SQL Server 2008R2 - sql-server-2008

Question

Table 1:
Date PlacementID CampaignID Impressions
04/01/2014 100 10 1000
04/01/2014 101 10 1500
04/01/2014 100 11 500
Table 2:
Date PlacementID CampaignID Cost
04/01/2014 100 10 5000
04/01/2014 101 10 6000
04/01/2014 100 11 7000
04/01/2014 103 10 8000
When I have joined this table using Full Join and Left Join statement, I am not able to get uncommon record which is last row in table2 that display PlacementID 103 and campaignID 10 and Cost 8000. However I have searched all raw data and file but this missing records are not common between two sources. However, I want to include this records in final table. How can I do that? This two table are two different source and I have got results only common records.
Moreover, when I found out that missing value is exact value that are required in final figure so want to include every thing. I am including my SQL script below:
SELECT A.palcementid,
A.campaignid,
A.date,
Sum(A.impressions) AS Impressions,
Sum(CASE
WHEN C.placement_count > 1 THEN ( B.cost / C.placement_count )
ELSE B.cost
END) AS Cost
FROM table1 A
FULL JOIN table2 B
ON A.placementid = B.placementid
AND A.campaignid = B.campaignid
AND A.date = B.date
LEFT JOIN (SELECT Count(A.placementid) AS Placement_Count,
placementid. campaignid,
date
FROM table1
GROUP BY placementid,
campaignid,
date) c
ON A.placementid = C.placementid
AND A.campaignid = C.campaignid
AND A.date = C.date
GROUP BY A.placementid,
A.campaignid,
A.date
I am dividing Cost by placement because in source the cost was allocated for one placement only and one time so I have to divide those because in actual table the same Placementid repeat more than 1 times on same date.

Answer 1

As you didn't provide any expected output I guessing here but if the result you want is this:
PlacementID CampaignID Date Impressions Cost
----------- ----------- ----------------------- ----------- -----------
100 10 2014-04-01 02:00:00.000 1000 5000
100 11 2014-04-01 02:00:00.000 500 7000
101 10 2014-04-01 02:00:00.000 1500 6000
103 10 2014-04-01 02:00:00.000 NULL 8000
Then the following query should do it:
SELECT COALESCE(A.PlacementID,b.placementid) AS PlacementID,
COALESCE(A.campaignid, b.campaignid) AS CampaignID,
COALESCE(A.date, b.date) AS [Date],
SUM(A.impressions) AS Impressions,
SUM(CASE
WHEN C.placement_count > 1 THEN ( B.cost / C.placement_count )
ELSE B.cost
END ) AS Cost
FROM table1 A
FULL JOIN table2 B
ON A.[PlacementID] = B.placementid
AND A.campaignid = B.campaignid
AND A.date = B.date
LEFT JOIN (SELECT COUNT(PlacementID) AS Placement_Count,
placementid, campaignid,
date
FROM table1
GROUP BY placementid,
campaignid,
date) c
ON A.[PlacementID] = C.placementid
AND A.campaignid = C.campaignid
AND A.date = C.date
GROUP BY COALESCE(A.PlacementID, B.PlacementID),
COALESCE(A.campaignid, b.campaignid),
COALESCE(A.date, b.date)
Sample SQL Fiddle