So I intend to Query data for a couple of charts in MySQL,
The data for the charts come from the same table, but work for multiple Time ranges. So group by doesn't work.
The Date itself I want in the format
Total Oranges Mangoes Bananas Tomatoes
----------------------------------------------
19 5 6 7 1
24 3 7 2 12
14 3 4 5 2
20 5 7 6 2
Now, I can get the Initial row using either
SELECT
sum(CASE WHEN Some_Criteria and (created between '2016-03-28' AND '2016-03-29')) THEN 1 ELSE 0 END ) Total ,
sum(CASE WHEN Some_Other_Criteria and (created between '2016-03-28' AND '2016-03-29')) THEN 1 ELSE 0 END ) Oranges
...
from SomeTable.Table1
left join OtherTable ON SomeId = OtherId
OR via
SELECT
(SELECT count(distinct Field) FROM from SomeTable.Table1 left join OtherTable ON SomeId = OtherId WHERE SomeCriteria and (DateRange)) AS Total
(SELECT count(distinct Field) FROM from SomeTable.Table1 left join OtherTable ON SomeId = OtherId WHERE SomeCriteria and (DateRange)) AS Oranges
...
Getting it in the same row would be easy as I just use the above method, but what if I want the data to be in multiple rows but based on the different date ranges?
You'll need those date ranges in a resultset (either a subquery, a temporary table, or a permanent table of some sort). Once you have that you can use your first query with a JOIN to your ranges table and then using GROUP BY on those ranges.
For example:
SELECT
DR.start_date,
DR.end_date,
SUM(CASE WHEN Some_Criteria AND (created BETWEEN DR.start_date AND DR.end_date)) THEN 1 ELSE 0 END ) Total,
SUM(CASE WHEN Some_Other_Criteria AND (created BETWEEN DR.start_date AND DR.end_date)) THEN 1 ELSE 0 END ) Oranges,
...
FROM
Date_Ranges DR
INNER JOIN SomeTable.Table1 T1 ON
T1.created >= DR.start_date AND
T1.created < DR.end_date
LEFT OUTER JOIN OtherTable OT ON OT.SomeId = T1.OtherId
GROUP BY
DR.start_date,
DR.end_date
Related
Below is my table let's call account
**ID accountID score tracking_date
1 1 3 2014-09-25 00:01:05
2 2 4 2014-09-26 01:05:18
3 1 6 2014-09-27 09:23:05
4 2 9 2014-09-28 20:01:05
5 1 1 2014-09-28 23:21:34
6 3 7 2014-09-21 00:01:00
7 2 1 2014-09-22 01:45:24
8 2 9 2014-09-27 14:01:43
9 3 1 2014-09-24 22:01:27
I want to select record with max date and also the difference of score with the records having tracking_date as minimum for that accountId. So I want output like below
ID accountID score_with_maxdate diff_score_with_mindate max_tracking_date
1 1 1 -2 2014-09-28 23:21:34
2 2 9 8 2014-09-28 20:01:05
3 3 1 -6 2014-09-24 22:01:27
Any help?
Here is one option. We can self-join a subquery which finds both the min and max tracking dates, for each account, twice to your original table. This will bring in all metadata for those max tracking date records, including the scores.
SELECT
t1.accountID,
t2.score AS score_with_maxdate,
t2.score - t3.score AS diff_score_with_mindate,
t1.max_tracking_date
FROM
(
SELECT
accountID,
MAX(tracking_date) AS max_tracking_date,
MIN(tracking_date) AS min_tracking_date
FROM yourTable
GROUP BY accountID
) t1
INNER JOIN yourTable t2
ON t1.accountId = t2.accountID AND t2.tracking_date = t1.max_tracking_date
INNER JOIN yourTable t3
ON t1.accountId = t3.accountID AND t3.tracking_date = t1.min_tracking_date
ORDER BY
t1.accountID;
Demo
This is a somewhat tricky question. I think conditional aggregation is a convenient way to solve the problem:
select min(t.id) as id, t.accountId,
max(case when t.tracking_date = t2.max_td then t.score end) as score_with_maxdate,
max(case when t.tracking_date = t2.max_td then t.score
when t.tracking_date = t2.min_td then - t.score
end) as diff_score_with_mindate,
max(t.tracking_date) as max_tracking_date
from t join
(select t2.accountId, min(t2.tracking_date) as min_td, max(t2.tracking_date) as max_td
from t t2
group by t2.accountId
) t2
on t.accountId = t2.accountId
group by t.accountId;
Another hackish way of getting same results by using aggregate and string fucntion
select t.accountID,
t.score_with_maxdate,
t.score_with_maxdate - t.score_with_mindate score_with_maxdate,
t.max_tracking_date
from(
select accountID,
substring_index(group_concat(score order by tracking_date desc),',', 1) + 0 score_with_maxdate,
substring_index(group_concat(score order by tracking_date asc),',', 1) + 0 score_with_mindate,
max(tracking_date) max_tracking_date
from demo
group by accountID
) t
Demo
But i would suggest you to go with other solutions mentioned by Tim & Gordon
I have been stuck in a recent problem with a SQL Query. What I'm trying to archieve is to get each product in the store and show how many of them has been sold each month. However, sometimes there are some months where these products were not sold, which means they won't be displayed.
For instance, this is the result I'm getting right now
Article Month Sold
CN140027 6 312
CN140027 7 293
CN140027 12 122
CN140186 1 10
CN140186 4 2
While I want to get something more like this
Article Month Sold
CN140027 6 312
CN140027 7 293
CN140027 8 0
CN140027 9 0
CN140027 10 0
CN140027 11 0
CN140027 12 122
CN140186 1 10
CN140186 2 0
CN140186 3 0
CN140186 4 2
And here is the query I'm using at the moment
SELECT k.artikelnr, Months.datefield as `Months`, IFNULL(SUM(k.menge),0) as `Quantity`
FROM store_shop_korb as k LEFT OUTER JOIN office_calendar AS Months
ON Months.datefield = month(k.date_insert)
WHERE k.date_insert BETWEEN "2014-12-01" AND "2015-12-31"
group by k.artikelnr, Months.datefield
What am I missing? Or what am I doing wrong? Any help is really appreciated.
Thanks in advance.
EDIT:
Additional information:
office_calendar is the calendar table. It only contains the months as registry, from 1 to 12.
Additionally, I'm taking the article/product ID from a table called 'store_shop_korb', which contains all the lines of a made order (so it contains the article ID, its price, the quantity for each order..)
This works for me:
SELECT k.artikelnr, c.datefield AS `Month`, COALESCE(s.Quantity, 0) AS Sold
FROM (
SELECT artikelnr
FROM store_shop_korb
GROUP BY artikelnr
) k
JOIN office_calendar c
LEFT JOIN (
SELECT artikelnr, MONTH(date_insert) AS monthfield, SUM(menge) AS Quantity
FROM store_shop_korb
GROUP BY artikelnr, MONTH(date_insert)
) s ON k.artikelnr = s.artikelnr AND c.datefield = s.monthfield
ORDER BY k.artikelnr, c.datefield
If you have a table of articles, you can use it in the place of subquery k. I'm basically normalizing on the fly.
Explanation:
There's basically 3 sets of data that get joined. The first is a distinct set of articles (k), the second is a distinct set of months (c). These two are joined without restriction, meaning you get the cartesian product (every article x every month). This result is then left-joined to the sales per month (s) so that we don't lose 0 entries.
Add another where condition , i think it will solve your problem
SELECT k.artikelnr, Months.datefield as `Months`, IFNULL(SUM(k.menge),0) as `Quantity`
FROM store_shop_korb as k LEFT OUTER JOIN office_calendar AS Months
ON Months.datefield = month(k.date_insert)
WHERE IFNULL(SUM(k.menge),0)>0 AND k.date_insert BETWEEN "2014-12-01" AND "2015-12-31"
group by k.artikelnr, Months.datefield
I have tried this in MSAccess and it seems to work OK
SELECT PRODUCT, CALENDAR.MONTH, A
FROM CALENDAR LEFT JOIN (
SELECT PRODUCT, MONTH(SALEDTE) AS M, SUM(SALEAMOUNT) AS A
FROM SALES
WHERE SALEDTE BETWEEN #1/1/2015# AND #12/31/2015#
GROUP BY PRODUCT, MONTH(SALEDTE) ) AS X
ON X.M = CALENDAR.MONTH
If you already have a calender table then use this.
SELECT B.Article,
A.Month,
COALESCE(c.Sold, 0)
FROM (SELECT DISTINCT Months.datefield --Considering this as months feild
FROM office_calendar AS Months) A
CROSS JOIN (SELECT DISTINCT article
FROM Yourtable) B
LEFT OUTER JOIN Yourtable C
ON a.month = c.Month
AND b.Article = c.Article
Else you need a months table. Try this.
SELECT *
FROM (SELECT 1 AS month UNION
SELECT 2 UNION
SELECT 3 UNION
SELECT 4 UNION
SELECT 5 UNION
SELECT 6 UNION
SELECT 7 UNION
SELECT 8 UNION
SELECT 9 UNION
SELECT 10 UNION
SELECT 11 UNION
SELECT 12) A
CROSS JOIN (SELECT DISTINCT article
FROM Yourtable) B
LEFT OUTER JOIN Yourtable C
ON a.month = c.Month
AND b.Article = c.Article
Table 1:
Date PlacementID CampaignID Impressions
04/01/2014 100 10 1000
04/01/2014 101 10 1500
04/01/2014 100 11 500
Table 2:
Date PlacementID CampaignID Cost
04/01/2014 100 10 5000
04/01/2014 101 10 6000
04/01/2014 100 11 7000
04/01/2014 103 10 8000
When I have joined this table using Full Join and Left Join statement, I am not able to get uncommon record which is last row in table2 that display PlacementID 103 and campaignID 10 and Cost 8000. However I have searched all raw data and file but this missing records are not common between two sources. However, I want to include this records in final table. How can I do that? This two table are two different source and I have got results only common records.
Moreover, when I found out that missing value is exact value that are required in final figure so want to include every thing. I am including my SQL script below:
SELECT A.palcementid,
A.campaignid,
A.date,
Sum(A.impressions) AS Impressions,
Sum(CASE
WHEN C.placement_count > 1 THEN ( B.cost / C.placement_count )
ELSE B.cost
END) AS Cost
FROM table1 A
FULL JOIN table2 B
ON A.placementid = B.placementid
AND A.campaignid = B.campaignid
AND A.date = B.date
LEFT JOIN (SELECT Count(A.placementid) AS Placement_Count,
placementid. campaignid,
date
FROM table1
GROUP BY placementid,
campaignid,
date) c
ON A.placementid = C.placementid
AND A.campaignid = C.campaignid
AND A.date = C.date
GROUP BY A.placementid,
A.campaignid,
A.date
I am dividing Cost by placement because in source the cost was allocated for one placement only and one time so I have to divide those because in actual table the same Placementid repeat more than 1 times on same date.
As you didn't provide any expected output I guessing here but if the result you want is this:
PlacementID CampaignID Date Impressions Cost
----------- ----------- ----------------------- ----------- -----------
100 10 2014-04-01 02:00:00.000 1000 5000
100 11 2014-04-01 02:00:00.000 500 7000
101 10 2014-04-01 02:00:00.000 1500 6000
103 10 2014-04-01 02:00:00.000 NULL 8000
Then the following query should do it:
SELECT COALESCE(A.PlacementID,b.placementid) AS PlacementID,
COALESCE(A.campaignid, b.campaignid) AS CampaignID,
COALESCE(A.date, b.date) AS [Date],
SUM(A.impressions) AS Impressions,
SUM(CASE
WHEN C.placement_count > 1 THEN ( B.cost / C.placement_count )
ELSE B.cost
END ) AS Cost
FROM table1 A
FULL JOIN table2 B
ON A.[PlacementID] = B.placementid
AND A.campaignid = B.campaignid
AND A.date = B.date
LEFT JOIN (SELECT COUNT(PlacementID) AS Placement_Count,
placementid, campaignid,
date
FROM table1
GROUP BY placementid,
campaignid,
date) c
ON A.[PlacementID] = C.placementid
AND A.campaignid = C.campaignid
AND A.date = C.date
GROUP BY COALESCE(A.PlacementID, B.PlacementID),
COALESCE(A.campaignid, b.campaignid),
COALESCE(A.date, b.date)
Sample SQL Fiddle
I have example data
ID DAY ORDER TIME PRODUCT
1 1 1 1 1
2 1 1 1 2
3 1 1 1 3
4 1 2 2 1
5 1 2 2 2
6 1 2 2 3
7 1 2 *3* 1
8 1 2 *3* 2
9 1 2 *3* 3
I want to prevent to having mltiple orders in different time at same day. if I set unique index on DAY,ORDER,TIME I will not be able to insert multiple time anyway, but I want to disable multiple different TIME. Is this possible with mysql?
Have can I find all records where there multiple different TIME value in same DAY and ORDER and delete them?
in this case I would like to delete records 7,8 ad 9 with SQL query because it is duplicate ORDER inserted.
I don't want to normalize table I will stick with this database structure.
Thank you very much
You can use delete with a join clause to find the duplicates and delete them:
delete
from t join
(select day, "order", min(time) as tokeeptime
from t
group by day, "order"
) tokeep
on t.day = tokeep.day and t."order" = tokeep."order" and t.time <> tokeeptime;
DELETE a
FROM tableName a
INNER JOIN
(
SELECT a.DAY, a.ORDER, MAX(a.TIME) Time
FROM tableName a
GROUP BY a.DAY, a.ORDER
HAVING COUNT(DISTINCT TIME) > 1
) b ON a.DAY = b.DAY AND
a.Order = b.Order AND
a.Time = b.Time
SQLFiddle Demo
I have a table that keeps record of targets assigned to different employees for different products for each month and it has a status field which keeps record of whether assigned target had been approved or not.
status - 1>>Pending, 2>>Approved
Eg:
pdt_id month emp_id status
1 04 1 2
2 04 2 2
3 04 3 1
1 05 1 2
2 05 2 2
3 05 3 2
Now I want to generate a report which shows the only the month for which there are no pending approvals. i.e from the above data the report should only show '05' because its the only month in which all the request have been approved
if i provide condition select month where status='2' it will fetch both 04 and 05 but i want to fetch only 05 ...
Plea
SELECT month
FROM myTable
WHERE month NOT IN (
SELECT month
FROM myTable
WHERE status = 1
)
LEFT JOIN the table onto itself to find out matches and eliminate them.
SELECT
t1.`month`
FROM
your_table AS t1
LEFT JOIN your_table AS t2
ON t1.`month` = t2.`month`
AND t2.`status` = 1
WHERE t2.month IS NULL
GROUP BY t1.month
There might be more elegant ways of doing this, but it gets the job done.
Months with Approved statuses only:
SELECT DISTINCT month
FROM myTable a
WHERE NOT EXISTS
( SELECT *
FROM myTable b
WHERE a.month = b.month
AND b.status <> 2
)
Months without any Pending:
SELECT DISTINCT month
FROM myTable a
WHERE NOT EXISTS
( SELECT *
FROM myTable b
WHERE a.month = b.month
AND b.status = 1
)
There are usually 3 ways to do this kind of problem, (using NOT EXISTS, using NOT IN and using LEFT JOIN with NULL check). You already have answers for the other 2 ways.
In this special case, there's another (4th) way. If you never plan to add more statuses than the 1 and 2, this will also work:
SELECT month
FROM myTable
GROUP BY month
HAVING MIN(status) = 2
Just a final comment/question. Do you only store month in the table, and not year? Because if you also have a year field, the query will not show correct results, once you have data from more than one year in the table.
You can just select months that don't have state Pending:
select month from table_name as tb1 where 0 = (select count(*) from table_name as tb2 where tb2.state = '1' AND tb1.month = tb2.month)
I dont understand why dont you do?
... WHERE month = "05" AND status = 2;
and if you have another concept which is "approved" why not add it as a column and include it in the query as well?
Sometimes fixing a thing means redesigning your tables.