Showing data by ignoring the time portion from the date - mysql

Question

I am using JasperReports/iReport to do my report. I have wrote a query for the client to key in the date,but there is 1 issue, the date is come along with the time portion.
How can I ignore the time portion for the client to key in the data?
date rate
2/2/2014 12:56:21.0000 PM ABC
4/2/2014 12:56:21.0000 PM EFG
5/2/2014 12:56:21.0000 PM HIJ
...
I have assign from customer to design with the parameter of year,month, and day.In other words, when the customer key in the year,month,and day,
the data will show this way:
2/2/2014 12:56:21.0000 PM ABC
The query i have wrote is show below:
select date,rate
from mytable
where rownum=1
and tran_dt<=(select date
from mytable
where year(date)=$P{year}
and month(date)=$P{month}
and day(date)=$P{day}
)
order by
date
I'm using pl/sql query...

Answer 1

SQL SERVER :
Use This
select convert(varchar(10), '2011-02-25 21:17:33.933', 120)
Like This
Select DATE_FORMAT(date,'%y-%m-%d'),rate from mytable
where rownum=1 and tran_dt<=(select tran_dt from bi01_trandetail where
year(date)=$P{year} and month(tran_dt)=$P{month} and day(tran_dt)=$P{day})
order by date
MYSQL
USE
DATE_FORMAT(date,'%y-%m-%d')
Select DATE_FORMAT(date,'%y-%m-%d'),rate from mytable
where rownum=1 and tran_dt<=(select tran_dt from bi01_trandetail where
year(date)=$P{year} and month(tran_dt)=$P{month} and day(tran_dt)=$P{day})
order by date
OR
SELECT DATE('2003-12-31 01:02:03');
'2003-12-31'
Select date(date),rate from mytable
where rownum=1 and tran_dt<=(select tran_dt from bi01_trandetail where
year(date)=$P{year} and month(tran_dt)=$P{month} and day(tran_dt)=$P{day})
order by date
Your New Query:
select date,rate
from mytable
where rownum=1
and tran_dt<=(select DATE_FORMAT(date,'%y-%m-%d')
from mytable
where year(date)=$P{year}
and month(date)=$P{month}
and day(date)=$P{day}
)
order by
date
MYSQL DATE FUNCTION

Answer 2

You have to ways, from the DDBB...
With PL/SQL check the TO_CHAR doc, http://www.techonthenet.com/oracle/functions/to_char.php, (and this SO question, ;D: How to format a Date variable in PLSQL).
Your query will be:
SELECT TO_CHAR(date, 'MM/DD/YYYY'), rate from mytable ...
With MySQL (NOTE: I leave the MySQL answer because I answered first with it because it wasn't specified RMDB)
MySQL DATE_FORMAT function, getting only what you want:
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_date-format
from the web as example:
SELECT DATE_FORMAT('2009-10-04 22:23:00', '%W %M %Y');
-> 'Sunday October 2009'
Testing the case you proposed:
SELECT DATE_FORMAT('2014-03-02 23:45:35', '%e/%c/%y %H:%i:%s %p');
-> 2/3/14 23:45:35 PM
With no time portion:
SELECT DATE_FORMAT('2014-03-02 23:45:35', '%e/%c/%y');
-> 2/3/14
Your query will be:
select DATE_FORMAT(date, '%e/%c/%y') ,rate from mytable ...
... and the other way is with the date functions from your server scripts, but that is another history and I'd need what language you use, XD

Answer 3

Thank you all for the reply, i have found the way to solved this question.
Let i share the query,
select rate,trunc(date) as EFFDT from mytable
Where rownum=1
and
date <= to_date(:DAY||'/'||:MTH||'/'||:YR, 'DD/MM/YYYY')
order by date desc