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I am trying to put together a report that shows what search criteria a user used.
Right now it is basic and uses SELECT DISTINCT and then GROUP BY.
The problem is we would like to see this broken down by words too. The phrase criteria is useful but we would like to see:
Searches:
red apples are good
yellow bananas are bad
bad apples are not bananas
pears are not red
What we would like to see:
red 2
apples 2
are 4
good 1
yellow 1
bananas 2
bad 2
pears 1
not 2
I should note too that we have too me search terms to go through and write seperate %LIKE statements for them - and they change.
try this example
SELECT word,COUNT(*) as count
FROM
(SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(CONCAT(searches,' '),' ',value.v),' ',-1) as word
FROM yourtable,(SELECT 1 as v UNION
SELECT 2 UNION
SELECT 3 UNION
SELECT 4 UNION
SELECT 5)value
)T
WHERE word != ''
GROUP BY word
sqlFiddle
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I have a table as follows:
name week effort
quentin 1 1
quentin 1 2
quentin 2 1
tracy 1 1
joe 2 2
There will only be a handful of unique names so it doesn't need to be dynamic
And I would like to query it to return something like
week QuentinEffortSum TracyEffortSum JoeEffortSum
1 3 1 0
2 1 0 2
I have tried something along the lines of
SELECT SUM(Effort) AS JoeEffort, Min (Week) AS week FROM [Group$]
WHERE name = "Joe"
GROUP BY week
ORDER By week
which returned:
week JoeEffort
1 3
2 1
and now I need the other columns and imagine in involves joins but am not sure how to complete the task
Please help
Thanks
I think a PIVOT table would work, like so:
SELECT *
FROM (
SELECT
week,name,effort
FROM [Group$]
) as s
PIVOT
(
SUM(effort)
FOR [name] IN ('quentin','joe','tracy')
)AS pvt
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My mySQL look like this
id visits
3 0
3 0
3 1
4 1
4 1
4 0
2 1
How can I have something more like group for all my entries id :
id visits
3 1
4 2
2 1
Use this query:
SELECT ID, SUM(visits) as visit FROM YOURTABLE GROUP BY ID;
SQLFIDDEL is here.
Use Group By Clause
SELECT ID, SUM(Visits) FROM YOURTABLE GROUP BY ID;
Ok so I'm trying to do the following. I have a table that has questions and answers. I'm trying to figure out how many answers I have of each answer on each question.
Question Answer
-------- ------
What is your favorite color? Blue
What is your favorite color? Red
What is your favorite color? Blue
What is your age? 12
What is your age? 15
Now what I want is results (query) to output something like this:
What is your favorite color? Blue 2
What is your favorite color? Red 1
What is your age? 12 1
What is your age? 15 1
OR
What is your favorite color? 2 1
What is your age? 1 1
In the last part...I would know what those values mean based on the query.
SELECT t.Question,
t.Answer,
COUNT(*) AS 'Count'
FROM YourTable AS t
GROUP BY t.Question,
t.Answer
The answer to the second question involves count(distinct):
select t.Question, count(distinct t.Answer) as NumAnswers,
count(*) as NumAnswered
from table t
group by t.Question;
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ItemID Quantity CustID
1 1 1000
6 1 1000
7 2 1000
2 12 1001
3 24 1001
4 16 1001
2 1 1002
how should I calculate the quantity based on each custID purchased?
i.e.
CustID Quantity
1000 4
For a particular customer ID you can use
select custid, sum(quantity)
from table_name
where custid=1000
Or for all customer id's you can use
select custid, sum(quantity)
from table_name
group by custid
Fiddle
Seems like a simple SUM:
SELECT CustID,SUM(Quantity) as Quantity
FROM TableName
GROUP BY CustID
You need to learn more about aggregate functions. Read more here.
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I have this table with 2 columns of interest: ID, Memo_No plus some other columns.
ID is primary key of int type and auto-increment. Memo_No. is also int.
I need query, such that if memo no. is occuring only once in the table, the ID associated with it have to be selected.Plus, if same Memo has two different ID's, ID which is greater has to be selected.
For example i have table like this:
ID || Memo_No
1 2
2 3
3 4
4 5
5 4
6 6
7 2
From above table, I want to select rows whose ID's are 2,4,5,6,7 .
Thanks.
This is quite easy as an aggregation:
select max(id), memo_no
from t
group by memo_no;