I'm trying to select all the data from the previous month to all the months in the future .. for example , I'd like to select everything from January till any date available in the future on the database, that goes for any month .. select the previous month till the future months of this year
This is my QUERY, It only starts with February , how can I make it start with the previous month .. current month - 1 is not working
SELECT *
FROM events
WHERE YEAR(event_start_date) = YEAR(CURDATE())
AND MONTH(event_start_date) = MONTH(CURDATE())
use DATE_SUB() to select previous month and >= to select all data in the future:
SELECT *
FROM events
WHERE YEAR(event_start_date) = YEAR(CURDATE())
AND MONTH(event_start_date) >= MONTH(DATE_SUB( CURDATE(), INTERVAL 1 MONTH))
Try:
AND MONTH(event_start_date) = MONTH(DATE_SUB(CURDATE(), INTERVAL 1 MONTHS))
The portion DATE_SUB(CURDATE(), INTERVAL 1 MONTH) will subtract a month from the current date. If you want last month and everything in the future, use:
AND MONTH(event_start_date) >= MONTH(DATE_SUB(CURDATE(), INTERVAL 1 MONTHS))
Notice '>='. Although there is an edge case at january that you'll have to get around. The best way might be like this:
WHERE event_start_date >= DATE_SUB(DATE_SUB(CURDATE(), INTERVAL 1 MONTHS), (DAYOFMONTH(CURDATE)) DAYS)
Which will get you everything from the 1st of last month. No edge cases.
Try this
SELECT *
FROM events
WHERE YEAR(event_start_date) = YEAR(CURDATE())
AND MONTH(event_start_date) >= MONTH(CURDATE() - INTERVAL 1 MONTH);
SELECT *
FROM events
WHERE event_start_date >= '1/'+MONTH(DATE_SUB( CURDATE(), INTERVAL 1 MONTH))+'/'+YEAR(DATE_SUB( CURDATE(), INTERVAL 1 MONTH))
For performance, you'd likely want an index range scan operation on the event_start_date column. That means (obviously), you'd want an index with event_start_date as a leading column.
To get an index range scan, the predicate needs to be on the bare event_start_date column, and NOT a function.
WHERE event_start_date >= some_value
For "some_value" in this case, one possible expression you can use would be:
CAST(DATE_FORMAT(NOW()+INTERVAL -1 MONTH ,'%Y-%m-01') AS DATE)
That takes the current date and time, subtracts one month, and then sets the day and time component to midnight of the first of the month.
Related
I have the following mysql query which shows the each day's total cash sale for the current week.
SELECT
sum(Price) as totalprice,
WEEKDAY(CreatedOn) as dayno,
DATE(CreatedOn) as CreatedOn,
AgentID
FROM records
WHERE CreatedOn BETWEEN (CURDATE()-WEEKDAY(CURDATE())) AND CURDATE()
GROUP BY DATE(CreatedOn)
When I run the query it looks like this:
There are records on 30th November(today's date). So,
day 0 (Monday) no cash sale
day 1 (Tuesday) $5049
day 2 (Wednsday) $99
Nothing is displayed for day 3 (Thursday/today). I cannot figure out the reason there are definitely record in the database but cannot get them to be displayed. I would appreciate any help.
CURDATE() is today's date but at 00:00:00+0000000
"push up" the higher date by 1 day and avoid using between for date/time ranges:
WHERE CreatedOn >= date_sub(CURDATE(), INTERVAL WEEKDAY(CURDATE()) DAY)
AND CreatedOn < date_add(CURDATE(), INTERVAL 1 DAY)
select date_sub(CURDATE(), INTERVAL WEEKDAY(CURDATE()) DAY)
, date_add(CURDATE(), INTERVAL 1 DAY)
The condition in the query currently specifies on or before midnight today, so any rows for today after midnight are going to be excluded.
I think you are intending to specify CreatedOn before midnight of the following day.
I also suggest you don't subtract an integer value from a date/datetime, and instead use the INTERVAL syntax
WHERE CreatedOn >= CURDATE() - INTERVAL WEEKDAY(CURDATE()) DAY
AND CreatedOn < CURDATE() + INTERVAL 1 DAY
To test those expressions before we include them in a query, we can run a SELECT statement:
SELECT CURDATE() - INTERVAL WEEKDAY(CURDATE()) DAY
, CURDATE() + INTERVAL 1 DAY
and verify that those expressions are returning what we expect, the values we want to use. For testing, we can replace CURDATE() with a date value to test the return for days other than today.
I am trying to introduce a new column for my query, it currently counts sum of expenses in this month, the new column should display last months expences. I am not quite sure where to place it.
SELECT cat.id_kat,
cat.nazwa,
coalesce(exp.tot, 0) AS PriceTotal
FROM wydatki_kategorie cat
LEFT JOIN
(SELECT wydatki_wpisy.kategoria,
sum(wydatki_wpisy.brutto) AS tot
FROM wydatki_wpisy
LEFT JOIN wydatki ON wydatki_wpisy.do_wydatku = wydatki.id_wydatku
WHERE MONTH(wydatki.data_zakupu) = MONTH(CURRENT_DATE())
AND wydatki.id_kupujacy = 1
GROUP BY wydatki_wpisy.kategoria) exp ON cat.id_kat = exp.kategoria
Possibly might be needed ( if I'm not wrong ) - Where clause for the previous month.
wydatki.data_zakupu >= DATE_ADD(LAST_DAY(DATE_SUB(NOW(), INTERVAL 2 MONTH)), INTERVAL 1 DAY) AND
wydatki.data_zakupu<= DATE_SUB(NOW(), INTERVAL 1 MONTH)
SQL Fiddle example
Two things.
First, if you stop using WHERE MONTH(wydatki.data_zakupu) = MONTH(CURRENT_DATE()) to choose your dates you'll get three benefits.
Your date searching will become sargable: an index will speed it up.
You'll get a more general scheme for choosing months.
If you have multiple years' worth of data in your tables, things will work better.
Instead, in general use this sort of expression to search for the present month. You already figured out most of this.
WHERE wydatki.data_zakupu >= LAST_DAY(CURRENT_DATE()) + INTERVAL 1 DAY - INTERVAL 1 MONTH
AND wydatki.data_zakupu < LAST_DAY(CURRENT_DATE()) + INTERVAL 1 DAY - INTERVAL 0 MONTH
This looks for all datetime values on or after midnight at the first day of the present month, and before, but not on <, midnight at the first day of next month.
It generalizes to any month you want. For example,
WHERE wydatki.data_zakupu >= LAST_DAY(CURRENT_DATE()) + INTERVAL 1 DAY - INTERVAL 2 MONTH
AND wydatki.data_zakupu < LAST_DAY(CURRENT_DATE()) + INTERVAL 1 DAY - INTERVAL 1 MONTH
gets you last month. This also works when the current month is January, and it works when you have multiple years' worth of data in your tables.
These expressions are a little verbose because MySQL doesn't have a FIRST_DAY(date) function, only a LAST_DAY(date) function. So we need all that + INTERVAL 1 DAY monkey business.
Second, pulling out a previous month's data is as simple as adding another LEFT JOIN ( SELECT... clause to your table, like so. (http://sqlfiddle.com/#!9/676df4/13)
SELECT ...
coalesce(month1.tot, 0) AS LastMonth
FROM wydatki_kategorie cat
LEFT JOIN
...
LEFT JOIN
(SELECT wydatki_wpisy.kategoria,
sum(wydatki_wpisy.brutto) AS tot
FROM wydatki_wpisy
LEFT JOIN wydatki ON wydatki_wpisy.do_wydatku = wydatki.id_wydatku
WHERE wydatki.data_zakupu >= LAST_DAY(CURRENT_DATE()) + INTERVAL 1 DAY - INTERVAL 2 MONTH
AND wydatki.data_zakupu < LAST_DAY(CURRENT_DATE()) + INTERVAL 1 DAY - INTERVAL 1 MONTH
AND wydatki.id_kupujacy = 1
GROUP BY wydatki_wpisy.kategoria
) month1 ON cat.id_kat = month1.kategoria
As you can see, the date range WHERE clause here gets the previous month's rows.
I have a table containing data about events and festivals with following columns recording their start and end dates.
Start_Date
End_Date
date format is in YYYY-MM-DD. I need to fetch event details with the following condition.
Need to fetch all events which start with a current month and there end dates can be anything say currentDate+next30days.
I am clear about end date concept. but not sure how I can fetch data whose start dates are in a current month.
For this, I need to compare current year and current month against the Start_Date column in my database.
Can anyone help me to point out as how I can do that?
select * from your_table
where year(Start_Date) = year(curdate())
and month(Start_Date) = month(curdate())
and end_date <= curdate() + interval 30 day
I don't like either of the other two answers, because they do not let the optimizer use an index on start_date. For that, the functions need to be on the current date side.
So, I would go for:
where start_date >= date_add(curdate(), interval 1 - day(curdate()) day) and
start_date < date_add(date_add(curdate(), interval 1 - day(curdate()) day), interval 1 month)
All the date functions are on curdate(), which does not affect the ability of MySQL to use an index in this case.
You can also include the condition on end_date:
where (start_date >= date_add(curdate(), interval 1 - day(curdate()) day) and
start_date < date_add(date_add(curdate(), interval 1 - day(curdate()) day), interval 1 month)
) and
end_date <= date_add(curdate(), interval 30 day)
This can still take advantage of an index.
DateTime functions are your friends:
SELECT
*
FROM
`event`
WHERE
(MONTH(NOW()) = MONTH(`Start_Date`))
AND
(`End_Date` <= (NOW() + INTERVAL 30 DAY))
AND
(YEAR(NOW()) = YEAR(`Start_Date`))
Comparing the year and month separately feels messy. I like to contain it in one line. I doubt it will make a noticeable difference in performance, so its purely personal preference.
select * from your_table
where LAST_DAY(Start_Date) = LAST_DAY(curdate())
and end_date <= curdate() + interval 30 day
So all I'm doing is using the last_day function to check the last day of the month of each date and then comparing this common denominator. You could also use
where DATE_FORMAT(Start_Date ,'%Y-%m-01') = DATE_FORMAT(curdate(),'%Y-%m-01')
I have a table with a timestamp field. How do I get data from the last 3 months?
In particular, March is my current month let say, 03/2012. I need to return records from the months March, February, and January only.
3 months before today:
select * from table where timestamp >= now()-interval 3 month;
Start with first of month:
select * from table where timestamp >= last_day(now()) + interval 1 day - interval 3 month;
To get the first day of the current month, you could use this:
DATE_FORMAT(CURDATE(), '%Y-%m-01')
if current date is 2013-03-13, it will return 2013-03-01, and we can just substract 2 months from this date to obtain 2013-01-01. Your query could be like this:
SELECT *
FROM yourtable
WHERE data >= DATE_FORMAT(CURDATE(), '%Y-%m-01') - INTERVAL 2 MONTH
I know this is an old question, but to possibly save others time and to sum the above answers up for the case of needing (1) dates from current month and (2) dates from the prior 2 months (common when displaying data statistics):
WHERE ((timestamp >= NOW() - DATE_FORMAT(CURDATE(), '%Y-%m-01'))
OR (timestamp >= DATE_FORMAT(CURDATE(), '%Y-%m-01') - INTERVAL 2 MONTH))
Assuming you're using SQL Server (Oracle, MySQL and others have similar date functions), you can use the dateadd function to add or subtract an interval to the current date.
If you want a full three months, you can subtract 3 months from today : DATEADD(m,-3,getdate())
But, as you state, you only want data from January, February and March. You have to make some calculation based on today's date: dateadd(m,-2, CONVERT(datetime, CONVERT(VARCHAR(2), MONTH(getdate())) + '/01/' + CONVERT(VARCHAR(4), YEAR(getdate()))))
And in the end, get a query like
SELECT fields
FROM table
WHERE timestampfield > DATEADD(m,-2, CONVERT(datetime, CONVERT(VARCHAR(2), MONTH(getdate())) + '/01/' + CONVERT(VARCHAR(4), YEAR(getdate()))))
--- edit ---
erf, I just noticed the "mysql" tag... you can get more information on MySQL date functions here : https://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html
Another possibility would be:
SELECT * WHERE your_date_column > LAST_DAY(CURRENT_DATE - INTERVAL 3 MONTH);
Use this code here to get the previous 3 months from a certain date
SELECT * FROM table WHERE date_column>= DATE_FORMAT(current_date(), '%Y-%m-01') - INTERVAL 3 MONTH and date_column< DATE_FORMAT(current_date(), '%Y-%m-01')
WHERE ((timestamp >= NOW() - DATE_FORMAT(CURDATE(), '%Y-%m-01'))
OR (timestamp >= DATE_FORMAT(CURDATE(), '%Y-%m-01') - INTERVAL 2 MONTH))
I need to select data from MySQL database between the 1st day of the current month and current day.
select*from table_name
where date between "1st day of current month" and "current day"
Can someone provide working example of this query?
select * from table_name
where (date between DATE_ADD(LAST_DAY(DATE_SUB(CURDATE(), interval 30 day), interval 1 day) AND CURDATE() )
Or better :
select * from table_name
where (date between DATE_FORMAT(NOW() ,'%Y-%m-01') AND NOW() )
I was looking for a similar query where I needed to use the first day of a month in my query.
The last_day function didn't work for me but DAYOFMONTH came in handy.
So if anyone is looking for the same issue, the following code returns the date for first day of the current month.
SELECT DATE_SUB(CURRENT_DATE, INTERVAL DAYOFMONTH(CURRENT_DATE)-1 DAY);
Comparing a date column with the first day of the month :
select * from table_name where date between
DATE_SUB(CURRENT_DATE, INTERVAL DAYOFMONTH(CURRENT_DATE)-1 DAY) and CURRENT_DATE
select * from table_name
where `date` between curdate() - dayofmonth(curdate()) + 1
and curdate()
SQLFiddle example
I have used the following query. It has worked great for me in the past.
select date(now()) - interval day(now()) day + interval 1 day
try this :
SET #StartDate = DATE_SUB(DATE(NOW()),INTERVAL (DAY(NOW())-1) DAY);
SET #EndDate = ADDDATE(CURDATE(),1);
select * from table where (date >= #StartDate and date < #EndDate);
Complete solution for mysql current month and current year, which makes use of indexing properly as well :)
-- Current month
SELECT id, timestampfield
FROM table1
WHERE timestampfield >= DATE_SUB(CURRENT_DATE, INTERVAL DAYOFMONTH(CURRENT_DATE)-1 DAY)
AND timestampfield <= LAST_DAY(CURRENT_DATE);
-- Current year
SELECT id, timestampfield
FROM table1
WHERE timestampfield >= DATE_SUB(CURRENT_DATE, INTERVAL DAYOFYEAR(CURRENT_DATE)-1 DAY)
AND timestampfield <= LAST_DAY(CURRENT_DATE);
select * from table
where date between
(date_add (CURRENT_DATE, INTERVAL(1 - DAYOFMonth(CURRENT_DATE)) day)) and current_date;
select * from <table>
where <dateValue> between last_day(curdate() - interval 1 month + interval 1 day)
and curdate();
I found myself here after needing this same query for some Business Intelligence Queries I'm running on an e-commerce store. I wanted to add my solution as it may be helpful to others.
set #firstOfLastLastMonth = DATE_SUB(LAST_DAY(DATE_ADD(NOW(), INTERVAL -2 MONTH)),INTERVAL DAY(LAST_DAY(DATE_ADD(NOW(), INTERVAL -2 MONTH)))-1 DAY);
set #lastOfLastLastMonth = LAST_DAY(DATE_ADD(NOW(), INTERVAL -2 MONTH));
set #firstOfLastMonth = DATE_SUB(LAST_DAY(DATE_ADD(NOW(), INTERVAL -1 MONTH)),INTERVAL DAY(LAST_DAY(DATE_ADD(NOW(), INTERVAL -1 MONTH)))-1 DAY);
set #lastOfLastMonth = LAST_DAY(DATE_ADD(NOW(), INTERVAL -1 MONTH));
set #firstOfMonth = DATE_ADD(#lastOfLastMonth, INTERVAL 1 DAY);
set #today = CURRENT_DATE;
Today is 2019-10-08 so the output looks like
#firstOfLastLastMonth = '2019-08-01'
#lastOfLastLastMonth = '2019-08-31'
#firstOfLastMonth = '2019-09-01'
#lastOfLastMonth = '2019-09-30'
#firstOfMonth = '2019-10-01'
#today = '2019-10-08'
A less orthodox approach might be
SELECT * FROM table_name
WHERE LEFT(table_name.date, 7) = LEFT(CURDATE(), 7)
AND table_name.date <= CURDATE();
as a date being between the first of a month and now is equivalent to a date being in this month, and before now. I do feel that this is a bit easier on the eyes than some other approaches, though.
SELECT date_sub(current_date(),interval dayofmonth(current_date())-1 day) as first_day_of_month;
I had some what similar requirement - to find first day of the month but based on year end month selected by user in their profile page.
Problem statement - find all the txns done by the user in his/her financial year. Financial year is determined using year end month value where month can be any valid month - 1 for Jan, 2 for Feb, 3 for Mar,....12 for Dec.
For some clients financial year ends on March and some observe it on December.
Scenarios - (Today is `08 Aug, 2018`)
1. If `financial year` ends on `July` then query should return `01 Aug 2018`.
2. If `financial year` ends on `December` then query should return `01 January 2018`.
3. If `financial year` ends on `March` then query should return `01 April 2018`.
4. If `financial year` ends on `September` then query should return `01 October 2017`.
And, finally below is the query. -
select #date := (case when ? >= month(now())
then date_format((subdate(subdate(now(), interval (12 - ? + month(now()) - 1) month), interval day(now()) - 2 day)) ,'%Y-%m-01')
else date_format((subdate(now(), interval month(now()) - ? - 1 month)), '%Y-%m-01') end)
where ? is year end month (values from 1 to 12).
The key here is to get the first day of the month. For that, there are several options. In terms of performance, our tests show that there isn't a significant difference between them - we wrote a whole blog article on the topic. Our findings show that what really matters is whether you need the result to be VARCHAR, DATETIME, or DATE.
The fastest solution to the real problem of getting the first day of the month returns VARCHAR:
SELECT CONCAT(LEFT(CURRENT_DATE, 7), '-01') AS first_day_of_month;
The second fastest solution gives a DATETIME result - this runs about 3x slower than the previous:
SELECT TIMESTAMP(CONCAT(LEFT(CURRENT_DATE, 7), '-01')) AS first_day_of_month;
The slowest solutions return DATE objects. Don't believe me? Run this SQL Fiddle and see for yourself 😊
In your case, since you need to compare the value with other DATE values in your table, it doesn't really matter what methodology you use because MySQL will do the conversion implicitly even if your formula doesn't return a DATE object.
So really, take your pick. Which is most readable for you? I'd pick the first since it's the shortest and arguably the simplest:
SELECT * FROM table_name
WHERE date BETWEEN CONCAT(LEFT(CURRENT_DATE, 7), '-01') AND CURDATE;
SELECT * FROM table_name
WHERE date BETWEEN DATE(CONCAT(LEFT(CURRENT_DATE, 7), '-01')) AND CURDATE;
SELECT * FROM table_name
WHERE date BETWEEN (LAST_DAY(CURRENT_DATE) + INTERVAL 1 DAY - INTERVAL 1 MONTH) AND CURDATE;
SELECT * FROM table_name
WHERE date BETWEEN (DATE(CURRENT_DATE) - INTERVAL (DAYOFMONTH(CURRENT_DATE) - 1) DAY) AND CURDATE;
SELECT * FROM table_name
WHERE date BETWEEN (DATE(CURRENT_DATE) - INTERVAL (DAYOFMONTH(CURRENT_DATE)) DAY + INTERVAL 1 DAY) AND CURDATE;
SELECT * FROM table_name
WHERE date BETWEEN DATE_FORMAT(CURRENT_DATE,'%Y-%m-01') AND CURDATE;
I used this one
select DATE_ADD(DATE_SUB(LAST_DAY(now()), INTERVAL 1 MONTH),INTERVAL 1 day) first_day
,LAST_DAY(now()) last_day, date(now()) today_day
All the responses here have been way too complex. You know that the first of the current month is the current date but with 01 as the date. You can just use YEAR() and MONTH() to build the month date by inputting the NOW() method.
Here's the solution:
select * from table_name
where date between CONCAT_WS('-', YEAR( NOW() ), MONTH( NOW() ), '01') and DATE( NOW() )
CONCAT_WS() joins a series of strings with a separator (a dash in this case).
So if today is 2020-08-28, YEAR( NOW() ) = '2020' and MONTH( NOW() ) = '08' and then you just need to append '01' at the end.
Voila!
Get first date and last date from month and year.
select LAST_DAY(CONCAT(year,'.',month,'.','01')) as registerDate from user;
select date_add(date_add(LAST_DAY(end_date),interval 1 DAY),interval -1 MONTH) AS closingDate from user;
SET #date:='2012-07-11';
SELECT date_add(date_add(LAST_DAY(#date),interval 1 DAY),
interval -1 MONTH) AS first_day