I read how I can query between two dates here, but I'm trying to do the opposite. I have a database of events, with start days and end days. I'm trying to check to see if now() is between any start days AND end days.
Of note, my events are cyclical so I don't care about the years. To use the data format in my database I just use 2000 for everything. I have events such as the Christmas season (2000-12-01 to 2000-12-25), Independence Day (2000-06-25 to 2000-07-04), and so forth.
At first I was thinking about doing something like:
SELECT * FROM `table` WHERE MONTH(NOW()) >= MONTH(`start`) AND DATE(NOW()) >= DATE(`start`) AND MONTH(NOW()) <= MONTH(`end`) AND DATE(NOW()) <= DATE(`end`)
But then I realized a major flaw in periods of time that span multiple months. If today is 27JUN then I'd like the Independence Day row to return, but while 27 >= 25, 27 <= 4 is not the case.
I was thinking of seeing if I can convert NOW(), start, and end to a timestamp to allow me to compare them, but discounted the idea because I might have something with a start date of 2000-12-26 and an end date of 2000-01-01 (remembering that I'm ignoring the year).
Is there a better way to store month/date pairs instead of dates? Or what can I do to fix my database query?
The current date has to be adjusted back to year 2000 before comparing to start and end dates. If the end date is before start date, the year of the end date is actually the year after the start date. Try this:
SELECT * from `table`
WHERE
(`end` >= `start` AND
DATE_ADD(CURDATE(), INTERVAL 2000-YEAR(CURDATE()) YEAR)
BETWEEN `start` AND `end`)
OR
(`end` < `start` AND
DATE_ADD(CURDATE(), INTERVAL 2000-YEAR(CURDATE()) YEAR)
BETWEEN `start` and DATE_ADD(`end`, INTERVAL 1 YEAR))
OR:
SELECT * from `table`
WHERE
CASE
WHEN `end` >= `start` THEN
DATE_ADD(CURDATE(), INTERVAL 2000-YEAR(CURDATE()) YEAR) BETWEEN `start` AND `end`
ELSE
DATE_ADD(CURDATE(), INTERVAL 2000-YEAR(CURDATE()) YEAR) BETWEEN `start` and DATE_ADD(`end`, INTERVAL 1 YEAR)
END
Use CURDATE() instead of NOW() cos NOW() has the time component that is not needed.
SELECT * FROM table WHERE CURDATE() between dateStart and dateEnd
where dateStart is your past date and dateEnd is your future date
I have the following mysql query which shows the each day's total cash sale for the current week.
SELECT
sum(Price) as totalprice,
WEEKDAY(CreatedOn) as dayno,
DATE(CreatedOn) as CreatedOn,
AgentID
FROM records
WHERE CreatedOn BETWEEN (CURDATE()-WEEKDAY(CURDATE())) AND CURDATE()
GROUP BY DATE(CreatedOn)
When I run the query it looks like this:
There are records on 30th November(today's date). So,
day 0 (Monday) no cash sale
day 1 (Tuesday) $5049
day 2 (Wednsday) $99
Nothing is displayed for day 3 (Thursday/today). I cannot figure out the reason there are definitely record in the database but cannot get them to be displayed. I would appreciate any help.
CURDATE() is today's date but at 00:00:00+0000000
"push up" the higher date by 1 day and avoid using between for date/time ranges:
WHERE CreatedOn >= date_sub(CURDATE(), INTERVAL WEEKDAY(CURDATE()) DAY)
AND CreatedOn < date_add(CURDATE(), INTERVAL 1 DAY)
select date_sub(CURDATE(), INTERVAL WEEKDAY(CURDATE()) DAY)
, date_add(CURDATE(), INTERVAL 1 DAY)
The condition in the query currently specifies on or before midnight today, so any rows for today after midnight are going to be excluded.
I think you are intending to specify CreatedOn before midnight of the following day.
I also suggest you don't subtract an integer value from a date/datetime, and instead use the INTERVAL syntax
WHERE CreatedOn >= CURDATE() - INTERVAL WEEKDAY(CURDATE()) DAY
AND CreatedOn < CURDATE() + INTERVAL 1 DAY
To test those expressions before we include them in a query, we can run a SELECT statement:
SELECT CURDATE() - INTERVAL WEEKDAY(CURDATE()) DAY
, CURDATE() + INTERVAL 1 DAY
and verify that those expressions are returning what we expect, the values we want to use. For testing, we can replace CURDATE() with a date value to test the return for days other than today.
I'm trying to select all the data from the previous month to all the months in the future .. for example , I'd like to select everything from January till any date available in the future on the database, that goes for any month .. select the previous month till the future months of this year
This is my QUERY, It only starts with February , how can I make it start with the previous month .. current month - 1 is not working
SELECT *
FROM events
WHERE YEAR(event_start_date) = YEAR(CURDATE())
AND MONTH(event_start_date) = MONTH(CURDATE())
use DATE_SUB() to select previous month and >= to select all data in the future:
SELECT *
FROM events
WHERE YEAR(event_start_date) = YEAR(CURDATE())
AND MONTH(event_start_date) >= MONTH(DATE_SUB( CURDATE(), INTERVAL 1 MONTH))
Try:
AND MONTH(event_start_date) = MONTH(DATE_SUB(CURDATE(), INTERVAL 1 MONTHS))
The portion DATE_SUB(CURDATE(), INTERVAL 1 MONTH) will subtract a month from the current date. If you want last month and everything in the future, use:
AND MONTH(event_start_date) >= MONTH(DATE_SUB(CURDATE(), INTERVAL 1 MONTHS))
Notice '>='. Although there is an edge case at january that you'll have to get around. The best way might be like this:
WHERE event_start_date >= DATE_SUB(DATE_SUB(CURDATE(), INTERVAL 1 MONTHS), (DAYOFMONTH(CURDATE)) DAYS)
Which will get you everything from the 1st of last month. No edge cases.
Try this
SELECT *
FROM events
WHERE YEAR(event_start_date) = YEAR(CURDATE())
AND MONTH(event_start_date) >= MONTH(CURDATE() - INTERVAL 1 MONTH);
SELECT *
FROM events
WHERE event_start_date >= '1/'+MONTH(DATE_SUB( CURDATE(), INTERVAL 1 MONTH))+'/'+YEAR(DATE_SUB( CURDATE(), INTERVAL 1 MONTH))
For performance, you'd likely want an index range scan operation on the event_start_date column. That means (obviously), you'd want an index with event_start_date as a leading column.
To get an index range scan, the predicate needs to be on the bare event_start_date column, and NOT a function.
WHERE event_start_date >= some_value
For "some_value" in this case, one possible expression you can use would be:
CAST(DATE_FORMAT(NOW()+INTERVAL -1 MONTH ,'%Y-%m-01') AS DATE)
That takes the current date and time, subtracts one month, and then sets the day and time component to midnight of the first of the month.
I want to run a MYSQL query to get data for the previous week. The datatype for the date column is DATETIME. Could anyone suggest?
SELECT *
FROM calendar
WHERE dt BETWEEN CURDATE()-INTERVAL 1 WEEK AND CURDATE();
Here is an another version:
SELECT * FROM table WHERE
YEARWEEK(`date`, 1) = YEARWEEK( CURDATE() - INTERVAL 1 WEEK, 1)
SELECT id FROM tbl
WHERE date >= curdate() - INTERVAL DAYOFWEEK(curdate())+6 DAY
AND date < curdate() - INTERVAL DAYOFWEEK(curdate())-1 DAY
Here is the solution I find most reliable for getting data between the previus monday to the current monday. (That is what most people mean when the say past week, but not all, and that reflect in mysql).
SELECT
*
FROM
table
WHERE
date BETWEEN
(CURDATE() - INTERVAL 1 DAY) + INTERVAL -1 WEEK - INTERVAL WEEKDAY((CURDATE() - INTERVAL 1 DAY)) DAY
and
(CURDATE() - INTERVAL 1 DAY) + INTERVAL 0 WEEK - INTERVAL WEEKDAY((CURDATE() - INTERVAL 1 DAY)) DAY
It's also easy to change it for another week intervall
Make variable for current datetime - 1 week and make this query:
SELECT * FROM table WHERE date > $datatime
I need to select data from MySQL database between the 1st day of the current month and current day.
select*from table_name
where date between "1st day of current month" and "current day"
Can someone provide working example of this query?
select * from table_name
where (date between DATE_ADD(LAST_DAY(DATE_SUB(CURDATE(), interval 30 day), interval 1 day) AND CURDATE() )
Or better :
select * from table_name
where (date between DATE_FORMAT(NOW() ,'%Y-%m-01') AND NOW() )
I was looking for a similar query where I needed to use the first day of a month in my query.
The last_day function didn't work for me but DAYOFMONTH came in handy.
So if anyone is looking for the same issue, the following code returns the date for first day of the current month.
SELECT DATE_SUB(CURRENT_DATE, INTERVAL DAYOFMONTH(CURRENT_DATE)-1 DAY);
Comparing a date column with the first day of the month :
select * from table_name where date between
DATE_SUB(CURRENT_DATE, INTERVAL DAYOFMONTH(CURRENT_DATE)-1 DAY) and CURRENT_DATE
select * from table_name
where `date` between curdate() - dayofmonth(curdate()) + 1
and curdate()
SQLFiddle example
I have used the following query. It has worked great for me in the past.
select date(now()) - interval day(now()) day + interval 1 day
try this :
SET #StartDate = DATE_SUB(DATE(NOW()),INTERVAL (DAY(NOW())-1) DAY);
SET #EndDate = ADDDATE(CURDATE(),1);
select * from table where (date >= #StartDate and date < #EndDate);
Complete solution for mysql current month and current year, which makes use of indexing properly as well :)
-- Current month
SELECT id, timestampfield
FROM table1
WHERE timestampfield >= DATE_SUB(CURRENT_DATE, INTERVAL DAYOFMONTH(CURRENT_DATE)-1 DAY)
AND timestampfield <= LAST_DAY(CURRENT_DATE);
-- Current year
SELECT id, timestampfield
FROM table1
WHERE timestampfield >= DATE_SUB(CURRENT_DATE, INTERVAL DAYOFYEAR(CURRENT_DATE)-1 DAY)
AND timestampfield <= LAST_DAY(CURRENT_DATE);
select * from table
where date between
(date_add (CURRENT_DATE, INTERVAL(1 - DAYOFMonth(CURRENT_DATE)) day)) and current_date;
select * from <table>
where <dateValue> between last_day(curdate() - interval 1 month + interval 1 day)
and curdate();
I found myself here after needing this same query for some Business Intelligence Queries I'm running on an e-commerce store. I wanted to add my solution as it may be helpful to others.
set #firstOfLastLastMonth = DATE_SUB(LAST_DAY(DATE_ADD(NOW(), INTERVAL -2 MONTH)),INTERVAL DAY(LAST_DAY(DATE_ADD(NOW(), INTERVAL -2 MONTH)))-1 DAY);
set #lastOfLastLastMonth = LAST_DAY(DATE_ADD(NOW(), INTERVAL -2 MONTH));
set #firstOfLastMonth = DATE_SUB(LAST_DAY(DATE_ADD(NOW(), INTERVAL -1 MONTH)),INTERVAL DAY(LAST_DAY(DATE_ADD(NOW(), INTERVAL -1 MONTH)))-1 DAY);
set #lastOfLastMonth = LAST_DAY(DATE_ADD(NOW(), INTERVAL -1 MONTH));
set #firstOfMonth = DATE_ADD(#lastOfLastMonth, INTERVAL 1 DAY);
set #today = CURRENT_DATE;
Today is 2019-10-08 so the output looks like
#firstOfLastLastMonth = '2019-08-01'
#lastOfLastLastMonth = '2019-08-31'
#firstOfLastMonth = '2019-09-01'
#lastOfLastMonth = '2019-09-30'
#firstOfMonth = '2019-10-01'
#today = '2019-10-08'
A less orthodox approach might be
SELECT * FROM table_name
WHERE LEFT(table_name.date, 7) = LEFT(CURDATE(), 7)
AND table_name.date <= CURDATE();
as a date being between the first of a month and now is equivalent to a date being in this month, and before now. I do feel that this is a bit easier on the eyes than some other approaches, though.
SELECT date_sub(current_date(),interval dayofmonth(current_date())-1 day) as first_day_of_month;
I had some what similar requirement - to find first day of the month but based on year end month selected by user in their profile page.
Problem statement - find all the txns done by the user in his/her financial year. Financial year is determined using year end month value where month can be any valid month - 1 for Jan, 2 for Feb, 3 for Mar,....12 for Dec.
For some clients financial year ends on March and some observe it on December.
Scenarios - (Today is `08 Aug, 2018`)
1. If `financial year` ends on `July` then query should return `01 Aug 2018`.
2. If `financial year` ends on `December` then query should return `01 January 2018`.
3. If `financial year` ends on `March` then query should return `01 April 2018`.
4. If `financial year` ends on `September` then query should return `01 October 2017`.
And, finally below is the query. -
select #date := (case when ? >= month(now())
then date_format((subdate(subdate(now(), interval (12 - ? + month(now()) - 1) month), interval day(now()) - 2 day)) ,'%Y-%m-01')
else date_format((subdate(now(), interval month(now()) - ? - 1 month)), '%Y-%m-01') end)
where ? is year end month (values from 1 to 12).
The key here is to get the first day of the month. For that, there are several options. In terms of performance, our tests show that there isn't a significant difference between them - we wrote a whole blog article on the topic. Our findings show that what really matters is whether you need the result to be VARCHAR, DATETIME, or DATE.
The fastest solution to the real problem of getting the first day of the month returns VARCHAR:
SELECT CONCAT(LEFT(CURRENT_DATE, 7), '-01') AS first_day_of_month;
The second fastest solution gives a DATETIME result - this runs about 3x slower than the previous:
SELECT TIMESTAMP(CONCAT(LEFT(CURRENT_DATE, 7), '-01')) AS first_day_of_month;
The slowest solutions return DATE objects. Don't believe me? Run this SQL Fiddle and see for yourself 😊
In your case, since you need to compare the value with other DATE values in your table, it doesn't really matter what methodology you use because MySQL will do the conversion implicitly even if your formula doesn't return a DATE object.
So really, take your pick. Which is most readable for you? I'd pick the first since it's the shortest and arguably the simplest:
SELECT * FROM table_name
WHERE date BETWEEN CONCAT(LEFT(CURRENT_DATE, 7), '-01') AND CURDATE;
SELECT * FROM table_name
WHERE date BETWEEN DATE(CONCAT(LEFT(CURRENT_DATE, 7), '-01')) AND CURDATE;
SELECT * FROM table_name
WHERE date BETWEEN (LAST_DAY(CURRENT_DATE) + INTERVAL 1 DAY - INTERVAL 1 MONTH) AND CURDATE;
SELECT * FROM table_name
WHERE date BETWEEN (DATE(CURRENT_DATE) - INTERVAL (DAYOFMONTH(CURRENT_DATE) - 1) DAY) AND CURDATE;
SELECT * FROM table_name
WHERE date BETWEEN (DATE(CURRENT_DATE) - INTERVAL (DAYOFMONTH(CURRENT_DATE)) DAY + INTERVAL 1 DAY) AND CURDATE;
SELECT * FROM table_name
WHERE date BETWEEN DATE_FORMAT(CURRENT_DATE,'%Y-%m-01') AND CURDATE;
I used this one
select DATE_ADD(DATE_SUB(LAST_DAY(now()), INTERVAL 1 MONTH),INTERVAL 1 day) first_day
,LAST_DAY(now()) last_day, date(now()) today_day
All the responses here have been way too complex. You know that the first of the current month is the current date but with 01 as the date. You can just use YEAR() and MONTH() to build the month date by inputting the NOW() method.
Here's the solution:
select * from table_name
where date between CONCAT_WS('-', YEAR( NOW() ), MONTH( NOW() ), '01') and DATE( NOW() )
CONCAT_WS() joins a series of strings with a separator (a dash in this case).
So if today is 2020-08-28, YEAR( NOW() ) = '2020' and MONTH( NOW() ) = '08' and then you just need to append '01' at the end.
Voila!
Get first date and last date from month and year.
select LAST_DAY(CONCAT(year,'.',month,'.','01')) as registerDate from user;
select date_add(date_add(LAST_DAY(end_date),interval 1 DAY),interval -1 MONTH) AS closingDate from user;
SET #date:='2012-07-11';
SELECT date_add(date_add(LAST_DAY(#date),interval 1 DAY),
interval -1 MONTH) AS first_day