I have a table whose content like this :
If I use :
SELECT
DATE_FORMAT(tgl_kecelakaan,'%M') AS NamaBulan,
COUNT(DATE_FORMAT(tgl_kecelakaan,'%M')) AS total
FROM
tbl_kecelakaan_kapal
WHERE
DATE_FORMAT(tgl_kecelakaan,'%M')='January'
The result is : January 2
But how to keep my query produces output like this (count all data) :
January 2
February 1
Without should I include WHERE condition as above ??
Thanks
Try GROUP BY:
SELECT
DATE_FORMAT(tgl_kecelakaan,'%M') AS NamaBulan,
COUNT(1) AS total
FROM
tbl_kecelakaan_kapal
GROUP BY NamaBulan # or DATE_FORMAT(tgl_kecelakaan,'%M')
Related
I am attempting to plot data cumulatively from a MySQL table which logs a value, resetting to 0 every day. After selecting the values using select * from table where DateTime BETWEEN DateA AND DateB, the data looks like this: current data. I would like the output to look like this: preferred data, ignoring the daily resets.
As I am a novice in SQL I was unable to find a solution to this. I did, however, obtain the correct output in Matlab using a for loop:
output = data;
for k=1:(size(data, 1)-1)
% check if next value is smaller than current
if data(k+1)<data(k)
% add current value to all subsequent values
output = output + (1:size(data, 1)>k)'.*input(k);
end
end
I would like the final product to connect to a web page, so I am curious if it would be possible obtain a similar result using only SQL. While I have tried using SUM(), I have only been able to sum all values, but I need to add the last value each day to all subsequent values.
Using CTE and comparing dates, you can sum all values each date.
Let's say that table1 below is defined.
create table table1 (col_date date, col_value int);
insert into table1 values
('2020-07-15',1000),
('2020-07-15',2000),
('2020-07-16',1000),
('2020-07-16',3000),
('2020-07-16',4000),
('2020-07-17',1000),
('2020-07-18',2000),
('2020-07-19',1000),
('2020-07-19',1000),
('2020-07-19',2000),
('2020-07-19',3000),
('2020-07-20',4000),
('2020-07-20',5000),
('2020-07-21',6000)
;
In this case, the query looks like this:
with cte1 as (
select col_date, sum(col_value) as col_sum from table1
where col_date between '2020-07-16' and '2020-07-20'
group by col_date
)
select a.col_date, max(a.col_sum), sum(b.col_sum)
from cte1 a inner join cte1 b on a.col_date >= b.col_date
group by a.col_date;
The output is below:
col_date |max(a.col_sum) |sum(b.col_sum)
2020-07-16 |8000 | 8000
2020-07-17 |1000 | 9000
2020-07-18 |2000 |11000
2020-07-19 |7000 |18000
2020-07-20 |9000 |27000
The column of max() is just for reference.
I am trying to write a quarry in a module for Dolibarr ERP. But module hase a part of code that is predefined and can not be changed. And I need to insert a SUM() function in it that will combine rows with similar id. That i know how to do in a regular MySQL:
SELECT fk_product AS prod, SUM(value) AS qty
FROM llx_stock_mouvement
WHERE type_mouvement = 2 AND label LIKE 'SH%'
GROUP BY fk_product
ORDER BY 1 DESC
LIMIT 26
that gives me what I want :
prod qty
1 13
2 10
BUT module has a predefined unchangeable code :
this part is predefined module writes it himself based on values provider in it:
SELECT DISTINCT
c.fk_product AS com,
c.value AS qty
THIS PART I CAN WRITE IN A MODULES GUI:
FROM
llx_stock_mouvement AS c
WHERE
type_mouvement = 2
AND label LIKE 'SH%'
And this part is predefined:
ORDER BY 1 DESC
LIMIT 26
I would appreciate any help and advice on question is there any workaround that can be done to make my desired and result ampere ? As it would using the first code I posted ?
If you can only modify the bit in the middle box then you might need to use a subquery;
--fixed part
SELECT DISTINCT
c.fk_product AS com,
c.value AS qty
--begin your editable part
FROM
(
SELECT fk_product,
SUM(value) AS value
FROM llx_stock_mouvement
WHERE type_mouvement = 2 AND label LIKE 'SH%'
GROUP BY fk_product
) c
--end your editable part
--fixed part
ORDER BY 1
DESC
LIMIT 26
In my database I have a field named DateLastSaved:
Suppose the values are:
1. 2016-05-12 08:07:00,
2. 2016-05-22 09:06:00,
3. 2016-05-22 09:06:00,
4. 2016-06-13 09:00:00,
5. 2016-06-13 09:00:00
I wan't such query that would return me that row whose DateLastSaved field has the minimum month, in above case "5" and the maximum date of that month, which is 2, 3, but my query should return one result, i.e either 2 or 3.
I am using the following query:
SELECT MIN(LAST_DAY(DateLastSaved))FirstMonth
FROM InitialLog
WHERE FileName='Dr. Adam Kotowski Patient Names.doc'
But it is returning me the first date, that is, minimum, not the maximum one. Any suggestions?
Try this:
SELECT *
FROM InitialLog
WHERE MONTH(DateLastSaved) = (SELECT MIN(MONTH(DateLastSaved)) FROM InitialLog)
ORDER BY DAY(DateLastSaved) DESC LIMIT 1
Demo here
I have table rozpis_riesitelov which contains columns :
id_rozpisu_riesit, id_zam, id_projektu, id_ulohy.
I made query :
select id_zam, id_ulohy, count(*) as counted
from rozpis_riesitelov
group by id_zam
having id_ulohy in (1,2,8)
which shows me id of employee (id_zam) and how many times He was in project (id_ulohy is irrevelant but I had to select it beacuse of having clause). It shows me everyone in db but I am looking for employee with ID of 4 who is in 6 projects (Yes, I could do order by but I want to see max). When I do max of this query like this:
select max(counted)
from (select id_zam, id_ulohy, count(id_zam) as counted
from rozpis_riesitelov
group by id_zam
having id_ulohy in (1,2,8)) as riesitel
which shows me number 149 instead of 6.
So basically I only need to find employee that occurs in the most of the projects.
What's wrong with sorting by the COUNT() value, and limiting to one result?
SELECT `id_zam`,
`id_ulohy`,
COUNT(*) AS `counted`
FROM `rozpis_riesitelov `
WHERE `id_ulohy` IN ( 1, 2, 8 )
GROUP BY `id_zam`
ORDER BY `counted` DESC
LIMIT 1
Not sure exactly what you are trying to accomplish but you only use HAVING to filter on your aggregate like this:
HAVING COUNT(*) > 1
you should be able to move the condition to a WHERE clause and get correct max returned:
select max(counted)
from (select id_zam, count(id_zam) as counted
from rozpis_riesitelov
where id_ulohy in (1,2,8)
group by id_zam) as riesitel
I have for example a query with return something as it
route value
1 3
2 2
3 4
4 5
5 1
then I need to put in 2 textbox the max and the min route so in sql this would be
select top 1 route from table where value=(select max(value) from table)
I add a image done in excel, how this would be.
I believe this is so easy but I dont have idea how to get it.
I got using expression, this was extactly expression
="Route "+
Convert.ToString (
Lookup(max(fields!value.Value),fields!value.Value ,fields!route.Value,"mydataset")
)
changing max for min, for the other...
thanks everyone.
I believe the query you're looking for would be:
With Min_Max_CTE as (
Select MIN(value) as Min_Value
, MAX(value) as Max_Value
From Table
)
Select Top 1 'Min' as Type
, T.route
, T.value
From Table T
Inner Join Min_Max_CTE CTE
on T.value = CTE.Min_Value
Union All
Select Top 1 'Max' as Type
, T.route
, T.value
From Table T
Inner Join Min_Max_CTE CTE
on T.value = CTE.Max_Value
Order by Type desc --This will put the Min Route first followed by the Max Route
Then, put that query into a dataset, and then create a tablix and use the Type, route, and value fields to return the minimum route and the maximum route. It should end up being set up just like your excel section with the min and max routes above.
You can do this SSRS by using a couple of separate tables. Your example data:
And two tables in the Designer:
Since the tables only have header rows, only the first row in the table will be displayed.
To make sure we get the MAX and MIN values in the two tables, each table needs to order its Dataset appropriately, i.e. by Value by descending and ascending respectively.
MAX table:
MIN table:
Which gives your expected result: