How get results without grouping it?
My table
id user_id amount currency_id type status
5 2 2.00 1 0 0
6 3 3.00 1 0 0
4 1 1.00 1 0 0
7 4 4.00 1 0 0
8 5 3.00 1 1 0
I do the following select
SELECT id, user_id, amount, currency_id, SUM( amount )
FROM market
WHERE amount <=3
AND type = 0
AND status = 0
Result:
id user_id amount currency_id SUM( amount )
5 2 2.00 1 6.00
How get this result:
id user_id amount currency_id SUM( amount )
5 2 2.00 1 0 6.00
6 3 3.00 1 0 6.00
4 1 1.00 1 0 6.00
If your intent is to return individual records that meet this criteria AND sum them up and you don't actually need the SUM value as a field on every row (not sure why you would), then I would suggest looking at the GROUP BY ... WITH ROLLUP modifier. It works like this:
SELECT id, user_id, SUM(amount) AS `amounts`, currency_id
FROM market
WHERE amount <=3
AND type = 0
AND status = 0
GROUP BY id WITH ROLLUP
Here I am grouping by id because this will keep the individual records intact as this value is unique
You output would look like this:
id user_id amounts currency_id
5 2 2.00 1
6 3 3.00 1
4 1 1.00 1
NULL 3 6.00 1
Note the last record provides the rollup to the SUM() function. Also note that values for user_id and currency_id in the rollup row are indeterminate as they were not part of the GROUP BY or aggregation. As such, they have no meaning.
You can do join
SELECT id,
user_id,
amount,
currency_id,
a.totalAmount
FROM market
CROSS JOIN
(
SELECT SUM(amount) totalAmount
FROM market
WHERE amount <=3
AND type = 0
AND status = 0
) a
WHERE amount <=3
AND type = 0
AND status = 0
or using inline subquery,
SELECT id,
user_id,
amount,
currency_id,
(
SELECT SUM(amount) totalAmount
FROM market
WHERE amount <=3
AND type = 0
AND status = 0
) totalAmount
FROM market
WHERE amount <=3
AND type = 0
AND status = 0
Here you go:
SELECT id, user_id, amount, currency_id, t2.total
FROM market, (
SELECT SUM(amount) AS total
FROM market
WHERE amount <=3
AND type = 0
AND status = 0
) AS t2
WHERE amount <=3
AND type = 0
AND status = 0
Related
I have two table
ORDER
prod_id qty gst gst_rate
1 25 yes 18
1 25 no 0
2 10 yes 12
3 5 no 0
RETURN
prod_id add less gst_rate
1 5 0 0
1 10 0 18
3 0 2 0
About the table ORDER
Product 1 have order 25 with gst 18% and order 25 without gst. Product
2 have order 10 with gst 12%. Product 3 have order 5 without gst.
About the table Return
Product 1 without gst have extra qty 5. Product 1 with gst have extra
qty 10. Product 3 (no gst) have less qty 2. Product 2 have no extra or
less qty.
So I have to create a VIEW for each entry in ORDER table
Result should look like this
prod_id qty gst_rate add less
1 25 18 10 0
1 25 0 5 0
2 10 12 0 0
3 5 0 0 2
What I tried is:
SELECT ord.prod_id, ord.qty, ord.gst_rate, ret.add, ret.less FROM order ord LEFT JOIN (SELECT case when ord.gst='no' then (select sum(add) from return,order where order.prod_id=return.prod_id and return.gst_rate=0) else (select sum(add) from return,order where order.prod_id=return.prod_id and return.gst_rate!=0) end as add FROM return) as ret ON ret.prod_id=ord.prod_id
But it is not working..
you query could be refactored avoiding subquery ..
SELECT ord.prod_id, ord.qty, ord.gst_rate,
case when rd.gst='no' then t1.sum_add else t2.sum_add end as add
FROM order ord
LEFT JOIN (
select prod_id, sum(add) as sum_add
from return
INNER JOIN order ON order.prod_id=return.prod_id and return.gst_rate=0
GROUP BY prod_id
) t1 on t1.prod_id = ord.prod_id
LEFT JOIN (
select prod_id, sum(add) as sum_add
from return
INNER JOIN order ON order.prod_id=return.prod_id and return.gst_rate!=0
GROUP BY prod_id
) t2 on t2.prod_id = ord.prod_id
(the less was not in you code so i have omitted by select )
Hi I have two tables one is product and next is price table
Product Table
Id Name
1 Bike
2 Car
3 Van
Price Table
Id Price Pid
1 100 1
2 150 1
3 200 1
4 100 2
5 110 2
6 120 2
7 300 3
8 310 3
My Sql query
$sql = "SELECT SUM(CASE WHEN price >= 0 AND price <= 200 THEN 1 ELSE 0 END) AS `0-2`,
SUM(CASE WHEN price >= 201 AND price <= 500 THEN 1 ELSE 0 END) AS `2-5`,
COUNT(pid) AS `All Values`
FROM price where pid IN(1,2,3)";
when I run this query price count values showing like below
0-2 has (6) count
2-5 has (2) count
but here I need to display as like.
here I am looking to display as two products between 0-200 matched that are 1,2 pids and so on
0-2 (2) count
2-5 (1) count
because in price table there are more price options there for products so every product has 2 to 5 different prices in the table but I should display it as one product count even more prices had.
Kindly tell me how to write mysql query.
I would appreciate you help.
You can use COUNT(DISTINCT CASE ..) and in THEN clause use pid instead of 1
SELECT
COUNT(DISTINCT CASE WHEN price >= 0 AND price <= 200 THEN pid END) AS `0-2`,
COUNT(DISTINCT CASE WHEN price >= 201 AND price <= 500 THEN pid END) AS `2-5`,
COUNT(DISTINCT pid) AS `All Values`
FROM price
WHERE pid IN(1,2,3)
DEMO
I need to get the difference of the sums of two fields which are in single table (really sorry if this is confusing), please read on for an example
Id type account_id stock_id volume price value
==========================================================
1 BUY 1 1 5 500 2500
2 BUY 1 4 30 200 6000
6 BUY 1 1 10 500 5000
7 SELL 1 1 3 500 1500
8 SELL 1 1 2 500 1000
9 SELL 1 4 20 120 2400
Above is my sample data and I would my SQL query result to be something like,
account_id stock_id volume totalAmount
============================================
1 1 10 5000
1 4 10 3600
basically here I am trying to get the total buy value of unique account & stock combination and subtract with the total sell value
Any help here would be highly appreciated.
Thanks in advance
Fiddle Test:
http://sqlfiddle.com/#!2/53035/1/0
select account_id,
stock_id,
sum(case when type = 'BUY' then volume else -volume end) as volume,
sum(case when type = 'BUY' then value else -value end) as totalamount
from tbl
group by account_id,
stock_id
having sum(case when type = 'BUY' then volume else -volume end) <> 0
I added the HAVING clause based on your comment.
Just to reduce duplication I would change Brian's code to this:
SELECT
account_id,
stock_id,
SUM(volume * type_sign) as total_volume,
SUM(value * type_sign) as total_value
FROM
(select t.*, case when type = 'BUY' then 1 else -1 end as type_sign
from tbl) t
GROUP BY account_id,
stock_id
select buy.account_id,buy.stock_id,(buy.volume-sell.volume) volume,(buy.totalAmount-sell.totalAmount) totalAmount from
(select account_id,stock_id,sum(volume) volume,sum(value) totalAmount from stock
where type = 'BUY'
group by account_id,stock_id) buy
inner join
(select account_id,stock_id,sum(volume) volume,sum(value) totalAmount from stock
where type = 'SELL'
group by account_id,stock_id) sell
on buy.account_id = sell.account_id and buy.stock_id = sell.stock_id
I have 2 tables, orders and order_lineitems.
orders contains the order status info (sold date, invoice no, type of sale, etc)
order_lineitems contains the item(s) for each order in a one to many relationship.
Since we provide shipping info by line item, ship_date is in the order_lineitems table, null if not shipped, a date if it is shipped.
I am trying to pull the orders where all items have shipped by comparing the number of line item rows against the line item rows that have a ship date. While I have successfully pulled all that info, I am unable to make the last step, limiting the result set to include only the completely shipped orders (number of rows = number of rows where ship_date is not null).
I know I am missing something simple, but just don't see it..
select sum(custom.lineitems) as totalitems, sum(custom.shipped) as totalshipped,
custom.invoice, z.shipregion
from (
select a.invoice, count(a.invoice) as lineitems, 0 as shipped
from order_lineitem a
group by a.invoice
UNION ALL
select b.invoice, 0 as notshipped, count(b.ship_date) as shipped
from order_lineitem b
where b.ship_date is not null
group by b.invoice
) as custom
left join orders z on custom.invoice = z.invoice
where z.result = 0
and z.respmsg like 'Approved%'
and z.shipregion <> 'PENDING'
and z.cancelorder = 0
group by custom.invoice;
This returns a result set like so (one row for each invoice in the DB)
totalitems totalshipped invoice shipregion
4 2 1000 REGION08
1 1 10001 REGION07
1 1 10004 REGION05
3 1 10006 REGION05
2 2 10007 REGION04
1 1 10008 REGION08
7 7 10009 REGION01
1 1 1001 REGION08
What I am looking for is a result set like this - only where totalitems = totalshipped
totalitems totalshipped invoice shipregion
1 1 10001 REGION07
1 1 10004 REGION05
2 2 10007 REGION04
1 1 10008 REGION08
7 7 10009 REGION01
1 1 1001 REGION08
Use HAVING clause
SELECT a.invoice, z.shipregion, COUNT(a.invoice) AS lineitems,
SUM(CASE WHEN a.ship_date IS NOT NULL THEN 1 ELSE 0 END) AS shipped
FROM order_lineitem a
LEFT JOIN orders z ON a.invoice = z.invoice AND z.result = 0 AND z.cancelorder = 0 AND
z.respmsg LIKE 'Approved%' AND z.shipregion <> 'PENDING'
GROUP BY a.invoice HAVING lineitems = shipped
OR
SELECT a.invoice, a.shipregion, a.lineitems, a.shipped
FROM (SELECT a.invoice, z.shipregion, COUNT(a.invoice) AS lineitems,
SUM(CASE WHEN a.ship_date IS NOT NULL THEN 1 ELSE 0 END) AS shipped
FROM order_lineitem a
LEFT JOIN orders z ON a.invoice = z.invoice AND z.result = 0 AND z.cancelorder = 0 AND
z.respmsg LIKE 'Approved%' AND z.shipregion <> 'PENDING'
GROUP BY a.invoice
) AS a WHERE a.lineitems = a.shipped
One more outer query needed.
select * from
(
\\Your whole query here
) as Result
where Result.totalitems = Result.totalshipped
I'm trying to put together a MYSQL query that will count the number of Non-Null (or better yet, non-zero) values in select fields in a single row and then sort from lowest to highest (based on the count). For example, I have a table with 5 fields... ID, Name, Score_1, Score_2, Score_3. I want to count how many times the value "0" exists in Score_1, Score_2 and Score_3 for each record, then sort from most non zero values to least.
ID Name Score_1 Score_2 Score_3
1 Dan 8 7 0
2 Joe 0 0 3
3 Chris 0 0 0
4 Mike 4 5 5
I assume the query has to look something like this...
Select ID, Name, Score_1, Score_2, Score_3 where (???) ORDER BY (???)
Output should look like this (ID 4 is displayed first since it has the least amount of non-zero entries)...
ID Name Score_1 Score_2 Score_3
4 Mike 4 5 5
1 Dan 8 7 0
2 Joe 0 0 3
3 Chris 0 0 0
I'm somewhat new to mysql query's, so any help would be greatly appreciated. I thought the COUNT function would help, but that function appears to count columns from all rows. Perhaps there is a way to use the COUNT function and limit it to a singel row so it can be sorted by that row count?
This should do what you want:
SELECT ID, Name, Score_1, Score_2, Score_3
FROM Table1
ORDER BY (Score_1 = 0) + (Score_2 = 0) + (Score_3 = 0)
Result:
ID Name Score_1 Score_2 Score_3
4 Mike 4 5 5
1 Dan 8 7 0
2 Joe 0 0 3
3 Chris 0 0 0
try This:
Select id, Count1, Count2, Count3, Count4
From
(Select
Sum(Case When IsNull(Score_1,0) = 0 Then 1 Else 0 End) Count1,
Sum(Case When IsNull(Score_2,0) = 0 Then 1 Else 0 End) Count2,
Sum(Case When IsNull(Score_3,0) = 0 Then 1 Else 0 End) Count3,
Sum(Case When IsNull(Score_4,0) = 0 Then 1 Else 0 End) Count4
From Table
Group By Id) Z -- This column (Id) better not be the PK for this table!!!
Order By Count1 + Count2 + Count3 + Count4