I have a MySQL table called "MyTable" and it basically lists usernames and points (two columns, name and points). I want to say something like "what is joe1928's rank?", which of course is based off his points. How could I do this in MySQL without having to download all that data and sort it and determine the rank myself?
The person with the highest number of points would be ranked 1.
Try getting the number of people with a higher score than your user:
select count(*) from MyTable where score > (select score from MyTable where user = 'Joe');
That will return 0 for the top user.
This page seems to describe and solve your problem.
Notes from that page:
SET #rownum := 0;
SELECT rank, correct FROM (
SELECT #rownum := #rownum + 1 AS rank, correct, uid
FROM quiz_user ORDER BY correct DESC
) as result WHERE uid=xxxxxxxx
SELECT #r AS Rank
FROM MyTable u, (SELECT #r := 0)
WHERE (#r := #r + 1) * (u.Username = 'joe1928')
ORDER BY u.Score DESC
LIMIT 1
select * from [TABLENAME] where [USERNAME] = blah order by [POINTS] desc limit 1;
Based on the link posted by #Dave your query will look like something below:
select Rank,name from
(select #rownum:=#rownum+1 AS 'Rank', p.name
from calls p, (select #rownum:=0) r
order by p.points desc) as rankResults
where name = 'joe';
This is from another stack overflow page, seems to solve your problem.
SELECT uo.*,
(
SELECT COUNT(*)
FROM users ui
WHERE (ui.points, ui.id) >= (uo.points, uo.id)
) AS rank
FROM users uo
WHERE id = #id
Related
I have the following table on my DataBase:
TimeRank(user-id, name, time)
I would like to order the table by time and get the position of an specific ID on the table, for example:
The user nº 68 is on the 3rd position.
I only need to do a query that returns the position of the user.
MySQL don't have the function row_number, so I don't know how to do it.
SELECT x.user-id,
x.name,
x.time,
x.position
FROM (SELECT t.user-id,
t.name,
t.time,
#rownum := #rownum + 1 AS position
FROM TABLE TimeRank t
JOIN (SELECT #rownum := 0) r
ORDER BY t.time) x
WHERE x.user-id = 123
Alternative:
SELECT user-id,
(SELECT COUNT(*) FROM TimeRank WHERE time <= (SELECT time FROM TimeRank WHERE user-id = 123)) AS position,
time,
name
FROM TimeRank
WHERE user-id = 123
You can generate a position column with a variable
set #pos=0;
select pos,user_id
from (select #pos:=#pos+1 pos,user_id from TimeRank order by time) s
where user_id=68;
If indexing is a concern, you can add a column to your table and update it with
set #pos=0;
update TimeRank set position=(#pos:=#pos+1) order by time;
SELECT * FROM ( SELECT #row := #row +1 AS rownum, [column name] FROM ( SELECT * FROM [table name] ) WHERE rownum % 5 = 1
This does indeed return every 5th row, but in ascending order. What I want is that it first gets all the data, put them in descending order and THEN apply the filter.
If you filter it first and then put it in descending order, it will not start with the latest data added (4/5th of the time).
I would like to know how one should do this.
Thanks in advance
Edit: For people with the same problem, this is what I used:
SELECT * FROM
(SELECT rank, id, Temperature FROM
(SELECT *, #rownum := #rownum + 1 AS rank FROM temperature_room1,
(SELECT #rownum := 0) r) AS T ORDER BY id DESC) AS J WHERE rank % 5 = 1
Select everything from:
Select rank, id and Temperature from:
Select everything and rownumber as rank from the table as t ordered by ID in descending order
Finally, only output the row numbers which can be divided by 5 and the remainder is 1
Don't quote me on this, I'm a big noob regarding SQL stuff. It works for me, so I'm happy.
seems like you just need an order by dec on the desired column in one of the three queries. I think the second one as order by applies to the select at the same level. ans since you want your rownum ordered desc... seems like that's the place...
SELECT *
FROM ( SELECT #row := #row +1 AS rownum, [column name]
FROM ( SELECT * FROM [table name] )
ORDER BY [column name] desc
)
WHERE rownum % 5 = 1
I am getting error : View's SELECT contains a variable or parameter with the query below.How do I create view for the same.I really appreciate any help.Thanks in Advance.
CREATE VIEW V AS SELECT #rownum := #rownum + 1 AS rank, name, vote
FROM uservotes, (SELECT #rownum := 0) t ORDER BY vote DESC
declare #rownum int
CREATE VIEW V AS SELECT #rownum := #rownum + 1 AS rank, name, vote
FROM uservotes, (SELECT #rownum := 0) t ORDER BY vote DESC
Try like this
CREATE VIEW V AS
(
SELECT (SELECT 1 + COUNT(*) FROM uservotes where votes < T.votes ) AS NUM, name, votes
FROM uservotes T ORDER BY votes DESC
)
Fiddle Demo
You can define a variable in order to get psuedo row number functionality, because MySQL doesn't have any ranking functions:
Can't Use A Variable in a MySQL View
If you do, you'll get the 1351 error, because you can't use a variable in a view due to design. The bug/feature behavior is documented here.
This is my mysql DB:
id, auth, name, points
and what I want to get is to create a rank. So sort all the records by points, and get the number of the row where the auth field is equal to '1'
I were looking for this in stockoverflow archive, in google etc. However, I havn't find what I were looking for. I were trying to do it myself, but none of them didn't work for me.
Could anyone help me, please?
SELECT a.iterator, a.id, a.name, a.points
FROM (
SELECT #rank:=#rank+1 AS iterator, id, name, points, auth
FROM table, (SELECT #rank:=0) tmp
ORDER BY points DESC) a
WHERE a.auth = 1
This should give you the record with rank for the record with auth = 1:
SELECT * FROM
(
SELECT id, auth, name, points, #rownum := #rownum + 1 AS rank
FROM (
SELECT id, auth, name, points
FROM yourTable
ORDER BY points DESC
) a
JOIN (
SELECT #rownum := 0
) r
) b
WHERE b.auth = 1;
sqlfiddle demo
I have table with id (store user id) and score in different match. I want what is the position of a user.
So for i try this sql fiddle;
in this I am getting all the row but I need only user having id 3 and it position in the table.
like this:
Score Postion
26 3
Even i try to do like this but no success
MySql: Find row number of specific record
With MySQL, how can I generate a column containing the record index in a table?
I got the answer: http://sqlfiddle.com/#!2/b787a/2
select * from (
select T.*,(#rownum := #rownum + 1) as rownum from (
select sum(score) as S,id from mytable group by id order by S desc ) as T
JOIN (SELECT #rownum := 0) r
) as w where id = 3
Updated sqlfiddle and above query. Now it is working perfectly.
I think this should do the trick:
SELECT totalScore, rownum FROM (
SELECT id,sum(score) AS totalScore,(#rownum := #rownum + 1) AS rownum
FROM mytable
JOIN (SELECT #rownum := 0) r
group by id) result
WHERE result.ID = 3;
just add a where clause
select x.id,x.sum,x.rownum
from(
select id,sum(score) as sum,(#rownum := #rownum + 1) as rownum
from mytable
JOIN (SELECT #rownum := 0) r
group by id
) x
where id =3