How to write EasyMock Unit test for http call timeout? - junit

Question

final HttpResponse response = this.call(queryUri);
entity = response.getEntity();public HttpResponse call(final URI queryUri) throws Exception
{
Future<HttpResponse> futureResponses = executor.submit(new Callable<HttpResponse>()
{
#Override
public HttpResponse call() throws Exception
{
final HttpGet httpget = new HttpGet(queryUri);
return httpclient.execute(httpget);
}
});
return futureResponses.get(A9_CALL_TIMEOUT, TimeUnit.MILLISECONDS);
}
final HttpResponse response = this.call(queryUri);
entity = response.getEntity();
parse(entity.getcontent());
wondering how do I mock all the object, can someone provide me the workable code on test class?

Answer 1

I would recommend that you pull out the creation of the Callable to a protected method.
public Callable<HttpResponse> createCallable(String queryUri){
return new Callable<HttpResponse>(){
#Override
public HttpResponse call() throws Exception
{
final HttpGet httpget = new HttpGet(queryUri);
return httpclient.execute(httpget);
}
});
}
I don't think you actually need EasyMock for this test. In fact it might be easier without it. In your test you can override this method to return a test stub. I think if the get times out, then it will throw a TimeoutException and not actually cancel the job. So I think you just need to catch TimeoutException to make sure everything works.
So maybe your mock just has to sleep for A9_CALL_TIMEOUT plus some additional fudge factor.
#Test
public void testTimeout(){
Subclass sut = new Subclass(){
#Override
public Callable<HttpResponse> createCallable(String queryUri){
return new Callable<HttpResponse>(){
#Override
public HttpResponse call() throws Exception{
try{
Thread.sleep(A9_CALL_TIMEOUT *2);
catch(InterruptException e) {}
}
});
};
//you can also use Junit ExpectedException rule instead
// of the try catch here
try{
sut.runQueryMethodWithExecutor();
fail("should throw timeout");
}catch(TimeoutException e){
//expected
}
}