I am trying to implement the following code into my own.
Here is the code I'm trying to implement. It's for getting Ranks with ties and the rank is non consecutive after the ties.
SET #rnk=0;
SET #rank=0;
SET #curscore=0;
SELECT score,ID,rank FROM (
SELECT AA.*,BB.ID,
(#rnk:=#rnk+1) rnk,
(#rank:=IF(#curscore=score,#rank,#rnk)) rank,
(#curscore:=score) newscore
FROM (
SELECT * FROM (
SELECT COUNT(1) scorecount,score
FROM scores GROUP BY score
) AAA
ORDER BY score DESC
) AA LEFT JOIN scores BB USING (score)
) A;
Here is the link to where I got the code from. It's the second answer.
https://dba.stackexchange.com/questions/13703/get-the-rank-of-a-user-in-a-score-table
My code is below. I swapped "score" with "totalPoints". This is as far as I got.
I am having trouble with two parts of the code.
This line, the BB.ID part.
SELECT AA.*, BB.ID,
And this line.
) AA LEFT JOIN scores BB USING (score)
I know what the code is doing I just don't know how to replace those parts with my code and tables to get them to work.
SET #rnk=0;
SET #rank=0;
SET #curscore=0;
SELECT AA.*, BB.ID,
(#rnk:=#rnk+1) rnk,
(#rank:=IF(#curscore=totalPoints,#rank,#rnk)) rank,
(#curscore:=totalPoints) newPoints
FROM (
SELECT * FROM (
SELECT COUNT(1) scorecount, totalPoints FROM (
#----------start of my code
SELECT *, (totalWins+(totalPushs*.5)) AS totalPoints, totalWins+totalLost+totalPushs AS totalBets FROM (
SELECT *, SUM(win) AS totalWins, SUM(lost) AS totalLost, SUM(push) AS totalPushs FROM (
SELECT *, (finalResult = 'Winner') AS win, (finalResult = 'Loser') AS lost, (finalResult = 'Push') AS push FROM (
SELECT nflp_users.userID, userName, avatar, teamColor,
IF (pickID=visitorID, visitorResult, homeResult) AS finalResult
FROM nflp_users
JOIN nflp_picks
ON nflp_users.userID = nflp_picks.userID
JOIN nflp_schedule
ON nflp_picks.gameID = nflp_schedule.gameID
) x
) x
GROUP BY userID
) x
#----------end of my code
) x GROUP BY totalPoints
) AAA
ORDER BY totalPoints DESC
) AA LEFT JOIN scores BB USING (score)
Related
This is my query
SELECT `email`, `score`, `score` * 100 / t.s AS `Grade Percentage %`
FROM `rank`
CROSS JOIN (SELECT SUM(`level`) AS s FROM `history`) t
GROUP BY `email`
rank Table:
history Table:
my desired output for example with kemp score after multiplying the score of kemp by 100, i want to divide it with the total of his level which is 4. help me i cant seem to solve the problem
You could also use only subquery instead
SELECT r.email, r.score,
(r.score * 100 / (SELECT SUM(level)
FROM history
WHERE email = r.email)) AS `Grade Percentage %`
FROM rank r;
However, this assumes always rank table has only one copy of email, else you would need to use GROUP BY
Edit :
update rank r
set r.`Grade Percentage %` = (r.score * 100 / (SELECT SUM(level)
FROM history
WHERE email = r.email));
Use sub query with GROUP BY in the join as below
SELECT r.email,
r.score,
(r.score * 100 / t.lvl) AS `Grade Percentage %`
FROM `rank` r
INNER JOIN (SELECT
email, SUM(`level`) lvl
FROM `history` GROUP BY email) t ON t.email = r.email
To store result in the column Grade Percentage % of rank table
UPDATE `rank` r
INNER JOIN (SELECT
email, SUM(`level`) lvl
FROM `history` GROUP BY email) t ON t.email = r.email
SET `Grade Percentage %` = (r.score * 100 / t.lvl)
I have the following sql query:
SELECT v.venue_id, s.zip, COUNT( * )
FROM bcs_scans s
JOIN bcs_scanners sc ON s.uuid = sc.uuid
JOIN bcs_venues v ON sc.venue_id = v.venue_id
WHERE v.banlist_id = '625'
AND s.del =0
GROUP BY s.zip
ORDER BY COUNT( * ) DESC
Which returns the count of individual zip codes, their count, and associated venue.
How do I go about selecting the top 5 zip codes for each unique venue id?
I believe I can run a subquery that groups results by venue id with the top 5 zip counts, but I am unsure of where to start
Could be you select the result in this way ... a bit complex ..
using the having for extract the value that match the max count group by venue_id from your original query ..
SELECT v.venue_id as venue_id, s.zip as , COUNT( * ) as num
FROM bcs_scans s
JOIN bcs_scanners sc ON s.uuid = sc.uuid
JOIN bcs_venues v ON sc.venue_id = v.venue_id
WHERE v.banlist_id = '625'
AND s.del =0
GROUP BY s.zip
HAVING ( v.venue_id, COUNT( * )) in
(select venue_id, max(num)
from
(SELECT v.venue_id as venue_id, s.zip as , COUNT( * ) as num
FROM bcs_scans s
JOIN bcs_scanners sc ON s.uuid = sc.uuid
JOIN bcs_venues v ON sc.venue_id = v.venue_id
WHERE v.banlist_id = '625'
AND s.del =0
GROUP BY s.zip
ORDER BY COUNT( * ) DESC ) a t
group by venue_id)
ORDER BY COUNT( * ) limit 5
I have 3 tables (stars mach the ids from the table before):
product:
prod_id* prod_name prod_a_id prod_b_id prod_user
keywords:
key_id** key_word key_prod* kay_country
data:
id dat_id** dat_date dat_rank_a dat_traffic_a dat_rank_b dat_traffic_b
I want to run a query (in a function that gets a $key_id) that outputs all these columns but only for the last 2 dates(dat_date) from the 'data' table for the key_id inserted - so that for every key_word - I have the two last dat_dates + all the other variables included in my SQL query:
So... This is what I have so far. and I don't know how to get only the MAX vars. I tried using "max(dat_date)" in different ways that didn't work.
SELECT prod_id, prod_name, prod_a_id, prod_b_id, key_id, key_word, kay_country, dat_date, dat_rank_a, dat_rank_b, dat_traffic_a, dat_traffic_b
FROM keywords
INNER JOIN data
ON keywords.key_id = data.dat_id
INNER JOIN prods
ON keywords.key_prod = prods.prod_id
Is there a possability to do this with only one query?
EDIT (FOR IgorM):
public function newnew() {
$query = $this->db->query('WITH CTE AS
(
SELECT *,
ROW_NUMBER() OVER (PARTITION BY dat_id ORDER BY dat_date ASC) AS
RowNo FROM data
)
SELECT *
FROM CTE
INNER JOIN keywords
ON keywords.key_id = CTE.dat_id
INNER JOIN prods
ON keywords.key_prod = prods.prod_id
WHERE RowNo < 3
');
$result = $query->result();
return $result;
}
This is the error on the output:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'CTE AS ( SELECT *, ROW_NUMBER() OVER (' at line 1
WITH CTE AS ( SELECT *, ROW_NUMBER() OVER (PARTITION BY dat_id ORDER BY dat_date ASC) AS RowNo FROM data ) SELECT * FROM CTE INNER JOIN keywords ON keywords.key_id = CTE.dat_id INNER JOIN prods ON keywords.key_prod = prods.prod_id WHERE RowNo < 3
For SQL
WITH CTE AS
(
SELECT *,
ROW_NUMBER() OVER (PARTITION BY dat_id ORDER BY dat_date ASC) AS
RowNo FROM data
)
SELECT *
FROM CTE
INNER JOIN keywords
ON keywords.key_id = CTE.dat_id
INNER JOIN prods
ON keywords.key_prod = prods.prod_id
WHERE RowNo < 3
For MySQL (not tested)
SET #row_number:=0;
SET #dat_id = '';
SELECT *,
#row_number:=CASE WHEN #dat_id=dat_id THEN #row_number+1 ELSE 1 END AS row_number,
#dat_id:=dat_id AS dat_id_row_count
FROM data d
INNER JOIN keywords
ON keywords.key_id = d.dat_id
INNER JOIN prods
ON keywords.key_prod = prods.prod_id
WHERE d.row_number < 3
The other approach is self joining. I don't want to take credit for somebody else's job, so please look on the following example:
ROW_NUMBER() in MySQL
Look for the following there:
SELECT a.i, a.j, (
SELECT count(*) from test b where a.j >= b.j AND a.i = b.i
) AS row_number FROM test a
If you only want to do this for one key_id at a time (as alluded to in your responses to other answers) and only want two rows, you can just do:
SELECT p.prod_id,
p.prod_name,
p.prod_a_id,
p.prod_b_id,
k.key_id,
k.key_word,
k.key_country,
d.dat_date,
d.dat_rank_a,
d.dat_rank_b,
d.dat_traffic_a,
d.dat_traffic_b
FROM keywords k
JOIN data d
ON k.key_id = d.dat_id
JOIN prods p
ON k.key_prod = p.prod_id
WHERE k.key_id = :key_id /* Bind in key id */
ORDER BY d.dat_date DESC
LIMIT 2;
Whether you want this depends on your data structure and whether there is more than one key/prod combination per date.
Another option limiting just the data rows would be:
SELECT p.prod_id,
p.prod_name,
p.prod_a_id,
p.prod_b_id,
k.key_id,
k.key_word,
k.key_country,
d.dat_date,
d.dat_rank_a,
d.dat_rank_b,
d.dat_traffic_a,
d.dat_traffic_b
FROM keywords k
JOIN (
SELECT dat_id,
dat_date,
dat_rank_a,
dat_rank_b,
dat_traffic_a,
dat_traffic_b
FROM data
WHERE dat_id = :key_id /* Bind in key id */
ORDER BY dat_date DESC
LIMIT 2
) d
ON k.key_id = d.dat_id
JOIN prods p
ON k.key_prod = p.prod_id;
If you want some kind of grouped results for all the keywords, you'll need to look at the other answers.
I think a window function is the best way to go. without knowing a lot about the structure of the data you can try a subquery of what you are trying to restrict and then joining that to the rest of the data. Then within the where clause restrict the rows you pull back.
select p.prod_id, p.prod_name, p.prod_a_id, p.prod_b_id,
t.key_id, t.key_word, t.kay_country, t.dat_date,
t.dat_rank_a, t.dat_rank_b, t.dat_traffic_a, t.dat_traffic_b
from
(
select
k.key_id, k.key_word, k.kay_country, d.dat_date, d.dat_rank_a,
d.dat_rank_b, d.dat_traffic_a, d.dat_traffic_b,
row_number() over (partition by dat_id order by dat_date desc) as 'RowNum'
from keywords as k
inner join
data as d on k.key_id = d.dat_id
) as t
inner join
prods as p on t.key_prod = p.prod_id
where tmp.RowNum <=2
This is a "groupwise max" problem. Reference. CTE does not exist in MySQL.
I'm not totally clear on how your tables are linked, but here is a stab:
SELECT
*
FROM
( SELECT #prev := '', #n := 0 ) init
JOIN
( SELECT #n := if(k.key_id != #prev, 1, #n + 1) AS n,
#prev := k.key_id,
d.*, k.*, p.*
FROM data d
JOIN keywords k ON k.key_id = d.dat_id
JOIN prods p ON k.key_prod = p.prod_id
ORDER BY
k.key_id ASC,
d.dat_date ASC
) x
WHERE n <= 2
ORDER BY k.key_id, n;
you can use this query:
select prod_id, prod_name, prod_a_id, prod_b_id, key_id, key_word,
kay_country, dat_date, dat_rank_a, dat_rank_b, dat_traffic_a, dat_traffic_b
from keywords where dat_date in (
SELECT MAX(dat_date) FROM keywords temp_1
where temp_1.prod_id = keywords.prod_id
union all
SELECT MAX(dat_date) FROM keywords
WHERE dat_date NOT IN (SELECT MAX(dat_date ) FROM keywords temp_2 where
temp_2.prod_id = keywords.prod_id)
)
The below one is my query. It's taking 12 seconds for process. I have created the index for T.DataViewId, but it's still taking long time due to Count(distinct()) and Sum. Thanks in Advance.
;WITH my_cte
AS (SELECT T.name AS name,
T.id AS id,
Count(DISTINCT( DD.dynamictableid )) AS counts,
Round(Sum(D.[employees]), 0) AS measure1
FROM dbo.treehierarchy T
LEFT JOIN dbo.dynamicdatatableid DD
ON T.id = DD.hierarchyid
AND T.dataviewid = DD.dataviewid
LEFT JOIN dbo.demo1 D
ON D.[demo1id] = DD.dynamictableid
WHERE T.dataviewid = 2
AND T.parentid = 0
GROUP BY T.id,
T.name)
SELECT name, id, counts, row_num, measure1
FROM (SELECT name,
id,
counts,
Row_number()
OVER(
ORDER BY counts DESC) AS row_num,
measure1
FROM my_cte) innertable
WHERE ( row_num BETWEEN 1 AND 15 )
It looks as if you only need top 15 records of descending counts. It could be done simply like this :
SELECT
TOP 15 T.name AS name,
T.id AS id,
Count(DISTINCT( DD.dynamictableid )) AS counts,
Round(Sum(D.[employees]), 0) AS measure1
FROM
dbo.treehierarchy T
LEFT JOIN
dbo.dynamicdatatableid DD
ON
T.id = DD.hierarchyid
AND
T.dataviewid = DD.dataviewid
LEFT JOIN
dbo.demo1 D
ON
D.[demo1id] = DD.dynamictableid
WHERE
T.dataviewid = 2
AND
T.parentid = 0
GROUP BY
T.id,T.name
ORDER BY
3 DESC
I'm selecting total count of villages, total count of population from my tables to build statistics. However, there is something wrong. It returns me everything (530 pop (there are 530 pop in total), (106 villages (there are 106 users in total)) in first row, next rows are NULLs
SELECT s1_users.id userid, (
SELECT count( s1_vdata.wref )
FROM s1_vdata, s1_users
WHERE s1_vdata.owner = userid
)totalvillages, (
SELECT SUM( s1_vdata.pop )
FROM s1_users, s1_vdata
WHERE s1_vdata.owner = userid
)pop
FROM s1_users
WHERE s1_users.dp >=0
ORDER BY s1_users.dp DESC
Try removing s1_users from inner SELECTS
You're already using INNER JOINs. Whan you list tables separated with comma, it is a shortcut for INNER JOIN.
Now, the most obvious answer is that your subqueries using aggregating functions (COUNT and SUM) are missing a GROUP BY clauses.
SELECT s1_users.id userid, (
SELECT count( s1_vdata.wref )
FROM s1_vdata, s1_users
WHERE s1_vdata.owner = userid
GROUP BY s1_vdata.owner
)totalvillages, (
SELECT SUM( s1_vdata.pop )
FROM s1_users, s1_vdata
WHERE s1_vdata.owner = userid
GROUP BY s1_vdata.owner
)pop
FROM s1_users
WHERE s1_users.dp >=0
ORDER BY s1_users.dp DESC
However, using subqeries in column list is really inefficient. It casues subqueries to be run once for each row in outer query.
Try like this instead
SELECT
s1_users.id AS userid,
COUNT(s1_vdata.wref) AS totalvillages,
SUM(s1.vdata.pop) AS pop
FROM
s1_users, s1_vdata --I'm cheating here! There's hidden INNER JOIN in this line ;P
WHERE
s1_users.dp >= 0
AND s1_users.id = s1_vdata.owner
GROUP BY
s1_users.id
ORDER BY
s1_users.dp DESC
SELECT s1_users.id AS userid,
(
SELECT COUNT(*)
FROM s1_vdata
WHERE s1_vdata.owner = userid
) AS totalvillages,
(
SELECT SUM(pop)
FROM s1_vdata
WHERE s1_vdata.owner = userid
) AS pop
FROM s1_users
WHERE dp >= 0
ORDER BY
dp DESC
Note that this is less efficient than this query:
SELECT s1_users.id AS user_id, COUNT(s1_vdata.owner), SUM(s1_vdata.pop)
FROM s1_users
LEFT JOIN
s1_vdata
ON s1_vdata.owner = s1_users.id
GROUP BY
s1_users.id
ORDER BY
dp DESC
since the aggregation needs to be done twice in the former.
SELECT userid,totalvillages,pop from
(
SELECT s1_users.id as userid, count( s1_vdata.wref ) as totalvillages
FROM s1_vdata, s1_users
WHERE s1_vdata.owner = userid
GROUP BY s1_users.id) tabl1 INNER JOIN
(
SELECT s1_users.id as userid, SUM( s1_vdata.pop ) as pop
FROM s1_users, s1_vdata
WHERE s1_vdata.owner = userid
GROUP BY s1_users.id) tabl2 on tabl1.userid = tabl2.userid