Sql to JSON/XML [duplicate] - mysql

Question

I am trying to export my MySQL tables from my database to a JSON file, so I can list them in an array.
I can create files with this code no problem:
$sql=mysql_query("select * from food_breakfast");
while($row=mysql_fetch_assoc($sql))
{
$ID=$row['ID'];
$Consumption=$row['Consumption'];
$Subline=$row['Subline'];
$Price=$row['Price'];
$visible=$row['visible'];
$posts[] = array('ID'=> $ID, 'Consumption'=> $Consumption, 'Subline'=> $Subline, 'Price'=> $Price, 'visible'=> $visible);
}
$response['posts'] = $posts;
$fp = fopen('results.json', 'w');
fwrite($fp, json_encode($response));
fclose($fp);
Now this reads a table and draws it's info from the fields inside it.
I would like to know if it is possible to make a JSON file with the names of the tables, so one level higher in the hierarchy.
I have part of the code:
$showtablequery = "
SHOW TABLES
FROM
[database]
LIKE
'%food_%'
";
$sql=mysql_query($showtablequery);
while($row=mysql_fetch_array($sql))
{
$tablename = $row[0];
$posts[] = array('tablename'=> $tablename);
}
$response['posts'] = $posts;
But now i am stuck in the last line where is says: $ID=$row['ID']; This relates to the info inside the Table and I do not know what to put here.
Also as you can see, I need to filter the Tables to only list the tables starting with food_ and drinks_
Any help is greatly appreciated:-)

Answer 1

There is no 'table id' in MySQL and therefore the result set from SHOW TABLES has no index id. The only index in the resultset is named 'Tables_in_DATABASENAME'.
Also you should use the mysqli library as the good old mysql library is depreacted. Having prepared an example:
<?php
$mysqli = new mysqli(
'yourserver',
'yourusername',
'yourpassword',
'yourdatabasename'
);
if ($mysqli->connect_errno) {
echo "Failed to connect to MySQL: (" . $mysqli->connect_errno . ") "
. $mysqli->connect_error;
}
$result = $mysqli->query('SHOW TABLES FROM `yourdatabasename` LIKE \'%food_%\'');
if(!$result) {
die('Database error: ' . $mysqli->error);
}
$posts = array();
// use fetch_array instead of fetch_assoc as the column
while($row = $result->fetch_array()) {
$tablename = $row[0];
$posts []= array (
'tablename' => $tablename
);
}
var_dump($posts);