Highstock mysql json compare multiple series - mysql

Question

Please help to create a query!
This is a working example of my query Retrieve data as JSON using PHP:
<?php
$con = mysql_connect("localhost","user","password");
if (!$con) {
die('Could not connect: ' . mysql_error());
}
mysql_select_db("admin_accounting", $con);
$result = mysql_query("SELECT unix_timestamp(date), sum(ksi2k) FROM accounting where lhc_vo like 'ops' group by year(date), month(date)");
$rows = array();
$rows['type'] = 'area';
$rows['name'] = 'Ops';
while($r = mysql_fetch_array($result)) {
$rows['data'][] = $r[0]*1000;
$rows['data'][] = $r[1];
array_push($rows);
}
print json_encode($rows, JSON_NUMERIC_CHECK);
mysql_close($con);
?>
The JSON results look like this:
{"type":"area","name":"Ops","data":[1167664515000,0,1170342915000,0,1172762115000,0,1175436915000,0,1178028915000,0]}
But I need the JSON results should look like this:
{"type":"area","name":"Ops","data":[[1167664515000,0],[1170342915000,0],[1172762115000,0],[1175436915000,0],[1178028915000,0]]}
I would be very grateful for the help

Answer 1

while($r = mysql_fetch_array($result)) {
$rows['data'][] = array($r[0]*1000, $r[1]);
}

Answer 2

In addition to my other answer, you ought to consider switching away from the ancient (and now deprecated, as of PHP v5.5) ext/mysql. Here is an example using PDO, in which you can see how simple your problem becomes:
<?php
$con = new PDO(
'mysql:hostname=localhost;dbname=admin_accounting',
'user',
'password'
);
$result = $con->query('
SELECT 1000*UNIX_TIMESTAMP(date), SUM(ksi2k)
FROM accounting
WHERE lhc_vo LIKE "ops"
GROUP BY YEAR(date), MONTH(date)
');
print json_encode([
'type' => 'area',
'name' => 'Ops',
'data' => $result->fetchAll(PDO::FETCH_NUM)
]);
?>
Note that:
I have moved the multiplication into the database layer in order that I can simply call fetchAll() to obtain the resulting array;
MySQL will select an indeterminate value from amongst those in each group for the first column in the resultset; should this be undesirable, you will need to apply a suitable aggregate function to the reference to the date column; and
I have used the short array syntax, which is only available from PHP v5.4—if you're using an earlier version, you will need to replace the [ … ] of the argument to json_encode() with array( … ).