Query multiple rows that leads to one row in other table - mysql

Question

I'm a noob at making mySQL queries so I couldn't get my work done. I hope you guys know the answer to my question.
I want to make options to my products. Like if you have a black t-shirt, with a tanktop model and diamonds on it. You must have the black t-shirt tanktop model and diamonds row. I want to make it like this:
table: product_option
--------------------------------
product_option_id name product_combination_id
1 Black 1
2 Diamond 1
3 Tanktop 1
4 Option 2
5 Option 2
table: product_combination
--------------------------------
product_combination_id name
1 Black tanktop with diamonds
So my question is. Is it possible to query the product_options and get an product_combination row out of it?
I hope you guys know the answer to my question! Thank you for your time :)
EDIT:
I think my question was too general and I want to ask it more specific.
Let's say. I have a shop with clothes. I have a product (let's say an T-shirt). And there are a couple of options to choose from.
Like this:
Color:
- Black
- Red
- Orange
Size
- Large
- Xtra Large
- Medium
- Small
Accessoire:
- Diamonds
- Printed
- Swarovski
Let's say I want to buy the Black / Xtra Large T-shirt with Diamonds on it. Then the product_combination must be Black/Large/Diamonds Row. I think I need an Foreign table with a Many to Many relation. Like product_combination_option table with the columns:
product_combination_option
- product_combination_option_id
- product_combination_id
- product_option_id
But then again. How can I query when someone chooses Black / Xtra Large with Diamonds and find which product_combination it is.
I hope I'm a bit clearer now. Sorry that I updated my question so late! I appreciate all your answers very much!

Answer 1

I think what you are looking for is joining your tables, so that you can pick up a combination based on the product you have.
So, for that, a query can be
Select *
from product_option inner join product_combination
using(product_combination_id);
This joins the 2 tables. so you can replace the * with the list of attributes you want to display/fetch.

Answer 2

If you mean you want to pass a list of options to the query and get a list of matching product_combination entries, then here's one way:
SELECT *
FROM product_combination
WHERE product_combination_id IN (
SELECT product_combination
FROM product_option
WHERE name IN ('option1', 'option2', 'option3')
GROUP BY product_combination
HAVING COUNT(*) = 3
);
The subquery returns a set of product_combination values that have all three options requested. The COUNT(*) = 3 condition assumes that a single product_combination value cannot have duplicate name values associated with it. (Which is only natural, but in case your table doesn't have the corresponding restriction, you could replace COUNT(*) with COUNT(DISTINCT name) to make sure a group being returned contains all three options specified and not just three rows of which some contain identical options.)
Of course, if the number of options queried isn't fixed, you'll need to build the query dynamically because of the IN predicate, because it is not parametrisable (in terms of the number of items). However, you could try using a temporary rowset instead of a hardcoded list. The table would be populated before running the query in question, which in this case would be modified to this effect:
SELECT *
FROM product_combination
WHERE product_combination_id IN (
SELECT product_combination
FROM product_option
WHERE name IN (SELECT option_name FROM requested_options)
GROUP BY product_combination
HAVING COUNT(*) = (SELECT COUNT(*) FROM requested_options)
);
In the above query, requested_options is the name of the temporary storage (possibly a temporary table, but I'm not sure if MySQL allows you to access one that was created and and populated beforehand in a different query), and option_name is its column containing the options being requested.