$_POST leads to empty fields in MySQL Database - mysql

Question

Thank you for taking the time to read this. This question may or may not have been answered before, I might have been looking in the wrong place, but I've hit a dead end wall here and I hope I could ask for some help finding a solution.
I'm using a basic form with a validation for specific fields and checkboxes before I'm sending them in a query to my database.
<?php
if ($_SERVER["REQUEST_METHOD"] == "POST") {
// validate the text inputs
$err = array();
if (empty($_POST['A'])) {
array_push($err, "A is required.");
}
if (empty($_POST['B'])) {
array_push($err, "B is required.");
}
if (empty($_POST['C'])) {
array_push($err, "C is required.");
} else {
$pattern = "^[_a-z0-9-]+(\.[_a-z0-9-]+)*#[a-z0-9-]+(\.[a-z0-9-]+)*(\.[a-z]{2,3})$";
if (!eregi($pattern, $_POST['email'])) {
array_push($err, "Incorrect email.");
}
}
if (empty($_POST['D'])) {
array_push($err, "D is required.");
if (sizeof($err) != 0) {
echo "<p style='color: red'>The following files haven't been filled yet.</p>";
echo "<ul style='list-style:circle !important;color: red !important;'>";
foreach ($err as &$value) {
echo "<li style='background: 0;list-style: disc inside none;color: red;'>" . $value . "</li>";
}
echo "</ul>";
echo "<br/>";
}
// validate the agree checkbox
if (sizeof($err) == 0 && !isset($_POST['agree'])) {
array_push($err, "Please agree with the ToS.");
foreach ($err as &$value) {
echo "<p style='color: red'>" . $value . "</p>";
}
}
}
?>
Then the inside the form we got this:
<?php echo isset($_POST['a']) ? $_POST['a'] : ''; ?>"
The other lines are the same, so I'll save you from having to read a huge block. From there on I sent the code towards:
<?php
// redirect if form is valid
if (sizeof($err) == 0 && isset($_POST['agree'])) {
// set post data in session
session_start();
$_POST = $_SESSION['POSTDATA'];
$con = mysqli_connect("localhost", "x", "y", "z");
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql = "INSERT INTO esselte_nl (a, b, email, c, d) VALUES
('$_POST[a]',
'$_POST[b]',
'$_POST[email]',
'$_POST[c]',
'$_POST[d]')";
if (!mysqli_query($con, $sql)) {
die('Error: ' . mysqli_error($con));
}
mysqli_close($con);
// redirect to result.php
exit('<meta http-equiv="refresh" content="0; url=resullt"/>');
return;
session_destroy();
}
?>
Worst thing is, I'm fairly certain it's some very small error somewhere and I'm overlooking it, terribly frustrating. So if anyone could potentially point out whatever I'm doing wrong here, I'd appreciate it.
With friendly regards,
user2747008 (I really should pick a name though)
PS: Sorry about that, I messed up copying pasting the information.

Answer 1

$sql = "INSERT INTO esselte_nl (a, b, email, c, d) VALUES
('$_POST[a]',
'$_POST[b]',
'$_POST[c]',
'$_POST[email]')";
Your insert statement has 5 field names, but only 4 values, and they aren't in the correct order.