I have upload my YII2 project to ubuntu 16.04.
My source is no problem when run on localhost on my computer, but when I run it on the server ubuntu 16.04 with network, it has a problem.
The model source can't find another relation model
public function getLokasiAwal()
{
return $this->hasOne(KotaBandara::className(), ['id_kota' => 'lokasi_awal']);
}
and i have error
Class 'backend\models\TypeNonstaf' not found
I have found the solution, I added the following code:
use backend\models\Kotabandara;
On top in model file but, in my source in localhost,
I do not need to add that code
Can someone explain that issue??
As #rob006 pointed out, it appears that you had been working/running your app on a Windows local file system, which is case-preserving, but not case-sensitive.
When you first call upon a namespaced class directly or via the use operator, it passes this full class name as $className into yii\BaseYii\autoload::($className) (Yii2's global class autoloading handler), which in turn attempts to include the corresponding class file, if found.
So, on your Windows local machine, when you use backend\models\KotaBandara, it will find and include any file associated with the corresponding path alias in a case-insensitive manner, thus it will find any of:
#backend/models/KotaBandara.php
#backend/models/Kotabandara.php
#backend/models/kotabandara.php
#backend/models/KoTaBaNdArA.php
There can be only 1 target file with this sequence of paths/characters anyway.
However, when you migrate this code to a Ubuntu system, which is both case-preserving and case-sensitive, there is a distinct difference between KotaBandara.php and kotabandara.php and in fact both files can exist side by side, unlike on Windows.
So, you have to be precise here - on Ubuntu, use backend\models\KotaBandara will trigger the autoloader to find only the file whose path AND case matches, i.e. KotaBandara.php. If you named the file kotabandara.php, it will be found on Windows, but not on Ubuntu!
I'm currently building a new CakePHP app with version 3.0.0-RC1, and trying to install and use the jasig/phpCAS plugin. Using this guide, I've run the following command from the command prompt: composer require jasig/phpcas
This correctly copies the jasig/phpcas files into the vendor directory of my app, but one of the other files that the guide says should be updated (vendor/cakephp-plugins.php) doesn't even exist.
I've had a tough time accessing the plugin. I want to be able to call its static methods, and I keep getting errors of the form: Error: Class 'App\Controller\phpCAS' not found. (The exact directory in the error changes depending on where I'm calling the method from.)
I don't know if this is due to not having the cakephp-plugins.php file, or if I'm not calling the plugin correctly. It's my understanding that if the plugin is loaded I should just be able to call static methods on it like this: phpCAS::methodName()
First of all jasig/phpcas is not a CakePHP plugin. And the vendor/cakephp-plugins.php file is created by the CakePHP plugin installer, so if you don't see such a file, you seem to have either not installed any plugins yet, or you are not using a recent version of the installer, as the creation of this file has been introduced just recently.
Regarding the error about the class not being found, you are missing the leading namespace separator (\phpCAS::methodName()) to access the class in the global namespace, respectively you are missing a proper import (use phpCAS;) that would make the class available in the current namespace.
In case you are not familiar with namespaces, you may want to start with: http://php.net/namespaces
I am trying to connect to MySQL using C++. The IDE that I am using is Visual C++ 2010. I followed the steps on the MySQL dev page (http://dev.mysql.com/tech-resources/articles/mysql-connector-cpp.html). I followed the steps exactly as given although i used a different OS(Windows). I get many linker errors in the process, which I am finding difficult to debug. Could somebody direct me towards a better or a simpler approach to acces MySQL using C++.
P.S. I have downloaded mysqlconnector for C++.
You could try mysql++, but you'll encounter the same linker errors I bet.
Have you set the include path (C:...\MySQL Server 5.1\include) and the library path (C:...\MySQL Server 5.1\lib\debug) ? In VC2010 to set global settings you have to :
VS2010 introduces the user settings
file
(Microsoft.cpp..users.props)
to control global settings including
Global search path. These files are
located at
$(USERPROFILE)\appdata\local\microsoft\msbuild\v4.0
directory.
The issue you are seeing is a bug in
the UI. To make it possible to change
the ordering of these read-only
directories, here is the workaround
that you can apply:
open up the property manager,
right click on the .user.props file to bring up the property page
open up VC++ Directories -> Include Directories, add new paths after
$(IncludePath)
Click on the "Edit" dropdown on VC++ Directories -> Include
Directories property, the user
directories as well as the inherited
values will show up in the upper pane
you can move the directory orders as you wish and save.
http://connect.microsoft.com/VisualStudio/feedback/details/550946/vs-2010-how-to-change-vc-directories-inherited-values-read-only
I am writing a WIX installer and I have a following requirement:
During installation, I need to pass an absolute path to a file (lets call it A) included in my installer to a COM component, which already exists on the hard drive and is a part of another program. I have already written an appropriate Custom Action which expects a path to the file A. I don't want to include A as a file installed in the Program Files folder and removed during the uninstallation process. Instead, I would like to put A only temporary on the hard drive, call my Custom Action which will cause the COM component to use the content of A, and then remove A from disk. Is there an easy way to accomplish this goal?
I have tried to utilize the Binary Table and store A there, however I don't know how to reference A using absolute path. I know I could put A outside of MSI file but I would like to keep every file installer needs in a single MSI.
Any help would be appreciated.
Deleting a file that MSI installed means that MSI will consider it "broken" and try to auto-repair it if called on to do so. That happens automatically in several cases (e.g., advertised shortcuts and COM registration) so I'd recommend against it. Leave the file there instead -- it's done its job and there's no harm in leaving it there.
I would take this approach.
Install the file "A" into any directory. Run your custom action needed to update the COM component. Then run another custom action or modify the currently written one to remove the file after it is no longer in use. This would leave no trace of the file "A" and if you schedule the custom action to only run during the install you won't have to worry about it on uninstall.
I've recently searched how I could get the application's directory in Java. I've finally found the answer but I've needed surprisingly long because searching for such a generic term isn't easy. I think it would be a good idea to compile a list of how to achieve this in multiple languages.
Feel free to up/downvote if you (don't) like the idea and please contribute if you like it.
Clarification:
There's a fine distinction between the directory that contains the executable file and the current working directory (given by pwd under Unix). I was originally interested in the former but feel free to post methods for determining the latter as well (clarifying which one you mean).
In Java the calls
System.getProperty("user.dir")
and
new java.io.File(".").getAbsolutePath();
return the current working directory.
The call to
getClass().getProtectionDomain().getCodeSource().getLocation().getPath();
returns the path to the JAR file containing the current class, or the CLASSPATH element (path) that yielded the current class if you're running directly from the filesystem.
Example:
Your application is located at
C:\MyJar.jar
Open the shell (cmd.exe) and cd to C:\test\subdirectory.
Start the application using the command java -jar C:\MyJar.jar.
The first two calls return 'C:\test\subdirectory'; the third call returns 'C:\MyJar.jar'.
When running from a filesystem rather than a JAR file, the result will be the path to the root of the generated class files, for instance
c:\eclipse\workspaces\YourProject\bin\
The path does not include the package directories for the generated class files.
A complete example to get the application directory without .jar file name, or the corresponding path to the class files if running directly from the filesystem (e.g. when debugging):
String applicationDir = getClass().getProtectionDomain().getCodeSource().getLocation().getPath();
if (applicationDir.endsWith(".jar"))
{
applicationDir = new File(applicationDir).getParent();
}
// else we already have the correct answer
In .NET (C#, VB, …), you can query the current Assembly instance for its Location. However, this has the executable's file name appended. The following code sanitizes the path (using System.IO and using System.Reflection):
Directory.GetParent(Assembly.GetExecutingAssembly().Location)
Alternatively, you can use the information provided by AppDomain to search for referenced assemblies:
System.AppDomain.CurrentDomain.BaseDirectory
VB allows another shortcut via the My namespace:
My.Application.Info.DirectoryPath
In Windows, use the WinAPI function GetModuleFileName(). Pass in NULL for the module handle to get the path for the current module.
Python
path = os.path.dirname(__file__)
That gets the path of the current module.
Objective-C Cocoa (Mac OS X, I don't know for iPhone specificities):
NSString * applicationPath = [[NSBundle mainBundle] bundlePath];
In Java, there are two ways to find the application's path. One is to employ System.getProperty:
System.getProperty("user.dir");
Another possibility is the use of java.io.File:
new java.io.File("").getAbsolutePath();
Yet another possibilty uses reflection:
getClass().getProtectionDomain().getCodeSource().getLocation().getPath();
In VB6, you can get the application path using the App.Path property.
Note that this will not have a trailing \ EXCEPT when the application is in the root of the drive.
In the IDE:
?App.Path
C:\Program Files\Microsoft Visual Studio\VB98
In .Net you can use
System.IO.Directory.GetCurrentDirectory
to get the current working directory of the application, and in VB.NET specifically you can use
My.Application.Info.DirectoryPath
to get the directory of the exe.
Delphi
In Windows applications:
Unit Forms;
path := ExtractFilePath(Application.ExeName);
In console applications:
Independent of language, the first command line parameter is the fully qualified executable name:
Unit System;
path := ExtractFilePath(ParamStr(0));
Libc
In *nix type environment (also Cygwin in Windows):
#include <unistd.h>
char *getcwd(char *buf, size_t size);
char *getwd(char *buf); //deprecated
char *get_current_dir_name(void);
See man page
Unix
In unix one can find the path to the executable that was started using the environment variables. It is not necessarily an absolute path, so you would need to combine the current working directory (in the shell: pwd) and/or PATH variable with the value of the 0'th element of the environment.
The value is limited in unix though, as the executable can for example be called through a symbolic link, and only the initial link is used for the environment variable. In general applications on unix are not very robust if they use this for any interesting thing (such as loading resources). On unix, it is common to use hard-coded locations for things, for example a configuration file in /etc where the resource locations are specified.
In bash, the 'pwd' command returns the current working directory.
In PHP :
<?php
echo __DIR__; //same as dirname(__FILE__). will return the directory of the running script
echo $_SERVER["DOCUMENT_ROOT"]; // will return the document root directory under which the current script is executing, as defined in the server's configuration file.
echo getcwd(); //will return the current working directory (it may differ from the current script location).
?>
in Android its
getApplicationInfo().dataDir;
to get SD card, I use
Environment.getExternalStorageDirectory();
Environment.getExternalStoragePublicDirectory(String type);
where the latter is used to store a specific type of file (Audio / Movies etc). You have constants for these strings in Environment class.
Basically, for anything to with app use ApplicationInfo class and for anything to do with data in SD card / External Directory using Environment class.
Docs :
ApplicationInfo ,
Environment
In Tcl
Path of current script:
set path [info script]
Tcl shell path:
set path [info nameofexecutable]
If you need the directory of any of these, do:
set dir [file dirname $path]
Get current (working) directory:
set dir [pwd]
Java:
On all systems (Windows, Linux, Mac OS X) works for me only this:
public static File getApplicationDir()
{
URL url = ClassLoader.getSystemClassLoader().getResource(".");
File applicationDir = null;
try {
applicationDir = new File(url.toURI());
} catch(URISyntaxException e) {
applicationDir = new File(url.getPath());
}
return applicationDir;
}
in Ruby, the following snippet returns the path of the current source file:
path = File.dirname(__FILE__)
In CFML there are two functions for accessing the path of a script:
getBaseTemplatePath()
getCurrentTemplatePath()
Calling getBaseTemplatePath returns the path of the 'base' script - i.e. the one that was requested by the web server.
Calling getCurrentTemplatePath returns the path of the current script - i.e. the one that is currently executing.
Both paths are absolute and contain the full directory+filename of the script.
To determine just the directory, use the function getDirectoryFromPath( ... ) on the results.
So, to determine the directory location of an application, you could do:
<cfset Application.Paths.Root = getDirectoryFromPath( getCurrentTemplatePath() ) />
Inside of the onApplicationStart event for your Application.cfc
To determine the path where the app server running your CFML engine is at, you can access shell commands with cfexecute, so (bearing in mind above discussions on pwd/etc) you can do:
Unix:
<cfexecute name="pwd"/>
for Windows, create a pwd.bat containing text #cd, then:
<cfexecute name="C:\docume~1\myuser\pwd.bat"/>
(Use the variable attribute of cfexecute to store the value instead of outputting to screen.)
In cmd (the Microsoft command line shell)
You can get the name of the script with %* (may be relative to pwd)
This gets directory of script:
set oldpwd=%cd%
cd %0\..
set app_dir=%pwd%
cd %oldpwd%
If you find any bugs, which you will. Then please fix or comment.
I released https://github.com/gpakosz/whereami which solves the problem in C and gives you:
the path to the current executable
the path to the current module (differs from path to executable when calling from a shared library).
It uses GetModuleFileNameW on Windows, parses /proc/self/maps on Linux and Android and uses _NSGetExecutablePath or dladdr on Mac and iOS.
Note to answer "20 above regarding Mac OSX only: If a JAR executable is transformed to an "app" via the OSX JAR BUNDLER, then the getClass().getProtectionDomain().getCodeSource().getLocation(); will NOT return the current directory of the app, but will add the internal directory structure of the app to the response. This internal structure of an app is /theCurrentFolderWhereTheAppReside/Contents/Resources/Java/yourfile
Perhaps this is a little bug in Java. Anyway, one must use method one or two to get the correct answer, and both will deliver the correct answer even if the app is started e.g. via a shortcut located in a different folder or on the desktop.
carl
SoundPimp.com