I'm trying to select the SUM of a few values with a limit of 2. I've seen a couple of example of this (9877872) but have been unable to get it working. I have
SELECT SUM(points)
FROM
(SELECT points FROM user_table
WHERE city=1 AND group =5)
AS min_points ORDER BY points DESC LIMIT 2
However the limit clause at the end of the query does not seem to be executed and I just get the sum of all the users in the table...
Would anyone know what I'm doing wrong...?
Try this
SELECT SUM(points)
FROM
(SELECT points FROM user_table
WHERE city=1 AND group =5 ORDER BY points DESC LIMIT 2) AS t1
Related
Actually I'm working with the following table fsa_areas:
Note that each area has a responsible
Now, what I need to do, is to order the same table as following:
Note that now the results are ordered by the the responsible with more areas and at the end the responsible with less areas.
Is there a way to order them in that way?
You can use a COUNT subquery in the ORDER BY clause:
select a.*
from fsa_areas a
order by (select count(*) from fsa_areas a1 where a1.Responsible = a.Responsible) desc
Another way is to get the count in a derived table and join the base table to it
select a.*
from (
select Responsible, count(*) as cnt
from fsa_areas
group by Responsible
) r
join fsa_areas a using(Responsible)
order by r.cnt desc
In MySQL 8 you can use COUNT() as window function:
select *, count(*) over (partition by Responsible) as cnt
from fsa_areas
order by cnt desc
I have a query with a count with some group by, and I want to get the greater count. I can do with an order by and limit 1, but I have multiple results with the same count and then does not work for me.
How do I solve this problem?
With MySql 8+, you can use CTE to get the maximum count, and then retrieve all records with a count equal to the maximum count.
However, since CTE is not available in MySql 5.6, you'd need to use a sub-query to get the maximum count, and then write the main query which compares the count of each record to the maximum count retrieved in the subquery.
Here is a query I wrote. Maybe it's not the most efficient solution, but it gets the desired result.
SELECT
group_id, COUNT(record_id) c
FROM
table_name
GROUP BY group_id
HAVING c IN (
SELECT
MAX(sub_query.c)
FROM
(SELECT
group_id, COUNT(record_id) c
FROM
table_name
GROUP BY group_id) AS sub_query
)
If you are not going to do this using window functions, you can do:
SELECT group_id, COUNT(*) as cnt
FROM table_name
GROUP BY group_id
HAVING cnt = (SELECT COUNT(*)
FROM table_name
GROUP BY group_id
ORDER BY COUNT(*) DESC
LIMIT 1
) ;
I would like to get all the rows from the two users with the greatest number of rows, that is, the two users with the greatest activity in a log table.
I have only found next solution: first, get the number of rows for every user, an limit it to 2:
SELECT userid, count(*) AS n_of_rows FROM my_table GROUP BY userid LIMIT 2;
Then, from the source code I'm querying the database (Python for example), query the database to get the rows of each user:
SELECT * FROM my_table where userid = $userid
Is it the best/elegant solution, taking into account SQL language itself and database performance?
Thanks!
I think what you're looking for is something like
select * from my_table where userid in
(select userid from my_table
group by userid
order by count(*) desc
limit 2)
To get the rows and keep the order, use a join with aggregation:
select t.*
from my_table t join
(select userid, count(*) as cnt
from my_table
group by userid
order by count(*) desc
limit 2
) top2
on t.userid = top2.userid
order by top2.cnt desc, userid;
Try this:
SELECT TOP 2 userid, count(*) AS n_of_rows
FROM my_table
GROUP BY userid
ORDER BY count(*) desc
I have the following data set.
How would the query look if wanted the most occuring show on top and limit the result for 20 shows?
EDIT
I have searched on the web for this and i need to use the GROUP BY method from sql. but when i make the query
SELECT `show` FROM fans GROUP BY `show` LIMIT 20
i do not get the desired result.
SELECT a.*, b.TotalCount
FROM TableName a
INNER JOIN
(
SELECT c.show, COUNT(*) totalCount
FROM TableName c
GROUP BY c.show
) b ON a.show = b.show
ORDER BY b.TotalCount DESC
LIMIT 20
if you want to list one record for every show, you can simply use GROUP BY
SELECT a.show, COUNT(*) TotalCount
FROM TableName a
GROUP BY a.Show
ORDER BY TotalCount DESC
LIMIT 20
I want to make some mysql query, query out 5 image order by date, but from 5 different upload user.
mysql datatable Structure: id, user_id, image, text, date
SELECT *
FROM mytable
WHERE image!=''
GROUP BY user_id
ORDER BY date DESC
LIMIT 5
But this GROUP BY always cause get the user_id earlier upload image then make a ORDER BY date DESC, I need the fresh 5 images which uploaded by 5 differents users. Maybe should use some UNION, ask for a help, thanks.
Use INNER JOIN with MAX
SELECT
mytable.*
FROM
mytable
INNER JOIN
(SELECT MAX(id) AS ID, id FROM mytable GROUP BY user_id) AS m
ON m.id = mytable.id
WHERE image != ''
GROUP BY user_id
ORDER BY DATE DESC
LIMIT 5
This will fetch the max(latest) id and integrate it to the outer select
Try this query
SELECT *
FROM temp
WHERE image!=''
GROUP BY user_id
HAVING date=max(date)
LIMIT 5
Not sure about mysql but this works in sybase.