I have a cron script that writes the total number of active users to a table every day. I'm trying to now generate a simple report that would show the "high water mark" for each month. Because some accounts expire during the month it's possible the highest number may NOT be at the end of the month.
Here's a sample of my table structure
tblUserLog
-----------
record_id INT(11) // PRIMARY KEY
run_date DATE // DATE RUN
ttl_count INT(11) // TOTAL FOR DAY
Sample data:
record_id run_date ttl_count
1 2013-06-01 500
2 2013-06-10 510
3 2013-06-20 520
4 2013-06-30 515
5 2013-07-01 525
6 2013-07-10 530
7 2013-07-20 540
8 2013-07-31 550
9 2013-08-01 560
What I would like returned is:
record_id run_date ttl_count
3 2013-06-20 520
8 2013-07-31 550
9 2013-08-01 560
I've tried two queries that are close...
// This will give me the total for the first of the month
SELECT s.record_id, s.run_date, s.ttl_count
FROM tblStatsIndividual s
JOIN (
SELECT record_id
FROM tblStatsIndividual
GROUP BY DATE_FORMAT(run_date, '%Y %m')
HAVING MAX(ttl_count)
) s2
ON s2.record_id = s.record_id
ORDER BY run_date DESC
This returns the total for the first of each month, along with the record_id and correct date for the total.
Tried this...
SELECT record_id,max(run_date), max(ttl)
FROM (
SELECT record_id,run_date, max(ttl_count) AS ttl
FROM tblStatsIndividual
GROUP BY DATE_FORMAT(run_date, '%Y %m')
) a
GROUP BY DATE_FORMAT(run_date, '%Y %m')
ORDER BY run_date DESC
This one appears to get the correct "high water mark" but it's not returning the record_id, or the run_date for the row that IS the high water mark.
How do you get the record_id and the run_date for the highest total?
Something like
Select detail.Record_ID, detail.Run_Date, detail.ttl_Count
From tblStatsIndividual detail
Inner Join
(Select Year(run_date) as Year, Month(Run_date) as Month, Max(ttl_count) as ttl
From tblStatsIndividual
Group By Year(run_date), Month(Run_date)) maximums
On maximums.Year = Year(detail.Run_date) and maximums.Month = Month(detail.Run_date)
and maximums.ttl = detail.ttl_count
Should do it. NB based on your requirement if you had two records in the same month with the same (and highest in the month) ttl_count, they would both be returned.
Based on the help from #Tony Hopkinson, This query gets me the info. The one caveat is it shows the ID and date for the first occurrence of the MAX total, so if the total is the same three days in a row on a month, the first day's ID is returned. For my purpose, the last ID would be more ideal, but I can live with this:
SELECT s.Record_ID, s.Run_Date, s.ttl_Count
FROM tblStatsIndividual s
INNER JOIN (
SELECT YEAR(run_date) AS yr, MONTH(run_date) AS mon, MAX(ttl_count) AS ttl
FROM tblStatsIndividual
GROUP BY DATE_FORMAT(run_date, '%Y %m')
) maximums
ON maximums.yr = YEAR(s.run_date)
AND maximums.mon = MONTH(s.run_date)
AND maximums.ttl = s.ttl_Count
GROUP BY ttl_count
ORDER BY run_date DESC
Related
I have an orders table
Order_id User_id Order_date
1 32 2020-07-19
2 24 2020-07-21
3 27 2020-07-27
4 24 2020-08-14
5 32 2020-08-18
6 32 2020-08-19
7 58 2020-08-20
Now I want to find how many of the users ordered in 1st month also ordered in the next month. In this case, user_id's 32,24,27 ordered in 7th month but only 24 and 32 ordered in the next month.
I want the result to be like :
Date Retained_Users Total_users
2020-07 Null 3
2020-08 2 3
I'm lost here. Can someone please help me with this?
In MySQL 8.0, you can do this with window functions:
select
order_month,
count(distinct case when cnt_orders_last_month > 0 then user_id end) retained_users,
count(distinct user_id) total_users
from (
select
user_id,
date_format(order_date, '%Y-%m-01') as order_month,
count(*) over(
partition by user_id
order by date(date_format(order_date, '%Y-%m-01'))
range between interval 1 month preceding and interval 1 day preceding
) cnt_orders_last_month
from mytable
) t
group by order_month
The logic lies in the range specification of the window function; it orders record by month, and counts how many orders the customer placed last month. Then all that is left to do is aggregate and count distinct users.
Demo on DB Fiddle
I have a table that shows , for each date, a list of customer ids - shows customers who were active on any particular day. So each date can include ids that are also present in another date.
bdate customer_id
2012-01-12 111
2012-01-13 222
2012-01-13 333
2012-01-14 111
2012-01-14 333
2012-01-14 666
2012-01-14 777
I am looking to write a query which calculates the total number of unique ids between two dates - the starting date is the row date and the ending date is a particular date in the future.
My query looks like this:
select
bdate,
count(distinct customer_id) as cts
from users
where bdate between bdate and current_date
group by 1
order by 1
But this produces a count of unique users for each date like this:
bdate customer_id
2012-01-12 1
2012-01-13 2
2012-01-14 4
my desired result is ( for a count of users between starting row date and 2012-01-14 )
bdate customer_id
2012-01-12 5 - includes (111,222,333,666,777)
2012-01-13 5 - includes (222,333,111,666,777)
2012-01-14 4 - includes (111,333,666,777)
Like #Strawberry said, you can make a join like this:
select
t1.bdate,
count(distinct t2.customer_id) as cts
from users t1
join users t2 on t2.bdate >= t1.bdate
where t1.bdate between t1.bdate and current_date
group by t1.bdate
order by t1.bdate
join t2 can get you all the users between particular day and current_date, then count t2's customer_id, that's it.
SqlFiddle Demo Here
I'm stuck on this query. I need to do a group by date, card_id and only show the highest hits. I have this data:
date card_name card_id hits
29/02/2016 Paul Stanley 1345 12
29/02/2016 Phil Anselmo 1347 16
25/02/2016 Dave Mustaine 1349 10
25/02/2016 Ozzy 1351 17
23/02/2016 Jhonny Cash 1353 13
23/02/2016 Elvis 1355 15
20/02/2016 James Hethfield 1357 9
20/02/2016 Max Cavalera 1359 12
My query at the moment
SELECT DATE(card.create_date) `day`, `name`,card_model_id, count(1) hits
FROM card
Join card_model ON card.card_model_id = card_model.id
WHERE DATE(card.create_date) >= DATE(DATE_SUB(NOW(), INTERVAL 1 MONTH)) AND card_model.preview = 0
GROUP BY `day`, card_model_id
;
I want to group by date, card_id and filter the higher hits result showing only one row per date. As if I run a max(hits) with group by but I won't work
Like:
date card_name card_id hits
29/02/2016 Phil Anselmo 1347 16
25/02/2016 Ozzy 1351 17
23/02/2016 Elvis 1355 15
20/02/2016 Max Cavalera 1359 12
Any light on that will be appreciated. Thanks for reading.
Here is one way to do this. Based on your sample data (not the query):
select s.*
from sample s
where s.hits = (select max(s2.hits)
from sample s2
where date(s2.date) = date(s.date)
);
Your attempted query seems to have no relationship to the sample data, so it is unclear how to incorporate those tables (the attempted query has different columns and two tables).
I am trying for join of two tables receipt and sale. but i dont get thse result.I want to get result between two date intervel
My sale table structure
id date total
26 2014-07-16 9000
27 2014-07-15 6000
Receipt table structure
id date nettotal
18 2014-07-16 1000
19 2014-07-15 2500
I want to get the result like
date total nettotal
2014-07-16 9000
2014-07-16 1000
2014-07-15 6000
2014-07-15 2500
Any body know these select query for get these result?
select date, total, nettotal
from (select date, total, null as nettotal, 2 as sort_col
from sale
union all
select date null as total, nettotal, 1 as sort_col
from receipt) as a
order by date desc, sort_col desc
Note: You need to show what you've tried
I Have a table called
CountryVisits
Visitor Date
4 20/12/12 14:27:7
5 20/12/12 15:45:11
6 20/12/12 16:36:51
12 21/12/12 11:17:2
145 21/12/12 12:37:57
445 21/12/12 13:35:15
435 21/12/12 14:34:35
I want to have a count of all visitors per Date not time :
So i expect :
VisitorCnt Date
3 20/12/12
4 21/12/12
I tried :
SELECT COUNT(DATE(Date)), DATE(Date) from CountryVisits GROUP BY Date ;
But i don't have the desired results.
When you write GROUP BY Date it's grouping by the Date column in the table, which includes times. If you want to group by just the day, you need to assign an alias and group by that:
SELECT COUNT(*), DATE(Date) AS VisitedOn
FROM CountryVisits
GROUP BY VisitedOn