I am building a Twitter-like app. There is a Feed in which I want to only show posts of Users who I follow.
I tried everything with joins, but nothing seems to work.
I have 3 tables: Users, Followers, Shares
The Tables look like this:
Users: id
Followers: user_id, follower_id
Shares: user_id
What I need to get is "ALL Shares WHERE share.user_id = followers.follower_id"
"ANDWHERE followers.user_id = users.id"
Assume, the users.id is 3, I tried this:
$shares = DB::table('shares')
->leftjoin('followers', 'shares.user_id', '=', 'followers.follower_id')
->leftjoin('users', 'followers.user_id', '=', 'users.id')
->where('users.id', 3)
->where('shares.user_id', 'followers.follower_id')
->get();
But it doesnt work.
Any help is appreciated :)
I believe your join is wrong:
$shares = DB::table('shares')
->join('users', 'users.id', '=', 'shares.user_id')
->join('followers', 'followers.user_id', '=', 'users.id')
->where('followers.follower_id', '=', 3)
->get();
I also suggest you to name your table as follows instead, it feels a bit more natural to say user has many followers through follows and user has many followees through follows.
Example
$shares = DB::table('shares')
->join('users', 'users.id', '=', 'shares.user_id')
->join('follows', 'follows.user_id', '=', 'users.id')
->where('follows.follower_id', '=', 3)
->get();
Model approach
I didn't realize you were using DB:: queries and not models. So I'm fixing the answer and providing a lot more clarity. I suggest you use models, it's a lot easier for those beginning with the framework and specially SQL.
Example of models:
class User extends Model {
public function shares() {
return $this->hasMany('Share');
}
public function followers() {
return $this->belongsToMany('User', 'follows', 'user_id', 'follower_id');
}
public function followees() {
return $this->belongsToMany('User', 'follows', 'follower_id', 'user_id');
}
}
class Share extends Model {
public function user() {
return $this->belongsTo('User');
}
}
Example of Model usage:
$my = User::find('my_id');
// Retrieves all shares by users that I follow
// eager loading the "owner" of the share
$shares = Share::with('user')
->join('follows', 'follows.user_id', '=', 'shares.user_id')
->where('follows.follower_id', '=', $my->id)
->get('shares.*'); // Notice the shares.* here
// prints the username of the person who shared something
foreach ($shares as $share) {
echo $share->user->username;
}
// Retrieves all users I'm following
$my->followees;
// Retrieves all users that follows me
$my->followers;
In terms of general MySQL syntax, this is best written:
SELECT * FROM USER a JOIN FOLLOWERS b ON (a.id = b.user_id) JOIN SHARES c on (b.follower_id = c.user_id) WHERE a.id = 3
will return a data set of all followers and their respective shares.
I believe you would want the following in Laravel
DB::table('USER')
->join('FOLLOWERS', 'USER.id', '=', 'FOLLOWERS.user_id')
->join('SHARES', 'FOLLOWERS.follower_id', '=', 'SHARES.user_id')
->where('USER.id', 3)
->get();
Instead of
->where('shares.user_id', 'followers.follower_id')
It should be
->whereRaw('shares.user_id=followers.follower_id')
because on the original example the 'followers.follower_id' is interpreted as a string.
$data[shares] = DB::table('shares')
->leftjoin('followers', 'shares.user_id', '=', 'followers.follower_id')
->leftjoin('users', 'users.id', '=', 'users.id')
->where('users.id','=', 3)
->get();
to see results.
print_r($data[shares]);die;
for other query Simply give discription of your table
First of all, go through users table and join it with followers table, and then with share table to get corresponding shares data of only followers. Here is the code
$shares = DB::table('users')
->leftjoin('followers', 'users.user_id', '=', 'followers.follower_id')
->leftjoin('shares', 'shares.user_id', '=', 'users.id')
->where('users.id', 3)
->get();
Related
I want to transform my MySql query into a Query in Laravel but I really don't know how to do this. I don't know how to rename in FROM like in SQL
My query is the following one :
SELECT f2.* FROM formation f2 WHERE f2.theme_id IN
(SELECT f.theme_id FROM user_formation uf JOIN formation f ON uf.formation_id = f.id WHERE uf.user_id = 2)
AND f2.id NOT IN
(SELECT formation_id FROM user_formation WHERE user_id = 2);
I tried something like this but ...
$q = Formation::query()
->from('formation AS f2')
->whereIn('f2.theme_id', function($r)
{
$r->select('f.theme_id')->from('user_formation AS uf')
->join('formation', function($join)
{
$join->on('uf.formation_id', '=', 'f.id')
->where ('uf.user_id', '=', $id)
});
});
->whereNotIn('f2.id', function($s){
$s->select('formation.id')
->from('user_formation')
->where('user_id', '=', $id)
})->get();
thanks for help.
If you want to run this raw query you can run:
$res = DB::select('
SELECT f2.*
FROM formation f2
WHERE f2.theme_id IN
(SELECT f.theme_id FROM user_formation uf JOIN formation f ON uf.formation_id = f.id WHERE uf.user_id = 2)
AND f2.id NOT IN
(SELECT formation_id FROM user_formation WHERE user_id = 2)');
Or you can rewrite this query in laravel query builder Eloquent ORM:
Formations::query()
->whereIn('formations.theme_id', function($q){
$user_formations_table = (new UserFormation)->getTable();
$formation_table = (new Formation)->getTable();
$q->select('paper_type_id')
->from($user_formations_table)
->join($formation_table, "$user_formations_table.formation_id", '=', "$formation_table.id")
->where("$user_formations_table.user_id", 2);
})->whereNotIn('formations.id', function($q){
$user_formations_table = (new UserFormation)->getTable();
$q->select('formation_id')
->where("$user_formations_table.user_id", 2);
})
->get();
Note that I have used models Formations, UserFormation, Formation Because you have used 3 different tables, you should add this models and specify tables to run ORM query
I advice to run first RAW query if there is no another need to run it with Eloquent
Hope this helps you
First of all, you need to fix your code indentations so you don't confuse yourself. Second, you placed semicolon in the wrong places. Third, you need to pass $id inside function because of the variable scope.
$q = Formation::query()
->whereIn('f2.theme_id', function($r) use ($id) {
$r->select('f.theme_id')->from('user_formation AS uf')
->join('formation', function($join) use ($id) {
$join->on('uf.formation_id', '=', 'f.id')
->where('uf.user_id', '=', $id);
}
);
})
->whereNotIn('f2.id', function($s) use ($id) {
$s->select('formation.id')
->from('user_formation')
->where('user_id', '=', $id);
})->get();
Note : If you are using VSCode, I suggest to use PHP Intelephense as it will help with autocomplete, syntax check, etc.
I have a collection of user skills but i need is to get only skills as an array i tried this
$builder->where('job_id', $value)
->join('users', 'job_applicants.user_id', '=', 'users.id')
->join('user_skills', 'users.id', '=', 'user_skills.user_id', function ($join){
$join->selectRaw("GROUP_CONCAT(user_skills.skill, ', ')");
})
->groupBy('job_applicants.job_id')
->get();
The exception message : Object of class Closure could not be converted to string
The join closure should be the first and only argument after the table name.
->join('user_skills', function ($join) {
$join->on('users.id', '=', 'user_skills.user_id')
->selectRaw("GROUP_CONCAT(user_skills.skill, ', ')");
});
However, a selectRaw inside the join closure doesn't make a whole lot of sense. Logically, this isn't where you select data. You've joined the table, your select statement belongs in the main query, it doesn't belong contained within the join, like so:
$builder->selectRaw("job_applicants.*, GROUP_CONCAT(user_skills.skill, ', ')")
->where('job_id', $value)
->join('users', 'job_applicants.user_id', '=', 'users.id')
->join('user_skills', 'users.id', '=', 'user_skills.user_id')
->groupBy('job_applicants.job_id')
->get();
I have a 3 table questions,registrations,ssi_tracks i need to get details from the registraions table by corresponding to other two tables
i need to get details from registrations based on
questions.question_schedul=0 ,ssi_tracks.track_first_status
i have wrote query but it says the column is not found here is my query
$register = DB::table('registrations')
->join('questions', 'registrations.registration_id', '=', 'questions.question_id')
->join('ssi_tracks','registrations.registration_id','=','ssi_tracks.registration_id')
->select('address', 'model', 'chassis', 'delivery_date','ssi_tracks.track_first_status')
->where([["questions.question_schedul", "=", $dropselected] and ['ssi_tracks.track_first_status',0]])
->get();
Try this:
$register = DB::table('registrations as R')
->select('R.address', 'R.model', 'R.chassis', 'R.delivery_date','S.track_first_status')
->join('questions as Q', 'R.registration_id', '=', 'Q.question_id')
->join('ssi_tracks as S','R.registration_id','=','S.registration_id')
->where('Q.question_schedul', '=', $dropselected)
->where('S.track_first_status', '=', 0)
->get();
Make sure you have used the right column here from question table for matching registration id:
->join('questions as Q', 'R.registration_id', '=', 'Q.question_id')
try this query :
$register = DB::table('registrations')
->leftJoin('questions', 'registrations.registration_id', '=', 'questions.question_id')
->leftJoin('ssi_tracks','registrations.registration_id','=','ssi_tracks.registration_id')
->select('registrations.address', 'registrations.model', 'registrations.chassis', 'registrations.delivery_date','ssi_tracks.track_first_status')
->where(['questions.question_schedul'=>$dropselected,'ssi_tracks.track_first_status'=>0])
->get();
So I'm not sure whether I asked the question well. I'm new to laravel and right now I'm building an application where I need to fetch data for a user if certain conditions are met. This is what I'm trying to achieve:
Select from database where userid = $user and userstatus = active or inactive. or pending.
So all rows with the user id($user) and status(active, inactive and pending) will be returned.
I tried doing:
$users = DB::table('users')
->where('status', '=', 'active')
->orwhere('status', '=', 'inactive')
->orwhere('status', '=', 'pending')
->get();
This returned all the data in that particular table. What is the best way to go about this.
You have at least two options for how to do this you can use, including both so you have one for use in this case and one for general usage. Using a function in where creates a new block, so works like adding parentheses to your query
$users = DB::table('users')
->where('id', $user)
->where(function($query) {
$query->where('status', 'active')
->orWhere('status', 'inactive')
->orWhere('status', 'pending');
})->get();
or
$users = DB::table('users')->where('id', $user)->whereIn('status', ['active', 'inactive', 'pending'])->get();
You can do it as:
$users = DB::table('users')
->where('userid', $userid)
->whereIn('status',['active', 'inactive','pending'])
->get();
I try these code in MySQl:
SELECT
A.*,
B.name,
C.name
FROM
eventlog_tbl as A
LEFT JOIN users B ON A.byuser=B.email
LEFT JOIN users C ON A.affectiveuser=C.email;
I try these in Laravel
return DB::table('eventlog_tbl')
->leftjoin('users', 'users.email', '=', 'eventlog_tbl.byuser')
->leftjoin('users', 'users.email', '=', 'eventlog_tbl.affectiveuser')
->select('eventlog_tbl.*','users.name','users.name')
->get();
How can i convert it to Laravel?
Try below code:
$res = DB::table('eventlog_tbl')
->leftjoin('users AS A', 'A.email', '=', 'eventlog_tbl.byuser')
->leftjoin('users AS B', 'B.email', '=', 'eventlog_tbl.affectiveuser')
->select('eventlog_tbl.*','A.name as byuser_name','B.name as affectiveuser_name')
->get();
print_r($res);
This is your query written using the Laravel query builder.
$events = DB::table('eventlog_tbl')
->select('eventlog_tbl.*', 'users_1.name', 'users_2.name')
->leftJoin('users AS users_1', 'users_1.email', '=', 'eventlog_tbl.byuser')
->leftJoin('users AS users_2', 'users_2.email', '=', 'eventlog_tbl.affectiveuser')
->get();
Edit:
$events = DB::table('eventlog_tbl')
->select('eventlog_tbl.*', 'users_1.name AS user_1', 'users_2.name AS user_2')
->leftJoin('users AS users_1', 'users_1.email', '=', 'eventlog_tbl.byuser')
->leftJoin('users AS users_2', 'users_2.email', '=', 'eventlog_tbl.affectiveuser')
->get();
The problem is that both name columns are called the same thing. As per the accepted answer, these will need to be aliased differently too.
Why don't you convert this to use relationships? I have probably got the relationships wrong, something like this:
class EventLog extends Model
{
public function byUser()
{
return $this->hasOne(User::class, 'byuser', 'id');
}
public function affectiveUser()
{
return $this->hasOne(User::class, 'affectiveuser', 'id');
}
}
And then
$event_log = EventLog::with(['byUser', 'affectiveUser')->all();
foreach ($event_log as $item) {
echo $item->byUser->email();
}