I need your help please. I have this SQL query :
SELECT * , COUNT( * ) AS count FROM mytable GROUP BY email ORDER BY id DESC LIMIT 0 , 30
But I would like to do this in Symfony2 with Doctrine and the createQueryBuilder().
I try this, but didn't work :
$db = $this->createQueryBuilder('s');
$db->andWhere('COUNT( * ) AS count');
$db->groupBy('s.email');
$db->orderBy('s.id', 'DESC');
Can you help me please ? Thanks :)
You need to run 2 queries:
$db = $this->createQueryBuilder();
$db
->select('s')
->groupBy('s.email')
->orderBy('s.id', 'DESC')
->setMaxResults(30);
$qb->getQuery()->getResult();
and
$db = $this->createQueryBuilder();
$db
->select('count(s)')
->groupBy('s.email')
//->orderBy('s.id', 'DESC')
->setMaxResults(1);
$qb->getQuery()->getSingleScalarResult();
I tried to use
$query->select('COUNT(DISTINCT u)');
and it's seem to work fine so far.
$db = $this->createQueryBuilder('mytable');
$db
->addSelect('COUNT(*) as count')
->groupBy('mytable.email')
->orderBy('mytable.id', 'DESC')
->setFirstResult(0)
->setMaxResults(30);
$result = $db->getQuery()->getResult();
Hope it helps even if it's an old stack
Related
I am trying to write a MySQL select query using Laravel's Database Query Builder
I have this mysql query:
SELECT * FROM `tweets` WHERE `user_id` = 1 OR `user_id` in (SELECT `follows_id` from `follows` where `user_id` = 1)
I am trying to write it for Laravel
$users = DB::table('tweets')
->where('user_id', '=', 1)
how can this be done?
You can do something like this even though it looks ugly.
$tweets = DB::table('tweets')
->where('user_id', 1)
->orWhereIn('user_id', DB::table('follows')->select('follows_id')->where('user_id', 1)->pluck('follows_id'))
->get();
I would suggest a SQL rewrite as OR and IN(SELECT ...) tends to optimize badly.
The SQL result might be wrong as you didn't provide example data and expected result see Why should I provide a Minimal Reproducible Example for a very simple SQL query? for providing those.
SELECT
tweets.*
FROM
tweets
WHERE
tweets.user_id = 1
UNION ALL
SELECT
tweets.*
FROM
tweets
INNER JOIN
follows ON tweets.user_id = follows.follows_id
WHERE
follows.user_id = 1
I believe the following Laraval code should do that. But not sure as i didn't program in Laravel for some time now.
<?php
$first = DB::table('tweets')
->select('tweets.*')
->where('user_id', '=', 1);
$second = DB::table('tweets')
->select('tweets.*')
->join('follows', 'tweets.user_id', '=', 'follows.follows_id')
->where('follows.user_id ', '=', 1)
->union($first)
->get();
?>
I have a working SQL query.
SELECT stuid,grade,SUM(full_amount) FROM due_payments group by stuid having SUM(full_amount) !=15600
This is working fine in MySQL workbench and phpmyadmin,But i cant seems to get this work in Laravel 5.3
I tried this on Laravel app with no Luck
$someVariable = Input::get(15600);
$results = DB::select( DB::raw("SELECT stuid,grade,SUM(full_amount) FROM due_payments
group by stuid having SUM(full_amount) =:somevariable)", array(
'somevariable' => $someVariable,
)));
Can someone Help me with this.Thank You.
First if all Input::get() doesn't take value as argument but the element name
$someVariable = Input::get(15600);
You can just use $someVariable = 15600;
Then use Query Builder rather than Raw SQL query
$results = DB::table('due_payments')
->select(array('stuid', 'grade', DB::raw('SUM(full_amount)')))
->groupBy('stuid')
->havingRaw('SUM(full_amount) != '.$someVariable)
->get();
Use query builder.
$results = DB::table('due_payments')
->select('stuid', 'grade',DB::raw('SUM(full_amount)'))
->groupBy('stuid')
->havingRaw('SUM(full_amount) != 15600')
->get();
I'm using Laravel and have a very specific query that I don't know how to implement with query builder.
The query:
SET #c_num=0;
SELECT *, #c_num:=#c_num+1 AS 'COUNT'
FROM table_name
WHERE USERID = 2
ORDER BY id
Thank you
You should be able to do something like:
DB::statement(DB::raw('SET #c_num = 0'));
$result = DB::table('table_name')
->selectRaw("*, #c_num:=#c_num+1 AS 'COUNT'")
->where('userid', 2)
->orderBy('id')
->get();
$data = DB::table('table_name')
->where('userid',2)
->select('table_name.*',DB::raw('(#c_num:=#c_num+1) Count')
->orderBy('id')
->get();
You can try the following
DB::table('table_name')
->selectRaw("*, #c_num:=IF(#c_num, #c_num+1, 1) as 'COUNT'")
->where('user_id', 2)
->orderBy('id');
In zend it is written like
$table = $this->getTable();
$select = $table->select()->where('status = ?',1)
->where('columnOne= ?', 1)
->order('columnTwo')
->limit(1);
similar to where, order, limit conditions how can I condition for LIKE?
My query is
SHOW TABLE STATUS LIKE 'tableName'
I tried in this way
$table = $this->getTable();
$query= $table->select("TABLE STATUS")
->like($table);
$id = mysql_query($query);
then I found that no method for LIKE is available in ZEND.
Then How can I write above query in Zend framerk?
Thanks in advance.
This works for me, so hopefully it should give you what you want:
$stmt = $dbAdapter->query("SHOW TABLE STATUS LIKE '$tableName';");
$tableStatus = $stmt->fetchObject();
How would you write the following query in Zend framework?
SELECT * FROM table_name ORDER BY FIELD(field_name, 'Small','Medium','Large');
I just need the "Order by" part :)
Thanks!
What about this:
$db = Zend_Db_Table::getDefaultAdapter();
$select = $db->select();
$select->from('table_name')
->order(new Zend_Db_Expr("FIELD(field_name, 'Small','Medium','Large')"));
var_dump($select->assemble());
Results in:
string 'SELECT `table_name`.* FROM `table_name` ORDER BY FIELD(field_name, 'Small','Medium','Large')' (length=92)
$select->order(new Zend_Db_Expr('FIELD(field_name, 'Small','Medium','Large')'));
I think you should do:
$db = Zend_Db::factory( ...options... );
$select = $db->select()
->from(table_name)
->order(new Zend_Db_Expr("FIELD(field_name, 'Small','Medium','Large')")));