Zend DB Select : ORDER BY FIELD('id',some_array) - how? - mysql

How would you write the following query in Zend framework?
SELECT * FROM table_name ORDER BY FIELD(field_name, 'Small','Medium','Large');
I just need the "Order by" part :)
Thanks!

What about this:
$db = Zend_Db_Table::getDefaultAdapter();
$select = $db->select();
$select->from('table_name')
->order(new Zend_Db_Expr("FIELD(field_name, 'Small','Medium','Large')"));
var_dump($select->assemble());
Results in:
string 'SELECT `table_name`.* FROM `table_name` ORDER BY FIELD(field_name, 'Small','Medium','Large')' (length=92)

$select->order(new Zend_Db_Expr('FIELD(field_name, 'Small','Medium','Large')'));

I think you should do:
$db = Zend_Db::factory( ...options... );
$select = $db->select()
->from(table_name)
->order(new Zend_Db_Expr("FIELD(field_name, 'Small','Medium','Large')")));

Related

Fat free Framework Parameterized queries LIKE [duplicate]

I am running problems in implementing LIKE in PDO
I have this query:
$query = "SELECT * FROM tbl WHERE address LIKE '%?%' OR address LIKE '%?%'";
$params = array($var1, $var2);
$stmt = $handle->prepare($query);
$stmt->execute($params);
I checked the $var1 and $var2 they contain both the words I want to search, my PDO is working fine since some of my queries SELECT INSERT they work, it's just that I am not familiar in LIKE here in PDO.
The result is none returned. Do my $query is syntactically correct?
You have to include the % signs in the $params, not in the query:
$query = "SELECT * FROM tbl WHERE address LIKE ? OR address LIKE ?";
$params = array("%$var1%", "%$var2%");
$stmt = $handle->prepare($query);
$stmt->execute($params);
If you'd look at the generated query in your previous code, you'd see something like SELECT * FROM tbl WHERE address LIKE '%"foo"%' OR address LIKE '%"bar"%', because the prepared statement is quoting your values inside of an already quoted string.
Simply use the following:
$query = "SELECT * FROM tbl WHERE address LIKE CONCAT('%', :var1, '%')
OR address LIKE CONCAT('%', :var2, '%')";
$ar_val = array(':var1'=>$var1, ':var2'=>$var2);
if($sqlprep->execute($ar_val)) { ... }
No, you don't need to quote prepare placeholders. Also, include the % marks inside of your variables.
LIKE ?
And in the variable: %string%
$query = "SELECT * FROM tbl WHERE address LIKE ? OR address LIKE ?";
$params = array("%$var1%", "%$var2%");
$stmt = $handle->prepare($query);
$stmt->execute($params);
You can see below example
$title = 'PHP%';
$author = 'Bobi%';
// query
$sql = "SELECT * FROM books WHERE title like ? AND author like ? ";
$q = $conn->prepare($sql);
$q->execute(array($title,$author));
Hope it will work.

Laravel - How to do a specific query with query builder

I'm using Laravel and have a very specific query that I don't know how to implement with query builder.
The query:
SET #c_num=0;
SELECT *, #c_num:=#c_num+1 AS 'COUNT'
FROM table_name
WHERE USERID = 2
ORDER BY id
Thank you
You should be able to do something like:
DB::statement(DB::raw('SET #c_num = 0'));
$result = DB::table('table_name')
->selectRaw("*, #c_num:=#c_num+1 AS 'COUNT'")
->where('userid', 2)
->orderBy('id')
->get();
$data = DB::table('table_name')
->where('userid',2)
->select('table_name.*',DB::raw('(#c_num:=#c_num+1) Count')
->orderBy('id')
->get();
You can try the following
DB::table('table_name')
->selectRaw("*, #c_num:=IF(#c_num, #c_num+1, 1) as 'COUNT'")
->where('user_id', 2)
->orderBy('id');

SQL query with count and group by in Symfony2 QueryBuilder

I need your help please. I have this SQL query :
SELECT * , COUNT( * ) AS count FROM mytable GROUP BY email ORDER BY id DESC LIMIT 0 , 30
But I would like to do this in Symfony2 with Doctrine and the createQueryBuilder().
I try this, but didn't work :
$db = $this->createQueryBuilder('s');
$db->andWhere('COUNT( * ) AS count');
$db->groupBy('s.email');
$db->orderBy('s.id', 'DESC');
Can you help me please ? Thanks :)
You need to run 2 queries:
$db = $this->createQueryBuilder();
$db
->select('s')
->groupBy('s.email')
->orderBy('s.id', 'DESC')
->setMaxResults(30);
$qb->getQuery()->getResult();
and
$db = $this->createQueryBuilder();
$db
->select('count(s)')
->groupBy('s.email')
//->orderBy('s.id', 'DESC')
->setMaxResults(1);
$qb->getQuery()->getSingleScalarResult();
I tried to use
$query->select('COUNT(DISTINCT u)');
and it's seem to work fine so far.
$db = $this->createQueryBuilder('mytable');
$db
->addSelect('COUNT(*) as count')
->groupBy('mytable.email')
->orderBy('mytable.id', 'DESC')
->setFirstResult(0)
->setMaxResults(30);
$result = $db->getQuery()->getResult();
Hope it helps even if it's an old stack

How to run raw SQL Query with Zend Framework 2

Is there a way to execute a SQL String as a query in Zend Framework 2?
I have a string like that:
$sql = "SELECT * FROM testTable WHERE myColumn = 5"
now I want to execute this string directly.
Just pass the sql string to your db adapter like this:
$resultSet = $adapter->query($sql, \Zend\Db\Adapter\Adapter::QUERY_MODE_EXECUTE);
And if you want to pass parameters:
$sql = "SELECT * FROM testTable WHERE myColumn = ?";
$resultSet = $adapter->query($sql, array(5));
EDIT: Please note that the query method does not always returns a resultset. When its a resultset producing query(SELECT) it returns a \Zend\Db\ResultSet\ResultSet otherwise(INSERT, UPDATE, DELETE, ...) it will return a \Zend\Db\Adapter\Driver\ResultInterface.
And when you leave the second Parameter empty you will get a \Zend\Db\Adapter\Driver\StatementInterface which you can execute.
use Zend\Db\Sql\Sql;
use Zend\Db\Adapter\Adapter;
$dbAdapterConfig = array(
'driver' => 'Mysqli',
'database' => 'dbname',
'username' => 'dbusername',
'password' => 'dbuserpassword'
);
$dbAdapter = new Adapter($dbAdapterConfig);
$sql = new Sql($dbAdapter);
$select = $sql->select();
$select->from('testTable');
$select->where(array('myColumn' => 5));
$statement = $sql->prepareStatementForSqlObject($select);
$result = $statement->execute();
S. docu: Zend\Db → Zend\Db\Sql
If you are using tableGateway, you can run your raw SQL query using this statement,
$this->tableGateway->getAdapter()->driver->getConnection()->execute($sql);
where $sql pertains to your raw query. This can be useful for queries that do not have native ZF2 counterpart like TRUNCATE / INSERT SELECT statements.
If you have EntityManager $em on your hands, you can do something like this:
$select = $em->getConnection()->executeQuery("
SELECT a.id, a.title, a.announcement, asvc.service_id, COUNT(*) AS cnt,
GROUP_CONCAT(asvc.service_id SEPARATOR \", \") AS svc_ids
FROM article AS a
JOIN articles_services AS asvc ON asvc.article_id = a.id
WHERE
asvc.service_id IN (
SELECT tsvc.service_id
FROM tender AS t
JOIN tenders_services AS tsvc ON tsvc.tender_id = t.id
WHERE t.id = :tenderId
)
GROUP BY a.id
ORDER BY cnt DESC, a.id DESC
LIMIT :articlesCount
", [
'articlesCount' => 5,
'tenderId' => $tenderId,
], [
'articlesCount' => \PDO::PARAM_INT,
]);
$result = $select->fetchAll(); // <-- here are array of wanted rows
I think this way to execute complex queries is best for Zend. But may be I'm not very smart in Zend still. Will glad to see if it helps to someone.

MySql SHOW query in ZEND

In zend it is written like
$table = $this->getTable();
$select = $table->select()->where('status = ?',1)
->where('columnOne= ?', 1)
->order('columnTwo')
->limit(1);
similar to where, order, limit conditions how can I condition for LIKE?
My query is
SHOW TABLE STATUS LIKE 'tableName'
I tried in this way
$table = $this->getTable();
$query= $table->select("TABLE STATUS")
->like($table);
$id = mysql_query($query);
then I found that no method for LIKE is available in ZEND.
Then How can I write above query in Zend framerk?
Thanks in advance.
This works for me, so hopefully it should give you what you want:
$stmt = $dbAdapter->query("SHOW TABLE STATUS LIKE '$tableName';");
$tableStatus = $stmt->fetchObject();