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I need to query a database table. structure:
id---bid ---veh_id---user_id
There is many data, all are veh_id related. User can place bid on veh_id as many as they want and on many veih_id.
I need to find the average bid on each veh_id and also the max bid receive for that veh_id. Can this be done in one SQL query. The optimal would have the difference betwenn the average and the max number. All group by veh_id.
I don't know where to start.
If I understood correctly:
SELECT MAX(bid), AVG(bid) FROM someTable GROUP BY veh_id
Related
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I am developing an application that has database of mysql having orders and orderdetails table. order table having column orderStatus. My question is whether it is necessary to create another order log table if order status is 'closed' (that means completed orders) or just orderstatus column is enough.
From what you have described, I would assume a column is sufficient.
You might need another table if:
An order can have more than one status at the same time
You need to keep a history of when the order changed status
There might be other cases that would require another table, but you haven't described that any such condition applies in your case, as far as I can tell.
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How to retrieve all the data pertaining to company name and agent from mysql? How to write the query statement?
Have you tried this?
SELECT *
FROM agent_info
WHERE policyCompany = 'Avia' and policyAgent = 'Ron';
I have to guess because you didn't tell us much about your tables, but this might work.
SELECT policyCompany,
GROUP_CONCAT(DISTINCT policyAgent ORDER BY policyAgent) agents
FROM mytable
GROUP BY policyCompany
You can read about GROUP_CONCAT() here.
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How can I add a grouping for the "retirements" table by the "id_type" field and not just for everyone?
select name,
sum(retirements.price_per_product)
from retirements
join type_of_products top on retirements.id_product = top.id
where (date between '1998-11-01' and '1998-11-14')
group by name;
Do not resort to aggregate functions of each type? It's so rude.
There are two different ways to achieve this.
1. You may use a sub-query but it is expensive in terms of performance.
2. You may utilize the #temp table and join it in later part. A downside is it is
longer to code but performance is good especially in the long run.
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Would anyone be able to help me with creating a procedure that reports the total amount paid in a specific month and specific year? Or how I would even go about creating this?
Thank you for any and all help.
I'm guessing you have a table that includes both a date column as well as an amount paid column. If that is the case, and you just want to sum the amount paid you can just use the SUM() function.
Try this:
SELECT SUM(totalAmountPaid) as totalForMonth
FROM tableName
WHERE MONTH(dateColumn) = monthYouWant AND YEAR(dateColumn) = yearYouWant
Here are date and time functions that may be useful.
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https://www.dropbox.com/s/7i5y1aggfjzl39c/photo.png
I want to get a total amount of playtime from the 38,000 users.
In addition, I want the sql query that will add the previous amount on the "playtime" column from each line and find a final sum.
Edit: Im really unsure If I was specific enough, I never ever got in a hard situation like this at expressing myself with English.
SELECT SUM(Playtime) FROM players;
That will give you the total amount of playtime from all users.
If you want to print the accumulated time on each row, try something like
SELECT #accumulated:=#accumulated+playtime as accum FROM players, (select #accumulated:=0) as accum