Forgive me if I get some terms wrong, still trying to learn advanced mySql queries. I am trying to export data from a ecommerce platform, and some of the data I need is in lookup tables, the issue is the one lookup table I have can have more than 1 value associated, and the system I need to get the data into requires a specific format for that column.
I am using zen cart as my source if that helps, and below is the query.
Select zp.products_id as id, zpd.products_name as name, products_price_w as cost, products_price as price, zp.products_date_added as date_created, zp.products_image as thumbnail
FROM `zen_products` as zp
LEFT JOIN `zen_products_description` as zpd ON zp.products_id = zpd.products_id
WHERE zp.products_status = 1
ORDER BY zp.products_id ASC;
What I need is theres a look up table that tells me what categories belong to each product, I know it's going to be another join, but I need it so if more than 1 category belongs to a product to put it in the same column, and join them with a # symbol, and its not the id's of the category, its the path, so I need to look up the category ID to another table to get the path.
So "category1/subcategory#category2" for example..
Thanks for any guidance.
EDIT: I still need to get the results merged as I am getting double the results I want, but I see a record for each category it's in with this..
Select zp.products_id as id, zpd.products_name as name, zcd.categories_name as categories, products_price_w as cost, products_price as price, zp.products_date_added as date_created, zp.products_image as thumbnail
FROM `zen_products` as zp
INNER JOIN `zen_products_description` as zpd ON zp.products_id = zpd.products_id
INNER JOIN `zen_products_to_categories`as zptc ON zp.products_id = zptc.products_id
INNER JOIN `zen_categories_description` as zcd on zptc.categories_id = zcd.categories_id
WHERE zp.products_status = 1
ORDER BY zp.products_id ASC;
What you are looking for is group_concat(). I think it would be something like this:
Select zp.products_id as id, zpd.products_name as name,
group_concat(zcd.categories_name separator '#') as categories,
products_price_w as cost, products_price as price,
zp.products_date_added as date_created, zp.products_image as thumbnail
FROM `zen_products` as zp
INNER JOIN `zen_products_description` as zpd ON zp.products_id = zpd.products_id
INNER JOIN `zen_products_to_categories`as zptc ON zp.products_id = zptc.products_id
INNER JOIN `zen_categories_description` as zcd on zptc.categories_id = zcd.categories_id
WHERE zp.products_status = 1
group by zp.products_id
ORDER BY zp.products_id ASC;
Related
I have one table products with id of product and name.
Second table is products_last_usage where I keep product_id, user_id and last_used_at.
Whenever a user clicks on a product, I have the field last_used_at updated.
Now, I need a query to list all products, and order them first by last_used_at, and then by name of product. It has to be PER USER. i.e. every user will have his own order of the table.
But I need all products, even if there are no records of them in the second table.
How to do that?
You can help me with a rails query or mysql query.
You can use a left join:
select p.*
from products p left join
products_last_usage plu
on plu.product_id = p.id and plu.user_id = $user_id
order by (last_used_at is not null) desc, last_used_at desc;
Ordering by last_used_at desc should also work. However, I think it is clearer to explicitly handle NULL values.
I think you can start from something like this. Pls next time post sample data, expected results etc.
SELECT A.PRODUCT_ID
, A.PRODUCT_NAME
, B.USER_ID
, B.LAST_USED_AT
FROM PRODUCTS A
LEFT JOIN PRODUCTS_LAST_USAGE B ON A.PRODUCT_ID = B.PRODUCT_ID
ORDER BY B.USER_ID, B.LAST_USED_AT DESC, A.PRODUCT_NAME;
I'm trying to merge these two statements into one query to get the a list of product names(or ids) against the average of their TTFF data, and I'm stuck.
select AVG(TTFF) from TTFFdata group by product_id
select product.product_name, count(*) from product join TTFFdata on product.product_id = TTFFdata.product_id
I've looked into using a temporary table (CREATE TEMPORARY TABLE IF NOT EXISTS averages AS (select AVG(TTFF) from TTFFdata group by product_id)) but couldn't get that to work with a join.
Anyone able to help me please?
You need to understand the components. Your second query is missing a group by. This would seem to be what you want:
select p.product_name, count(t.product_id), avg(t.TTFF)
from product p left join
TTFFdata t
on p.product_id = t.product_id
group by p.product_name
It is better to do group by on product_id, product_name for two reasons. One is, you can select product id along with product name. Second reason is, If the product name is not unique then it may give wrong results(this may be a rare scenario like product name is same but it differs based on other columns like version or model). The below is the final query.
select Product.product_id,
product_name,
AVG(TTFF) as Avg_TTFF
from Product
inner join
TTFFdata
on Product.product_id = TTFFdata.product_id
group by Product.product_id,Product.product_name
TTFFdata:
product:
Output:
I am trying to fetch some combined result from two separate individual tables.
The transaction_fact table has around 3.6 million rows and translation_table has around 300000 rows.
Now i want a sum of amount for all transactions grouped by location and the product within that location. But as the fact table has only location id and product id and i would like the names in the result , I am using sub query.
My query is as follows:
SELECT
( SELECT translation
FROM translation_table
WHERE dim_name LIKE 'location_dim'
AND lang_id LIKE 'es'
AND dim_id LIKE CAST(o.loc_id AS CHAR(50))
AND field_name LIKE 'city') AS Location
, ( SELECT product_name
FROM prod_dim
WHERE prod_id = o.prod_id) AS Product
, SUM(amount)
FROM transaction_fact o
GROUP
BY loc_id
, prod_id
ORDER
BY loc_id
, prod_id;
But this query is not returning anything , just keeps on processing.
I waited for about one and half hour but still no result.
Please tell me what might be going wrong.
Joining the tables should eliminate the need for subqueries and give some performance boost. If not you may need to provide more details on the table structure before we can help. Something like this should get you started:
SELECT t.translation AS Location, p.product_name AS Product, SUM(o.amount) AS Total
FROM transaction_fact o
INNER JOIN translation_table t ON CAST(o.loc_id AS char(50)) = t.dim_id
INNER JOIN prod_dim p ON p.prod_id = o.prod_id
WHERE t.dim_name = 'location_dim'
AND t.lang_id = 'es'
AND t.field_name = 'city'
GROUP BY t.translation, p.product_name
ORDER BY o.loc_id, o.prod_id;
Notes: I've changed the LIKEs to =, as LIKE is for when you want to match on a pattern that includes wildcards.
The CAST that is used in the join to translation_table is not ideal. If you could do away with that you'd get better performance.
I have a mysql table Products.
It contains the Columns "id,product_name,product_seller,price"
I am trying to create a PHP script to Insert/Update data in the table Products using the seller name (product_seller).
The issue
I don't know what mysql query to use in order to get: A list with All the products NO matter if the seller has it or not and if the seller has the products to give me the details (id,product_name,product_seller,price).
EXAMPLE of what i want to get:
1 - apples - seller A - 12
2 - banana - -
3 - oil - -
4 - dvd - seller A - 25
The product_name must be DISTINCT
Thanks in advance!
* Query must be something like "SELECT DISTINCT product_name FROM Products and let me know where Seller A has the product, at what price, what id what product WHERE seller_name = 'seller A'...yet, show me all products, n matter if seller has it"
Seems to be a straight forward subquery to get a unique list of products then an outer join to get the seller info.
SELECT A.ID, A.Product_name, B.product_Seller, B.Price
FROM (SELECT DISTINCT ID, Product_Name FROM products) A
LEFT JOIN Products B
on A.ID = B.ID
and B.product_Seller = 'seller A'
The LEFT JOIN will ensure you return all the products and only seller information related to the items for 'SELLER A'
SQL generally operates best on data SETS. So I first generate a set of unique IDs and products and then LEFT JOIN this to the sellers product data you desire. The left join ensures we keep all the items. The filtering of the seller MUST be on the JOIN itself and not in the where clause. Otherwise the left join in essence becomes an inner as the NULLS generated from the outer join are removed.
SELECT A.ID, A.Product_name, B.product_Seller, B.Price
FROM (SELECT DISTINCT ID, Product_Name FROM products) A
LEFT JOIN Products B
on A.ID = B.ID
WHERE B.product_Seller = 'seller A'
Wouldn't get the desired result. This is because the where clause is applied after the join so the items that are not associated to the seller would be excluded. Since you want those records, you must use a left join and apply the limit on the JOIN so the items not associated to the seller are returned.
When I initially started with SQL I had trouble with this type of logic. It wasn't until I considered data in terms of "SETS" and how those sets related, that how to solve these questions became easier.
try to use the
SELECT * FROM Products_Table ;
this will obtain all the table values
working with mySql I would like to list all purchases that customers made on a specific cathegory of products.
So, I had 3 tables: customers (idCustomer, Name) , cathegories (idCategory, CategoryName) and orders (idOrder, idCustomer, idCathegory, Qty, Price)
But I want a listing with ALL of the customers.
Not only the one who bought that specific idCategory
I thought something like:
select sum(Orders.Qty), Customers.Name
from Orders
right join Customers on Orders.idCustomer = Customer.idCustomer
where Orders.idCategory = 'Notebooks'
group by Orders.idCategory
but this statement only lists the records for customers who exists in Orders table.
And I want all of them ( the one who didnt buy, with qty =0 )
thanks in advance
Most people find left join easier to follow than right join. The logic for left join is to keep all rows in the first table, plus additional information from the remaining tables. So, if you want all customers, then that should be the first table.
You will then have a condition on the second table. Conditions on all but the first table should be in the on clause rather than a where. The reason is simple: when there is no match, then the value will be NULL and the where condition will fail.
So, try something like this:
select sum(o.Qty) as sumqty, c.Name
from Customers c left join
Orders o
on o.idCustomer = c.idCustomer and
o.idCategory = 'Notebooks'
group by c.Name;
Finally, the group by should have a relationship to the select clause.
Try this query
select sum(Orders.Qty), Customers.Name
from Customers
right join Orders on Customer.idCustomer = Orders.idCustomer and Orders.idCategory = 'Notebooks'
group by Customers.Name