I have a Database table userinfo. In that userinfo-table there are fields user_id, user_name, user_birth.
My goal is to get upcoming birthdays of the users, in my case 6 next ones. I have found examples for same kind of thing but they all have used DATE-dbformat and those examples doesnt work for me because in my table the user_birth values are in unix timestamp-format.
I would appreciate if someone has an examplecode for that how it would be possible to make.
The result what I have tried to get out would be something like(when today is 23.06):
27.06 Mike
11.10 Steve
23.10 John
25.12 Dave
07.01 Andy
12.02 Mark
Those would be the next 6 birthdays after 23.06, year should not matter.
Thanks in advance.
Well, use from_unixtimestamp() to get it in a date/time format. So, the query would be something like this:
select *
from t
order by (case when month(date(from_unixtimestamp(user_birth))) = month(now()) and
day(date(from_unixtimestamp(user_birth))) > day(now()) or
month(date(from_unixtimestamp(user_birth))) > month(now())
then 1 else 0
end) desc,
month(date(from_unixtimestamp(user_birth))),
day(date(from_unixtimestamp(user_birth)))
limit 6
The first part of the order by puts later dates in the year first. Then dates are ordered by month and day of month.
Related
I've just started a job and my boss wants me to learn mySQL so please bear with me, i've been learning for only 2 days and i'm not that good at it yet.
So i've been given 3 tables and several tasks to do.
The tables are:
mobile_log_messages_sms
mobile_providers
service_instances
And in them i've got to:
Find out how many messages there were in the last 25 days and how
much income did they make
Then i need to group them by day (so per day, exclude hours) and
provider name.
Also i need to ignore all the messages that have an empty string
under the service column
Also i need to ignore the messages that made 0 income and count only
those that have the column service_enabled = 1
And then i need to sort it descending, by date.
in the tables
mobile_log_messages_sms:
message_id - used to count the messages
price - using for price obviously, exlude those with 0
time - date in yyyy/mm/dd hh:mm:ss format
service - exclude all those that have an empty string (or null)
mobile_providers
provider_name - to use to group with
service_instances
enabled - only use if value is 1
I've started with:
SELECT message_id, price, time
FROM mobile_log_messages_sms
WHERE time BETWEEN '2017-02-26 00:00:00'
AND time AND '2017-03-22 00:00:00'
But i need to change the date format and then use the JOIN commands but i don't know how, and i know i need to add more to it, but i'm stumped even at the start. Also the starting just lists the messages but i need to count the total sum of the income (price) per day.
Can anyone point me in the right direction at least since i'm still a noob? Many thanks in advance and sorry if i worded something badly, english is not my first language.
Find out how many messages there were in the last 25 days and how much income did they make
1.
SELECT COUNT(message_id), SUM(price)
FROM mobile_log_messages_sms
WHERE CAST(time AS DATE) BETWEEN DATE_SUB(CURRENT_DATE,INTERVAL 25 DAY)
AND CURRENT_DATE;
2.
SELECT COUNT(message_id), SUM(price)
FROM mobile_log_messages_sms
WHERE CAST(time AS DATE) BETWEEN DATE_SUB(CURRENT_DATE,INTERVAL 25 DAY)
AND CURRENT_DATE
GROUP BY CAST(time AS DATE);
3.
SELECT COUNT(message_id), SUM(price)
FROM mobile_log_messages_sms
WHERE CAST(time AS DATE) BETWEEN DATE_SUB(CURRENT_DATE,INTERVAL 25 DAY)
AND CURRENT_DATE AND service IS NULL
GROUP BY CAST(time AS DATE);
rest can't done with join so make sure that at least one column should be common in tables.
I am trying to retrieve last 3 months records. I need to sum order total amount by week. I have made following query.
select CONCAT("Week", WEEK(created_at)) as week_number, sum(total_cost)
from certified_diamond_orders
where created_at > 2016-11-22
and status = "delivered"
group by week("created_at")
But I am only getting one record with this. Infact my table has 2 years entries. Also I was trying to figure out how I can pull week start date and end date to diplay on my chart.
Any suggestions where I am making mistake?
week("created_at") looks like you're trying to determine the week of the string "created_at" rather than the column created_at. Which might explain why you're only getting one row in your result.
The date 2016-11-22 also looks suspiciously like a sum instead of a date (2016 - 11 - 22 = 1983 vs "2016-11-22"
Try this:
SELECT
CONCAT('Week', WEEK(created_at)) AS week_number,
SUM(total_cost)
FROM certified_diamond_orders
WHERE
created_at > '2016-11-22' AND
status = 'delivered'
GROUP BY WEEK(created_at)
I'm in need of some help structuring in-time queries. There's a few of them I need - but I think that if I can be shown how to do one, I can figure out the others.
What I'm after:
-Rolling 12 month view of 'inactive accounts'...ie number of accounts that have not placed an order in the 12 months prior.
-This ideally will be a subquery (in a much larger script) joining back on to a dates table (see below)
January 2015 | # of customers with no orders from 1/2014-1/2015
February 2015 | # of customers with no orders from 2/2014-2/2015
March 2015 | # of customers with no orders from 3/2014-3/2015
etc...
What I'm having trouble wrapping my mind around is how I'd structure a where clause to ensure that it scans all orders and only returns the total of account ID's that had not placed an order in the year prior to that month. I've used different combinations of DATEDIFF, DATESUB etc.
SELECT DATE_FORMAT(order_datetime, '%Y-%m'), COUNT DISTINCT (account_id)
FROM warehouse.orders
JOIN warehouse.accounts ON xyz
WHERE...
It feels like I'm on the right path - I just keep mentally going in circles trying to figure this out.
Cheers and thanks in advance.
I don't have enough reputation points to simply comment on your question. I don't fully understand it though.
Are you using SQLServer/TSQL or MySQL?
Do you want to have just one column which calculates the last 12 months' rolling average or 12 columns for the rolling average each month? If it is just one figures for the last 12 months tolling do you want that to be from the current day or the beginning of that month?
If it was SQL Server and a rolling 12 months to now, the calculation could be:
SELECT SUM(CASE WHEN DATEDIFF(y,GETDATE(),order_date_time) < 1 THEN COUNT(DISTINCT account_id) END) as January2015
If you're using MySQL replace GETDATE() with NOW()
If you want one value rolling but to the beginning of the month then you could use:
SELECT SUM(CASE WHEN DATEDIFF(y,DATEADD(M, DATEDIFF(M, 0, GETDATE()), 0),order_date_time) < 1 THEN COUNT(DISTINCT account_id) END) as January2015
If I've missed the point entirely, please let me know and I'll happily amend the answer
You should query between dates, in order to get the count of events for each id.
select case
when count(account_id)<0 then 'INACTIVE'
when count(account_id)>0 then 'ACTIVE'
from warehouse.orders
where data_format(order_datetime, '%m/%Y') between '1/2014' and '1/2015'
group by account_id)
There is a table Post in my database which contains posts of different users. What I wanna do is to create an sql query that'll return as per respective month the number of posts being made each day. Kindly let me know how can i do that generically in one query i can create multiple queries for all days but that is a worst case scenario. So I need expert's solution to this.
Thanks
Expected output:
(Query counts the number of posts for all the days in a respective month)
Day : Number of posts
1 : 20
2 : 25
3 : 10
4 : 17
.........................
30 : 6
Table Structure:
ID | postid | post | date
select DAYOFMONTH(date) as Day , count(*) as Number_of_posts
from table
group by DAYOFMONTH(date)
You should know that if table contains data from different months number of posts will be wrong.
So the group by should be by date and you should use date in selected instead of day of month.
SELECT DAYOFMONTH(date), count(*) FROM Post
GROUP BY DAYOFMONTH(date)
ORDER BY DAYOFMONTH(date) ASC;
If you want to query for a specific month (say, February) then use this:
SELECT DAYOFMONTH(date), count(*) FROM Post
WHERE MONTH(date) = '2'
GROUP BY DAYOFMONTH(date)
ORDER BY DAYOFMONTH(date) ASC;
Note: Months are returned in number form where the MONTH() function is used.
EDIT: If you're looking to return counts for EVERY day in a given month, then I'd push you here - a great accepted answer to a similar question: How to get values for every day in a month
SELECT date, COUNT(id) as number_of_posts FROM table_name GROUP BY date.
As part of database testing, we are to verify if the data is correctly rendered onto the webpage from database.
We have a table called 'emp_details' which stores employee details. We store joining date of an employee in it. Now, using this joining date field, I need to get a list all the employees who have a start date or anniversary date within the last ten days.
I tried various combinations of DATEDIFF() in MySQL but did not succeed.
The format on the webpage would look like this:
Name Start Date Years
----------------------------------
William 07/25/2004 8
Gordon 07/22/2007 5
Jill 07/26/2009 3
Could anyone please help me with the query for MySQL DB.
Thanks,
select * from
employees where
dayofyear(`start date`) between dayofyear(curdate())-10 and dayofyear(curdate())
You can use following in WHERE clause
DAYOFYEAR(CURDATE()) - DAYOFYEAR(start_date) < 10
OR is greater than (365 - 10)