As part of database testing, we are to verify if the data is correctly rendered onto the webpage from database.
We have a table called 'emp_details' which stores employee details. We store joining date of an employee in it. Now, using this joining date field, I need to get a list all the employees who have a start date or anniversary date within the last ten days.
I tried various combinations of DATEDIFF() in MySQL but did not succeed.
The format on the webpage would look like this:
Name Start Date Years
----------------------------------
William 07/25/2004 8
Gordon 07/22/2007 5
Jill 07/26/2009 3
Could anyone please help me with the query for MySQL DB.
Thanks,
select * from
employees where
dayofyear(`start date`) between dayofyear(curdate())-10 and dayofyear(curdate())
You can use following in WHERE clause
DAYOFYEAR(CURDATE()) - DAYOFYEAR(start_date) < 10
OR is greater than (365 - 10)
Related
How do I find all records 7 days before a field in an SQL database?
I need to find all transaction dates that were placed 7 days before the pickup date of the same record.
I am currently using SequelPro so that my have an effect on available syntaxes.
This is currently my table that I am pulling the records from.
This is the exact question I am being asked;
Write a query to display all details of transactions that were made at least one
week before the pickup date.
Isn't it straightforward?
SELECT * FROM TransactionTable
WHERE DATEDIFF(pickupdate, transactiondate) >= 7;
I have no experience working with DB2 before and I'm kind of stuck in something. I'm working on a project in SSIS reading from DB2 where I write into a flat file. I need to run the process weekly and get data from past 7 days.
My query works this way:
Select * From Table
Where ServiceDate >= 2200624 - 7
The above query brings data from the past 7 days, but this query don't work for me since I need to execute this process weekly. I need something like this:
Select * From Table
Where ServiceDate >= DATE(CURRENT_DATE - 7 DAY)
The second query throws an error, is there any other way to achieve this? I'm using ODBC source and I was thinking to use a dynamic query in SSIS but I'm not sure how this works in ODBC source, any suggestions or help will be appreciated.
EDIT:
This tables were created a long time ago, so I don't have any information about the data type of these tables.
The actual date 2200624 correspond to 20200624. This is the way that my date shows in the table.
Thanks in advance
For ServiceDate as YYYYMMDD INT:
Select * From Table
Where ServiceDate >= INT(TO_CHAR(CURRENT_DATE - 7 DAY, 'YYYYMMDD'));
If ServiceDate is CHAR(7) or equivalent, and if value 2200624 corresponds to YYYYMMDD date 20200624 as per your edited question, then the following examples might help.
It assumes ServiceDate values beginning with first character 1 are in the 20th century (19xx years), and dates with first character 2 are in the 21st century.
SELECT ... FROM ... WHERE ( TO_DATE(CASE SUBSTR(ServiceDate,1,1) WHEN '1' THEN '19'||SUBSTR(ServiceDate,2,6) WHEN '2' THEN '20'||SUBSTR(ServiceDate,2,6) END,'YYYYMMDD')) >= CURRENT DATE - 7 DAYS
This will perform badly, so don't use that!
An alternative that will perform better is to convert CURRENT DATE - 7 DAYS into a number that matches your storage-format like this:
...WHERE ServiceDate >= '2'||substr(TO_CHAR(CURRENT_DATE - 7 DAY, 'YYYYMMDD'),2,6)
and if ServiceDate is INTEGER column datatype then:
...WHERE ServiceDate >= int('2'||substr(TO_CHAR(CURRENT_DATE - 7 DAY, 'YYYYMMDD'),2,6))
Always state your Db2-server platform (Z/OS, i-series, Linux/Unix/Windows) when asking for help with Db2, because the answer may be different depending on the platform + version of your Db2-server.
I started a HR management project and I want to count days between 2 dates without counting the holidays and weekends. So the HR can count employee's day off
Here's the case, I want to count between 2018-02-14 and 2018-02-20 where there is an office holiday on 2018-02-16. The result should be 3 days.
I have already created a table called tbl_holiday where I put all weekends and holidays in one year there
I found this post, and I tried it on my MariaDB
Here's my query:
SELECT 5 * (DATEDIFF('2018-02-20', '2018-02-14') DIV 7) +
MID('0123444401233334012222340111123400012345001234550', 7 *
WEEKDAY('2018-02-14') + WEEKDAY('2018-02-20') + 1, 1) -
(SELECT COUNT(dates) FROM tbl_holiday WHERE dates NOT IN (SELECT dates FROM tbl_holiday)) as Days
The query works but the result is 4 days, not 3 days. It means the query only exclude the weekends but not the holiday
What is wrong with my query? Am I missing something? Thank you for helping me
#RichardDoe, from the question comments.
In a reasonable implementation of a date table, you create a list of all days (covering a sufficient range to cope with any query you may run against it - 15 years each way from today is probably a useful minimum), and alongside each day you store a variety of derived attributes.
I wrote a Q&A recently with basic tools that would get you started in SQL Server: https://stackoverflow.com/a/48611348/9129668
Unfortunately I don't have a MySQL environment or intimate familiarity with it to allow me to write or adapt queries off the top of my head (as I'm doing here), but I hope this will illustrate the structure of a solution for you in SQL Server syntax.
In terms of the answer I link to (which generates a date table on the fly) and extending it by adding in your holiday table (and making some inferences about how you've defined your holiday table), and noting that a working day is any day Mon-Fri that isn't a holiday, you'd write a query like so to get the number of working days between any two dates:
WITH
dynamic_date_table AS
(
SELECT *
FROM generate_series_datetime2('2000-01-01','2030-12-31',1)
CROSS APPLY datetime2_params_fxn(datetime2_value)
)
,date_table_ext1 AS
(
SELECT
ddt.*
,IIF(hol.dates IS NOT NULL, 1, 0) AS is_company_holiday
FROM
dynamic_date_table AS ddt
LEFT JOIN
tbl_holiday AS hol
ON (hol.dates = ddt.datetime2_value)
)
,date_table_ext2 AS
(
SELECT
*
,IIF(is_weekend = 1 OR is_company_holiday = 1, 0, 1) AS is_company_work_day
FROM date_table_ext1
)
SELECT
COUNT(datetime2_value)
FROM
date_table_ext2
WHERE
(datetime2_value BETWEEN '2018-02-14' AND '2018-02-20')
AND
(is_company_work_day = 1)
Obviously, the idea for a well-factored solution is that these intermediate calculations (being general in nature to the entire company) get rolled into the date_params_fxn, so that any query run against the database gains access to the pre-defined list of company workdays. Queries that are run against it then start to resemble plain English (rather than the approach you linked to and adapted in your question, which is ingenious but far from clear).
If you want top performance (which will be relevant if you are hitting these calculations heavily) then you define appropriate parameters, save the lot into a stored date table, and index that table appropriately. This way, your query would become as simple as the final part of the query here, but referencing the stored date table instead of the with-block.
The sequentially-numbered workdays I referred to in my comment on your question, are another step again for the efficiency and indexability of certain types of queries against a date table, but I won't complicate this answer any further for now. If any further clarification is required, please feel free to ask.
I found the answer for this problem
It turns out, I just need to use a simple arithmetic operator for this problem
SELECT (SELECT DATEDIFF('2018-02-20', '2018-02-14')) - (SELECT COUNT(id) FROM tbl_holiday WHERE dates BETWEEN '2018-02-14' AND '2018-02-20');
I have attendance data for employees stored in the table attendance with the following column names:
emp_id (employee ID)
date
type (leave, absent, etc.)
(there are others but I'm omitting them for the sake of simplicity)
My objective is to retrieve all dates of the given month on which the employee was on leave (type = 'Leave') and the last leave taken in the last month, if any.
It's easy to do it using two queries (I'm using PHP to get process the data), but is there any way this can be done in a single query?
I'm answering my own question so as to close it. As #bpgergo pointed out in the comments, UNION will do the trick here.
SELECT * FROM table_name
WHERE type="Leave" AND
date <= (CURRENT_DATE() - 30)
Select the fields, etc you want then se a combined where clause using mysql's CURRENT_DATE() function. I subtracted 30 for 30 days in a month.
If date is a date column, this will return everyone who left 1 month or longer ago.
Edit:
If you want a specific date, change the 2nd month like this:
date <= (date_number - 30)
Quite a simple question, but I haven't been able to find any useful resources to help with this.
Basically, I want to query my SQL database table, of which one of the fields is of type 'date'. Currently, the webpage outputs the three most recent records dependent on this date field. Ideally, I want to display all records which are under 4 months old, but I'm not sure how to go about implementing this in my query.
Can anyone advise?
SELECT * FROM table WHERE datecolumn > DATE_SUB(NOW(), INTERVAL 4 MONTH)
Will select all rows where the date is larger than 4 months ago (assuming you have no dates in the future - else you could use a BETWEEN)